Sequences Series Geometric Common ratio TOPIC #1: POLYNOMIAL OPERATIONS Factoring Trinomials Example: x 2 + 7 x + 10 = ( x + 5 ) ( x + 2 ) x^2 + 7x + 10 = (x+5)(x+2) x 2 + 7 x + 10 = ( x + 5 ) ( x + 2 ) Grouping Rearrange first, necessary. Example:4 x 3 − x 2 + 16 x − 4 4x^3 - x^2 + 16x - 4 4 x 3 − x 2 + 16 x − 4 Rearrange: 4 x 3 + 16 x − x 2 − 4 4x^3 + 16x - x^2 - 4 4 x 3 + 16 x − x 2 − 4 4 x ( x 2 + 4 ) − 1 ( x 2 + 4 ) 4x(x^2 + 4) - 1(x^2 + 4) 4 x ( x 2 + 4 ) − 1 ( x 2 + 4 ) ( x 2 + 4 ) ( 4 x − 1 ) (x^2 + 4)(4x - 1) ( x 2 + 4 ) ( 4 x − 1 ) AC Method Example:2 x 2 + x − 3 2x^2 + x - 3 2 x 2 + x − 3 2 x 2 + 3 x − 2 x − 3 2x^2 + 3x - 2x - 3 2 x 2 + 3 x − 2 x − 3 x ( 2 x + 3 ) − 1 ( 2 x + 3 ) x(2x + 3) - 1(2x + 3) x ( 2 x + 3 ) − 1 ( 2 x + 3 ) ( 2 x + 3 ) ( x − 1 ) (2x + 3)(x - 1) ( 2 x + 3 ) ( x − 1 ) Difference of Two Perfect Squares Example:4 x 2 − 49 4x^2 - 49 4 x 2 − 49 ( 2 x + 7 ) ( 2 x − 7 ) (2x + 7)(2x - 7) ( 2 x + 7 ) ( 2 x − 7 ) Long Division Put zeros in for missing terms. Example:Divide 2 x 4 + 4 x 2 − 1 2x^4 + 4x^2 - 1 2 x 4 + 4 x 2 − 1 by x + 1 x+1 x + 1 Quotient: 2 x 3 − 2 x 2 + 6 x − 6 2x^3 - 2x^2 + 6x - 6 2 x 3 − 2 x 2 + 6 x − 6 Remainder: 5 Remainder Theorem The function's value will tell you the remainder. If remainder = 0, then you have found a root and a factor. Example:Is x − 5 x-5 x − 5 a factor of 2 x 3 − 4 x 2 − 7 x − 10 2x^3 - 4x^2 - 7x - 10 2 x 3 − 4 x 2 − 7 x − 10 ? Answer: 2 ( 5 ) 3 − 4 ( 5 ) 2 − 7 ( 5 ) − 10 = 105 2(5)^3 - 4(5)^2 - 7(5) - 10 = 105 2 ( 5 ) 3 − 4 ( 5 ) 2 − 7 ( 5 ) − 10 = 105 . No, not a factor. Graphically: If x + 1 x+1 x + 1 is a factor of f ( x ) f(x) f ( x ) , then the remainder (y-value) is 0. Synthetic Division Example:Divide 2 x 4 + 0 x 3 + 4 x 2 + 0 x − 1 2x^4 + 0x^3 + 4x^2 + 0x - 1 2 x 4 + 0 x 3 + 4 x 2 + 0 x − 1 by x + 1 x+1 x + 1 Quotient: 2 x 3 − 2 x 2 + 6 x − 6 2x^3 - 2x^2 + 6x - 6 2 x 3 − 2 x 2 + 6 x − 6 Remainder: 5 Solving Fractional Equations Get a common denominator. Set numerators equal. Solve and reject solutions that make the denominator undefined. Extraneous solutions are solutions that get rejected! TOPIC #2: RATIONAL EXPRESSIONS / ALGEBRAIC FRACTIONS Example: x x − 5 + 3 x + 2 = 7 x x 2 − 3 x − 10 \frac{x}{x-5} + \frac{3}{x+2} = \frac{7x}{x^2 - 3x - 10} x − 5 x + x + 2 3 = x 2 − 3 x − 10 7 x x ( x + 2 ) ( x − 5 ) ( x + 2 ) + 3 ( x − 5 ) ( x − 5 ) ( x + 2 ) = 7 x ( x − 5 ) ( x + 2 ) \frac{x(x+2)}{(x-5)(x+2)} + \frac{3(x-5)}{(x-5)(x+2)} = \frac{7x}{(x-5)(x+2)} ( x − 5 ) ( x + 2 ) x ( x + 2 ) + ( x − 5 ) ( x + 2 ) 3 ( x − 5 ) = ( x − 5 ) ( x + 2 ) 7 x Undefined when x 2 + 2 x − 8 = 0 x^2 + 2x - 8 = 0 x 2 + 2 x − 8 = 0 , which means ( x + 4 ) ( x − 2 ) = 0 (x+4)(x-2) = 0 ( x + 4 ) ( x − 2 ) = 0 , so x = − 4 x = -4 x = − 4 and x = 2 x = 2 x = 2 Based on the denominators, x ≠ 