thermodynamics

Thermodynamics Overview

  • Definition: Thermodynamics is the study of the relationship between heat, work, temperature, and energy. In chemistry, every chemical reaction involves a change in energy, often in the form of heat transfer.

  • Related Terminology:
        - Thermochemistry: the study of energy transfers as heat that accompany physical changes and chemical reactions.
        - Temperature Scales: Celsius (°C) and Kelvin (K) are used in thermochemical calculations.

Systems in Thermodynamics

  • System: The specific portion singled out for study.

  • Surroundings: Everything else outside the system.

Types of Systems

  • Open System: Matters and energy are exchanged with surroundings.

  • Closed System: Energy (but not matter) is exchanged with surroundings.

  • Isolated System: Neither matter nor energy is exchanged with surroundings.

Examples of Systems
  • Open System: A pot of boiling water with no lid. Heat enters from the burner, and steam (matter) escapes.

  • Closed System: A pot of boiling water with a lid that prevents steam from escaping. Heat enters, but matter remains contained.

  • Isolated System: A well-insulated thermos storing hot coffee, preventing heat and matter escape.

Analyzing Systems

  • Examples to categorize:
        - The Earth: Closed system due to atmosphere and energy exchange.
        - The Human Body: Open system due to matter and energy intake/exhaust.
        - Electric hair straightener: Often treated as a closed system.

Laws of Thermodynamics

Zeroth Law of Thermodynamics

  • Equilibrium: A system whose properties do not change over time without external influences.

  • Statement: If two systems are in thermodynamic equilibrium with a third system, they are in equilibrium with each other.

First Law of Thermodynamics

  • Law of Conservation of Matter: Matter cannot be created or destroyed, only transformed.

  • First Law of Thermodynamics: States that energy must be conserved; the energy in a system can change forms, but not in quantity.

Second Law of Thermodynamics

  • Entropy (S): Represents the unavailability of a system's thermal energy for work; indicative of system disorder.

  • Irreversible Processes: Any process increases total entropy; heat flow occurs spontaneously from hot to cold bodies.

  • Example: In a car engine, some energy as heat cannot be utilized for work, increasing system's disorder.

Third Law of Thermodynamics

  • Kinetic Molecular Theory: States all matter is in perpetual motion. As temperature decreases, kinetic energy and entropy decrease.

  • Absolute Zero: The state at which all molecular motion stops. Entropy approaches a constant value (zero for perfect crystalline solids).

Entropy Formula

S=kextlogWS = k ext{log} W

  • Where $k$ is the Boltzmann constant, and $W$ is the number of microstates of a system.

Energy Dynamics

Nature of Energy

  • Energy Definition: The capacity to do work or transfer heat.

  • Types of Energy:
        - Work (W): Energy used to cause an object to move against a force.
        - Heat (q): Energy causing temperature increases in an object.

  • Kinetic Energy (Ek):
        - Formula: Ek=rac12mv2E_k = rac{1}{2}mv^2
        - Depends on mass ($m$) and speed ($v$).

  • Potential Energy: Stored energy from attractions or repulsions between objects.

Energy Units

  • SI Unit: Joule (J), defined as 1J=1extkgracm2s21 J = 1 ext{kg} rac{m^2}{s^2}.

  • Conversions:
        - 1 calorie (cal) = 4.184 J
        - 1 kilocalorie (kcal) = 1000 cal.

Internal Energy and Changes

Internal Energy

  • Internal Energy (E): Sum of all kinetic and potential energies in a system.

  • Change in Internal Energy ($ riangle E$): Defined as
    riangleE=EfinalEinitialriangle E = E_{final} - E_{initial}

  • Implications of $ riangle E$:
        - Positive $ riangle E$: System gains energy from surroundings.
        - Negative $ riangle E$: System loses energy to surroundings.

Heat and Work Relation

  • Change in internal energy can be expressed as:
    riangleE=q+wriangle E = q + w

  • Meaning:
        - Heat added ($q > 0$) or work done on the system ($w > 0$) results in increased internal energy.

Example Problem
  • A system loses 1375 J of heat and experiences 235 J of work done on it:
        - riangleE=(1375J)+(235J)=1140Jriangle E = (-1375J) + (235J) = -1140J

Heat Transfer in Reactions

Endothermic & Exothermic Processes

  • Endothermic: System absorbs heat (e.g., ice melting).

