Center of Gravity, Center of Mass & Centroid – Comprehensive Notes

Center of Gravity (C.o.G.)

  • Definition
    • Point where the entire weight of a body is considered to act, regardless of the body’s orientation.
    • Equivalent statement: the point about which the algebraic sum of gravitational‐force moments is zero: W<em>ix</em>i=0,  W<em>iy</em>i=0\sum W<em>i x</em>i = 0,\; \sum W<em>i y</em>i = 0 when referenced to that point.
  • Fundamental Properties
    • Unique for any rigid body; does not shift when the object is reoriented.
    • Depends on weight distribution; therefore varies with changes in gravitational field strength only through the change in weight itself.
  • Conceptual Significance
    • Serves as the ideal location to apply a single resultant weight force in statics/dynamics problems.
    • In engineering design (e.g., vehicles, structures, robots) stability is assessed with respect to whether the projected C.o.G. lies within the support base.

Center of Mass (C.o.M.)

  • Definition
    • Point at which the whole mass of a body may be assumed to be concentrated for translational motion analysis.
  • Key Attributes
    • Represents the average location of mass distribution: m=m<em>i,r</em>cm=m<em>ir</em>imim = \sum m<em>i, \qquad \vec r</em>{cm} = \frac{\sum m<em>i \vec r</em>i}{\sum m_i}.
    • Independent of gravitational field; remains fixed when gg varies or is zero (e.g., space-flight).
    • For bodies of uniform density in a uniform gravitational field, C.o.G. coincides with C.o.M.
  • Practical Insight
    • Crucial in dynamics (e.g., projectile motion, spacecraft attitude) where external forces act on the mass center.

Centroid (C)

  • Definition for Plane Areas
    • The geometric center at which the entire area of a 2-D lamina is assumed to be concentrated.
    • For laminae of uniform thickness/density in a uniform gravitational field: Centroid ≡ C.o.G. ≡ C.o.M.
  • Coordinate Formulas for a Plane Area
    xˉ=<em>AxdA</em>AdA,yˉ=<em>AydA</em>AdA\bar x = \frac{\int<em>A x \, dA}{\int</em>A dA}, \qquad \bar y = \frac{\int<em>A y \, dA}{\int</em>A dA}
    • Discrete composite form (used in examples): xˉ=A<em>ix</em>iA<em>i,yˉ=A</em>iy<em>iA</em>i\bar x = \frac{\sum A<em>i x</em>i}{\sum A<em>i}, \qquad \bar y = \frac{\sum A</em>i y<em>i}{\sum A</em>i}

Relationship & Distinctions

  • C.o.G. → weight focus; C.o.M. → mass focus; Centroid → area (or volume) focus.
  • In uniformly dense, homogeneous bodies in a uniform gravitational field: all three points coincide.
  • Under variable density or non-uniform gg: C.o.M. remains unchanged while C.o.G. may shift; centroid remains purely geometric.

Procedure for Determining Centroid / C.o.G. / C.o.M. of Composite Bodies

  1. Decompose the body/area into basic shapes (segments): rectangles, triangles, circles, annuli, sectors, cylinders, hemispheres, etc.
  2. For each segment identify its individual centroid coordinates (x<em>i,y</em>i)(x<em>i, y</em>i) relative to a chosen reference axis system.
  3. Construct a summary table:
    • Segment label
    • Area (or mass/weight) A<em>iA<em>i • Coordinates x</em>ix</em>i, y<em>iy<em>i • Area–moment products A</em>ix<em>iA</em>i x<em>i and A</em>iyiA</em>i y_i
  4. Compute totals A<em>i\sum A<em>i, A</em>ix<em>i\sum A</em>i x<em>i, A</em>iyi\sum A</em>i y_i.
  5. Apply composite formulas to locate the overall centroid:
    xˉ=A<em>ix</em>iA<em>i,yˉ=A</em>iy<em>iA</em>i\bar x = \frac{\sum A<em>i x</em>i}{\sum A<em>i}, \qquad \bar y = \frac{\sum A</em>i y<em>i}{\sum A</em>i}.
  6. For bodies with cut-outs (negative areas) treat removed segments with negative AiA_i.

