Comprehensive Study Notes: Integrated Rate Laws, Temperature Effects, and Reaction Theories

General Principles for Complex Reactions

  • Rate-Determining Step: For a complex reaction, the overall order of the reaction is determined by the slowest step in the reaction mechanism.
  • Molecularity and Order: The molecularity of the slowest step in a complex reaction is identical to the overall order of the reaction.

Intext Questions and Applications

  • Question 3.3: For a reaction A+BProductA + B \rightarrow \text{Product}, given the rate law r=k[A]1/2[B]2r = k [A]^{1/2} [B]^2, find the order of the reaction.     * Calculation: The order is the sum of the powers of the concentration terms in the rate law. Total order = 12+2=2.5\frac{1}{2} + 2 = 2.5.
  • Question 3.4: The conversion of molecule XX to YY follows second-order kinetics. If the concentration of XX is increased to three times, how will it affect the rate of formation of YY?     * Analysis: Rate law r=k[X]2r = k [X]^2. If [X]<em>new=3[X][X]<em>{\text{new}} = 3[X], then r</em>new=k(3[X])2=9k[X]2r</em>{\text{new}} = k(3[X])^2 = 9k[X]^2. The rate increases by 9 times.

Integrated Rate Equations: Overview

  • Differential vs. Integrated Rate Equations: The concentration dependence of the rate is expressed as a differential rate equation. However, determining instantaneous rates (slopes of tangents at point tt) is inconvenient and difficult for finding rate laws/orders.
  • Purpose of Integration: Differential rate equations are integrated to establish a direct relationship between measured experimental data (concentrations at specific times) and the rate constant (kk).
  • Specificity: Integrated rate equations vary depending on the reaction order.

Zero Order Reactions: Derivation and Characteristics

  • Definition: A zero-order reaction occurs when the rate of reaction is proportional to the zero power of the reactant concentration.
  • Derivation:     * Reaction: RPR \rightarrow P     * Rate expression: Rate=d[R]dt=k[R]0=k×1\text{Rate} = -\frac{d[R]}{dt} = k [R]^0 = k \times 1     * Differential form: d[R]=kdtd[R] = -k dt     * Integration: Integrating both sides yields [R]=kt+I[R] = -kt + I, where II is the integration constant.
  • Determination of Integration Constant (II):     * At t=0t = 0, [R]=[R]0[R] = [R]_0 (initial concentration).     * Substitution: [R]0=k(0)+II=[R]0[R]_0 = -k(0) + I \Rightarrow I = [R]_0.
  • Final Zero Order Equation: [R]=kt+[R]0[R] = -kt + [R]_0
  • Graphical Representation: A plot of concentration ([R][R]) against time (tt) yields a straight line with a slope equal to k-k and a y-intercept equal to [R]0[R]_0.
  • Calculation of Rate Constant (kk): k=[R]0[R]tk = \frac{[R]_0 - [R]}{t}

Zero Order Reactions: Examples and Mechanism

  • General Nature: These reactions are uncommon and typically occur under special conditions, such as enzyme-catalyzed reactions or reactions on metal surfaces.
  • Specific Examples:     * Decomposition of Gaseous Ammonia on Platinum: 2NH3(g)1130KPt catalystN2(g)+3H2(g)2NH_3 (g) \xrightarrow[1130K]{\text{Pt catalyst}} N_2 (g) + 3H_2 (g). Rate =k[NH3]0=k= k [NH_3]^0 = k. At high pressure, the metal surface becomes saturated with ammonia molecules, making the reaction rate independent of further concentration increases.     * Thermal Decomposition of HI on Gold Surface: Another instance of surface-mediated zero-order kinetics.

