Properties of Gases & Gas Laws

Introduction & Everyday Importance of Gases

  • Gases play critical roles in daily life:
    • Air mixture inhaled in respiration.
    • Natural gas used as fuel in combustion (cooking, heating).
    • Medical uses (e.g., anesthetic gases) due to their ability to diffuse through tissues & the blood–brain barrier.

Kinetic Molecular Theory (KMT)

  • Describes molecular-level behavior of gases.
  • Core postulates:
    • Gas particles (atoms or molecules) are in constant, random, straight-line motion.
    • Average speed (and thus kinetic energy, KEKE) scales with absolute temperature TT.
    • Higher TT \rightarrow higher speed \rightarrow greater KEKE.
    • Collisions are perfectly elastic (no net energy loss to surroundings).
    • Size of individual particles is negligible compared with total container volume ⇒ large intermolecular distances; attractive forces essentially zero.
    • Result: gas particles fill entire available volume.

Unique Macroscopic Properties of Gases

  • Highly compressible: volume can be significantly reduced with applied pressure (movable piston demonstration).
  • Expand to occupy full container volume because of random motion & negligible attraction.
  • Variable density (much lower than liquids/solids).

Pressure: Definition, Units & Measurement

  • Molecular view: pressure arises from billions of particle collisions with container walls.
  • Macroscopic definition: P=FAP = \frac{F}{A} (force per unit area).
  • Common units & conversions (exact by definition):
    1  atm=760  mmHg=760  Torr=14.7  psi=101325  Pa1\;\text{atm} = 760\;\text{mmHg} = 760\;\text{Torr} = 14.7\;\text{psi} = 101\,325\;\text{Pa}
  • Measurement device – barometer (mercury column):
    • Atmospheric pressure pushes Hg up a sealed tube; height at sea level ≈ 760  mmHg760\;\text{mmHg} (defines 1atm1\,\text{atm}).
    • Lower external PP (mountains) ⇒ lower Hg height.

Atmospheric Pressure & Altitude Effects

  • Composition of dry air (by volume): 78%N<em>278\%\,N<em>2, 21%O</em>221\%\,O</em>2, 1%\sim1\% others (Ar, CO$2$, H$2$O, \dots).
  • PatmP_{\text{atm}} decreases with elevation:
    • Denver (≈3000m3000\,\text{m}): P0.83atmP \approx 0.83\,\text{atm}.
    • Mt. Everest summit: P0.33atmP \approx 0.33\,\text{atm} (≈ one-third of sea-level air & O$_2$).
  • Physiological consequences:
    • Less O<em>2O<em>2 per breath ⇒ rapid breathing (hyperventilation), need for supplemental O$2$ tanks in extreme altitudes.
    • In aircraft (~10000m10\,000\,\text{m} cruising): cabin is pressurised to 0.75atm0.75\,\text{atm} while outside P0.27atmP \approx 0.27\,\text{atm}; ear-popping results from delayed equalisation across eardrum.

Fundamental Gas Variables

  • Four inter-related macroscopic variables:
    • Pressure PP (atm, Pa, etc.)
    • Volume VV (L, m$^3$)
    • Temperature TT (K)
    • Amount (moles nn)
  • Holding some constant while varying others leads to simple gas laws discovered in the 17th–19th centuries.

Boyle’s Law (Pressure–Volume, PVP\text{–}V)

  • Conditions: nn & TT constant.
  • Statement: PP and VV are inversely proportional.
    PVP \uparrow \Rightarrow V \downarrow and vice-versa.
  • Mathematical form: P<em>1V</em>1=P<em>2V</em>2P<em>1 V</em>1 = P<em>2 V</em>2.
  • Graphs:
    • PP vs VV → hyperbola.
    • PP vs 1V\frac{1}{V} → straight line.
  • Demonstration: increasing piston mass compresses gas ⇒ P<em>final>P</em>initialP<em>{\text{final}} > P</em>{\text{initial}}, V<em>final<V</em>initialV<em>{\text{final}} < V</em>{\text{initial}}.
  • Sample problems addressed:
    1. Moving 1-L gas at 1atm1\,\text{atm} into larger container ⇒ VV ↑ so PP ↓ (qualitative).
    2. Oxygen cylinder: given P<em>i=8.5atmP<em>i = 8.5\,\text{atm}, V</em>i=10.7LV</em>i = 10.7\,\text{L}, P<em>f=0.92atmP<em>f = 0.92\,\text{atm}V</em>f=98.6LV</em>f = 98.6\,\text{L} using Boyle’s equation.

