AP Physics Reflecting on stuff I did wrong

Test 1

1- does not return to origin since there's no negative velocity, it is going the positive direction the entire time

6- position time graph - object one went the longer path with a bunch of curves and stuff even tho the line ended lower at the end meaning it traveled farther

8- the speed was decreasing not increasing since it started at 15 and went to 0

10 - the answer was 4 not 2 bc it was v^2

did good on frq only lost 2 points on part b bc i needed to say to plot d vs t^2 not v vs t, on actual graph you can plot v vs t and get full points

AP classroom test review 1 reflection

Q2) when I looked at the acceleration time graph i said that the velocity was 0 at time 1-2 but that's acceleration not velocity, half correct answer chosen

Q3) we were given t, acceleration, vf and vo, when we use the 2nd equation for both cars car a is just vot since acceleration = 0 and we can cancel out the vo for car b since it'll = 0 so whats left is 1/2at^2. then we set both final positions equations equal to each other and solve

Q5) dont just look at the numbers in the table you also have to solve, if you notice at point b the velocity is negative and when you subtract the vectors to see the greatest change you will get 10 (the largest magnitude and correct answer)

Q6) didnt solve for the slope but had the correct direction for the velocity on the position time graph

Q9) Since car 2 is going left, the velocity will double since the car experiences an acceleration to the left when they cross each other

Q10) The acceleration is not unknown, as the velocity never changes over the 4 seconds meaning that the acceleration is 0, so that kid is correct

Q13) It is a velocity time graph not position time graph meaning when it hits 0 that doesn't mean position is zero, that means velocity is zero, it will go back to zero when it starts having a negative velocity and enough time is passed

Q15) You have to solve for the acceleration then plug it in the 2nd equation to solve for displacement (just the 1/2at^2 part tho since vo is 0 when you are dropping anything)

Q16) In the acceleration time graph to solve for the change in velocity you find the area under the curve, we can then use that velocity to figure out how far he goes in the 1 second the acceleration was 0, for the 1st half you plug in the acceleration and time to the 2nd equation to solve for d, leaving us with 2 distances to add to give us our final answer

Q18) to find the distance traveled on a velocity time graph solve for the area under the line

Q20) Velocity increases as an object falls, so that means it will travel more displacement since displacement = velocity times time and bc time passed is the same each period, you just have to look at for the largest velocity to see the largest displacement

Conceptual Quiz reflection

When acceleration and velocity are opposites then an object is slowing down

Acceleration can be positive, negative, or 0 at a given time

Gravity is constant and downward (negative), acts the same on ALL objects

P vs T graphs

vertical line - teleporting

horizontal - no velocity or acceleration

parabola - velocity is changing

straight line at an angle - constant velocity

Steepest slope is fastest, flat slope is 0

constant velocity means no acceleration

When there's an interception that means position is the same at that point

Linearizing graphs worksheet reflection

did the basics correct (identifying the graph, the relationship, how to linearize, finding acceleration from slope)

did not use the given information to compare the equation of situation to the equation of linear line (which led to us bot being able identify the acceleration correctly)

in that problem we had a position time graph, and with that we had been given d, t, and Vo, with d as our y value and t^2 as our x value, what was left for our slope was 1/2a (which meant that the acceleration was 10 not 5)

FRQ rubric practice worksheet reflection

whenever it asks how to make it more accurate say "test each data point multiple times and use the average to better account for random or human errors that may affect the data"

write every step when solving for something (every equation, the rearranged equation, ect.) and make the answer obvious and easy to understand

when working with slope, make sure you relate the value of the slope to the value you are solving (ex: since the slope is 1/2a that means to find the actual acceleration you must multiply the slope by 2)