5 x \neq 5 x = 5 and x ≠ − 2 x \neq -2 x = − 2 x ( x + 2 ) + 3 ( x − 5 ) = 7 x x(x+2) + 3(x-5) = 7x x ( x + 2 ) + 3 ( x − 5 ) = 7 x x 2 + 2 x + 3 x − 15 = 7 x x^2 + 2x + 3x - 15 = 7x x 2 + 2 x + 3 x − 15 = 7 x x 2 − 2 x − 15 = 0 x^2 - 2x - 15 = 0 x 2 − 2 x − 15 = 0 ( x − 5 ) ( x + 3 ) = 0 (x-5)(x+3) = 0 ( x − 5 ) ( x + 3 ) = 0 x = 5 x = 5 x = 5 or x = − 3 x = -3 x = − 3 x = 5 x = 5 x = 5 is extraneous, so reject it.TOPIC #3: EXPONENTS, RADICALS, + IMAGINARY NUMBERS Exponent Rules Add exponents: x 3 ⋅ x 4 = x 7 x^3 \cdot x^4 = x^7 x 3 ⋅ x 4 = x 7 Subtract exponents: x 5 x 2 = x 3 \frac{x^5}{x^2} = x^3 x 2 x 5 = x 3 Multiply exponents: ( x 3 ) 2 = x 6 (x^3)^2 = x^6 ( x 3 ) 2 = x 6 Zero exponent: x 0 = 1 x^0 = 1 x 0 = 1 Fractional exponents: x m n = x m n = ( x n ) m x^{\frac{m}{n}} = \sqrt[n]{x^m} = (\sqrt[n]{x})^m x n m = n x m = ( n x ) m Denominator is the root, numerator is the power. Simplifying using Exponents Much easier to work with fractional exponents than radicals! Example: Convert to fractions, subtract exponents. Simplifying Imaginary Numbers i = − 1 i = \sqrt{-1} i = − 1 i 2 = − 1 i^2 = -1 i 2 = − 1 Set calculator to a+bi mode! Example: ( 2 − 3 k i ) 2 = ( 2 − 3 k i ) ( 2 − 3 k i ) (2 - 3ki)^2 = (2 - 3ki)(2 - 3ki) ( 2 − 3 ki ) 2 = ( 2 − 3 ki ) ( 2 − 3 ki ) = 4 − 6 k i − 6 k i + 9 k 2 i 2 = 4 - 6ki - 6ki + 9k^2i^2 = 4 − 6 ki − 6 ki + 9 k 2 i 2 = 4 − 12 k i + 9 k 2 ( − 1 ) = 4 - 12ki + 9k^2(-1) = 4 − 12 ki + 9 k 2 ( − 1 ) = 4 − 12 k i − 9 k 2 = 4 - 12ki - 9k^2 = 4 − 12 ki − 9 k 2 This is simplified completely. Radical Equations Isolate the radical. Square both sides. Solve and check; usually have to reject solutions. Check back to radicals. Example:x + 2 + 4 = x \sqrt{x+2} + 4 = x x + 2 + 4 = x x + 2 = x − 4 \sqrt{x+2} = x - 4 x + 2 = x − 4 ( x + 2 ) 2 = ( x − 4 ) 2 (\sqrt{x+2})^2 = (x-4)^2 ( x + 2 ) 2 = ( x − 4 ) 2 x + 2 = x 2 − 8 x + 16 x+2 = x^2 - 8x + 16 x + 2 = x 2 − 8 x + 16 x 2 − 9 x + 14 = 0 x^2 - 9x + 14 = 0 x 2 − 9 x + 14 = 0 ( x − 7 ) ( x − 2 ) = 0 (x-7)(x-2) = 0 ( x − 7 ) ( x − 2 ) = 0 x = 7 x = 7 x = 7 or x = 2 x = 2 x = 2 Check:7 + 2 + 4 = 7 ⇒ 3 + 4 = 7 \sqrt{7+2} + 4 = 7 \Rightarrow 3 + 4 = 7 7 + 2 + 4 = 7 ⇒ 3 + 4 = 7 2 + 2 + 4 = 2 ⇒ 2 + 4 = 2 \sqrt{2+2} + 4 = 2 \Rightarrow 2 + 4 = 2 2 + 2 + 4 = 2 ⇒ 2 + 4 = 2 (reject!) Quadratics with Imaginary Solutions x 2 + 4 = 0 x^2 + 4 = 0 x 2 + 4 = 0 x 2 = − 4 x^2 = -4 x 2 = − 4 x = ± − 4 x = \pm \sqrt{-4} x = ± − 4 x = ± 2 i x = \pm 2i x = ± 2 i Example:x 2 − 2 x + 3 = 0 x^2 - 2x + 3 = 0 x 2 − 2 x + 3 = 0 x = 2 ± 4 − 4 ( 1 ) ( 3 ) 2 ( 1 ) x = \frac{2 \pm \sqrt{4 - 4(1)(3)}}{2(1)} x = 2 ( 1 ) 2 ± 4 − 4 ( 1 ) ( 3 ) = 2 ± − 8 2 = \frac{2 \pm \sqrt{-8}}{2} = 2 2 ± − 8 TOPIC #4: SOLVING EQUATIONS + INEQUALITIES Solving by Factoring Finding roots means x-intercepts, solutions, or