Charles’s Law (Volume–Temperature, VTV\text{–}T)

  • Conditions: nn & PP constant.
  • Statement: VV directly proportional to absolute TT.
    V<em>1T</em>1=V<em>2T</em>2\frac{V<em>1}{T</em>1} = \frac{V<em>2}{T</em>2} (temperatures in Kelvin only).
  • Graph: straight line through origin; extrapolation meets V=0V = 0 at T=0KT = 0\,\text{K} (absolute zero = 273!C-273\,^{\circ}!\text{C}).
  • Examples:
    1. Doubling TT ((25\,^{\circ}\text{C} \rightarrow 50\,^{\circ}\text{C})) doubles VV for fixed P,nP,n.
    2. Neon sample: V<em>i=19.5LV<em>i = 19.5\,L, T</em>i=76!CT</em>i = 76^{\circ}!\text{C}, cool to 38!C38^{\circ}!\text{C}Vf=17.4LV_f = 17.4\,L.

Gay-Lussac’s Law (Pressure–Temperature, PTP\text{–}T)

  • Conditions: nn & VV constant.
  • Statement: PP directly proportional to TT.
    P<em>1T</em>1=P<em>2T</em>2\frac{P<em>1}{T</em>1} = \frac{P<em>2}{T</em>2}.
  • Illustration: Barrel fixed volume heated from 200K200\,K to 400K400\,KPP doubles.

Combined Gas Law

  • Consolidates Boyle, Charles & Gay-Lussac for fixed nn:
    P<em>1V</em>1T<em>1=P</em>2V<em>2T</em>2\frac{P<em>1 V</em>1}{T<em>1} = \frac{P</em>2 V<em>2}{T</em>2}.
  • Example (diver’s nitrogen bubble):
    • P<em>i=4.2atmP<em>i = 4.2\,\text{atm}, T</em>i=11!CT</em>i = 11^{\circ}!\text{C}, Vi=0.01mLV_i = 0.01\,\text{mL}.
    • Upon ascent to sea level P<em>f=1atmP<em>f = 1\,\text{atm}, T</em>f=29!CT</em>f = 29^{\circ}!\text{C}Vf=0.045mLV_f = 0.045\,\text{mL}.
    • Medical relevance: rapid ascent may produce large gas bubbles ⇢ decompression sickness.

Avogadro’s Law (Volume–Moles, VnV\text{–}n)

  • Conditions: PP & TT constant.
  • Statement: VV directly proportional to number of moles nn.
    V<em>1n</em>1=V<em>2n</em>2\frac{V<em>1}{n</em>1} = \frac{V<em>2}{n</em>2}.
  • Everyday example: inflating a balloon – adding gas molecules increases volume proportionally.
  • Calculation: Start with n<em>i=2moln<em>i = 2\,\text{mol}, V</em>i=1.0LV</em>i = 1.0\,L, add 1mol1\,\text{mol}n<em>f=3moln<em>f = 3\,\text{mol}; V</em>f=1.5LV</em>f = 1.5\,L.

Standard Temperature & Pressure (STP) & Molar Volume

  • Defined conditions:
    • T=0!C=273.15KT = 0^{\circ}!\text{C} = 273.15\,K (often 273K273\,K).
    • P=1atmP = 1\,\text{atm}.
  • Molar volume: At STP, 1mol1\,\text{mol} of any ideal gas occupies 22.4L22.4\,L.
    • Equality statement (conversion factor): 1mol  STP  22.4L1\,\text{mol}\;\xleftrightarrow{\text{STP}}\;22.4\,L.
  • Example: Find volume for 2.0mol2.0\,\text{mol} O$_2$ at STP ⇒ 2.0  mol×22.4  L/mol=44.8L2.0\;\text{mol} \times 22.4\;\text{L/mol} = 44.8\,L.

