Boltzmann Statistics Notes

Boltzmann Statistics

Introduction
  • This chapter provides a detailed approach to compute thermodynamic quantities using microscopic models and first principles.

  • Expands upon earlier models such as the two-state paramagnet, Einstein solid, and monatomic ideal gas, incorporating more complex scenarios.

  • Introduces essential theoretical tools designed for handling intricate models where direct combinatorics becomes challenging.

The Boltzmann Factor
  • The Boltzmann factor is introduced to determine the probability of a system existing in a specific microstate when thermodynamically balanced with a reservoir at a defined temperature.

  • A single atom with microstates that correspond to its energy levels exemplifies this system.

    • Energy levels are dictated by the solutions to the Schrodinger equation for the atom, solved given the atom's potential.

  • Degeneracy: Degeneracy occurs when an energy level is associated with multiple independent states.

    • Mathematically, if multiple states s1,s2,,sns1, s2, …, sn all have energy E(s1) = E(s2) = … = E(sn) then this energy level is said to be degenerate.

    • Degeneracy is often associated with symmetry, where different quantum numbers can yield the same energy.

  • The fundamental postulate in statistical mechanics states that every accessible microstate in an isolated system has equal probability.

    • Accessible refers to states that are permissable given the macroscopic constraints on the system like total energy, number of particles, and volume.

  • The combination of the atom and the reservoir creates an isolated system.


  • :Representsthereservoirsmultiplicitywhentheatomisinstate: Represents the reservoir's multiplicity when the atom is in state s1s_1.

  • The likelihood of the atom being in a particular state is directly proportional to the count of microstates available to the reservoir.

  • P(s2)P(s1)=(s2)Ω(s1)\frac{P(s2)}{P(s1)}=\frac{\left|(s2)\right.}{\Omega(s1)}

  • Expressing multiplicity via entropy using S=klnΩS = k \ln \Omega:

P(s<em>2)P(s</em>1)=eS<em>R(s</em>2)/keS<em>R(s</em>1)/k=e[S<em>R(s</em>2)S<em>R(s</em>1)]/k\frac{P(s<em>2)}{P(s</em>1)} = \frac{e^{S<em>R(s</em>2)/k}}{e^{S<em>R(s</em>1)/k}} = e^{[S<em>R(s</em>2) - S<em>R(s</em>1)]/k}

  • The thermodynamic identity is defined as:

dS<em>R=1TdU</em>R+PdV<em>RμdN</em>RdS<em>R = \frac{1}{T} dU</em>R + P dV<em>R - \mu dN</em>R

  • The energy, volume, and particle number changes in the reservoir are linked to the atom's energy changes.

  • S<em>R(s</em>2)S<em>R(s</em>1)=1T[U<em>R(s</em>2)U<em>R(s</em>1)]=1T[E(s<em>2)E(s</em>1)]S<em>R(s</em>2) - S<em>R(s</em>1) = \frac{1}{T}[U<em>R(s</em>2) - U<em>R(s</em>1)] = - \frac{1}{T}[E(s<em>2) - E(s</em>1)]

  • The probability ratio is:

P(s<em>2)P(s</em>1)=e[E(s<em>2)E(s</em>1)]/kT=eE(s<em>2)/kTeE(s</em>1)/kT\frac{P(s<em>2)}{P(s</em>1)} = e^{-[E(s<em>2) - E(s</em>1)]/kT} = \frac{e^{-E(s<em>2)/kT}}{e^{-E(s</em>1)/kT}}

  • Boltzmann factor:

eE(s)/kTe^{-E(s)/kT}

  • The probability of each state:
    P(s)=1ZeE(s)/kTP(s) = \frac{1}{Z} e^{-E(s)/kT}

    • ZZ represents the partition function, a normalizing constant to ensure the total probability equals 1.

    • Equation 6.8, also known as the Boltzmann or canonical distribution, is fundamental in statistical mechanics.