Centroids of Common Shapes

  • Rectangle (width bb, height hh)
    xˉ=b/2\bar x = b/2, yˉ=h/2\bar y = h/2
  • Right Triangle (base bb along x-axis, height hh along y-axis, right angle at origin)
    xˉ=b/3\bar x = b/3, yˉ=h/3\bar y = h/3
  • Circle (radius RR)
    • Centroid at center (0,0)
  • Semicircle (radius RR, flat side on x-axis)
    xˉ=0\bar x = 0, yˉ=4R/(3π)\bar y = 4R/(3\pi) from the diameter line
  • Quarter-circle (radius RR, along positive x & y)
    xˉ=yˉ=4R/(3π)\bar x = \bar y = 4R/(3\pi) from the corner
  • Circular Sector (radius RR, angle θ\theta in radians, apex at origin)
    rˉ=2Rsin(θ/2)3θ/2\bar r = \frac{2R \sin(\theta/2)}{3\theta/2} along the bisector
    • For thin sector plates the polar form or rectangular projections may be used.

Worked Examples Highlight (Slides 8–10)

  • Example 5.1 – Trapezoid
    • Shape divided into simpler figures (e.g., rectangle + triangle) or treated via trapezoid formula.
    • Apply composite method to find (xˉ,yˉ)(\bar x, \bar y).
  • Example 5.2 – Complex Lamina (millimetres)
    • Possibly involves holes or stepped geometry; negative areas accounted for.
    • Reinforces systematic tabulation.
  • Example 5.3 – Thin Plate with Dimension a=30cma = 30\,\text{cm}
    • Emphasises scalability: centroid location scales proportionally with aa.
    • Encourages expressing final coordinates as multiples of aa (dimensionless form).
    • All examples use the tabular form: A<em>i,x</em>i,y<em>i,A</em>ix<em>i,A</em>iyiA<em>i, x</em>i, y<em>i, A</em>i x<em>i, A</em>i y_i.

Tutorial Problems Mentioned (Slides 11–12)

  • Tutorial 6.2 (Fig. 5.9)
    • Thin plate with parameters a=1cm,  b=6cm,  c=d=3cma = 1\,\text{cm},\; b = 6\,\text{cm},\; c = d = 3\,\text{cm}.
    • Likely composite of rectangles/triangles; aims to solidify student practice.
  • Tutorial 6.4 (Fig. 5.11)
    • Another irregular plate; students to apply identical procedure.
    • Reinforces attention to sign convention and coordinate reference selection.

Practical & Theoretical Implications

  • Structural design: Knowing centroid/C.o.G. essential for stress distribution, bending analysis, and stability.
  • Robotics & Aerospace: Control algorithms use C.o.M. to predict motion and orientation.
  • Ergonomics & Safety: Position of C.o.G. influences tipping, gait stability, and crash performance.
  • Philosophical note: Although C.o.G./C.o.M. are abstract points, they encapsulate the aggregate behaviour of distributed matter—demonstrating the power of mathematical abstraction in engineering.

Recap of Key Equations

  • Composite centroid of area:
    xˉ=A<em>ix</em>iA<em>i,yˉ=A</em>iy<em>iA</em>i\bar x = \frac{\sum A<em>i x</em>i}{\sum A<em>i}, \qquad \bar y = \frac{\sum A</em>i y<em>i}{\sum A</em>i}
  • Mass analogue:
    r<em>cm=m</em>ir<em>iM,M=m</em>i\vec r<em>{cm} = \frac{\sum m</em>i \vec r<em>i}{M}, \qquad M = \sum m</em>i
  • Moment-zero definition of C.o.G. with respect to any axis through C.o.G.:
    W<em>i(x</em>ixˉ)=0,W<em>i(y</em>iyˉ)=0\sum W<em>i (x</em>i - \bar x) = 0, \qquad \sum W<em>i (y</em>i - \bar y) = 0

Study Tips

  • Always sketch the composite area, label segment centroids, and choose a convenient coordinate origin (often at symmetry lines or lower-left corner) to minimise negative coordinates.
  • Exploit symmetry: If the area is symmetric about an axis, the centroid lies on that axis; only one coordinate needs calculation.
  • Keep units consistent; convert mm2\text{mm}^2 to cm2\text{cm}^2 if mixing units will occur in tabulation.
  • Double-check arithmetic in the A<em>ix</em>iA<em>i x</em>i and A<em>iy</em>iA<em>i y</em>i summations; small sign errors move the centroid dramatically.