At sea level, standard atmospheric pressure is: 1~\text{atm} = 760~\text{mmHg}</p></li><li><p>Everydayreference:1atmospherecorrespondstoabout33feetofwatercolumn;thisisaroughphysicalintuitionratherthanapracticalcalculationintherapyscreens.Thisillustratesthesignificantforceexertedbyatmosphericpressure.</p></li><li><p>Themainpressureconceptsyou’llneedtoselectcorrectvaluesontests:inspiredoxygenpartialpressure(PIO</p></li></ul></li></ul><p>),alveolaroxygenpartialpressure(PAO</p><p>),andtotalpressuresassumsofpartialpressures(Dalton’slaw).</p><h5collapsed="false"seolevelmigrated="true">OxygenintheAtmosphereandPartialPressures</h5><ul><li><p>Theambientatmospherecontains21\text{FiO₂} = 0.21\,.Thisisaconstantvalueundernormalconditions.</p></li><li><p>PartialpressureofinspiredO</p><p>inairdependsonbarometricpressure(PB)andwatervaporpressure(PH2O):</p><ul><li><p>Indrygasatsealevel:\text{P_IO₂} = \text{P_B} \times \text{FiO₂}</p></li><li><p>Whenconsideringhumidifiedair(airenteringthelungsafterwatervapor),use:\text{P_IO₂} = (\text{P_B} - \text{P_H_2O}) \times \text{FiO₂}.Watervapordisplacesothergasesintheair,soitspressuremustbesubtractedfromthetotalbarometricpressuretofindthepartialpressureofthedrygases.</p></li><li><p>Atsealevel,typically:\text{P_B} = 760~\text{mmHg}, \quad \text{P_H_2O} \approx 47~\text{mmHg}(atbodytemperature37^{\circ}\text{C}).</p></li></ul></li><li><p>Example:roomairinhalation(FiO2=0.21):</p><ul><li><p>Withoutsubtractingwatervapor:\text{P_IO₂} = 760 \times 0.21 \approx 159~\text{mmHg}</p></li><li><p>Withwatervaporsubtraction(PB−PH2O=713):\text{P_IO₂} = 713 \times 0.21 \approx 150~\text{mmHg}Thelattercalculationismorephysiologicallyaccurateforgasesreachingthealveoli.</p></li></ul></li></ul><h5collapsed="false"seolevelmigrated="true">TheAlveolarGasEquation(PAO2)</h5><ul><li><p>ThealveolargasequationrelatesalveolarO2tobarometricpressure,humidity,FiO2,andPaCO2witharespiratoryquotient(R):</p><ul><li><p>Generalform:\text{P_AO₂} = \big(\text{P_B} - \text{P_H_2O}\big) \cdot \text{FiO₂} - \frac{\text{P_aCO₂}}{\text{R}}.Therespiratoryquotient(R)typicallyrangesfrom0.8to1.0andrepresentstheratioofcarbondioxideproductiontooxygenconsumptionwithinthebody.</p></li><li><p>Examplevaluesandcalculationusedinlecture:</p></li><li><p>PB=760mmHg,PH2O=47mmHg,FiO2=0.55,PaCO2=48mmHg,R=0.80</p></li><li><p>Compute:\text{P_AO₂} = (760 - 47) \cdot 0.55 - \frac{48}{0.8} = 713 \cdot 0.55 - 60 = 392.15 - 60 \approx 332~\text{mmHg}Thiscalculationhelpsdeterminethedrivingpressureforoxygentodiffusefromthealveoliintotheblood.</p></li></ul></li><li><p>Whythismatters:PAO2representstheavailableoxygentensionatthealveolarsite;ifmeasuredPaO2islowerthanexpected(e.g.,80–100mmHg),diffusion,shunt,orventilation–perfusionmismatchmaybeimplicated.Itisacriticalvalueforassessinglungfunction.</p></li><li><p>Arelated,simplercalculationshown:</p><ul><li><p>Inatmosphere,withFiO2=0.55,PB−PH2O=713,thealveolarequationyieldsapproximately332mmHgunderthegivenconditions.</p></li></ul></li></ul><h5collapsed="false"seolevelmigrated="true">TheGasLaws(FoundationalConceptsforRespiratoryTherapy)</h5><ul><li><p>Avogadro’sLaw(brief,lesstested):equalvolumesofgasatthesameTandPcontainthesamenumberofmolecules.Focusisonmoleculecount;notacommondirectexamquestionhere,butfundamentaltounderstandinggasmolarvolumes.</p></li><li><p>Bernoulli’sPrinciple(Venturimasksandentrainment)</p><ul><li><p>Asvelocityofgasincreases,thesurroundingpressuredecreases.Thisprincipleisvitalinrespiratorydevices.</p></li><li><p>VenturimasksusethistoentrainambientairtoachieveapreciseFiO2bychangingtheadaptersizeandtheentrainedflow.Thisallowsforpreciseoxygendeliverybeyondsimpleflowrates,ensuringaccurateFiO2forpatients.</p></li><li><p>Example:aVenturidevicemaydeliver40\text{P_tot} = \text{P_1} + \text{P_2} + \text{P_3} + \text{…}$$ This law is fundamental for understanding gas exchange in the lungs, as