  • Setting E0=0E_0 = 0 for the ground state, states having energies significantly less than kTkT have probabilities close to 1/Z1/Z, whereas those with energies far greater than kTkT have negligible probabilities.

  • A constant shift in all energies does not impact probabilities. All Boltzmann factors get an added factor of eE0/kTe^{-E_0/kT}, which also multiplies ZZ, leading to cancellation.

The Partition Function

  • The cumulative probability of the atom existing in any state must be 1:

1=<em>sP(s)=</em>s1ZeE(s)/kT=1ZseE(s)/kT1 = \sum<em>s P(s) = \sum</em>s \frac{1}{Z} e^{-E(s)/kT} = \frac{1}{Z} \sum_s e^{-E(s)/kT}

  • Solving for ZZ yields:

Z=seE(s)/kT=sum of all Boltzmann factorsZ = \sum_s e^{-E(s)/kT} = \text{sum of all Boltzmann factors}

  • The partition function effectively calculates the number of accessible states for the atom, weighting each by its probability.

    • The partition function tells us how probability is distributed among the various energy states for a given temperature.

  • At very low temperatures, Z1Z \approx 1 since Boltzmann factors for excited states are minimal.

  • At elevated temperatures, ZZ becomes significantly larger, indicating greater accessibility to numerous states.

  • Shifting all energies by a constant E<em>0E<em>0 results in the partition function being multiplied by eE</em>0/kTe^{-E</em>0/kT}, which is inconsequential when computing probabilities.

Thermal Excitation of Atoms

  • Examines a hydrogen atom in the sun's atmosphere at approximately 5800 K.

  • The probability ratio for finding the atom in its first excited states (s<em>2s<em>2) versus the ground state (s</em>1s</em>1) is:

P(s<em>2)P(s</em>1)=eE<em>2/kTeE</em>1/kT=e(E<em>2E</em>1)/kT\frac{P(s<em>2)}{P(s</em>1)} = \frac{e^{-E<em>2/kT}}{e^{-E</em>1/kT}} = e^{-(E<em>2 - E</em>1)/kT}

  • With an energy difference of 10.2 eV and kTkT at (8.62×105 eV/K)(5800 K)=0.50 eV(8.62 \times 10^{-5} \text{ eV/K})(5800 \text{ K}) = 0.50 \text{ eV}, the probability ratio is approximately e20.4=1.4×109e^{-20.4} = 1.4 \times 10^{-9}.

  • Approximately 1.4 atoms are in any first excited state for every billion in the ground state.

  • Considering there are four such excited states with identical energy, the total number of atoms in these states is about 5.6 per billion in the ground state.

  • This thermal excitation of atoms leads to phenomena like the Balmer series, observed through missing wavelengths in sunlight, as electrons transition between energy levels.

Average Values
  • This section defines how to calculate the average value of any property of the system like its energy, position, or momentum.

  • Considering an atom with three states: a ground state at 0 eV, a state at 4 eV, and one at 7 eV. If there are five such atoms, with two in the ground state, two at 4 eV, and one at 7 eV.

  • The average energy is calculated as:

E=<em>sE(s)N(s)N=</em>sE(s)P(s)E = \sum<em>s E(s) \frac{N(s)}{N} = \sum</em>s E(s)P(s)

  • The average energy equals the sum of all energies, each weighted by its probability.

  • Using probabilities from equation 6.12:

E=1ZsE(s)eE(s)E = \frac{1}{Z} \sum_s E(s) e^{-E(s)}

  • The average for any variable is found similarly. If the variable is XX, with a value X(s)X(s) in state ss, then

X=<em>sX(s)P(s)=1Z</em>sX(s)eE(s)X = \sum<em>s X(s)P(s) = \frac{1}{Z} \sum</em>s X(s) e^{-E(s)}

  • Average values are additive; the total average energy of two objects sums their individual average energies.

  • For a collection of independent particles, the total average energy is the average energy of one particle times the number of particles:

U=NEU = NE

  • UU represents the entire system's average energy.

