(12)Organic Chemistry: IR Spectroscopy and Mass Spectrometry - Comprehensive Notes

Organic Chemistry: Infrared Spectroscopy and Mass Spectrometry

Introduction to Spectroscopy

  • Spectroscopy is a technique used to determine the structure of a compound.
  • Most techniques are nondestructive, meaning they destroy little to no sample.
  • Absorption spectroscopy measures the amount of light absorbed by a sample as a function of wavelength.

Types of Spectroscopy

  • Infrared (IR) spectroscopy: Measures the bond vibration frequencies in a molecule and is used to determine the functional group.
  • Mass spectrometry (MS): Fragments the molecule and measures the mass. MS can give the molecular weight of the compound and functional groups.
  • Nuclear magnetic resonance (NMR) spectroscopy: Analyzes the environment of the hydrogens in a compound, providing clues about alkyl and other functional groups present.
  • Ultraviolet (UV) spectroscopy: Uses electronic transitions to determine bonding patterns.

Wavelength and Frequency

  • The frequency ν\nu of a wave is the number of complete wave cycles that pass a fixed point in a second.
  • Wavelength λ\lambda is the distance between any two peaks (or any two troughs) of the wave.

Electromagnetic Spectrum

  • Frequency and wavelength are inversely proportional, related by the equation: ν=cλ\nu = \frac{c}{\lambda}, where cc is the speed of light (approximately 3×10103 × 10^{10} cm/sec).
  • The energy of a photon is given by: E=hνE = h\nu, where hh is Planck’s constant (6.62×10376.62 × 10^{-37} kJ•sec).

The Infrared (IR) Region

  • The IR region is located from just below the visible region to just above the highest microwave and radar frequencies.
  • Wavelengths typically range from 2.5×1042.5 × 10^{-4} to 25×10425 × 10^{-4} cm.
  • Wavenumbers (cm⁻¹) are commonly used units, representing the number of cycles (wavelengths) in a centimeter. They are proportional to frequency and energy.

Molecular Vibrations

  • When a bond is stretched, a restoring force pulls the two atoms together toward their equilibrium bond length.
  • When a bond is compressed, the restoring force pushes the two atoms apart.
  • If a bond is stretched or compressed and then released, the atoms vibrate.

Bond Stretching Frequencies

  • Frequency decreases with increasing atomic mass.
  • Frequency increases with increasing bond energy.

Vibrational Modes

  • A nonlinear molecule with nn atoms has 3n63n – 6 fundamental vibrational modes.
  • Water (H₂O) has 3(3)6=33(3) – 6 = 3 modes: two stretching modes and one bending mode (scissoring).

Fingerprint Region of the Spectrum

  • No two molecules (except enantiomers) will give exactly the same IR spectrum.
  • The fingerprint region is between 600 and 1400 cm⁻¹ and contains the most complex vibrations.
  • The region between 1600 and 3500 cm⁻¹ has the most common vibrations and can be used to identify specific functional groups.

Effect of an Electric Field on a Polar Bond

  • A bond with a dipole moment (e.g., HF) is either stretched or compressed by an electric field, depending on the field's direction.
  • The force on the positive charge is in the direction of the electric field (EE), and the force on the negative charge is in the opposite direction.

Carbon–Carbon Bond Stretching

  • Stronger bonds absorb at higher frequencies because they are more difficult to stretch.
  • Conjugation lowers the frequency:
    • Isolated C=C: 1640-1680 cm⁻¹ (e.g., cyclohexene at 1645 cm⁻¹)
    • Conjugated C=C: 1620-1640 cm⁻¹ (e.g., cyclohexa-1,3-diene at 1620 cm⁻¹)
    • Aromatic C=C: approximately 1600 cm⁻¹

Carbon–Hydrogen Stretching

  • A greater percentage of s character in the hybrid orbitals will make the C—H bond stronger.
  • The C—H bond of an sp³ carbon will be slightly weaker than the C—H bond of an sp² or an sp carbon.

IR Spectrum of Alkanes

  • An alkane will show stretching and bending frequencies for C—H and C—C bonds only.
  • The C—H stretching is a broad band between 2800 and 3000 cm⁻¹, a band present in virtually all organic compounds.
  • The absence of other bands indicates the presence of no other functional groups.

IR Spectrum of Alkenes

  • The most important absorptions in 1-hexene are the C=C stretch at 1642 cm⁻¹ and the unsaturated C-H stretch at 3080 cm⁻¹.
  • The bands of the alkane are also present in the alkene.

IR Spectra of Alkynes

  • Terminal alkynes (e.g., oct-1-yne) show:
    • ≡C-H stretch around 3313 cm⁻¹
    • C≡C stretch around 2119 cm⁻¹
  • Internal alkynes (e.g., oct-4-yne) may not show a C≡C or ≡C-H stretch.

O—H and N—H Stretching

  • Both O—H and N—H stretching occur around 3300 cm⁻¹, but they look different:
    • Alcohol O—H is broad with a rounded tip.
    • Secondary amine (R₂NH) is broad with one sharp spike.
    • Primary amine (RNH₂) is broad with two sharp spikes.
    • There is no signal for a tertiary amine (R₃N) because there is no hydrogen.