Density of Gases at STP

  • General formula: ρ=mV\rho = \frac{m}{V}.
  • Substituting STP molar quantities:
    ρSTP=M22.4L\rho_{\text{STP}} = \frac{M}{22.4\,L} where MM = molar mass.
  • Examples:
    • Helium: M=4.00gmol1ρ=0.179gL1M = 4.00\,g\,mol^{-1} \Rightarrow \rho = 0.179\,g\,L^{-1}.
    • CO$_2$: M=44.01gmol1ρ=1.965gL1M = 44.01\,g\,mol^{-1} \Rightarrow \rho = 1.965\,g\,L^{-1}.
    • Since \rho{\text{CO}2} > \rho{\text{air}} (1.29\,g\,L^{-1}) ⇒ CO$2$ sinks in air.

Dalton’s Law of Partial Pressures

  • In a gas mixture, each component exerts a partial pressure as if it alone occupied the volume.
  • Total pressure:
    P<em>tot=P</em>1+P<em>2+P</em>3+P<em>{\text{tot}} = P</em>1 + P<em>2 + P</em>3 + \dots
  • If mole (or volume) percentages known: partial pressure of gas ii is
    P<em>i=x</em>iP<em>totP<em>i = x</em>i P<em>{\text{tot}} where x</em>ix</em>i = mole or volume fraction (e.g., %100\frac{\%}{100}).
  • Applications & examples:
    1. Air at sea level: P<em>O</em>2=0.21×1atm=0.21atmP<em>{\text{O}</em>2} = 0.21 \times 1\,\text{atm} = 0.21\,\text{atm}.
    2. Cylinder with P<em>tot=3.00atmP<em>{\text{tot}} = 3.00\,atm, P</em>O<em>2=0.63atmP</em>{\text{O}<em>2} = 0.63\,atmP</em>N2=2.37atmP</em>{\text{N}_2} = 2.37\,atm (by subtraction).
    3. Heliox mixture (60% He, 40% O$2$) at 700mmHg700\,\text{mmHg}P</em>O2=0.40×700=280mmHgP</em>{\text{O}_2} = 0.40 \times 700 = 280\,\text{mmHg}.

Worked‐Problem Themes & Strategies

  • Always translate word problems to variable lists
    (e.g., P<em>i,V</em>i,T<em>i,n</em>iP<em>i,V</em>i,T<em>i,n</em>i ➜ identify unknown).
  • Convert all temperatures to Kelvin before substitution.
  • Match units: use consistent pressure units or convert via equality factors.
  • For Boyle/Charles/Gay-Lussac: hold two variables constant explicitly.
  • For STP or molar volume conversions: verify the gas is indeed at STP.
  • Use dimensional analysis to ensure units cancel correctly.

Real-World & Physiological Implications

  • Mountain climbing & aviation: decreasing P<em>O</em>2P<em>{\text{O}</em>2} ⇒ hypoxia; supplemental O$_2$ or cabin pressurisation required.
  • Scuba diving: combined gas law predicts nitrogen bubble expansion ⇒ controlled ascent prevents decompression sickness (“the bends”).
  • Medical gas mixtures (heliox) reduce airway resistance; Dalton’s law permits calculation of therapeutic P<em>O</em>2P<em>{\text{O}</em>2}.
  • Gas compressibility underpins piston engines & industrial gas storage (Boyle’s law in action).

Key Takeaways

  • Molecular motion underlies all gas properties; temperature is the average kinetic-energy gauge.
  • Four variables P,V,T,nP,V,T,n interact via predictable gas laws; holding two constant yields simple two-variable relations.
  • STP provides a universal yardstick (molar volume 22.4L22.4\,L); handy for density & stoichiometric calculations.
  • Mixtures obey Dalton’s law: total pressure is additive; fractions determine partial pressures crucial for respiration & industry.
  • Correct unit handling (Kelvin, atm, L, mol) is essential for accurate problem solving.