zeros. Example:x 4 − 4 x 3 − 9 x 2 + 36 x = 0 x^4 - 4x^3 - 9x^2 + 36x = 0 x 4 − 4 x 3 − 9 x 2 + 36 x = 0 x ( x 3 − 4 x 2 − 9 x + 36 ) = 0 x(x^3 - 4x^2 - 9x + 36) = 0 x ( x 3 − 4 x 2 − 9 x + 36 ) = 0 x [ x 2 ( x − 4 ) − 9 ( x − 4 ) ] = 0 x[x^2(x-4) - 9(x-4)] = 0 x [ x 2 ( x − 4 ) − 9 ( x − 4 )] = 0 x ( x 2 − 9 ) ( x − 4 ) = 0 x(x^2 - 9)(x-4) = 0 x ( x 2 − 9 ) ( x − 4 ) = 0 x = 0 x = 0 x = 0 , x = ± 3 x = \pm 3 x = ± 3 , x = 4 x = 4 x = 4 Circle-Line System Algebraically:Solve the line for x or y. Substitute into the circle equation. Solve for points of intersection. Example:( x + 1 ) 2 + ( y − 2 ) 2 = 25 (x+1)^2 + (y-2)^2 = 25 ( x + 1 ) 2 + ( y − 2 ) 2 = 25 y − x = − 2 ⇒ y = x − 2 y - x = -2 \Rightarrow y = x - 2 y − x = − 2 ⇒ y = x − 2 ( x + 1 ) 2 + ( x − 2 − 2 ) 2 = 25 (x+1)^2 + (x-2-2)^2 = 25 ( x + 1 ) 2 + ( x − 2 − 2 ) 2 = 25 ( x + 1 ) 2 + ( x − 4 ) 2 = 25 (x+1)^2 + (x-4)^2 = 25 ( x + 1 ) 2 + ( x − 4 ) 2 = 25 x 2 + 2 x + 1 + x 2 − 8 x + 16 = 25 x^2 + 2x + 1 + x^2 - 8x + 16 = 25 x 2 + 2 x + 1 + x 2 − 8 x + 16 = 25 2 x 2 − 6 x − 8 = 0 2x^2 - 6x - 8 = 0 2 x 2 − 6 x − 8 = 0 x 2 − 3 x − 4 = 0 x^2 - 3x - 4 = 0 x 2 − 3 x − 4 = 0 ( x − 4 ) ( x + 1 ) = 0 (x-4)(x+1) = 0 ( x − 4 ) ( x + 1 ) = 0 x = 4 ⇒ y = 4 − 2 = 2 x = 4 \Rightarrow y = 4 - 2 = 2 x = 4 ⇒ y = 4 − 2 = 2 x = − 1 ⇒ y = − 1 − 2 = − 3 x = -1 \Rightarrow y = -1 - 2 = -3 x = − 1 ⇒ y = − 1 − 2 = − 3 Solutions: ( 4 , 2 ) (4, 2) ( 4 , 2 ) and ( − 1 , − 3 ) (-1, -3) ( − 1 , − 3 ) Check by plugging back into the original equations. Graphically:0 solutions (imaginary solutions) 1 solution 2 solutions TOPIC #5: SYSTEMS OF EQUATIONS Systems of 3 Equations Pick 2 equations and eliminate one variable. Pick 2 different equations and eliminate the SAME variable. Now solve your 2 equations + 2 unknowns system for two solutions. Find the third solution by plugging back into one of the original equations. Check using MATRIX. Do NOT rely on your calc! These are often asked in the short answer sections. Example Equations:− 6 x + 5 y + 2 z = − 11 -6x + 5y + 2z = -11 − 6 x + 5 y + 2 z = − 11 − 2 x + y + 4 z = − 9 -2x + y + 4z = -9 − 2 x + y + 4 z = − 9 4 x − 5 y + 5 z = − 4 4x - 5y + 5z = -4 4 x − 5 y + 5 z = − 4 Steps:Equation 1 + Equation 3:− 6 x + 5 y + 2 z = − 11 -6x + 5y + 2z = -11 − 6 x + 5 y + 2 z = − 11 4 x − 5 y + 5 z = − 4 4x - 5y + 5z = -4 4 x − 5 y + 5 z = − 4 − 2 x + 7 z = − 15 -2x + 7z = -15 − 2 x + 7 z = − 15 Equation 2:5 ( − 2 x + y + 4 z = − 9 ) 5(-2x + y + 4z = -9) 5 ( − 2 x + y + 4 z = − 9 ) − 10 x + 5 y + 20 z = − 45 -10x + 5y + 20z = -45 − 10 x + 5 y + 20 z = − 45 4 x − 5 y + 5 z = − 4 4x - 5y + 5z = -4 4 x − 5 y + 5 z = − 4 − 6 x + 25 z = − 49 -6x + 25z = -49 − 6 x + 25 z = − 49 Solve for z:− 3 ( − 2 x + 7 z = − 15 ) -3(-2x + 7z = -15) − 3 ( − 2 x + 7 z = − 15 ) − 6 x + 25 z = − 49 -6x + 25z = -49 − 6 x + 25 z = − 49 6 x − 21 z = 45 6x - 21z = 45 6 x − 21 z = 45 − 6 x + 25 z = − 49 -6x + 25z = -49 − 6 x + 25 z = − 49 4 z = − 4 ⇒ z = − 1 4z = -4 \Rightarrow z = -1 4 z = − 4 ⇒ z = − 1 Solve for x:− 2 x + 7 ( − 1 ) = − 15 -2x + 7(-1) = -15 − 2 x + 7 ( − 1 ) = − 15 − 2 x − 7 = − 15 -2x - 7 = -15 − 2 x − 7 = − 15 x = 4 x = 4 x = 4 Solve for y:− 2 ( 4 ) + y + 4 ( − 1 ) = − 9 -2(4) + y + 4(-1) = -9 − 2 ( 4 ) + y + 4 ( − 1 ) = − 9 − 8 + y − 4 = − 9 -8 + y - 4 = -9 − 8 + y − 4 = − 9 y − 12 = − 9 ⇒ y = 3 y - 12 = -9 \Rightarrow y = 3 y − 12 = − 9 ⇒ y = 3 Solution: ( 4 , 3 , − 1 ) (4, 3, -1) ( 4 , 3 , − 1 ) Calculate Intersection Where does f ( x ) = g ( x ) f(x) = g(x) f ( x ) = g ( x ) ? Also useful if you have two weird equations set equal to each other. 2nd TRACE #5: INTERSECTFirst Curve: move cursor to where you think the intersection is, Enter. Second Curve: move cursor to where you think the intersection is, Enter. Guess: Enter. TOPIC #6: FUNCTIONS Degree : highest exponentEven degree:Both ends in the same direction. Positive: As x → ∞ x \rightarrow \infty x → ∞ , f ( x ) → ∞ f(x) \rightarrow \infty f ( x ) → ∞ . As x → − ∞ x \rightarrow -\infty x → − ∞ , f ( x ) → ∞ f(x) \rightarrow \infty f ( x ) → ∞ . End behavior: ↑↑ Negative: As x → ∞ x \rightarrow \infty x → ∞ , f ( x ) → − ∞ f(x) \rightarrow -\infty f ( x ) → − ∞ . As x → − ∞ x \rightarrow -\infty x → − ∞ , f ( x ) → − ∞ f(x) \rightarrow -\infty f ( x ) → − ∞ . End behavior:↓↓ Odd degree:Both ends in opposite directions. Positive: As x → ∞ x \rightarrow \infty x → ∞ , f ( x ) → ∞ f(x) \rightarrow \infty f ( x ) → ∞ . As x → − ∞ x \rightarrow -\infty x → − ∞ , f ( x ) → − ∞ f(x) \rightarrow -\infty f ( x ) → − ∞ . End behavior: ↗ Negative: As x → ∞ x \rightarrow \infty x → ∞ , f ( x ) → − ∞ f(x) \rightarrow -\infty f ( x ) → − ∞ . As x → − ∞ x \rightarrow -\infty x → − ∞ , f ( x ) → ∞ f(x) \rightarrow \infty f ( x ) → ∞ . End behavior: ↘ Where is a function increasing/decreasing? Identify intervals of increase and decrease on the graph. Relative Max / Min 2nd TRACE #3 MIN 2nd TRACE #4 MAXLeft Bound, Right Bound, Guess, Enter Multiplicity : how many times a root appearsIf even, the graph is tangent (bounce). If odd, the graph crosses through. Example: f ( x ) = ( x − 1 ) 2 ( x + 2 ) ( x − 4 ) f(x) = (x-1)^2 (x+2) (x-4) f ( x ) = ( x − 1 ) 2 ( x + 2 ) ( x − 4 ) x = 1 x = 1 x = 1 , multiplicity 2, bouncex = − 2 x = -2 x = − 2 , multiplicity 1, crossx = 4 x = 4 x = 4 , multiplicity 1, cross General Cubic : Degree 3, shape: ⅃ or ↄGeneral Quartic : Degree 4, shape: W or MTOPIC #7: EVEN/ODD FUNCTIONS Not the same as even/odd degree! Even Function Symmetric about y-axis. Examples: cosine, random graph symmetric about y-axis. Algebraically: Plug in -x, if f ( − x ) = f ( x ) f(-x) = f(x) f ( − x ) = f ( x ) , then even.Example: f ( x ) = x 4 + 3 x 2 + 2 f(x) = x^4 + 3x^2 + 2 f ( x ) = x 4 + 3 x 2 + 2 f ( − x ) = ( − x ) 4 + 3 ( − x ) 2 + 2 = x 4 + 3 x 2 + 2 = f ( x ) f(-x) = (-x)^4 + 3(-x)^2 + 2 = x^4 + 3x^2 + 2 = f(x) f ( − x ) = ( − x ) 4 + 3 ( − x ) 2 + 2 = x 4 + 3 x 2 + 2 = f ( x ) , therefore even. Odd Function Symmetric about origin. Examples: sine, random graph symmetric about origin. Algebraically: Plug in -x, if f ( − x ) = − f ( x ) f(-x) = -f(x) f ( − x ) = − f ( x ) , then odd.Example: f ( x ) = 3 x 3 − 6 x f(x) = 3x^3 - 6x f ( x ) = 3 x 3 − 6 x f ( − x ) = 3 ( − x ) 3 − 6 ( − x ) = − 3 x 3 + 6 x = − f ( x ) f(-x) = 3(-x)^3 - 6(-x) = -3x^3 + 6x = -f(x) f ( − x ) = 3 ( − x ) 3 − 6 ( − x ) = − 3 x 3 + 6 x = − f ( x ) , therefore odd. TOPIC #8: AVERAGE RATE OF CHANGE Slope! m = y < e m > 2 − y < / e m > 1 x < e m > 2 − x < / e m > 1 m = \frac{y<em>2 - y</em>1}{x<em>2 - x</em>1} m = x < e m > 2 − x < / e m > 1 y < e m > 2 − y < / e m > 1 If the y-values are not given, find them and do the slope formula. TOPIC #9: INVERSE FUNCTIONS f − 1 ( x ) f^{-1}(x) f − 1 ( x ) Switch x and y. Solve for y. Example: f ( x ) = 2 x − 3 f(x) = 2x - 3 f ( x ) = 2 x − 3 x = 2 y − 3 x = 2y - 3 x = 2 y − 3 x + 3 = 2 y x + 3 = 2y x + 3 = 2 y y = 1 2 x + 3 2 y = \frac{1}{2}x + \frac{3}{2} y = 2 1 x + 2 3 Example: f ( x ) = x − 1 x + 3 f(x) = \frac{x-1}{x+3} f ( x ) = x + 3 x − 1 x = y − 1 y + 3 x = \frac{y-1}{y+3} x = y + 3 y − 1 x ( y + 3 ) = y − 1 x(y+3) = y-1 x ( y + 3 ) = y − 1 x y + 3 x = y − 1 xy + 3x = y - 1 x y + 3 x = y − 1 x y − y = − 3 x − 1 xy - y = -3x - 1 x y − y = − 3 x − 1 y ( x − 1 ) = − 3 x − 1 y(x-1) = -3x - 1 y ( x − 1 ) = − 3 x − 1 y = − 3 x − 1 x − 1 = 3 x + 1 1 − x y = \frac{-3x-1}{x-1} = \frac{3x+1}{1-x} y = x − 1 − 3 x − 1 = 1 − x 3 x + 1 f − 1 ( x ) = − 3 x − 1 x − 1 = 3 x + 1 1 − x f^{-1}(x) = \frac{-3x-1}{x-1} = \frac{3x+1}{1-x} f − 1 ( x ) = x − 1 − 3 x − 1 = 1 − x 3 x + 1 TOPIC #10: PARABOLAS - FOCUS/DIRECTRIX A parabola is a set of points equidistant from a point (focus) and a line (directrix). p p p = distance from vertex to focus or directrixEquations:y = ± 1 4 p ( x − h ) 2 + k y = \pm \frac{1}{4p} (x-h)^2 + k y = ± 4 p 1 ( x − h ) 2 + k x = ± 1 4 p ( y − k ) 2 + h x = \pm \frac{1}{4p} (y-k)^2 + h x = ± 4 p 1 ( y − k ) 2 + h ( h , k ) (h, k) ( h , k ) is the vertex.Graph always opens toward the focus! y = + opens up. y = - opens down. x = + opens right. x = - opens left. Example:Vertex ( 1 , 2 ) (1, 2) ( 1 , 2 ) , p = 2 p = 2 p = 2 , opens down. Equation: y = − 1 4 ( 2 ) ( x − 1 ) 2 + 2 = − 1 8 ( x − 1 ) 2 + 2 y = -\frac{1}{4(2)} (x-1)^2 + 2 = -\frac{1}{8} (x-1)^2 + 2 y = − 4 ( 2 ) 1 ( x − 1 ) 2 + 2 = − 8 1 ( x − 1 ) 2 + 2 Converting to Focus/Directrix Form Solve for the