IR Spectrum of Alcohols

  • Alcohols show a broad, intense O—H stretching absorption centered around 3300 cm⁻¹.
  • The broad shape is due to the diverse nature of hydrogen bonding interactions of alcohol molecules.

IR Spectrum of Amines

  • Amines show a broad N—H stretching absorption centered around 3300 cm⁻¹.
  • Dipropylamine (secondary amine) has only one hydrogen, so it will have only one spike in its spectrum. A primary amine (RNH₂) gives two spikes around 3300 cm⁻¹.

Ketones, Aldehydes, and Acids

  • The C=O bond of simple ketones, aldehydes, and carboxylic acids absorbs around 1710 cm⁻¹.
  • Usually, the carbonyl is the strongest IR signal.
  • Carboxylic acids will also have O—H stretching.
  • Aldehydes have two C—H signals around 2700 and 2800 cm⁻¹.

IR Spectrum of Ketones

  • 2-Heptanone shows a strong, sharp absorption at 1718 cm⁻¹ due to the C=O stretch.

IR Spectrum of Aldehydes

  • Aldehydes have the C=O stretch around 1710 cm⁻¹.
  • They also have two different stretch bands for the C—H bond at 2720 and 2820 cm⁻¹.

O—H Stretch of Carboxylic Acids

  • This O—H absorbs broadly, 2500–3500 cm⁻¹, due to strong hydrogen bonding.
  • Both peaks (C=O and O-H) need to be present to identify the compound as a carboxylic acid.

Conjugated Carbonyl Compounds

  • Conjugation lowers the carbonyl absorption to around 1685 cm⁻¹.

Resonance in Amides

  • The carbonyl groups of amides absorb at particularly low IR frequencies: about 1640 to 1680 cm⁻¹.

IR Spectrum of Amides

  • Amides will show a strong absorption for the C=O at 1640–1680 cm⁻¹.
  • If there are hydrogens attached to the nitrogen of the amide, there will be N—H absorptions around 3300 cm⁻¹.

Carbonyl Absorptions Above 1725 cm⁻¹

  • Esters typically absorb around 1735 cm⁻¹.
  • Strained cyclic ketones absorb at a higher frequency because the angle strain on the carbonyl results in a stronger, stiffer bond.

Carbon-Nitrogen Stretching

  • C-N single bond: approximately 1200 cm⁻¹
  • C=N double bond: approximately 1660 cm⁻¹
  • C≡N triple bond: greater than 2200 cm⁻¹
    • C≡C triple bond: less than 2200 cm⁻¹

IR Spectrum of Nitriles

  • A carbon–nitrogen triple bond has an intense and sharp absorption, centered around 2200 to 2300 cm⁻¹.
  • Nitrile bonds are more polar than carbon–carbon triple bonds, so nitriles produce stronger absorptions than alkynes.

Summary of IR Absorptions

  • Key functional groups and their approximate absorption ranges:
    • O-H: 3300 cm⁻¹ (broad)
    • N-H: 3300 cm⁻¹ (may be broad, sharp, or broad with spikes)
    • ≡C-H: 3300 cm⁻¹ (always sharp, usually strong)
    • =C-H: just above 3000 cm⁻¹
    • -C-H (alkane): just below 3000 cm⁻¹
    • C≡N: approximately 2200 cm⁻¹ (very strong)
    • C=O: approximately 1710 cm⁻¹
    • C=C: approximately 1660 cm⁻¹

Solved Problem Example

  • To determine the functional group(s) in a compound, look for peaks outside the fingerprint region that don't look like alkane peaks.
  • For example, a weak peak around 3400 cm⁻¹, a strong peak about 1720 cm⁻¹, and C–H stretching peaks around 2720 and 2820 cm⁻¹ suggest an aldehyde.
  • The peak at 1720 cm⁻¹ indicates a C=O, and the peaks at 2720 and 2820 cm⁻¹ confirm an aldehyde.

Strengths and Limitations of IR Spectroscopy

  • IR alone cannot determine a structure.
  • Some signals may be ambiguous.
  • The functional group is usually indicated.
  • The absence of a signal is definite proof that the functional group is absent.
  • Correspondence with a known sample’s IR spectrum confirms the identity of the compound.

Introduction to Mass Spectrometry (MS)

  • Molecular weight and molecular formula can be obtained from a very small sample.
  • Mass spectrometry is fundamentally different from spectroscopy.
  • Destructive technique: The sample cannot be recovered.

Mass Spectrometry Process

  • A beam of high-energy electrons breaks the molecule apart.
  • The masses of the fragments and their relative abundance reveal information about the structure of the molecule.

Radical Cation Formation

  • When a molecule loses one electron, it then has a positive charge and one unpaired electron. This ion is therefore called a radical cation.

Electron Impact Ionization

  • Other fragments can be formed when C—C or C—H bonds are broken during ionization. Only the positive fragments can be detected in MS.

