Lesson 3: Atoms and Molecules

Symbols and Formulas

  • Each element is represented by a unique name and symbol.

  • Symbols are based on elemental properties or derived from scientists, places, astronomical bodies, or mythological characters.

  • Elemental symbols: One capital letter or a capital letter followed by a lowercase letter.

Compound Formula

  • Consists of the symbols of the atoms in the molecule.

  • Each elemental symbol represents one atom of the element.

  • Subscripts indicate the number of atoms of an element present in the compound.

  • At least 2 atom types in compound (ex. triatomic - 3 types of atoms)

  • Example:

    • Nitrogen dioxide: NO2NO_2 (one nitrogen atom, two oxygen atoms).

    • Sulfuric acid: H2SO4 (two hydrogen atoms, one sulfur atom, four oxygen atoms).

Atomic Structure

  • Atoms are composed of three subatomic particles: protons, neutrons, and electrons.

  • Protons(+, defines element) and neutrons(+- is a filler):

    • Located in the nucleus.

    • Tightly bound together.

  • Electrons(-):

    • Located outside the nucleus.

    • Move rapidly throughout a large volume of space surrounding the nucleus.

Atomic and Mass Numbers

  • Atomic number:

    • Equal to the number of protons in the nucleus.

    • Symbol: Z

    • Located above the element symbol in the periodic table.

  • Mass number:

    • Equal to the sum of protons and neutrons in the nucleus.

    • Symbol: A

Isotopes

  • Atoms with the same number of protons but different numbers of neutrons.

  • Same atomic number (Z) but different mass numbers (A).

  • Example: Chlorine-35 and Chlorine-37.

  • All isotopes of the same element have:

    • Same number of electrons outside the nucleus.

    • Same number of protons in the nucleus.

Masses of Atoms and Molecules

  • Atomic Mass:

    • Numbers beneath the element symbol in the periodic table.

    • Provide a means of comparing the masses of atoms.

    • Atomic weight of elements is the average relative mass of the atoms in the isotope mixture.

  • Atomic Mass Unit (u):

    • Used to express the relative masses of atoms.

    • 1u=1/121 u = 1/12 the mass of a carbon-12 atom.

    • One carbon-12 atom has a relative mass of 12 u.

    • An atom with a mass equal to twice the mass of a carbon-12 atom would have a relative mass of 24 u.

  • Molecular Weight:

    • Relative mass of a molecule expressed in atomic mass units.

    • Calculated by adding together the atomic weights of the atoms in the molecule.

    • Example: Water (H2OH_2O)

      • MW = (2 × atomic weight of H) + (1 × atomic weight of O)

      • MW = (2×1.01u)+(1×16.00u)=18.02u(2 × 1.01 u) + (1 × 16.00 u) = 18.02 u

  • Example Problem: Molecular weight of urea, CH<em>4N</em>2OCH<em>4N</em>2O

Avogadro’s Number and the Mole Concept

  • Avogadro’s number: Number of atoms or molecules in a specific sample of an element or compound.

  • Mole (mol): Number of particles in a sample with a mass in grams equal to the atomic or molecular weight.

    • 1 mol = 6.022×10236.022 × 10^{23}

    • Example: 1 mol S atoms = 6.02×10236.02 × 10^{23} S atoms = 32.1 g S

  • Relationships:

    • 1 mol S atoms = 6.02×10236.02 × 10^{23} S atoms

    • 6.02×10236.02 × 10^{23} S atoms = 32.1 g S

    • 1 mol S atoms = 32.1 g S

The Mole and Chemical Formulas

  • Chemical formulas represent numerical relationships among atoms in a compound.

  • Example: H2OH_2O represents a 2:1 ratio of hydrogen to oxygen atoms.

  • Relationships:

    • 6.02×1023H2O6.02 × 10^{23} H_2O molecules contain 12.04×102312.04 × 10^{23} H atoms and 6.02×10236.02 × 10^{23} O atoms

    • 1 mol H2OH_2O contains 2 mol H atoms and 1 mol O atoms

    • 18.0 g H2OH_2O contains 2.0 g H and 16.0 g O

  • Mole Calculations:

Mole Calculation Example

  • Calculate the number of moles of Ca in a 15.84 g sample of Ca.

    • 15.84gCa×(1moleCa/40.08gCa)=0.3952molesCa15.84 g Ca × (1 mole Ca / 40.08 g Ca) = 0.3952 moles Ca

Example - Factor-Unit Calculations for Sulfur (S)

  • Determine the following using the factor-unit method:

    • The mass in grams of 1.35 mol of S:

      • 1.35molS×(32.1gS/1molS)=43.3gS1.35 mol S × (32.1 g S / 1 mol S) = 43.3 g S

    • The number of moles of S atoms in 98.6 g of S:

      • 98.6gS×(1molS/32.1gS)=3.07molS98.6 g S × (1 mol S / 32.1 g S) = 3.07 mol S

    • The number of S atoms in 98.6 g of S:

      • 98.6gS×(6.02×1023Satoms/32.1gS)=1.85×1024Satoms98.6 g S × (6.02 × 10^{23} S atoms / 32.1 g S) = 1.85 × 10^{24} S atoms

    • The mass in grams of one atom of S:

      • 1Satom×(32.1gS/6.02×1023Satoms)=5.33×1023gS1 S atom × (32.1 g S / 6.02 × 10^{23} S atoms) = 5.33 × 10^{-23} g S

The Mole Concept Applied to Compounds

  • One mole of any compound is a sample with a mass in grams equal to the molecular weight of the compound.

    • 1 mol CO2==6.02 × 10^{23} CO2molecules=44.0gmolecules = 44.0 gCO2

  • Relationships for factor-unit calculations:

    • 1 mol CO2==6.02 × 10^{23} CO2molecules

    • 6.02 × 10^{23} CO2molecules=44.0gmolecules = 44.0 gCO2

    • 1 mol CO2=44.0g= 44.0 gCO2

    • 1 mol CO2CO_2 contains 1 mol C atoms

    • 1 mol CO2CO_2 contains 2 mol O atoms

    • 1 mol C atoms = 12.01 g C

Mole Calculation Examples

Example - Factor-Unit Calculations for Carbon Dioxide