Hardy-Weinberg Equilibrium

BIOL 101: Hardy-Weinberg Equilibrium Study Notes

Introduction

  • Topics discussed include the conditions necessary for non-evolution, the concepts of evolution in relation to allele frequency, and Hardy-Weinberg calculations.

  • Important terms include:

    • Hardy-Weinberg Equilibrium: A model that describes a non-evolving population.

Key Ideas

Hardy-Weinberg Model Overview
  • The Hardy-Weinberg model represents a theoretical framework for understanding genetic variation in a population that is not evolving.

  • This model can be viewed as a baseline from which evolutionary changes can be measured.

Historical Figures
  • Godfrey Hardy: An English mathematician known for his work in population genetics.

  • Wilhelm Weinberg: A German obstetrician who independently derived the same conclusions as Hardy.

  • Both Hardy and Weinberg contributed to the foundation of the Hardy-Weinberg equilibrium model.

Conditions for Non-Evolution

Five Conditions for Hardy-Weinberg Equilibrium

To maintain a non-evolving population, the following five conditions must be met:

  1. Mutations: Must be absent (no new genetic variations).

  2. Population Size: Must be large (effectively infinite) to avoid genetic drift.

  3. Immigration/Emigration: Must be none (no gene flow).

  4. Mating: Must occur randomly (no preferences).

  5. Reproductive Success: Must be equal (no natural selection favoring one genotype over another).

Table of Conditions

Condition

Status

Mutations

None (mutations create genetic variation)

Population Size

Large (effectively infinite)

Immigration/Emigration

None (no gene flow between populations)

Mating

Random (no preferences)

Reproductive Success

Equal (no natural selection)

Genetic Variation and Evolution

  • The Hardy-Weinberg model describes an idealized state against which genetic variations in nature can be measured. It allows for the detection of evolutionary changes by indicating deviations from the equilibrium state.

  • This means by defining what non-evolution looks like, we can identify evolution in action in natural populations.

Hardy-Weinberg Calculations

Population Example: Butterflies
  • Population Data: Total number of butterflies = 1000

    • 490 AA (dark-blue wings)

    • 420 Aa (medium-blue wings)

    • 90 aa (white wings)

Genotype Frequencies
  • Calculate the genotype frequencies using the following formulas:

    • Dark blue (AA): \frac{490}{1000} = 0.49

    • Medium blue (Aa): \frac{420}{1000} = 0.42

    • White (aa): \frac{90}{1000} = 0.09

Allele Frequencies
  • Total alleles in the population = 2000 (since each butterfly has 2 alleles)

  • Frequency of allele A:

    • A = \frac{(490 \text{ AA}) \times 2 + (420 \text{ Aa})}{2000} = \frac{1400}{2000} = 0.7

  • Frequency of allele a:

    • a = \frac{(90 \text{ aa}) + (420 \text{ Aa})}{2000} = \frac{600}{2000} = 0.3

Predicting Next Generation Genotype Frequencies
  • If the population remains in Hardy-Weinberg equilibrium,

    • The frequencies in the next generation will remain:

    • AA (0.49)

    • Aa (0.42)

    • aa (0.09)

Evolutionary Conditions

Conditions Leading to Evolution

If evolution were to occur, the following conditions would be present:

Condition

Status

Mutations

Yes

Population Size

Small

Immigration/Emigration

Yes

Mating

Non-random (selection involved)

Reproductive Success

Unequal (natural selection present)

Hardy-Weinberg Equations

  • Allele Frequencies: p + q = 1

    • Where p is the frequency of the dominant allele (A), and q is the frequency of the recessive allele (a).

  • Genotype Frequencies: p^2 + 2pq + q^2 = 1

    • Where

    • p^2 = frequency of homozygous dominant (AA)

    • 2pq = frequency of heterozygous (Aa)

    • q^2 = frequency of homozygous recessive (aa)

Examples and Applications

Blue-footed Boobies Case Study
  • Example given where frequency of recessive allele (w) is 0.4:

    • Frequency of non-webbed feet = 1 - q^2 ext{(for recessive trait)}

    • If q = 0.4 then p = 1 - 0.4 = 0.6.

Case Study for Cystic Fibrosis
  • 4% of individuals are homozygous recessive (aa), hence:

    • q^2 = 0.04
      ightarrow q = 0.2
      ightarrow p = 0.8

    • Calculate heterozygote frequency: 2pq = 2(0.8)(0.2) = 0.32 ext{ (approx. 1 in 3)}

Conclusion

  • The Hardy-Weinberg equilibrium provides a crucial framework for understanding allele and genotype frequencies in non-evolving populations. Through its application, one can gain insights into the evolutionary pressures acting on real populations.