Mass Spectrometer Components

  • Ion source
  • Magnet
  • Flight tube
  • Detector
  • Recorder

Separation of Ions

  • The most common mass spectrometer separates ions by magnetic deflection.
  • The mixture of ions is accelerated and passes through a magnetic field where the paths of lighter ions are bent more than those of heavier atoms.
  • By varying the magnetic field, the spectrometer plots the abundance of ions of each mass.
  • The exact radius of curvature of an ion's path depends on its mass-to-charge ratio, symbolized by m/z. In this expression, m is the mass of the ion (in amu) and z is its charge.
  • The vast majority of ions have a +1 charge, so we consider their path to be curved by an amount that depends only on their mass.

The Mass Spectrum

  • In the spectrum, the tallest peak is called the base peak and it is assigned an abundance of 100%. The % abundance of all other peaks is given relative to the base peak.
  • The molecular ion or parent peak (M+) corresponds to the molecular weight of the original molecule.

Gas Chromatography–Mass Spectrometry (GC–MS)

  • The gas chromatograph column separates the mixture into its components.
  • The mass spectrometer scans mass spectra of the components as they leave the column.

High-Resolution MS

  • Masses are measured to an accuracy of about 1 part in 20,000.
  • A molecule with a mass of 44 could be C3H8, C2H4O, CO2, or CN2H4.
  • Using HRMS, the exact mass can be found and the compound successfully identified.

Masses of Common Isotopes

  • ¹²C: 12.000000 amu
  • ¹H: 1.007825 amu
  • ¹⁶O: 15.994914 amu
  • ¹⁴N: 14.003050 amu

Molecules with Heteroatoms

  • Isotopes are present in their usual abundance.
  • Carbon has a ¹³C isotope present in 1.1% abundance. The spectrum will show the normal M+ and small M+1 peak.
  • Bromine has two isotopes: ⁷⁹Br (50.5%) and ⁸¹Br (49.5%). Since the abundances are almost equal, there will be an M+ peak and an M+2 peak of equal height.

Isotopic Abundance

  • Key elements and their isotopic composition:
    • Hydrogen: ¹H (100.0%)
    • Carbon: ¹²C (98.9%), ¹³C (1.1%)
    • Nitrogen: ¹⁴N (99.6%), ¹⁵N (0.4%)
    • Oxygen: ¹⁶O (99.8%), ¹⁸O (0.2%)
    • Sulfur: ³²S (95.0%), ³³S (0.8%), ³⁴S (4.2%)
    • Chlorine: ³⁵Cl (75.5%), ³⁷Cl (24.5%)
    • Bromine: ⁷⁹Br (50.5%), ⁸¹Br (49.5%)
    • Iodine: ¹²⁷I (100.0%)

Mass Spectrum with Bromine

  • Bromine is a mixture of 50.5% ⁷⁹Br and 49.5% ⁸¹Br. The molecular ion peak M+ (⁷⁹Br) is nearly as tall as the M+2 peak (⁸¹Br).

Mass Spectrum with Chlorine

  • Chlorine is a mixture of 75.5% ³⁵Cl and 24.5% ³⁷Cl. Since the ratio is approximately 3:1, the molecular ion peak M+ is three times higher than the M+2 peak.

Mass Spectrum with Sulfur

  • Sulfur has three isotopes: ³²S (95%), ³³S (0.8%), and ³⁴S (4.2%).
  • The M+ peak will have an M+2 peak that is larger than usual (about 4% of M+).

Mass Spectrum of n-Hexane

  • Groups of ions correspond to loss of one-, two-, three-, and four-carbon fragments.

Fragmentation of the Hexane Radical Cation

  • Fragmentations often split off simple alkyl groups:
    • Methyl (CH₃): 15
    • Ethyl (C₂H₅): 29
    • Propyl (C₃H₇): 43
    • Butyl (C₄H₉): 57

Mass Spectrum of 2-Methylpentane

  • Characteristic fragmentations due to branching, such as loss of methyl (M-15), ethyl (M-29), and propyl (M-43) groups.

Fragmentation of Branched Alkanes

  • The most stable carbocation fragments form in greater amounts.

Resonance-Stabilized Cations

  • Fragmentation in the mass spectrometer gives resonance-stabilized cations whenever possible. The most common fragmentation of alkenes is cleavage of an allylic bond to give a resonance-stabilized allylic cation.

Mass Spectrum of Alkenes

  • Resonance-stabilized cations are favored.

Benzylic Cation

  • Compounds containing aromatic rings tend to fragment at the carbon next to the aromatic ring.
  • Such a cleavage forms a resonance-stabilized benzylic cation.

Mass Spectrum of Alcohols

  • Alcohols often lose water (H2OH_2O).

MS of 3-Methylbutan-1-ol

  • Loss of water and formation of an allylic cation.

Fragmentation of Ethers, Amines, and Carbonyl Compounds

  • Ethers, amines, and carbonyl compounds can also fragment to give resonance-stabilized cations.

EI MS of Di-sec-butyl Ether

  • Shows almost no molecular ion.
  • Molecular ion formed by loss of an electron from the ether oxygen.
  • Next, an ethyl radical is lost via α-cleavage forming the base peak at m/z = 45.