Useful Formula for Average Energy

  • An alternate representation of average energy is:

E=1ZZβ=βlnZE = - \frac{1}{Z} \frac{\partial Z}{\partial \beta} = - \frac{\partial}{\partial \beta} \ln Z

Standard Deviation

  • Quantifies energy fluctuations around the mean:

ΔE=E2(E)2\Delta E = \sqrt{E^2 - (E)^2}

Fluctuation Formula

  • Another way to express energy fluctuation is:

ΔE=kT2C\Delta E = \sqrt{kT^2 C}

  • CC denotes heat capacity.

Paramagnetism

  • An ideal two-state paramagnet features elementary dipoles with two states: “up” at energy μB-\mu B, and “down” at +μB+\mu B.

  • The partition function for a single dipole is:

Z=seE(s)=e+μB+eμB=2cosh(βμB)Z = \sum_s e^{-E(s)} = e^{+ \mu B} + e^{-\mu B} = 2 \cosh(\beta \mu B)

  • The probability of the dipole being in the “up” state:

P=e+μBZ=e+μB2cosh(βμB)P_{\uparrow} = \frac{e^{+ \mu B}}{Z} = \frac{e^{+ \mu B}}{2 \cosh(\beta \mu B)}

  • Conversely, the probability of it being in the “down” state:

P=eμBZ=eμB2cosh(βμB)P_{\downarrow} = \frac{e^{-\mu B}}{Z} = \frac{e^{-\mu B}}{2 \cosh(\beta \mu B)}

Average Energy and Total Energy

  • The average energy of the dipole is:

E=<em>sE(s)P(s)=(μB)P</em>+(+μB)P<em>=μB(P</em>P)=μBeμBeμB2cosh(βμB)=μBtanh(βμB)E = \sum<em>s E(s)P(s) = (-\mu B)P</em>{\uparrow} + (+\mu B)P<em>{\downarrow} = -\mu B(P</em>{\uparrow} - P_{\downarrow}) = -\mu B \frac{e^{\mu B} - e^{-\mu B}}{2 \cosh(\beta \mu B)} = -\mu B \tanh(\beta \mu B)

  • For NN such dipoles, the total energy is:

U=NμBtanh(βμB)U = -N \mu B \tanh(\beta \mu B)

  • The average magnetic moment of a dipole along BB:

μ<em>z=</em>sμ<em>z(s)P(s)=(+μ)P</em>+(μ)P=μtanh(βμB)\mu<em>z = \sum</em>s \mu<em>z(s)P(s) = (+\mu)P</em>{\uparrow} + (-\mu)P_{\downarrow} = \mu \tanh(\beta \mu B)

  • Therefore, the sample's total magnetization is:

M=Nμz=Nμtanh(βμB)M = N \mu_z = N \mu \tanh(\beta \mu B)

Rotation of Diatomic Molecules

  • Considers the rotational motion of an isolated diatomic molecule in low-density gas, where rotational energies are quantized.

  • For molecules like CO or HCl, allowed rotational energies are E(j)=j(j+1)ϵE(j) = j(j + 1) \epsilon, with jj being 0, 1, 2, etc., and ϵ\epsilon inversely proportional to the molecule’s moment of inertia.

  • Each level jj has 2j+12j + 1 degenerate states.

  • The partition function is a sum over jj:

Z<em>rot=</em>j=0(2j+1)eE(j)/kT=j=0(2j+1)ej(j+1)ϵ/kTZ<em>{\text{rot}} = \sum</em>{j=0} (2j + 1)e^{-E(j)/kT} = \sum_{j=0} (2j + 1)e^{-j(j+1)\epsilon/kT}

  • The constant ϵ\epsilon is generally a small fraction of an electron-volt, setting the energy scale for rotational excitations.

  • If ϵ=0.00024\epsilon = 0.00024 eV for CO, then ϵ/k=2.8\epsilon/k = 2.8 K.

