2D Mathematical Methods, Vector Mechanics, Projectile Motion, and Wave Equations

Scalar and Vector Quantities

  • Scalar Quantity:

    • Definition: A physical quantity that possesses magnitude only and has no direction.

    • Examples: Distance, speed, mass, temperature, work, power, energy, pressure.

  • Vector Quantity:

    • Definition: A physical quantity that possesses both magnitude and direction.

    • Examples: Displacement, velocity, acceleration, force, momentum, torque.

  • Special Case - Electric Current:

    • Electric current has both magnitude and direction.

    • However, it is classified as a scalar quantity because it does not obey the laws of vector addition.

Types of Vectors

  • Equal Vectors:

    • Definition: Vectors that have the exact same magnitude and the exact same direction.

  • Null Vector or Zero Vector:

    • Definition: A vector having zero magnitude.

    • Example: The displacement vector of a body when it completes a round trip and returns to its initial position.

  • Unit Vector:

    • Definition: A vector having unit magnitude in a specified or particular direction.

    • Mathematical expression: \n\mathbf{\hat{A}} = \frac{\mathbf{A}}{|\mathbf{A}|}\n

Laws of Vector Addition and Derivations

  • Triangle Law of Vector Addition:

    • Statement: If two vectors are represented in magnitude and direction by the two sides of a triangle taken in the same order, then their resultant vector is represented in magnitude and direction by the third side of the triangle taken in reverse order (R=A+B\mathbf{R} = \mathbf{A} + \mathbf{B}).

  • Parallelogram Law of Vector Addition:

    • Statement: If two vectors are represented in magnitude and direction by two adjacent sides of a parallelogram, then their resultant vector is represented in magnitude and direction by the diagonal of the parallelogram passing through their common point of intersection (R=A+B\mathbf{R} = \mathbf{A} + \mathbf{B}).

  • Derivation of Resultant Vector Magnitude (RR):

    • Consider two vectors A\mathbf{A} and B\mathbf{B} inclined at an angle θ\theta to each other.

    • From geometry of the triangle formed by extending vector A\mathbf{A}:

      • OS2=ON2+SN2OS^2 = ON^2 + SN^2

      • OS2=(OP+PN)2+SN2OS^2 = (OP + PN)^2 + SN^2

    • Substituting OP=AOP = A, PN=Bcos⁡(θ)PN = B\cos(\theta), and SN=Bsin⁡(θ)SN = B\sin(\theta):

      • R2=(A+Bcos⁡(θ))2+(Bsin⁡(θ))2R^2 = (A + B\cos(\theta))^2 + (B\sin(\theta))^2

      • R2=A2+2ABcos⁡(θ)+B2cos⁡2(θ)+B2sin⁡2(θ)R^2 = A^2 + 2AB\cos(\theta) + B^2\cos^2(\theta) + B^2\sin^2(\theta)

      • R2=A2+2ABcos⁡(θ)+B2(cos⁡2(θ)+sin⁡2(θ))R^2 = A^2 + 2AB\cos(\theta) + B^2(\cos^2(\theta) + \sin^2(\theta))

      • R2=A2+B2+2ABcos⁡(θ)R^2 = A^2 + B^2 + 2AB\cos(\theta)

      • R=A2+B2+2ABcos⁡(θ)R = \sqrt{A^2 + B^2 + 2AB\cos(\theta)}

  • Direction of Resultant Vector:

    • Let α\alpha be the angle made by the resultant R\mathbf{R} with vector A\mathbf{A}:

      • tan⁡(α)=SNON\tan(\alpha) = \frac{SN}{ON}

      • tan⁡(α)=Bsin⁡(θ)A+Bcos⁡(θ)\tan(\alpha) = \frac{B\sin(\theta)}{A + B\cos(\theta)}

Projectile Motion

  • Path and Velocity Components:

    • The trajectory or path followed by a projectile is a parabola.

    • Horizontal component of initial velocity: ucos⁡(θ)u\cos(\theta)

    • Vertical component of initial velocity: usin⁡(θ)u\sin(\theta)

  • Proof that the Path of a Projectile is a Parabola:

    • Horizontal distance covered in time tt:

      • x=ucos⁡(θ)t  ⟹  t=xucos⁡(θ)x = u\cos(\theta)t \implies t = \frac{x}{u\cos(\theta)}

    • Vertical displacement in time tt:

      • y=usin⁡(θ)t−12gt2y = u\sin(\theta)t - \frac{1}{2}gt^2

    • Substituting the expression for tt into the vertical displacement equation:

      • y=usin⁡(θ)(xucos⁡(θ))−12g(xucos⁡(θ))2y = u\sin(\theta)\left(\frac{x}{u\cos(\theta)}\right) - \frac{1}{2}g\left(\frac{x}{u\cos(\theta)}\right)^2

      • y=tan⁡(θ)x−(g2u2cos⁡2(θ))x2y = \tan(\theta)x - \left(\frac{g}{2u^2\cos^2(\theta)}\right)x^2

    • This equation is of the standard form y=ax+bx2y = ax + bx^2, which defines a parabola.