First Order Reactions: Derivation and Analytical Representation

  • Definition: The rate of reaction is proportional to the first power of the reactant concentration.
  • Derivation:     * Reaction: RPR \rightarrow P     * Rate expression: Rate=d[R]dt=k[R]\text{Rate} = -\frac{d[R]}{dt} = k [R]     * Differential form: d[R][R]=kdt\frac{d[R]}{[R]} = -k dt     * Integration: ln[R]=kt+I\ln [R] = -kt + I.
  • Determination of Integration Constant (II):     * At t=0t = 0, [R]=[R]0[R] = [R]_0.     * Substitution: \ln [R]_0 = -k(0) + I \Rightarrow I = \ln [R]_0.
  • Integrated Rate Equation: ln[R]=kt+ln[R]0\ln [R] = -kt + \ln [R]_0
  • Alternative Forms:     * Logarithmic rearrangement: ln[R][R]<em>0=kt\ln \frac{[R]}{[R]<em>0} = -kt or k=1tln[R]0[R]k = \frac{1}{t} \ln \frac{[R]_0}{[R]}     * Exponential form: [R]=[R]0ekt[R] = [R]_0 e^{-kt}     * Common Logarithm (log</em>10\log</em>{10}) form: k=2.303tlog[R]0[R]k = \frac{2.303}{t} \log \frac{[R]_0}{[R]}

First Order Reactions: Comparison at Different Times

  • Let concentrations be [R]1[R]_1 at time t1t_1 and [R]2[R]_2 at time t2t_2.
  • Equations:     1. ln[R]1=kt1+ln[R]0\ln [R]_1 = -kt_1 + \ln [R]_0     2. ln[R]2=kt2+ln[R]0\ln [R]_2 = -kt_2 + \ln [R]_0
  • Subtraction yields: ln[R]1[R]2=k(t2t1)\ln \frac{[R]_1}{[R]_2} = k(t_2 - t_1).
  • Rate constant solution: k=1t2t1ln[R]1[R]2k = \frac{1}{t_2 - t_1} \ln \frac{[R]_1}{[R]_2}.

First Order Reactions: Graphical Representation and Examples

  • Natural Log Plot: Plotting ln[R]\ln [R] against tt gives a straight line with slope k-k and intercept ln[R]0\ln [R]_0.
  • Common Log Plot: Plotting log[R]0[R]\log \frac{[R]_0}{[R]} vs. tt gives a slope equal to k2.303\frac{k}{2.303}.
  • Examples:     * Hydrogenation of Ethene: C2H4(g)+H2(g)C2H6(g)C_2H_4(g) + H_2(g) \rightarrow C_2H_6(g). Rate =k[C2H4]= k [C_2H_4].     * Radioactive Decay: All natural and artificial radioactive decays of unstable nuclei follow first-order kinetics (e.g., 226<em>88Ra24He+222</em>86Rn^{226}<em>{88}Ra \rightarrow ^4_2He + ^{222}</em>{86}Rn).     * Decomposition: Decomposition of N2O5N_2O_5 and N2ON_2O.

Mathematical Application: Integrated First Order Equations

  • Example 3.5: Decomposition of N2O5N_2O_5 at 318K318\,K.     * Initial concentration ([R]1[R]_1): 1.24×102mol/L1.24 \times 10^{-2}\,mol/L.     * Final concentration ([R]2[R]_2) at t=60mint = 60\,min: 0.20×102mol/L0.20 \times 10^{-2}\,mol/L.     * Calculation: k=2.30360minlog(1.24×1020.20×102)=2.30360log6.2=0.0304min1k = \frac{2.303}{60\,min} \log (\frac{1.24 \times 10^{-2}}{0.20 \times 10^{-2}}) = \frac{2.303}{60} \log 6.2 = 0.0304\,min^{-1}.

Gas Phase First Order Reactions

  • Reaction Type: A(g)B(g)+C(g)A(g) \rightarrow B(g) + C(g)
  • Assume initial pressure is pip_i and total pressure at time tt is ptp_t. Let xx be the pressure decrease in reactant AA.
  • Stoichiometry at time tt:     * PA=pixP_A = p_i - x     * PB=xP_B = x     * PC=xP_C = x
  • Total pressure (ptp_t): (pix)+x+x=pi+x(p_i - x) + x + x = p_i + x.
  • Solving for xx: x=ptpix = p_t - p_i.
  • Partial pressure of AA: PA=pi(ptpi)=2piptP_A = p_i - (p_t - p_i) = 2p_i - p_t.
  • Gas Phase Rate Constant: k=2.303tlogpi2piptk = \frac{2.303}{t} \log \frac{p_i}{2p_i - p_t}.