  • Exothermic: System releases heat (e.g., combustion of gasoline).

  • Figure comparison of reaction progress illustrates differences in energy absorption/release between the two types of reactions.

Examples of Endothermic & Exothermic Reactions

  • Determine whether the following are endothermic or exothermic:
        - Making an ice cube: Exothermic
        - Melting NaI at its melting point: Endothermic
        - Hydrogen gas fire: Exothermic
        - Evaporation of ammonia: Endothermic

Reaction Rates

Kinetic Molecular Theory and Reaction Rate

  • Chemical Reactions: Occur when particles collide at correct orientations due to their motion.

  • Impact of Temperature: Increasing temperature increases molecular speed and, consequently, collision frequency, enhancing reaction rates.

Collision Requirements
  • Not all collisions yield reactions; correct orientation is required.

  • Example Reaction: extCl+extNOCl<br>ightarrowextNO+extCl2ext{Cl} + ext{NOCl} <br>ightarrow ext{NO} + ext{Cl}_2 (must collide correctly to form Cl₂).

Calculating Reaction Rate
  • Reaction rates calculated as concentration per time (M/s).

  • Example Reaction:
        - 3H₂ + N₂ = 2NH₃
        - Initial concentration of NH₃ (time 0) = 0.0 M, at time 10s = 0.25 M.
        - Rate determined from concentration change over time.

Calorimetry

Heat Measurement Method

  • Calorimetry: Measures heat absorbed or released using a calorimeter (e.g., bomb calorimeter).

  • Calorimeter function: Measures temperature changes of water to determine energy absorbed or released in chemical or physical changes.

Specific Heat

Definition and Calculation

  • Specific Heat (cᵖ): Energy required to raise the temperature of 1 gram of a substance by 1 °C or 1 K, measured in j/g·K.

  • Specific heat formula:
    cp=racqmriangleTc^p = rac{q}{m riangle T}

  • Parameters:
        - $q$ = heat added,
        - $m$ = mass,
        - $ riangle T$ = change in temperature.

Example of Specific Heat Calculation
  • Example: A 4.0g sample of glass absorbs 32 J of heat, heated from 274 K to 314 K:
        - cp=rac32J4.0gimes40K=0.20J/gKc^p = rac{32J}{4.0g imes 40K} = 0.20 J/gK

Specific Heats of Common Materials

Material

Specific Heat (J/g·°C)

Liquid water

4.18

Solid water (ice)

2.11

Water vapor

2.00

Dry air

1.01

Basalt

0.84

Granite

0.79

Iron

0.45

Copper

0.38

Lead

0.13

Enthalpy Changes in Reactions

Enthalpy ($ riangle H$)

  • Definition: The heat absorbed or released during a chemical reaction under constant pressure.

  • Positive $ riangle H$: System is endothermic (absorbing heat).

  • Negative $ riangle H$: System is exothermic (releasing heat).

  • Enthalpy change formula:
    riangleH=HfinalHinitialriangle H = H_{final} - H_{initial}

Enthalpy of Reactions

Example of Enthalpy Change
  • Reaction:
        2H2(g)+O2(g)<br>ightarrow2H2O(g)extwithriangleH=483.6kJ2H_2(g) + O_2(g) <br>ightarrow 2H_2O(g) ext{ with } riangle H = -483.6 kJ

  • Indicates an exothermic reaction as the heat is released.

  • Thermochemical equations: Coefficients indicate moles of reactants/products.

Thermochemical Equation Guidelines
  1. Enthalpy ($ riangle H$) is extensive; magnitude is proportional to reaction size.

  2. Enthalpy change is equal in magnitude but opposing in sign for the reverse reaction.

  3. The state of reactants/products influences the enthalpy change.

Example Problem of Heat Release
  • Calculate heat released when 4.5g of methane gas burns:
    rac(4.5gCH4)(1molCH4/16.0gCH4)(890kJ/1molCH4)=250kJrac{(4.5g CH_4)(1 mol CH_4/16.0g CH_4)(-890kJ/1 mol CH_4) = -250 kJ}

Additional Example
  • Decomposing 2H2O2(l)<br>ightarrow2H2O(l)+O2(g)extwithriangleH=196kJ2H_2O_2(l) <br>ightarrow 2H_2O(l) + O_2(g) ext{ with } riangle H = -196 kJ.

  • Calculate heat released by decomposing 5.00g of H2O2H_2O_2.