Series Convergence Tests

Conditions for Series Convergence and Divergence

  • Divergence Conclusion:

    • If the individual terms do NOT go to zero:

    • Mathematical notation: If limnan\lim_{n \to \infty} a_n
      eq 0thentheseriesdiverges(thesumisinfinite).</p></li></ul></li><li><p><strong>GrowthRateComparisons</strong>:</p><ul><li><p>Ifthen the series diverges (the sum is infinite).</p></li></ul></li><li><p><strong>Growth Rate Comparisons</strong>:</p><ul><li><p>If\lim_{x \to \infty} \frac{f(x)}{g(x)} = \infty:</p></li><li><p>Impliesthat:</p></li><li><p>Implies thatf(x)growsfasterthangrows faster thang(x).</p></li><li><p>If.</p></li><li><p>If\lim_{x \to \infty} \frac{f(x)}{g(x)} = 0:</p></li><li><p>Impliesthat:</p></li><li><p>Implies thatg(x)growsfasterthangrows faster thanf(x)(or(orf(x)growsslowerthangrows slower thang(x)).</p></li><li><p>If).</p></li><li><p>If\lim_{x \to \infty} \frac{f(x)}{g(x)} = Lwherewhere0<L<\infty{}impliesthatimplies thatf(x)andandg(x)growatthesamerate.</p></li></ul></li></ul><h3id="3706706b2dc7483c963e9bd3b19773f9"datatocid="3706706b2dc7483c963e9bd3b19773f9"collapsed="false"seolevelmigrated="true">TestsforConvergence</h3><ul><li><p><strong>ConvergingSeriesInvestigation</strong>:</p><ul><li><p>UsetheDivergenceTest,theIntegralTest,orthepseriestesttodetermineconvergenceforspecificseries.</p></li></ul></li></ul><h4id="5f6874ac612147ecb1f649fc88027f17"datatocid="5f6874ac612147ecb1f649fc88027f17"collapsed="false"seolevelmigrated="true">ExampleSeries</h4><h5id="1ac2890a0db1474fb4c1d23f5ea6fae5"datatocid="1ac2890a0db1474fb4c1d23f5ea6fae5"collapsed="false"seolevelmigrated="true">SeriesUnderInvestigation</h5><ul><li><p>Series:grow at the same rate.</p></li></ul></li></ul><h3 id="3706706b-2dc7-483c-963e-9bd3b19773f9" data-toc-id="3706706b-2dc7-483c-963e-9bd3b19773f9" collapsed="false" seolevelmigrated="true">Tests for Convergence</h3><ul><li><p><strong>Converging Series Investigation</strong>:</p><ul><li><p>Use the Divergence Test, the Integral Test, or the p-series test to determine convergence for specific series.</p></li></ul></li></ul><h4 id="5f6874ac-6121-47ec-b1f6-49fc88027f17" data-toc-id="5f6874ac-6121-47ec-b1f6-49fc88027f17" collapsed="false" seolevelmigrated="true">Example Series</h4><h5 id="1ac2890a-0db1-474f-b4c1-d23f5ea6fae5" data-toc-id="1ac2890a-0db1-474f-b4c1-d23f5ea6fae5" collapsed="false" seolevelmigrated="true">Series Under Investigation</h5><ul><li><p>Series:\sum_{k=1}^{\infty} (5k) \frac{1}{k}</p></li></ul><h5id="91a0591d09104053b91415ad7d577ddd"datatocid="91a0591d09104053b91415ad7d577ddd"collapsed="false"seolevelmigrated="true">Step1:AnalyzetheGeneralTerm</h5><ol><li><p>Identifythelimitofthegeneraltermas</p></li></ul><h5 id="91a0591d-0910-4053-b914-15ad7d577ddd" data-toc-id="91a0591d-0910-4053-b914-15ad7d577ddd" collapsed="false" seolevelmigrated="true">Step 1: Analyze the General Term</h5><ol><li><p>Identify the limit of the general term askapproachesinfinity:</p><ul><li><p>approaches infinity:</p><ul><li><p>a_k = (5k)^{\frac{1}{k}}resultinginanindeterminateformresulting in an indeterminate form ext{infinity}^0.</p></li></ul></li><li><p>SuggestusingtheDivergenceTestasthestartingpoint.</p></li></ol><h5id="c7a576abbc22408cb1b30ae9713d5831"datatocid="c7a576abbc22408cb1b30ae9713d5831"collapsed="false"seolevelmigrated="true">Step2:DivergenceTestApplication</h5><ul><li><p>If.