Comprehensive Notes on Periodic Functions and Trigonometric Identities

Foundations of Periodic and Trigonometric Functions

  • Definition of a Periodic Function: A function is classified as periodic if it exhibits a repeating pattern of yy values at regular intervals. This repetition suggests that the function's behavior can be predicted over time or distance based on its past cycles.

  • The Cycle: A cycle represents the smallest unique portion of the graph that repeats. Identifying one cycle is necessary for determining the properties of the entire function.

  • The Period: The period is the horizontal length (measured along the x-axis) of one complete cycle.

    • Determining Period Algebraically: To find the period, identify the x-coordinate at the start of a cycle (x1x_1) and the x-coordinate at the start of the subsequent cycle (x2x_2). The period is calculated as:     P=x2x1P = x_2 - x_1

    • Example Calculation: If a cycle starts at x=4x = -4 and the next starts at x=1x = 1, the period is calculated as 1(4)=5units1 - (-4) = 5\,units. If a graph starts at x=0x = 0 and ends a cycle at x=7x = 7, the period is 70=77 - 0 = 7.

  • Evaluating Periodic Functions: To find local values of a function at large domain points, the period can be subtracted repeatedly.

    • Example: If the period is 77 and you need to find f(20)f(20), you can calculate f(207)=f(13)f(20 - 7) = f(13). If f(13)f(13) is still outside the known graph range, subtract the period again: f(137)=f(6)f(13 - 7) = f(6). If f(6)=1f(6) = -1, then f(20)=1f(20) = -1.

Amplitude and the Axis of the Curve

  • The Maximum and Minimum: The maximum value is the highest peak reached by the function, and the minimum is the lowest trough.

  • Amplitude: This is the distance from the horizontal midline (axis of the curve) to either the maximum or the minimum. It represents half of the total vertical height of the function.

    • Formula: Amplitude=maxmin2\text{Amplitude} = \frac{\text{max} - \text{min}}{2}

    • Example: For a function with a maximum of 33 and a minimum of 1-1, the calculation is:     3(1)2=42=2units\frac{3 - (-1)}{2} = \frac{4}{2} = 2\,units

  • Axis of the Curve: The horizontal line that is the average of the maximum and minimum values. It is expressed by the equation:     y=max+min2y = \frac{\text{max} + \text{min}}{2}

Properties of Basic Trigonometric Functions

  • The Sine Function (y=sin(θ)y = \sin(\theta)):

    • Initial Values: 0=00^\circ = 0, 30=0.530^\circ = 0.5, 90=190^\circ = 1, 180=0180^\circ = 0, 270=1270^\circ = -1, 360=0360^\circ = 0.

    • Amplitude: 11

    • Period: 360360^\circ

    • Axis of the Curve: y=0y = 0

    • Domain: θR\theta \in \mathbb{R}, often specific cycles are observed (e.g., 360θ720-360^\circ \leq \theta \leq 720^\circ).

    • Range: {yR1y1}\{y \in \mathbb{R} | -1 \leq y \leq 1\}

  • The Cosine Function (y=cos(θ)y = \cos(\theta)):

    • Initial Values: 0=10^\circ = 1, 60=0.560^\circ = 0.5, 90=090^\circ = 0, 180=1180^\circ = -1, 270=0270^\circ = 0, 360=1360^\circ = 1.

    • Amplitude: 11

    • Period: 360360^\circ

    • Axis of the Curve: y=0y = 0

    • Domain: θR\theta \in \mathbb{R}

    • Range: {yR1y1}\{y \in \mathbb{R} | -1 \leq y \leq 1\}

Radian and Degree Measure

  • Definition: Degrees and Radians are units for measuring angles.

  • The Relationship: A full rotation in a circle is 360360^\circ or 2πradians2\pi\,radians. This simplifies to the fundamental conversion identity:     πradians=180\pi\,radians = 180^\circ

  • Conversion Formulas:

    • Degrees to Radians: Multiply by π180\frac{\pi}{180^\circ}.

    • Radians to Degrees: Multiply by 180π\frac{180^\circ}{\pi}.

  • Worked Examples:

    • Convert 6060^\circ to radians: 60×π180=π3rad1.046rad60^\circ \times \frac{\pi}{180^\circ} = \frac{\pi}{3}\,rad \approx 1.046\,rad

    • Convert 4545^\circ to radians: 45×π180=π4rad0.785rad45^\circ \times \frac{\pi}{180^\circ} = \frac{\pi}{4}\,rad \approx 0.785\,rad

    • Convert π2radians\frac{\pi}{2}\,radians to degrees: π2×180π=90\frac{\pi}{2} \times \frac{180^\circ}{\pi} = 90^\circ

Transformations of Periodic Functions

All algebraic transformation principles apply to trigonometric functions using the standard model: y=af(k(xd))+cy = a f(k(x - d)) + c

  • Vertical Stretches and Compressions (aa):

    • If |a| > 1, the function undergoes a vertical expansion.

    • If 0 < |a| < 1, the function undergoes a vertical compression.

    • The value of a|a| always represents the amplitude of the function.

    • Example: For y=4cos(x)y = 4\cos(x), the amplitude is 44. The range becomes {yR4y4}\{y \in \mathbb{R} | -4 \leq y \leq 4\}.

  • Horizontal Stretches and Compressions (kk):

    • If k > 1, the function undergoes a horizontal compression.

    • If 0 < k < 1, the function undergoes a horizontal expansion.

