Physics 2211K: Study Notes on Newton's Laws

Newton's Laws of Motion Overview

Basic Concepts of Newton's Laws

  • Newton's Laws of Motion are foundational principles that describe the relationship between the motion of an object and the forces acting upon it.

  • There are three primary laws:

    • First Law (Law of Inertia): An object at rest will remain at rest and an object in motion will remain in motion at a constant velocity unless acted upon by a net external force.

    • Second Law (Law of Acceleration): The acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. Mathematically expressed as:
      F=maF = ma
      where

    • $F$ is the net force,

    • $m$ is the mass of the object, and

    • $a$ is the acceleration.

    • Third Law (Action-Reaction Law): For every action, there is an equal and opposite reaction. This means that forces always occur in pairs; if object A exerts a force on object B, then object B exerts an equal and opposite force on object A.

Example Problems

Problem 1: Skydiver
  • A skydiver of mass 72 kg is descending with a parachute, experiencing an acceleration of 1.2 m/s². The problem is to determine the magnitude and direction of the force exerted by the parachute harness on the diver.

    • Calculation: Using Newton's second law,
      F=maF = ma

    • Given:

    • $m = 72$ kg

    • $a = 1.2$ m/s²

    • Thus,
      F=72imes1.2=86.4extN(netforce)F = 72 imes 1.2 = 86.4 ext{ N (net force)}

    • The gravitational force ($Fg$) acting on the diver: F</em>g=mg=72imes9.8=705.6extNdownwardF</em>g = mg = 72 imes 9.8 = 705.6 ext{ N downward}

    • The force of the parachute harness ($F_H$) is 619.2 N upward, balancing out the forces involved during descent.

Problem 2: Block on Incline
  • A 50 kg block is resting on a 25° rough incline.

    • Objective:

    • A) Find the magnitude of the normal force ($F_N$) acting on the block.

    • B) Find the magnitude of the static friction force ($F_S$) acting on the block.

  • Calculations:

    • The normal force can be calculated as follows:
      FN=mgimesextcos(25°)F_N = mg imes ext{cos}(25°)

    • Given:

    • $m = 50$ kg

    • Gravitational force:
      Fg=50imes9.8=490extNF_g = 50 imes 9.8 = 490 ext{ N}

    • Therefore,
      F<em>N=490imesextcos(25°)ightarrowF</em>N=444.1extNF<em>N = 490 imes ext{cos}(25°) ightarrow F</em>N = 444.1 ext{ N}

    • Static friction force can be calculated as follows:
      F<em>Sext(approx.)=extfrictioncoefficientimesF</em>N<br>ightarrowextAssumingapplicablecoefficienthere,FS=207.1extNF<em>S ext{ (approx.)} = ext{friction coefficient} imes F</em>N <br>ightarrow ext{Assuming applicable coefficient here, } F_S = 207.1 ext{ N}

Problem 3: Atwood Machine
  • Description: An Atwood machine consists of two masses connected by a light string over a massless pulley.

  • Given mass $m1 = 31$ kg on one side and $m2 = 22$ kg on the other:

  • To find acceleration ($a$), consider the difference in weight:
    F<em>net=m</em>1gm<em>2g=(m</em>1m2)gF<em>{net} = m</em>1g - m<em>2g = (m</em>1 - m_2)g

  • Substituting the values results in:
    m<em>1=31extkg,m</em>2=22extkg,g=9.8extm/s2m<em>1 = 31 ext{ kg}, m</em>2 = 22 ext{ kg}, g = 9.8 ext{ m/s²}
    Fnet=(3122)imes9.8=88.2extNF_{net} = (31-22) imes 9.8 = 88.2 ext{ N}

  • The mass of the system:
    m<em>total=m</em>1+m2=31+22=53extkgm<em>{total} = m</em>1 + m_2 = 31 + 22 = 53 ext{ kg}

  • The acceleration is thus:
    a=racF<em>netm</em>total=rac88.253<br>ightarrowa=1.66extm/s2a = rac{F<em>{net}}{m</em>{total}} = rac{88.2}{53} <br>ightarrow a = 1.66 ext{ m/s²}

Multiple Choice Questions

  1. Acceleration Graph of a Pulled Cart: Options include various forms of graphs; understanding the nature of constant force and resultant acceleration is crucial here.

  2. Train and Wall Collision: Regarding the collision between a train and a wall:

    • Correct Option: C. The train exerts the same force on the wall as the wall exerts on the train, illustrating Newton's third law.

  3. Tension in Ropes: In a system with multiple ropes, options examine the relationship between tensions depending on mass distribution and positioning.

  4. Free-Body Diagram for a Car Engine: Understanding the forces to include (tensions in chains) in a free-body diagram is essential for analyzing static or dynamic situations.

  5. Frictionless Surface and Tension Forces: Exploring scenarios of blocks on a frictionless surface, the tension forces reflect directly on the block's mass and movement dynamics.

  6. Free-Body Diagram for Crate on Surface: Determining relevant forces acting on crate B demonstrates understanding of inter-object interactions and forces of nature.

  • Encouragement to work in groups to solve problems signifies the importance of collaborative learning in physics problem-solving.

  • Solutions to problems (1-16, 17-19) are to be checked with instructors or teaching assistants as a means of verifying understanding.