</p></li></ul></li><li><p>Suggest using the Divergence Test as the starting point.</p></li></ol><h5 id="c7a576ab-bc22-408c-b1b3-0ae9713d5831" data-toc-id="c7a576ab-bc22-408c-b1b3-0ae9713d5831" collapsed="false" seolevelmigrated="true">Step 2: Divergence Test Application</h5><ul><li><p>If\lim_{k \to \infty} a_k = 0:</p><ul><li><p>Theseriesdiverges.</p></li></ul></li><li><p>If:</p><ul><li><p>The series diverges.</p></li></ul></li><li><p>If\lim_{k \to \infty} a_k \ne 0:</p><ul><li><p>Thetestisinconclusive.</p></li></ul></li></ul><h5id="d0ac374a06f744b39f1165c74bcdb6d6"datatocid="d0ac374a06f744b39f1165c74bcdb6d6"collapsed="false"seolevelmigrated="true">Step3:FindtheLimitoftheGeneralTerm</h5><ul><li><p>Focusonthelimitas:</p><ul><li><p>The test is inconclusive.</p></li></ul></li></ul><h5 id="d0ac374a-06f7-44b3-9f11-65c74bcdb6d6" data-toc-id="d0ac374a-06f7-44b3-9f11-65c74bcdb6d6" collapsed="false" seolevelmigrated="true">Step 3: Find the Limit of the General Term</h5><ul><li><p>Focus on the limit askapproachesinfinity:</p><ul><li><p>approaches infinity:</p><ul><li><p>\lim_{k \to \infty} (5k)^{\frac{1}{k}} = \lim_{k \to \infty} e^{\frac{\ln(5k)}{k}}.</p></li></ul></li><li><p>Evaluatethebehavioroftheexponent:</p><ul><li><p>Notethat.</p></li></ul></li><li><p>Evaluate the behavior of the exponent:</p><ul><li><p>Note that\ln(5k)leadstoanindeterminateformleads to an indeterminate form\frac{\infty}{\infty}.</p></li></ul></li></ul><h5id="d0466c70a36947dab8e9e8457546ac64"datatocid="d0466c70a36947dab8e9e8457546ac64"collapsed="false"seolevelmigrated="true">Step4:LHo^pitalsRule</h5><ol><li><p>ApplyLHo^pitalsRuletoresolveindeterminateform:</p><ul><li><p>.</p></li></ul></li></ul><h5 id="d0466c70-a369-47da-b8e9-e8457546ac64" data-toc-id="d0466c70-a369-47da-b8e9-e8457546ac64" collapsed="false" seolevelmigrated="true">Step 4: L'Hôpital's Rule</h5><ol><li><p>Apply L'Hôpital's Rule to resolve indeterminate form:</p><ul><li><p>\lim_{k \to \infty} \frac{\ln(5k)}{k} = \lim_{k \to \infty} \frac{1/k}{1}.</p></li></ul></li><li><p>Evaluatetheresultinglimit:</p><ul><li><p>.</p></li></ul></li><li><p>Evaluate the resulting limit:</p><ul><li><p>\lim_{k \to \infty} \frac{1}{k} = 0.</p></li></ul></li></ol><h5id="ecc1c8b2aad54ab7b25c2d79203cb3c2"datatocid="ecc1c8b2aad54ab7b25c2d79203cb3c2"collapsed="false"seolevelmigrated="true">Step5:ResultInterpretation</h5><ul><li><p>Returningtotheoriginallimitgives:</p><ul><li><p>.</p></li></ul></li></ol><h5 id="ecc1c8b2-aad5-4ab7-b25c-2d79203cb3c2" data-toc-id="ecc1c8b2-aad5-4ab7-b25c-2d79203cb3c2" collapsed="false" seolevelmigrated="true">Step 5: Result Interpretation</h5><ul><li><p>Returning to the original limit gives:</p><ul><li><p>\lim_{k \to \infty} a_k = \lim_{k \to \infty} e^0 = 1.</p><p>Therefore,since.</p><p>Therefore, since\lim_{k \to \infty} a_k \ne 0,theseriesdivergesbytheDivergenceTest.</p></li></ul></li></ul><h3id="5bedf420491f4829bcb0d9ee6b730c55"datatocid="5bedf420491f4829bcb0d9ee6b730c55"collapsed="false"seolevelmigrated="true">pSeriesTest</h3><ul><li><p>Apseriesisdefinedas, the series diverges by the Divergence Test.</p></li></ul></li></ul><h3 id="5bedf420-491f-4829-bcb0-d9ee6b730c55" data-toc-id="5bedf420-491f-4829-bcb0-d9ee6b730c55" collapsed="false" seolevelmigrated="true">p-Series Test</h3><ul><li><p>A p-series is defined as\sum_{k=1}^{\infty} \frac{1}{k^p}.