  • Time of Flight (TT):

    • Using kinematic equation S=ut+12at2S = ut + \frac{1}{2}at^2 for total vertical motion (S=0S = 0):

      • 0=usin⁡(θ)T−12gT20 = u\sin(\theta)T - \frac{1}{2}gT^2

      • 12gT2=usin⁡(θ)T\frac{1}{2}gT^2 = u\sin(\theta)T

      • T=2usin⁡(θ)gT = \frac{2u\sin(\theta)}{g}

  • Horizontal Range (RR):

    • Calculated as the product of horizontal velocity and total time of flight:

      • R=Horizontal velocity×Time of flightR = \text{Horizontal velocity} \times \text{Time of flight}

      • R=ucos⁡(θ)×2usin⁡(θ)gR = u\cos(\theta) \times \frac{2u\sin(\theta)}{g}

      • R=u2(2sin⁡(θ)cos⁡(θ))gR = \frac{u^2(2\sin(\theta)\cos(\theta))}{g}

      • R=u2sin⁡(2θ)gR = \frac{u^2\sin(2\theta)}{g}

  • Maximum Height (HH):

    • Using kinematic relation v2−u2=2asv^2 - u^2 = 2as for vertical displacement at the peak where vertical velocity is zero:

      • 0−u2sin⁡2(θ)=−2gH0 - u^2\sin^2(\theta) = -2gH

      • 2gH=u2sin⁡2(θ)2gH = u^2\sin^2(\theta)

      • H=u2sin⁡2(θ)2gH = \frac{u^2\sin^2(\theta)}{2g}

  • Key Properties of Projectile Motion:

    • The horizontal range RR is maximum when the angle of projection \theta = 45^\circ$.\n * The horizontal range Risidenticalforcomplimentaryanglesofprojectionis identical for complimentary angles of projection\thetaandand(90^\circ - \theta).\n * At the highest point of the trajectory, the vertical component of velocity becomes zero (u\sin(\theta) = 0).\n * Acceleration acts solely in the vertical direction: a_y = -g$.

Relation Between Linear Velocity and Angular Velocity

  • Derivation:

    • By definition of angle in radians:

      • Angle=arcradius\text{Angle} = \frac{\text{arc}}{\text{radius}}

      • Δθ=Δrr\Delta\theta = \frac{\Delta r}{r}

      • Δr=rΔθ\Delta r = r\Delta\theta

    • Dividing both sides by time interval Δt\Delta t:

      • ΔrΔt=rΔθΔt\frac{\Delta r}{\Delta t} = r\frac{\Delta\theta}{\Delta t}

    • Taking the limit as Δt→0\Delta t \rightarrow 0:

      • drdt=rdθdt\frac{dr}{dt} = r\frac{d\theta}{dt}

    • Since linear speed v=drdtv = \frac{dr}{dt} and angular velocity ω=dθdt\omega = \frac{d\theta}{dt}:

      • v=rωv = r\omega

Centripetal Acceleration

  • Definition:

    • The acceleration experienced by a body moving in a circular path directed towards the centre of the circle along the radius is called centripetal acceleration.

  • Derivation:

    • Using similar triangle geometric relations for velocity vectors and position vectors:

      • Δvv=Δrr\frac{\Delta v}{v} = \frac{\Delta r}{r}

      • Δv=vΔrr\Delta v = v\frac{\Delta r}{r}

    • Dividing by Δt\Delta t:

      • ΔvΔt=vrΔrΔt\frac{\Delta v}{\Delta t} = \frac{v}{r}\frac{\Delta r}{\Delta t}

    • Taking the limit as Δt→0\Delta t \rightarrow 0:

      • dvdt=vrdrdt\frac{dv}{dt} = \frac{v}{r}\frac{dr}{dt}

    • Substituting acceleration a=dvdta = \frac{dv}{dt} and velocity v=drdtv = \frac{dr}{dt}:

      • a=vr×va = \frac{v}{r} \times v

      • a=v2ra = \frac{v^2}{r}


Handwritten mathematical derivations for projectile motion, circular motion, and wave formulas

Wave Mechanics and Wave Speed Equations

  • Speed of Longitudinal Waves:

    • Speed of a longitudinal wave in a solid bar:

      • v=Yρv = \sqrt{\frac{Y}{\rho}}

      • Where YY is Young's modulus and ρ\rho is density.

    • General speed of a longitudinal wave in a medium:

      • v=Bρv = \sqrt{\frac{B}{\rho}}

      • Where BB is Bulk modulus and ρ\rho is density.

    • Newton's formula for the speed of a longitudinal wave in an ideal gas:

      • v=Pρv = \sqrt{\frac{P}{\rho}}

      • Where PP is pressure and ρ\rho is density.

  • Superposition and Standing Waves:

    • Superposition of two waves travelling in opposite directions:

      • y1=asin⁡(kx−ωt)y_1 = a\sin(kx - \omega t)

      • y2=asin⁡(kx+ωt)y_2 = a\sin(kx + \omega t)

      • y=y1+y2=asin⁡(kx−ωt)+asin⁡(kx+ωt)y = y_1 + y_2 = a\sin(kx - \omega t) + a\sin(kx + \omega t)

      • y=(2asin⁡(kx))cos⁡(ωt)y = (2a\sin(kx))\cos(\omega t)

    • Amplitude of the resulting standing wave:

      • A=2asin⁡(kx)A = 2a\sin(kx)

    • Condition for Nodes (points of zero amplitude):

      • Amplitude=0\text{Amplitude} = 0

      • 2asin⁡(kx)=0  ⟹  sin⁡(kx)=02a\sin(kx) = 0 \implies \sin(kx) = 0

      • kx=nπkx = n\pi

      • Substituting k=2πλk = \frac{2\pi}{\lambda}:

      • 2πλx=nπ  ⟹  x=nλ2\frac{2\pi}{\lambda}x = n\pi \implies x = \frac{n\lambda}{2}

    • Condition for Antinodes (points of maximum amplitude):

      • Amplitude=maximum\text{Amplitude} = \text{maximum}

      • 2asin⁡(kx)=±2a2a\sin(kx) = \pm 2a

      • sin⁡(kx)=±1\sin(kx) = \pm 1