variable that is NOT being squared! Example:( x − 1 ) 2 = − 8 ( y − 2 ) (x-1)^2 = -8(y-2) ( x − 1 ) 2 = − 8 ( y − 2 ) ( x − 1 ) 2 = − 8 y + 16 (x-1)^2 = -8y + 16 ( x − 1 ) 2 = − 8 y + 16 ( x − 1 ) 2 − 16 = − 8 y (x-1)^2 - 16 = -8y ( x − 1 ) 2 − 16 = − 8 y y = − 1 8 ( x − 1 ) 2 + 2 y = -\frac{1}{8} (x-1)^2 + 2 y = − 8 1 ( x − 1 ) 2 + 2 Vertex: ( 1 , 2 ) (1, 2) ( 1 , 2 ) , p = 2 p = 2 p = 2 TOPIC #6A: EXPONENTIALS Exponential Growth Asymptote on x-axis (y = 0 y = 0 y = 0 ). x-int: NONE y-int: ( 0 , 1 ) (0, 1) ( 0 , 1 ) As x → ∞ x \rightarrow \infty x → ∞ , f ( x ) → ∞ f(x) \rightarrow \infty f ( x ) → ∞ As x → − ∞ x \rightarrow -\infty x → − ∞ , f ( x ) → 0 f(x) \rightarrow 0 f ( x ) → 0 Examples: y = 2 x y = 2^x y = 2 x , y = e x y = e^x y = e x Table of values is increasing. Exponential Decay Asymptote on x-axis (y = 0 y = 0 y = 0 ). x-int: NONE y-int: ( 0 , 1 ) (0, 1) ( 0 , 1 ) As x → ∞ x \rightarrow \infty x → ∞ , f ( x ) → 0 f(x) \rightarrow 0 f ( x ) → 0 As x → − ∞ x \rightarrow -\infty x → − ∞ , f ( x ) → ∞ f(x) \rightarrow \infty f ( x ) → ∞ Examples: y = ( 1 2 ) x y = (\frac{1}{2})^x y = ( 2 1 ) x , y = 2 − x y = 2^{-x} y = 2 − x Table of values is decreasing. Know how to graph weird exponentials by typing them into your calculator and graphing values from the table! Asymptote Usually on x-axis unless graph is shifted up or down. Example: y = 2 x + 2 y = 2^x + 2 y = 2 x + 2 . Asymptote is now at y = 2 y = 2 y = 2 .As x → ∞ x \rightarrow \infty x → ∞ , f ( x ) → ∞ f(x) \rightarrow \infty f ( x ) → ∞ As x → − ∞ x \rightarrow -\infty x → − ∞ , f ( x ) → 2 f(x) \rightarrow 2 f ( x ) → 2 Basic Exponential Growth / Decay Formulas A = A 0 ( 1 ± r ) t A = A_0 (1 \pm r)^t A = A 0 ( 1 ± r ) t A A A = amount after t timeA 0 A_0 A 0 = initial amountr r r = rate as a decimalt t t = time
*Example:
*Solve for r:150 = 130 ( 1 + r ) 5 150=130(1+r)^5 150 = 130 ( 1 + r ) 5 150 130 = ( 1 + r ) 5 \frac{150}{130}=(1+r)^5 130 150 = ( 1 + r ) 5 150 130 5 = 1 + r \sqrt[5]{\frac{150}{130}}=1+r 5 130 150 = 1 + r r = 0.029 = 2.9033 r = 0.029 = 2.9033 r = 0.029 = 2.9033 Half Life A = A 0 ( 1 2 ) t v A = A_0 (\frac{1}{2})^{\frac{t}{v}} A = A 0 ( 2 1 ) v t A A A = amount after t timeA 0 A_0 A 0 = initial amountv v v = half life in time
*If v = .00357 then rate as a decimial is l n ( .5 ) / v = − 194.11 ln(.5)/v = -194.11 l n ( .5 ) / v = − 194.11 Compound Interest A = P ( 1 + r n ) n t A = P(1 + \frac{r}{n})^{nt} A = P ( 1 + n r ) n t A A A = amount after t timeP P P = initial amount (principal)r r r = rate as a decimaln n n = number of times it is compounded per year.n = 1 n = 1 n = 1 annuallyn = 2 n = 2 n = 2 semiannuallyn = 4 n = 4 n = 4 quarterlyn = 12 n = 12 n = 12 monthlyn = 52 n = 52 n = 52 weeklyContinuous Compound Interest A = P e r t A = Pe^{rt} A = P e r t A A A = amount after t timeP P P = initial amount (principal)r r r = rate as a decimalt t t = time