</p><p>ConvergenceCondition:Theseriesconvergesif.</p><p>Convergence Condition: The series converges ifp > 1.</p><p>DivergenceCondition:Theseriesdivergesif.</p><p>Divergence Condition: The series diverges if0 < p \le 1.</p></li></ul><h3id="e2e773091b2a40539056acd65424e343"datatocid="e2e773091b2a40539056acd65424e343"collapsed="false"seolevelmigrated="true">LimitComparisonTest</h3><ul><li><p>Giventwoseries.</p></li></ul><h3 id="e2e77309-1b2a-4053-9056-acd65424e343" data-toc-id="e2e77309-1b2a-4053-9056-acd65424e343" collapsed="false" seolevelmigrated="true">Limit Comparison Test</h3><ul><li><p>Given two seriesanandandbnwherebotharegreaterthanzero,theconditionsareasfollows:</p><ul><li><p>Ifwhere both are greater than zero, the conditions are as follows:</p><ul><li><p>If\lim_{n \to \infty} \frac{a_n}{b_n} = L(where(where0 < L < \infty):</p><ul><li><p>Thenbothseriesconvergeordivergetogether</p></li></ul></li><li><p>If):</p><ul><li><p>Then both series converge or diverge together</p></li></ul></li><li><p>IfL = 0andand\sum b_nconverges:</p><ul><li><p>Thenconverges:</p><ul><li><p>Then\sum a_nconverges.</p></li></ul></li><li><p>Ifconverges.</p></li></ul></li><li><p>IfL = \inftyandand\sum b_ndiverges:</p><ul><li><p>Thendiverges:</p><ul><li><p>Then\sum a_ndiverges.</p></li></ul></li></ul></li></ul><h3id="0d184330d948492a9c0a254003999e25"datatocid="0d184330d948492a9c0a254003999e25"collapsed="false"seolevelmigrated="true">RationalFunctionsandtheirLimits</h3><ul><li><p>Forarationalfunctionoftheformdiverges.</p></li></ul></li></ul></li></ul><h3 id="0d184330-d948-492a-9c0a-254003999e25" data-toc-id="0d184330-d948-492a-9c0a-254003999e25" collapsed="false" seolevelmigrated="true">Rational Functions and their Limits</h3><ul><li><p>For a rational function of the formf(k) = \frac{p(k)}{q(k)}wherewherep(k)andandq(k)arepolynomials:</p><ul><li><p>Ifare polynomials:</p><ul><li><p>Ifm < n::\lim_{k \to \infty} f(k) = 0.</p></li><li><p>If.</p></li><li><p>Ifm = n::\lim_{k \to \infty} f(k) = \frac{a_m}{b_n}</p></li><li><p>If</p></li><li><p>Ifm = n::\lim_{k \to \infty} f(k) = \frac{a_m}{b_n}.</p></li></ul></li></ul><h3id="ec43575225924a9abafca9d716fb75ec"datatocid="ec43575225924a9abafca9d716fb75ec"collapsed="false"seolevelmigrated="true">DivergenceTestforSeries</h3><ul><li><p>TheDivergenceTeststates:</p><ul><li><p>IfIf.</p></li></ul></li></ul><h3 id="ec435752-2592-4a9a-bafc-a9d716fb75ec" data-toc-id="ec435752-2592-4a9a-bafc-a9d716fb75ec" collapsed="false" seolevelmigrated="true">Divergence Test for Series</h3><ul><li><p>The Divergence Test states:</p><ul><li><p>If If\sum a_kconverges,thenconverges, then\lim_{k \to \infty} a_k = 0.</p></li><li><p>Equivalently:if.</p></li><li><p>Equivalently: if\lim_{k \to \infty} a_k \ne 0,thentheseriesdiverges.</p></li></ul></li></ul><h3id="88b26e569e814b06b3c589b02175d141"datatocid="88b26e569e814b06b3c589b02175d141"collapsed="false"seolevelmigrated="true">GeometricSeries</h3><ul><li><p>Forageometricseries, then the series diverges.</p></li></ul></li></ul><h3 id="88b26e56-9e81-4b06-b3c5-89b02175d141" data-toc-id="88b26e56-9e81-4b06-b3c5-89b02175d141" collapsed="false" seolevelmigrated="true">Geometric Series</h3><ul><li><p>For a geometric series\sum_{k=0}^{\infty} ar^k:</p><ul><li><p>Convergesif:</p><ul><li><p>Converges if|r| < 1.</p></li><li><p>Divergesif.</p></li><li><p>Diverges if|r| \ne 1$$