  • Typically, temperatures of interest far exceed ϵ/k\epsilon/k, making kT/ϵkT/\epsilon much greater than 1.

  • With many terms contributing significantly, the partition function approximates the area under a smooth curve:

Z<em>rot</em>0(2j+1)ej(j+1)ϵ/kTdj=kTϵ(when kTϵ)Z<em>{\text{rot}} \approx \int</em>{0} (2j + 1)e^{-j(j+1)\epsilon/kT} dj = \frac{kT}{\epsilon} \quad (\text{when } kT \gg \epsilon)

High-Temperature Approximation

  • Using formula 6.25, the average rotational energy is:

Erot=1ZZβ=(βϵ)β1βϵ=1β=kT(when kTϵ)E_{\text{rot}} = - \frac{1}{Z} \frac{\partial Z}{\partial \beta} = -(\beta \epsilon) \frac{\partial}{\partial \beta} \frac{1}{\beta \epsilon} = \frac{1}{\beta} = kT \quad (\text{when } kT \gg \epsilon)

  • This aligns with the equipartition theorem, given the two rotational degrees of freedom of a diatomic molecule.

The Equipartition Theorem
  • The equipartition theorem is applicable to systems where energy presents in quadratic form, E(q)=cq2E(q) = cq^2, with cc being a constant and qq a coordinate or momentum variable.

  • Z is expressed as:

Z=eβcq2dqZ = \int e^{-\beta cq^2} dq

Average Energy

  • The average energy is:

E=12kTE = \frac{1}{2}kT

The Maxwell Speed Distribution
  • This distribution describes the speeds of molecules in a gas, with some moving faster and others slower.

  • Probability(v1 . . . v2): Probability(v<em>1v</em>2)=<em>v</em>1v2D(v)dv\text{Probability}(v<em>1 \ldots v</em>2) = \int<em>{v</em>1}^{v_2} D(v) dv, where D(v)D(v) is the distribution function.

  • The function D(v)D(v) is represented as:

D(v)probability of a molecule having velocity v×number of vectors v corresponding to speed vD(v) \propto \text{probability of a molecule having velocity } \vec{v} \times \text{number of vectors } \vec{v} \text{ corresponding to speed } v

  • Each velocity vector corresponds to a molecular state, with probability proportional to the Boltzmann factor eE(s)/kTe^{-E(s)/kT}.

  • With translational kinetic energy 12mv2\frac{1}{2}mv^2:

probability of a molecule having velocity vemv2/2kT\text{probability of a molecule having velocity } \vec{v} \propto e^{-mv^2/2kT}

Number of Vectors

  • For speed vv, the number of vectors v\vec{v} is:

4πv24\pi v^2

Maxwell Distribution

  • This distribution is:

D(v)=C4πv2emv2/2kTD(v) = C \cdot 4\pi v^2 e^{-mv^2/2kT}

  • With a constant:

C=(m2πkT)3/2C = \Big( \frac{m}{2\pi kT} \Big)^{3/2}

Maxwell Speed Distribution Formula

  • The complete distribution is:

D(v)=(m2πkT)3/24πv2emv2/2kTD(v) = \Big( \frac{m}{2\pi kT} \Big)^{3/2} 4\pi v^2 e^{-mv^2/2kT}

Most Probable Speed

  • The most probable speed is at:

vmax=2kTmv_{\text{max}} = \sqrt{\frac{2kT}{m}}

Average Speed

  • Average speed is defined by

  • v=all vvD(v)dvv = \int_{\text{all } v} v D(v) dv

  • v=8kTπmv = \sqrt{\frac{8kT}{\pi m}}

Partition Functions and Free Energy
  • The partition function is denoted as:

Z(T)Z(T)

Free energy Formula

  • Free energy is defined as:

F=kTlnZF = -kT \ln Z

  • In terms of the partition function

  • Z=eF/kTZ = e^{-F/kT}

Partition Functions for Composite Systems
  • Systems of noninteracting, distinguishable particles:

Z<em>total=Z</em>1Z2(noninteracting, distinguishable particles)Z<em>{\text{total}} = Z</em>1 Z_2 \quad (\text{noninteracting, distinguishable particles})

  • Systems of noninteracting, indistinguishable particles:

Z<em>total=12Z</em>1Z2(noninteracting, indistinguishable particles)Z<em>{\text{total}} = \frac{1}{2} Z</em>1 Z_2 \quad (\text{noninteracting, indistinguishable particles})

  • For N noninteracting, distinguishable systems:

Z<em>total=Z</em>1Z<em>2Z</em>3ZN(noninteracting, distinguishable systems)Z<em>{\text{total}} = Z</em>1 Z<em>2 Z</em>3 \ldots Z_N \quad (\text{noninteracting, distinguishable systems})

  • N noninteracting, indistinguishable particles have:

Z<em>total=1N!Z</em>1N(noninteracting, indistinguishable particles)Z<em>{\text{total}} = \frac{1}{N!}Z</em>1^N \quad (\text{noninteracting, indistinguishable particles})

Ideal Gas Revisited
  • For an ideal gas, the partition function is:

Z=1N!Z1NZ = \frac{1}{N!} Z_1^N

  • Z1Z_1 represents the partition function for a single molecule.

  • The Boltzmann factor accounts for both translational kinetic energy (E<em>trE<em>{\text{tr}}) and internal energy (E</em>intE</em>{\text{int}}):

eE(s)/kT=eE<em>tr(s)/kTeE</em>int(s)/kTe^{-E(s)/kT} = e^{-E<em>{\text{tr}}(s)/kT} e^{-E</em>{\text{int}}(s)/kT}

  • Therefore, Z<em>1=Z</em>trZintZ<em>1 = Z</em>{\text{tr}} Z_{\text{int}}, with:

Z<em>tr=</em>translational stateseEtr/kTZ<em>{\text{tr}} = \sum</em>{\text{translational states}} e^{-E_{\text{tr}}/kT}

  • and
    Z<em>int=</em>internal stateseEint/kTZ<em>{\text{int}} = \sum</em>{\text{internal states}} e^{-E_{\text{int}}/kT}

Energy Levels for Molecule in 1D box

  • The energy levels are:

En=h2n28mL2E_n = \frac{h^2 n^2}{8mL^2}

  • The partition function in a 1D box is Z1d=L/ΛZ_{\text{1d}} = L/\Lambda, where Λ=h2πmkT\Lambda = \frac{h}{\sqrt{2 \pi mkT}}

    • Λ\Lambda is the thermal de Broglie wavelength.

Quantum Volume

  • The quantum volume is:

vQ=Λ3=(h2πmkT)3v_Q = \Lambda^3 = \Big( \frac{h}{\sqrt{2 \pi mkT}} \Big)^3

Single Particle Parition Function

  • The single particle partition function is

  • Z<em>1=Vv</em>QZintZ<em>1 = \frac{V}{v</em>Q} \cdot Z_{\text{int}}

N Molecule Partition Function

  • Extended to N molecules, this becomes:

Z=1N!(VZ<em>intv</em>Q)NZ = \frac{1}{N!} \Big( \frac{V Z<em>{\text{int}}}{v</em>Q} \Big)^N

  • And:

lnZ=N[lnV+lnZ<em>intlnNlnv</em>Q+1]\ln Z = N \Big[ \ln V + \ln Z<em>{\text{int}} - \ln N - \ln v</em>Q + 1 \Big]

Total Average Energy

  • Average energy is

  • U=Uint+32NkTU = U_{\text{int}} + \frac{3}{2}NkT

Thermal properties of an Ideal gas

  • The Helmholtz Free Energy is:

$$ F= -NkT \Big[ \ln V - \ln N - \ln vQ + 1 \Big] + F{\text{int