*Example:
*Solve for Ao:150 = A < e m > 0 ( 1.03 ) 5 150 = A<em>0(1.03)^5 150 = A < e m > 0 ( 1.03 ) 5 A < / e m > 0 = 129.4 A</em>0=129.4 A < / e m > 0 = 129.4 Exponential Time Adjustments
*40 ( 1.65 ) t 40(1.65)^t 40 ( 1.65 ) t
*Given 40 ( 1.65 ) t 40(1.65)^t 40 ( 1.65 ) t where t is in years. Convert to months m = 12 t m = 12t m = 12 t
*40 ( 1.65 ) m 12 = 40 ( 1.0426 ) 12 t 12 40(1.65)^{\frac{m}{12}} = 40(1.0426)^{\frac{12t}{12}} 40 ( 1.65 ) 12 m = 40 ( 1.0426 ) 12 12 t Down Payment : how much money you pay first before taking out a loan.
*House Costs: $200,000. Down payment is $50,000.Loan amount would be $150,0000
*Car Costs $18,000. Loan amount is $15,000. Down payment is $3,000.Total Cost = Down Payment + Loan/Borrowed Amount Down Payment = Total Cost - Loan/Borrowed Amount TOPIC #6B: LOGARITHMS Log Graphsy = log x y = \log x y = log x Y-int: NONE As x → ∞ x \rightarrow \infty x → ∞ , f ( x ) → ∞ f(x) \rightarrow \infty f ( x ) → ∞ As x → 0 x \rightarrow 0 x → 0 , f ( x ) → − ∞ f(x) \rightarrow -\infty f ( x ) → − ∞ Asymptote on y-axis (x = 0 x = 0 x = 0 ). x-int: ( 1 , 0 ) (1, 0) ( 1 , 0 ) A shift right or left will move the asymptote.y = log ( x − 2 ) y = \log(x-2) y = log ( x − 2 ) Asymptote is at x = 2 x = 2 x = 2 As x → ∞ x \rightarrow \infty x → ∞ , f ( x ) → ∞ f(x) \rightarrow \infty f ( x ) → ∞ As x → 2 x \rightarrow 2 x → 2 , f ( x ) → − ∞ f(x) \rightarrow -\infty f ( x ) → − ∞ Since it was moved right 2 units. Logs + Exps are INVERSES!
*Inverse of y = 2 x y = 2^x y = 2 x is y = l o g 2 x y = log_2x y = l o g 2 x
*Inverse of y = e x y = e^x y = e x is y = l n x y = lnx y = l n x ExpLog Conversion a b = c a^b = c a b = c converts to l o g < e m > a c = b log<em>ac = b l o g < e m > a c = b
*Solve for X: l o g < / e m > 8 x = 2 → 8 2 = x → x = 64 log</em>8x = 2 \rightarrow 8^2 = x \rightarrow x = 64 l o g < / e m > 8 x = 2 → 8 2 = x → x = 64 Special LogsCommon log: base 10, l o g 10 x = l o g x log_{10}x = log x l o g 10 x = l o gx Natural log: base e, l o g e x = ln x log_ex = \ln x l o g e x = ln x Solving for Exponents using LogsIsolate the exponential first (divide any coefficients out, move constants over). Use explog conversion.
*Examples:
*Basic: 2 X + 3 = 6 → l o g < e m > 26 = x + 3 ⇒ x = l o g < / e m > 26 − 3 = − .415 2^{X+3} = 6 \rightarrow log<em>26 = x+3 \Rightarrow x = log</em>26 - 3 = -.415 2 X + 3 = 6 → l o g < e m > 26 = x + 3 ⇒ x = l o g < / e m > 26 − 3 = − .415
*100 = 80 e 2 t → 1.25 = e 2 t ⇒ l n ( 1.25 ) = 2 t ⇒ t = .112 100 = 80e^{2t} \rightarrow 1.25 = e^{2t} \Rightarrow ln(1.25) = 2t\Rightarrow t=.112 100 = 80 e 2 t → 1.25 = e 2 t ⇒ l n ( 1.25 ) = 2 t ⇒ t = .112
*Equations w/ Fractional Exp.
