Waves and Electromagnetic Radiation Notes

Waves and Electromagnetic Radiation

Waves

  • This unit explores the physics and phenomena of waves from a chemistry perspective.

  • Light waves and electrons exhibit wave-like properties.

  • Light waves are electromagnetic phenomena with both electric and magnetic components.

  • Light waves propagate through space at the speed of light (3.0×1083.0 \times 10^8 m/s).

  • Electromagnetic waves (light waves) have no mass but can exhibit particle-like behavior. These particles of light are called "photons".

Wave Measurements

  • Any wave can be mathematically described by wavelength, frequency, and amplitude.

  • Wavelength (λ\lambda, "lambda") is the distance between two identical points on a wave in one cycle. The base unit is meters.

  • Frequency (ν\nu, "nu") measures the number of wave cycles passing a point in one second. The unit is 1/s or Hertz (Hz).

  • Amplitude describes the height or magnitude of the peaks and troughs. For electromagnetic waves, this relates to intensity or brightness.

  • The amplitudes of waves will be ignored hereafter.

Electromagnetic Spectrum

  • Frequency and wavelength are inversely proportional (as one increases, the other decreases).

  • The electromagnetic spectrum includes (from high frequency/short wavelength to low frequency/long wavelength):

    Gummy X-rays Unsee Visible Internal Microwaves Radiowaves

    • Gamma rays

    • X-rays

    • UV

    • Visible Light

    • Infrared

    • Microwaves

    • Radio waves

  • Visible light has wavelengths ranging from 400 to 700 nanometers.

  • The colors of visible light are red, orange, yellow, green, blue, indigo, and violet.

  • Violet has higher frequencies and shorter wavelengths, while red has lower frequencies and longer wavelengths.

  • Red light has lower energy than violet light.

  • The visible light region progresses from lower energy (red) to higher energy (violet).

ROY G BIV

  • Mnemonic for colors of visible light: ROY G BIV (Red, Orange, Yellow, Green, Blue, Indigo, Violet)

  • Low Energy → High Energy

  • Long Wavelength → Short Wavelength

  • Low Frequency → High Frequency

Electromagnetic Radiation

  • Relationship between speed, wavelength, and frequency: u=λνu = \lambda \nu where: * uu is the speed of the wave. * λ\lambda is the wavelength. * ν\nu is the frequency.

    • Units: meters x (1/s) = m/s

  • The speed of light (c) in a vacuum is a fundamental constant:
    c=λνc = \lambda \nu
    c=3.00×108c = 3.00 \times 10^8 m/s

  • Assume the electromagnetic wave is traveling in a vacuum unless specified otherwise.

Guided Problem
  • A wave with a wavelength of 902 picometers (pm) has a frequency of 5.81×1075.81 \times 10^7 Hz. What is the speed of this wave?

    • Known:

      • λ=902\lambda = 902 pm

      • ν=5.81×107\nu = 5.81 \times 10^7 Hz

    • Unknown:

      • uu (speed)

    • Formula:

      • u=λνu = \lambda \nu

    • Plug in variables:

      • u=(902 pm)×(5.81×107 Hz)=5.24×1010 pm/su = (902 \text{ pm}) \times (5.81 \times 10^7 \text{ Hz}) = 5.24 \times 10^{10} \text{ pm/s}

    • Conversion to m/s:

      • 5.24×1010pms×1×1012 m1 pm=5.24×102ms5.24 \times 10^{10} \frac{\text{pm}}{\text{s}} \times \frac{1 \times 10^{-12} \text{ m}}{1 \text{ pm}} = 5.24 \times 10^{-2} \frac{\text{m}}{\text{s}}

    • Alternative method:

      • Convert wavelength to meters first:
        902 pm×1×1012 m1 pm=9.02×1010 m902 \text{ pm} \times \frac{1 \times 10^{-12} \text{ m}}{1 \text{ pm}} = 9.02 \times 10^{-10} \text{ m}

      • Then calculate speed:
        (9.02×1010 m)×(5.81×107 Hz)=5.24×102ms(9.02 \times 10^{-10} \text{ m}) \times (5.81 \times 10^7 \text{ Hz}) = 5.24 \times 10^{-2} \frac{\text{m}}{\text{s}}

Planck's Constant

  • Max Planck observed that electromagnetic radiation energy is emitted or absorbed in discrete bits called photons.
    E=hνE = h\nu
    where:
    * E is the energy of one photon of light (in Joules, J).
    * hh is Planck's constant = 6.63×10346.63 \times 10^{-34} J⋅s
    * ν\nu is the frequency.

  • The energy of a photon changes with its frequency.

  • Higher frequency photons have higher energy.

  • An atom can absorb a photon if the energy (frequency) is just right.

  • When an atom absorbs a photon, an electron is promoted to a higher energy state (excited state).

  • When the excited electron releases energy, it emits a photon.

  • After releasing a photon, the electron returns to a lower energy state ("relaxed").