Physical Quantities & Measurements

1.1 Dimensions of Physical Quantities

  • Definition

    • Dimension = qualitative description of a physical quantity in terms of basic (fundamental) quantities, independent of the unit system.
    • Notation: enclose the quantity or symbol in square brackets, e.g. [v][v] or [velocity][velocity].
    • Example: 100cm=1m=2mi=3ly100\,\text{cm}=1\,\text{m}=2\,\text{mi}=3\,\text{ly} all share the dimension [L][L] (length).
  • Fundamental (base) dimensions

    • Mass [M][M]
    • Length [L][L]
    • Time [T][T]
    • Electric current [I][I]
    • Thermodynamic temperature [Θ][\Theta]
    • Amount of substance [N][N]
    • Luminous intensity [J][J]
  • Dimensional analysis: purposes

    • Derive the SI unit of any derived quantity.
    • Check or derive equations by treating dimensions as algebraic symbols.
    • Verify dimensional homogeneity: dimension LHS=dimension RHS\text{dimension LHS}=\text{dimension RHS}.
    • Reminder: pure numerical factors (e.g. 12,34\tfrac12,\,\tfrac34) carry no dimension.
    • Addition/Subtraction rule: quantities may be added or subtracted only if their dimensions match.
  • Common derived quantities

    • Velocity: [v]=[L][T]1;  unit=m s1[v]=[L][T]^{-1};\;\text{unit}=\text{m s}^{-1}
    • Acceleration: [a]=[L][T]2;  unit=m s2[a]=[L][T]^{-2};\;\text{unit}=\text{m s}^{-2}
    • Linear momentum: [p]=[M][L][T]1;  unit=kg m s1[p]=[M][L][T]^{-1};\;\text{unit}=\text{kg m s}^{-1}
    • Density: [ρ]=[M][L]3;  unit=kg m3[\rho]=[M][L]^{-3};\;\text{unit}=\text{kg m}^{-3}
    • Force: [F]=[M][L][T]2;  unit=N=kg m s2[F]=[M][L][T]^{-2};\;\text{unit}=\text{N}=\text{kg m s}^{-2}
    • Pressure: [P]=[M][L]1[T]2;  unit=Pa=kg m1s2[P]=[M][L]^{-1}[T]^{-2};\;\text{unit}=\text{Pa}=\text{kg m}^{-1} \text{s}^{-2}
  • Illustrative homogeneity checks

    • Kinematic expression s=ut+12at2s=ut+\tfrac12 at^{2}
    • [s]=[L][s]=[L]; [ut]=[L][T]1[T]=[L][u t]=[L][T]^{-1}[T]=[L]; [12at2]=[L][T]2[T]2=[L][\tfrac12 a t^{2}]=[L][T]^{-2}[T]^{2}=[L]
    • All terms [L]\rightarrow [L] ⇒ equation homogeneous.
    • v2=u2+2asv^{2}=u^{2}+2as: [v2]=[L]2[T]2[v^{2}]=[L]^{2}[T]^{-2} equals [u2][u^{2}]; [2as]=[L][T]2[L]=[L]2[T]2[2as]=[L][T]^{-2}[L]=[L]^{2}[T]^{-2} ⇒ homogeneous.
    • Period of a simple pendulum: T=2πlgT=2\pi\sqrt{\tfrac{l}{g}}
    • [l]=[L][l]=[L], [g]=[L][T]2[g]=[L][T]^{-2} ⇒ radicand =[T]2=[T]^{2}T=[T]T=[T]; homogeneous.
  • Multiple-choice recall

    • Dimension of temperature is [Θ][\Theta] (option D, symbol θ\theta sometimes used).
    • Refractive index is dimensionless.

1.2 Scalars and Vectors

  • Scalar quantity
    • Defined by magnitude only.
    • Examples: mass, distance, speed, work, pressure, electric current, temperature, energy.
  • Vector quantity
    • Defined by both magnitude and direction.
    • Examples: displacement, velocity, acceleration, force, momentum, impulse, torque, electric field E\vec E, magnetic field B\vec B.
    • Graphical representation: arrow; length → magnitude, arrowhead → direction.
  • Mathematical operations
    • While adding, subtracting, or multiplying vectors, always account for both magnitude and direction.

Resolving a Vector Into Perpendicular Components

  • Consider vector A\vec A making an angle θ\theta with the positive xx-axis.
    • Horizontal (x) component: Ax=AcosθA_x = A\cos\theta (adjacent).
    • Vertical (y) component: Ay=AsinθA_y = A\sin\theta (opposite).
    • Direction of A\vec A expressed as θ=tan1(A<em>yA</em>x)\theta=\tan^{-1}\bigl(\tfrac{A<em>y}{A</em>x}\bigr), measured from xx-axis.

Determining a Resultant Vector (Component Method)

Flow map / strategy:

  1. Resolve every vector into its xx and yy components.
    • Keep correct signs (+ toward +axes, − toward −axes).
  2. Add components separately:
    ΣF<em>x=A</em>x,ΣF<em>y=A</em>y\Sigma F<em>x = \sum A</em>x, \qquad \Sigma F<em>y = \sum A</em>y.
  3. Form the resultant vector R\vec R:
    • Magnitude R=(ΣF<em>x)2+(ΣF</em>y)2R = \sqrt{(\Sigma F<em>x)^2 + (\Sigma F</em>y)^2}.
    • Direction θ=tan1(ΣF<em>yΣF</em>x)\theta = \tan^{-1}\bigl( \tfrac{\Sigma F<em>y}{\Sigma F</em>x} \bigr) measured from xx-axis.
  4. Never mix xx and yy values directly (e.g. do not add them).
  5. Present direction clearly (e.g. 6.66.6^{\circ} above −x-axis, or “due north”, etc.).

