Simplifying Expressions Containing Surds

Fundamental Rules of Surds

  • Multiplication Rule for Surds:

    • When multiplying two surds, multiply the numbers inside the root signs (radicands) together:     a×b=a×b\sqrt{a} \times \sqrt{b} = \sqrt{a \times b}

    • Example:     5×6=5×6=30\sqrt{5} \times \sqrt{6} = \sqrt{5 \times 6} = \sqrt{30}

  • Division Rule for Surds:

    • When dividing two surds, divide the numbers inside the root signs. This can be expressed in division notation or as a fraction:     a÷b=ab=ab\sqrt{a} \div \sqrt{b} = \frac{\sqrt{a}}{\sqrt{b}} = \sqrt{\frac{a}{b}}

    • Example:     20÷10=2010=2010=2\sqrt{20} \div \sqrt{10} = \frac{\sqrt{20}}{\sqrt{10}} = \sqrt{\frac{20}{10}} = \sqrt{2}

  • Restrictions on Addition and Subtraction with Different Radicands:

    • Surds with different numbers inside the root signs cannot be combined via addition or subtraction:     13+6≠19\sqrt{13} + \sqrt{6} \neq \sqrt{19}     13−6≠7\sqrt{13} - \sqrt{6} \neq \sqrt{7}

  • Addition and Subtraction Rules for Surds with Matching Radicands:

    • When surds share the exact same number inside the radical, combine them by adding or subtracting their coefficients (the numbers in front of the surd):

    • Addition Example:       23+53=732\sqrt{3} + 5\sqrt{3} = 7\sqrt{3}

    • Subtraction Example:       67−27=476\sqrt{7} - 2\sqrt{7} = 4\sqrt{7}

  • Self-Multiplication Rule:

    • Multiplying a surd by itself removes the radical sign, leaving only the radicand:     a×a=a\sqrt{a} \times \sqrt{a} = a

    • Conceptual Explanation:     7×7=7×7=49=7\sqrt{7} \times \sqrt{7} = \sqrt{7 \times 7} = \sqrt{49} = 7

Standard Exam Notation and Simplification Strategy

  • Standard Answer Format:

    • Exam problems frequently require writing a simplified surd expression in the form:     a+b5a + b\sqrt{5}

    • The variables aa and bb represent integers (positive or negative whole numbers).

    • Valid example expressions in this format include:     4+354 + 3\sqrt{5}     7−257 - 2\sqrt{5}

  • Core Simplification Method:

    • Rewrite the surd as a product of its factor pairs.

    • Select the factor pair that contains the largest square number.

    • Take the square root of the square factor and multiply it by the remaining surd factor.

Worked Example 1: Simplifying Complex Expressions

  • Problem Statement:

    • Simplify the expression:     125−245+(5+2)2\sqrt{125} - 2\sqrt{45} + (\sqrt{5} + 2)^2

    • Write the final answer in the form a+b5a + b\sqrt{5}, where aa and bb are integers.

  • Step 1: Simplifying the First Term (125\sqrt{125}):

    • Identify factor pairs of 125125 with the largest square number: 2525 and 55.

    • Rewrite as:     125=25×5\sqrt{125} = \sqrt{25} \times \sqrt{5}

    • Evaluate the square root of 2525 (25=5\sqrt{25} = 5):     5×5=555 \times \sqrt{5} = 5\sqrt{5}

  • Step 2: Simplifying the Second Term (−245-2\sqrt{45}):

    • Express 45\sqrt{45} using its factor pair containing the largest square number (99 and 55):     45=9×5\sqrt{45} = \sqrt{9} \times \sqrt{5}

    • Evaluate the square root of 99 (9=3\sqrt{9} = 3):     45=35\sqrt{45} = 3\sqrt{5}

    • Include the initial coefficient of 22:     2×3×5=652 \times 3 \times \sqrt{5} = 6\sqrt{5}

    • Include the subtraction operator from the original expression:     −65-6\sqrt{5}

  • Step 3: Simplifying the Third Term ((5+2)2(\sqrt{5} + 2)^2):

    • A squared binomial indicates multiplying the entire bracketed term by itself:     (5+2)(5+2)(\sqrt{5} + 2)(\sqrt{5} + 2)

    • Expand the brackets by multiplying each term in the first bracket by each term in the second bracket:

    • Multiply first terms:       5×5=5\sqrt{5} \times \sqrt{5} = 5

    • Multiply outer terms:       5×2=25\sqrt{5} \times 2 = 2\sqrt{5}

    • Multiply inner terms:       2×5=252 \times \sqrt{5} = 2\sqrt{5}

    • Multiply last terms:       2×2=42 \times 2 = 4

    • Combine the numeric values and like surd terms:     5+4=95 + 4 = 9     25+25=452\sqrt{5} + 2\sqrt{5} = 4\sqrt{5}

    • Simplified form of the third term:     9+459 + 4\sqrt{5}

  • Step 4: Combining All Simplified Terms:

    • Sum the simplified results from all three terms:     55−65+9+455\sqrt{5} - 6\sqrt{5} + 9 + 4\sqrt{5}

    • Group and combine like surd terms:     (5−6+4)5+9=35+9(5 - 6 + 4)\sqrt{5} + 9 = 3\sqrt{5} + 9

  • Step 5: Formatting for Required Exam Form:

    • Rearrange 35+93\sqrt{5} + 9 to fit the target format a+b5a + b\sqrt{5}:     9+359 + 3\sqrt{5}

    • Corresponding integer values are a=9a = 9 and b=3b = 3.

Worked Example 2: Alternative Simplification Problem

  • Problem Statement:

    • Simplify the expression:     48+275+(3)2\sqrt{48} + 2\sqrt{75} + (\sqrt{3})^2

    • Express the final answer in the form a+b3a + b\sqrt{3}.

  • Step 1: Simplify 48\sqrt{48}:

    • Identify factor pair with the largest square number (1616 and 33):     48=16×3=43\sqrt{48} = \sqrt{16} \times \sqrt{3} = 4\sqrt{3}

  • Step 2: Simplify 2752\sqrt{75}:

    • Identify factor pair for 7575 with the largest square number (2525 and 33):     75=25×3=53\sqrt{75} = \sqrt{25} \times \sqrt{3} = 5\sqrt{3}

    • Multiply by coefficient 22:     2×53=1032 \times 5\sqrt{3} = 10\sqrt{3}

  • Step 3: Simplify (3)2(\sqrt{3})^2:

    • Apply self-multiplication rule:     (3)2=3(\sqrt{3})^2 = 3

  • Step 4: Sum and Format Solution:

    • Combine all simplified terms:     43+103+3=143+34\sqrt{3} + 10\sqrt{3} + 3 = 14\sqrt{3} + 3

    • Rearrange to match target form a+b3a + b\sqrt{3}:     3+1433 + 14\sqrt{3}

    • Corresponding integer values are a=3a = 3 and b=14b = 14.