Half-Life of a Reaction (t1/2t_{1/2})

  • Definition: The time required for the concentration of a reactant to be reduced to exactly one-half of its initial concentration.
  • Zero Order Reaction Half-Life:     * Condition: At t1/2t_{1/2}, [R]=[R]<em>02[R] = \frac{[R]<em>0}{2}.     * Substitution into k=[R]0[R]tk = \frac{[R]_0 - [R]}{t} yields k=[R]0[R]0/2t</em>1/2k = \frac{[R]_0 - [R]_0/2}{t</em>{1/2}}.     * Formula: t1/2=[R]<em>02kt_{1/2} = \frac{[R]<em>0}{2k}.     * Relationship: t</em>1/2t</em>{1/2} is directly proportional to initial concentration and inversely proportional to the rate constant.
  • First Order Reaction Half-Life:     * Condition: At t1/2t_{1/2}, [R]=[R]<em>02[R] = \frac{[R]<em>0}{2}.     * Substitution into k=2.303tlog[R]0[R]k = \frac{2.303}{t} \log \frac{[R]_0}{[R]} yields k=2.303t</em>1/2log(2)k = \frac{2.303}{t</em>{1/2}} \log (2).     * Formula: t1/2=2.303×0.301k=0.693kt_{1/2} = \frac{2.303 \times 0.301}{k} = \frac{0.693}{k}.     * Relationship: t1/2t_{1/2} is independent of the initial concentration for a first-order reaction.

Summary of Integrated Rate Laws (Table 3.4)

  • Zero Order:     * Differential rate law: d[R]dt=k\frac{d[R]}{dt} = -k     * Integrated rate law: kt=[R]0[R]kt = [R]_0 - [R]     * Straight line plot: [R][R] vs tt     * Half-life: [R]02k\frac{[R]_0}{2k}     * Units of kk: conc time1\text{conc time}^{-1} or molL1s1mol\,L^{-1}\,s^{-1}
  • First Order:     * Differential rate law: d[R]dt=k[R]\frac{d[R]}{dt} = -k[R]     * Integrated rate law: [R]=[R]0ekt[R] = [R]_0 e^{-kt} or kt=ln[R]0[R]kt = \ln \frac{[R]_0}{[R]}     * Straight line plot: ln[R]\ln [R] vs tt     * Half-life: ln2k\frac{\ln 2}{k}     * Units of kk: time1\text{time}^{-1} or s1s^{-1}

Pseudo First Order Reactions

  • Definition: Reactions that are high-order but behave as first-order reactions due to specific conditions (e.g., one reactant present in large excess).
  • Example: Hydrolysis of Ethyl Acetate:     * Reaction: CH3COOC2H5+H2OH+CH3COOH+C2H5OHCH_3COOC_2H_5 + H_2O \xrightarrow{H^+} CH_3COOH + C_2H_5OH     * Scenario: if 0.01mol0.01\,mol of ester reacts with 10mol10\,mol of water, the change in water concentration (9.99mol9.99\,mol) is negligible.     * The rate becomes dependent only on the concentration of ethyl acetate, behaving as pseudo first-order.
  • Example: Inversion of Cane Sugar:     * C12H22O11+H2OH+C6H12O6+C6H12O6C_{12}H_{22}O_{11} + H_2O \xrightarrow{H^+} C_6H_{12}O_6 + C_6H_{12}O_6     * Rate =k[C12H22O11]= k [C_{12}H_{22}O_{11}].