Worked Vector Examples

  • Example – component identification

    • Given vector of magnitude 10units10\,\text{units} at 4545^{\circ} in 4th quadrant (x positive, y negative).
    • Ax=+10cos45=+10/2A_x = +10\cos45^{\circ}=+10/\sqrt2.
    • Ay=10sin45=10/2A_y = -10\sin45^{\circ}=-10/\sqrt2.
    • Correct multiple-choice: 10cos45-10\cos45^{\circ} or 10sin45-10\sin45^{\circ} depending on the given orientation (transcript answer: 10cos45-10\cos45^{\circ} for x component shown).
  • Car velocity problem

    • Speed 30m s130\,\text{m s}^{-1}, direction “north 6060^{\circ} west”.
    • Due north (y): 30cos60=15m s130\cos60^{\circ}=15\,\text{m s}^{-1}.
    • Due west (x negative): 30sin60=25.98m s130\sin60^{\circ}=-25.98\,\text{m s}^{-1}.
  • Force on particle S

    • Force magnitude 100N100\,\text{N} at given angle (from diagram).
    • Components extracted using sin\sin/cos\cos according to its orientation; transcript solution yields F<em>x,F</em>yF<em>x, F</em>y.
  • Three-force system (Fig. 7.1) – two methods (table or graphical) both yield same resultant magnitude; transcript lists R|\vec R|\approx value, confirm with calculation.

Multiple-Choice Highlights (Sample Questions & Answers)

  • Correct dimension/quantity mismatches: any listed except given wrong pair.
  • 1N=1kg m s21\,\text{N}=1\,\text{kg m s}^{-2}.
  • Pressure dimension [M][L]1[T]2[M][L]^{-1}[T]^{-2} and unit kg m1s2\text{kg m}^{-1}\text{s}^{-2} (option B).
  • Scalar pair: area & speed.
  • Vector pair: stress & magnetic field.

Tutorial-Style Practice (with provided answers)

  1. Determine dimensions/units

    • Linear momentum [M][L][T]1    (kg m s1)[M][L][T]^{-1}\;\;(\text{kg m s}^{-1})
    • Kinetic energy [M][L]2[T]2  (kg m2s2)[M][L]^{2}[T]^{-2}\;(\text{kg m}^{2}\text{s}^{-2})
    • Elastic potential energy same as kinetic energy.
    • (Extra given answers: kg m s2\text{kg m s}^{-2} – actually matches force, transcript typo; kg m3\text{kg m}^{-3} matches density.)
  2. Show mechanical wave equation v=Aωsin(ωt+kx)v=A\omega\sin(\omega t+kx) is homogeneous

    • [v]=[L][T]1[v]=[L][T]^{-1}; [A]=[L][A]=[L]; [ω]=[T]1[\omega]=[T]^{-1} ⇒ RHS =[L][T]1=[L][T]^{-1}; sine function dimensionless; homogeneous.
  3. Homogeneity checks

    • v=u+2asv=u+2as not homogeneous (dimension mismatch) – validate.
    • v=u+atv=u+at homogeneous.
    • Work W=FsW=Fs homogeneous.
  4. Resolve each listed vector; numerical answers supplied in bracket.

    • Examples include forces, accelerations, electric fields; answers: 7.66N,6.43N7.66\,\text{N},\,6.43\,\text{N} etc.
  5. Magnetic field system (Fig. 1.1)

    • B<em>1=20T,  B</em>2=40T,  B3=80TB<em>1=20\,\text{T},\;B</em>2=40\,\text{T},\;B_3=80\,\text{T}
    • Results: B<em>x=75.14T,  B</em>y=+8.78TB<em>x=-75.14\,\text{T},\;B</em>y=+8.78\,\text{T}
    • Resultant BR=75.65T,θ=6.66 above –x axis|\vec B_R|=75.65\,\text{T},\,\theta=-6.66^{\circ}\text{ above –x axis}.
  6. Electric field system (Fig. 1.2)

    • E<em>1=15N C1,E</em>2=38N C1,E3=17N C1E<em>1=15\,\text{N C}^{-1}, E</em>2=38\,\text{N C}^{-1}, E_3=17\,\text{N C}^{-1}
    • Resultant 29.98N C1,  62.96 above –x axis29.98\,\text{N C}^{-1},\;62.96^{\circ}\text{ above –x axis}.
  7. Sailboat displacement (Fig. 1.3)

    • Legs: 2.00km2.00\,\text{km} east, 3.50km3.50\,\text{km} southeast, unknown.
    • Final displacement 5.80km5.80\,\text{km} east of start.
    • Third leg magnitude 0.81km0.81\,\text{km} at 61.8461.84^{\circ} (direction per diagram).

Study Tips & Connections

  • Dimensional analysis links directly to error-checking in experimental physics and to model building in engineering (e.g., Buckingham Π-theorem).
  • Master vector components early; they recur in kinematics, dynamics, electromagnetism and fluid mechanics.
  • Treat sine/cosine arguments as dimensionless ⇒ any phase term ωt,kx\omega t,\,kx must itself be dimensionless, a universal consistency test.
  • Remember scalars can still be negative (e.g., work, potential energy) even though they lack direction.
  • When carrying significant figures & uncertainty (topic slated for laboratory work), keep at most one uncertain digit in the final quoted value.