*Isolate Variable
*Raise to reciprocal power:
Example: 2 x 3 2 + 4 = 36 ⇒ x 3 2 = 16 ⇒ ( x 3 2 ) 2 3 = 16 2 3 ⇒ x = 64 2x^{\frac{3}{2}} + 4 = 36 \Rightarrow x^{\frac{3}{2}} = 16 \Rightarrow (x^{\frac{3}{2}})^{\frac{2}{3}} = 16^{\frac{2}{3}} \Rightarrow x = 64 2 x 2 3 + 4 = 36 ⇒ x 2 3 = 16 ⇒ ( x 2 3 ) 3 2 = 1 6 3 2 ⇒ x = 64
*Solving Exponentials by Changing Bases
*get common base.
*Example: 4 9 x − 5 = 32 x + 8 ⇒ ( 2 2 ) 9 x − 5 = ( 2 5 ) x + 8 ⇒ 18 x − 10 = 5 x + 40 4^{9x-5} = 32^{x+8} \Rightarrow (2^2)^{9x-5} = (2^5)^{x+8} \Rightarrow 18x-10 = 5x+40 4 9 x − 5 = 3 2 x + 8 ⇒ ( 2 2 ) 9 x − 5 = ( 2 5 ) x + 8 ⇒ 18 x − 10 = 5 x + 40 13 x = 50 ⇒ x = 50 13 13x = 50 \Rightarrow x = \frac{50}{13} 13 x = 50 ⇒ x = 13 50 TOPIC #7: SEQUENCES + SERIES Arithmetic Sequence Created by adding a certain value (common difference, d) to the previous term. TERM FORMULA: a < e m > n = a < / e m > 1 + ( n − 1 ) d a<em>n = a</em>1 + (n-1)d a < e m > n = a < / e m > 1 + ( n − 1 ) d (on ref. sheet)
*Example:
*$-7, -3, 1, 5, 9,…∗ d = + 4 d = + 4 < u l > < l i > F i n d 11 t h t e r m : *d = +4 d = +4<ul>
<li>Find 11th term: ∗ d = + 4 d = + 4 < u l >< l i > F in d 11 t h t er m : a_{11} = -7 + (11-1)(4) = -7 + 10(4) = 33< b r / > ∗ E x p l i c i t F o r m u l a − W r i t t e n i n t e r m s o f n : < b r / > ∗ <br />
*Explicit Formula - Written in terms of n:<br />
* < b r / > ∗ E x pl i c i tF or m u l a − W r i tt e nin t er m so f n :< b r / > ∗ -7, -3, 1, 5, 9,…< / l i > < / u l > < / l i > < l i > </li></ul></li>
<li> < / l i >< / u l >< / l i >< l i > a_n = -7 + (n-1)(4) = 4n-11∗ F I N D I N G S U M : < / l i > < l i > O f f i r s t 11 t e r m s : < u l > < l i > * FINDING SUM:</li>
<li>Of first 11 terms:<ul>
<li> ∗ F I N D I NGS U M :< / l i >< l i > O ff i rs t 11 t er m s :< u l >< l i > \sum_{n=1}^{11} (4n-11) = 143
Math --> summation Sequence a pattern of numbers in a certain order Series a sum of a sequence Geometric Sequence Created by multiplying each term by a certain value (common ratio, r). TERM FORMULA: an = a 1 \cdot r^{n-1}< u l > < l i > ( o n r e f s h e e t ) ∗ T w o W a y s : E x a m p l e ∗ 8 , 2 , .5 , .125 , … < u l > < l i > F i n d 5 t h t e r m : <ul>
<li>(on ref sheet)
*Two Ways:
Example
*8, 2, .5, .125,…<ul>
<li>Find 5th term: < u l >< l i > ( o n re f s h ee t ) ∗ Tw o Wa ys : E x am pl e ∗ 8 , 2 , .5 , .125 , … < u l >< l i > F in d 5 t h t er m : a5 = 8 (\frac{1}{4})^{5-1} = 8(\frac{1}{4})^4 = \frac{1}{32}∗ F I N D I N G S U M : F i n d S u m o f f i r s t 11 t e r m s *FINDING SUM:
Find Sum of first 11 terms ∗ F I N D I NGS U M : F in d S u m o ff i rs t 11 t er m s \sum {n=1}^{11}8(\frac{1}{4})^{n-1}=[10.66666412]$$
Sum formula from ref sheet