Temperature Dependence of Reaction Rates

  • Observation: Reaction rates typically increase with rising temperature. For many reactions, a 1010^{\circ} rise in temperature approximately doubles the rate constant.
  • Example: Decomposition of N2O5N_2O_5 to half original amount:     * At 0C0^{\circ}C: takes 10 days.     * At 25C25^{\circ}C: takes 5 hours.     * At 50C50^{\circ}C: takes 12 minutes.
  • Example: Potassium Permanganate (KMnO4KMnO_4) and Oxalic Acid (H2C2O4H_2C_2O_4): Decolourization occurs faster at higher temperatures.

The Arrhenius Equation and Activation Energy

  • Formula: k=AeEa/RTk = A e^{-E_a/RT}     * AA: Arrhenius factor, frequency factor, or pre-exponential factor (constant specific to a reaction).     * EaE_a: Activation energy (Jmol1J\,mol^{-1}).     * RR: Gas constant.     * TT: Temperature.
  • Mechanism (Intermediate Complex Theory): Reactants (e.g., H2H_2 and I2I_2) collide to form an unstable intermediate known as the activated complex (CC). The energy required to form this complex is the Activation Energy (EaE_a). Products are formed when the complex decomposes, releasing energy.
  • Maxwell-Boltzmann Distribution: Describes distribution of kinetic energies among large numbers of molecules.     * Plot: Fraction of molecules (NE/NtN_E/N_t) vs. Kinetic energy (EE).     * Peak: Most probable kinetic energy.     * Temperature Effect: Higher temperature shifts the curve to the right and broadens it. The area representing molecules with energy Ea\ge E_a effectively doubles with a 10K10\,K rise.
  • Logarithmic Arrhenius Equation: lnk=EaRT+lnA\ln k = -\frac{E_a}{RT} + \ln A.     * Plotting lnk\ln k vs. 1/T1/T gives a straight line with slope EaR-\frac{E_a}{R} and intercept lnA\ln A.
  • Two-Temperature Equation: logk2k1=Ea2.303R[T2T1T1T2]\log \frac{k_2}{k_1} = \frac{E_a}{2.303R} [\frac{T_2 - T_1}{T_1 T_2}].

Effect of Catalyst on Reaction Rate

  • Catalyst: A substance that increases the reaction rate without being permanently changed. Example: MnO2MnO_2 in the decomposition of KClO3KClO_3.
  • Inhibitor: A substance used specifically to reduce the rate of a reaction.
  • Theoretical Action: A catalyst provides an alternative reaction pathway with a lower activation energy, thereby lowering the potential energy barrier.
  • Properties of Catalysts:     * Small amounts can catalyze large quantities of reactants.     * Does not alter Gibbs energy (ΔG\Delta G).     * Only catalyzes spontaneous reactions.     * Does not change the equilibrium constant (KeqK_{eq}) but helps reach equilibrium faster by catalyzing both forward and backward reactions equally.

Collision Theory of Chemical Reactions

  • Context: Developed by Max Trautz and William Lewis (1916-18), based on the kinetic theory of gases.
  • Postulate: Reactants are hard spheres; reactions occur upon collision.
  • Collision Frequency (ZZ): The number of collisions per second per unit volume of reaction mixture.
  • Bimolecular Elementary Reaction (A+BProductsA + B \rightarrow \text{Products}):     * Rate=ZABeEa/RT\text{Rate} = Z_{AB} e^{-E_a/RT}.
  • Effective Collisions: Only collisions with sufficient kinetic energy (Threshold energy) and proper orientation result in product formation.     * Threshold Energy = Activation Energy + energy possessed by reacting species.
  • Steric Factor (PP): Introduced to account for the probability of proper orientation.     * Rate=PZABeEa/RT\text{Rate} = P Z_{AB} e^{-E_a/RT}.     * Example: Formation of methanol from bromoethane varies based on the attack angle of the OHOH^- ion relative to the CH3BrCH_3Br molecule.
  • Drawbacks: Collision theory treats molecules as hard spheres, ignoring their complex structural aspects.