Integration of Rational Functions by Partial Fractions
7 Techniques of Integration
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7.4 Integration of Rational Functions by Partial Fractions
Copyright Cengage Learning. All rights reserved.
Integration of Rational Functions by Partial Fractions (1 of 2)
Objective: Integrate rational functions (a ratio of polynomials).
Method: Express a rational function as a sum of simpler fractions, known as partial fractions, which are easier to integrate.
Process: Taking fractions to a common denominator enables integration on the right side of the equation.
Integration of Rational Functions by Partial Fractions (2 of 2)
Illustrates how to integrate the right-side function using the method developed.
The Method of Partial Fractions
Overview:
Consider a rational function where P and Q are polynomials.
Possible to express f as a sum of simpler fractions when the degree of P is less than the degree of Q.
Such rational functions are termed proper.
The Method of Partial Fractions (1 of 14)
If we denote the degree of P by n (with a_n ≠ 0), we establish that deg(P) = n.
If f is improper (deg(P) ≥ deg(Q)), we must divide Q into P via long division to yield a remainder R(x) such that deg(R) < deg(Q).
The Method of Partial Fractions (2 of 14)
Result of Division:
We derive S and R (also polynomials) where S represents the integral of the whole part obtained by division and R is the proper polynomial.
Example demonstration: Sometimes, this initial division represents the complete solution.
Example 1
Task: Find the integral where the degree of the numerator is greater than the degree of the denominator.
Procedure: Perform long division first to represent the function correctly.
The Method of Partial Fractions (4 of 14)
Next Step: Factor Q(x) maximally.
Every polynomial Q can be expressed as a product of linear factors (of the form ax + b) and irreducible quadratic factors (of the form ax² + bx + c).
Example Provided:
Similar factorization procedure is illustrated with a polynomial denominator.
The Method of Partial Fractions (5 of 14)
Third Step: Express the proper rational function as a sum of partial fractions based on a theorem in algebra.
Details: Four different cases arise based on the nature of the denominator.
Case I: Distinct Linear Factors
Denominator Q(x) is a product of distinct linear factors.
Representation involves no factors being repeated.
Partial Fraction Theorem: There exist constants A1, A2, …, Ak such that
Constants determined through example.
Example 2
Task: Evaluate and find partial fraction decomposition.
Solution Approach:
Since the numerator's degree is less than the denominator's, long division is unnecessary.
Factor the denominator as needed.
Example 2 – Solution (1 of 4)
Workflow: Denominator has three distinct linear factors, leading to its representation as:
Determine values A, B, C through multiplication by the common denominator, yielding a solvable equation set.
Example 2 – Solution (2 of 4)
Expansion of Equation: Expanding and equating powers of x leads to distinct coefficients, generating a systematic equation set:
Coefficient of x²:
Coefficient of x: Equations provide balanced structures for solving constants.
Example 2 – Solution (3 of 4)
Outcome: Generates a system of linear equations for A, B, and C with solutions extracted through methods of linear algebra.
Example 2 – Solution (4 of 4)
Integration: Utilize substitution: letting u = 2x − 1, , leads to direct integration of the obtained terms within the context of function integration.
The Method of Partial Fractions (8 of 14)
Alternate Approach: Utilize values of x that satisfy the equation for simplification purposes.
By setting x = 0 and strategically chosen points, values become feasible, facilitating easier computation of constants A, B, C.
Case II: Repeated Linear Factors
For repeated factors, expression expands to accommodate the repetition:
Illustrative expansion follows sequential logical representation as prior functions with singular repetitions.
Example 4
Task: Evaluate
Long Division Step: Execute long division.
Example 4 – Solution (1 of 4)
Factoring: Realize that x - 1 is a known factor leading to simpler subsequent expressions in steps.
Example 4 – Solution (2 of 4)
Partial Fraction Decomposition Formulation: Employ structure based on derived polynomial characteristics:
Utilize least common denominator approach.
Example 4 – Solution (3 of 4)
System of Equations for Coefficients: Generate a process where coefficients lead to unique variables resembling the earlier steps concluded.
Example 4 – Solution (4 of 4)
Results: Establish values A, B, and C, substituting back to evaluate integral proposition for completion.
Case III: Irreducible Quadratic Factors
When Q(x) contains irreducible quadratic factors absent of repetitions, extend expression with quadratic structures:
Example of function with irreducible quadratic is noted to show practical application of the method.
Example 6
Task: Evaluate a specific integral tied to quadratics requiring initial long division due to the numerator's degree.
Example 6 – Solution (1 of 3)
Completing the Square Approach: Tackle irreducible quadratics by transitioning into perfect square completion techniques.
Example 6 – Solution (2 of 3)
Utilization of substitution leads to simplified integral forms positioned for resolution through elementary functions.
Example 6 – Solution (3 of 3)
Final evaluation uses trigonometric identities to conclude the computation effectively, establishing the final output in manageable terms.
The Method of Partial Fractions (13 of 14)
General Procedure: For integrals resembling forms with squares, employ substitutions that facilitate integration against established forms resulting in logarithms and other identities.
Case IV: Repeated Irreducible Quadratic Factor
Presentation of polynomial decomposition expands into repetitive forms where substituted functions maintain operand integrity across variables.
Example 8
Task: Evaluate a complicated rational function with multiple polynomial features requiring a robust factorization approach for expansion.
Example 8 – Solution (1 of 2)
Equate Coefficients: Resolve generated systems to provide definitively the relationship between variables and their constant counterparts.
Example 8 – Solution (2 of 2)
Final integrated representations connect integral steps yielding results across variable shifts and derived functions, showcasing completion of complex rational integration.
Rationalizing Substitutions
Overview: Some nonrational functions may transform into rational ones via strategic substitutions; notably, expressions in square root contexts.
Example 9
Task: Evaluate the integral involving square roots potentially reshaping the nature of the function and leading to rational forms.
Example 9 – Solution
Through calculated substitutions, the transformation into simplified forms yields manageable integral tasks or application of direct computational formulas.