    • The period is directly affected by kk:     Period=360korPeriod=2πk\text{Period} = \frac{360^\circ}{k}\,\text{or}\,\text{Period} = \frac{2\pi}{k}

    • Example: For y=sin(3x)y = \sin(3x), the period is 3603=120\frac{360^\circ}{3} = 120^\circ.

  • Horizontal Translations (Phase Shifts, dd):

    • A shift to the right occurs if the term is units of (xd)(x - d).

    • A shift to the left occurs if the term is units of (x+d)(x + d).

    • Example: For y=0.5sin(x+90)y = 0.5\sin(x + 90^\circ), the graph is shifted 9090^\circ to the left.

  • Vertical Translations (cc):

    • The value of cc shifts the entire function up or down. This value determines the location of the axis of the curve (y=cy = c).

Real-World Modelling Applications

  • Ferris Wheel Problem:

    • Data: Diameter = 38m38\,m, rotation time = 6min6\,min, boarding height = 4m4\,m.

    • Analysis:

      • The radius is 19m19\,m, so the amplitude a=19a = 19.

      • The lowest point is 4m4\,m, and the highest point is 4+38=42m4 + 38 = 42\,m.

      • The axis of curve is y=23my = 23\,m (4+422=23\frac{4 + 42}{2} = 23).

      • Period is 6min=360s6\,min = 360\,s.

    • Equation: Since the rider starts at the bottom, a negative cosine function is easiest to use:     h(t)=19cos(t)+23h(t) = -19\cos(t) + 23 (if time is in degrees relative to the period).

    • Height Prediction: To find height at 1260seconds1260\,seconds, substitute into the function: h(1260)=42mh(1260) = 42\,m.

  • Mass on a Spring:

    • Data: 12 cycles in 24 seconds, amplitude = 3.0cm3.0\,cm, minimum height = 4.0cm4.0\,cm, starts at 7.0cm7.0\,cm moving up at t=0t=0.

    • Analysis:

      • Period = 24s12cycles=2s/cycle\frac{24\,s}{12\,cycles} = 2\,s/cycle.

      • AOC = 4.0+3.0=7.0cm4.0 + 3.0 = 7.0\,cm.

      • Maximum height = 7.0+3.0=10.0cm7.0 + 3.0 = 10.0\,cm.

    • Equation: Because it starts at the axis (y=7y=7) and moves upward, a sine function is appropriate:     h(t)=3sin(180t)+7h(t) = 3\sin(180t) + 7

Trigonometric Ratios and the CAST Rule

  • Coordinates on a Circular Path: For any point P(x,y)P(x, y) on a terminal arm of angle θ\theta:

    • r=x2+y2r = \sqrt{x^2 + y^2}

    • sin(θ)=yr\sin(\theta) = \frac{y}{r}

    • cos(θ)=xr\cos(\theta) = \frac{x}{r}

    • tan(θ)=yx\tan(\theta) = \frac{y}{x}

  • The CAST Rule: Determines which primary ratios are positive in each quadrant:

    • Quadrant I (All): All ratios (Sine, Cosine, Tangent) are positive.

    • Quadrant II (Sine): Only Sine is positive.

    • Quadrant III (Tangent): Only Tangent is positive.

    • Quadrant IV (Cosine): Only Cosine is positive.

  • Reciprocal Ratios:

    • Cosecant: csc(θ)=1sin(θ)=ry\csc(\theta) = \frac{1}{\sin(\theta)} = \frac{r}{y}

    • Secant: sec(θ)=1cos(θ)=rx\sec(\theta) = \frac{1}{\cos(\theta)} = \frac{r}{x}

    • Cotangent: cot(θ)=1tan(θ)=xy\cot(\theta) = \frac{1}{\tan(\theta)} = \frac{x}{y}

Special Triangles and Exact Values

Trigonometric ratios for specific angles should be expressed in exact radical form rather than decimals.

  • 45-45-90 Triangle: Sides are 1,1,21, 1, \sqrt{2}.

    • sin(45)=12\sin(45^\circ) = \frac{1}{\sqrt{2}}

    • cos(45)=12\cos(45^\circ) = \frac{1}{\sqrt{2}}

    • tan(45)=1\tan(45^\circ) = 1

  • 30-60-90 Triangle: Sides are 1,3,21, \sqrt{3}, 2.

    • sin(30)=12\sin(30^\circ) = \frac{1}{2}; sin(60)=32\sin(60^\circ) = \frac{\sqrt{3}}{2}

    • cos(30)=32\cos(30^\circ) = \frac{\sqrt{3}}{2}; cos(60)=12\cos(60^\circ) = \frac{1}{2}

    • tan(30)=13\tan(30^\circ) = \frac{1}{\sqrt{3}}; tan(60)=3\tan(60^\circ) = \sqrt{3}

  • Examples:

    • Find exact value of tan(150)\tan(150^\circ).: Angle is in Quadrant II, reference angle is 180150=30180^\circ - 150^\circ = 30^\circ. Since Tangent is negative in QII: tan(150)=tan(30)=13\tan(150^\circ) = -\tan(30^\circ) = -\frac{1}{\sqrt{3}}.

    • Find value of sec(210)\sec(210^\circ).: Reference angle is 210180=30210^\circ - 180^\circ = 30^\circ. Secant is the reciprocal of Cosine. In QIII, Cosine is negative. cos(210)=32\cos(210^\circ) = -\frac{\sqrt{3}}{2}, therefore sec(210)=23\sec(210^\circ) = -\frac{2}{\sqrt{3}}.