acids and bases
Chemistry Acids and Bases Review Sheet
Chapter 13:
1. Understand the following terms:
-Disassociation
-Ionization
-Strong electrolyte
-Weak electrolyte
2. Be able to write a net ionic equation and determine if a precipitate forms (Ex: Will a
precipitate form if solutions of barium chloride and sodium sulfate are combined? If so write a
net ionic equation).
3. Understand how to calculate molarity and moles of various equations.
Chapter 14:
1. Understand the properties of both acids and bases
2. be able to name binary acids and oxyacids
-HCl H 2 S
-HNO 3 H 2 CO 3
-HNO 2 HBr
3. Understand the definition of an acid and base according to:
-Arrhenius
-Bronsted-lowry
4. Understand what makes a strong and weak acid or base and be familiar with the strong acids
and bases.
5. Be able to write a reaction between an acid and a metal and determine if a reaction will
occur.
6. Understand how to write the reaction between an acid and base.
7. Know in which direction an acid/base reaction will occur. (aka, understand the concept of
conjugate acids and bases as well as their relative strengths)
Chapter 15:
1. Know how to perform all the calculations on the practice sheet (finding concentrations of
H3O+ or OH-, determining pH, Determining [H3O+] or [OH-] if given pH)
2. Understand what the pH scale signifies and what pOH stands for.
3. Understand how to calculate the molarity or pH of a solution when performing a titration. Ex:
By titration, 17.6 mL of H 2 SO 4 neutralized 27.4 mL of 0.0165 M LiOH solution. What is the
molarity of the aqueous acid solution?
4. Understand how to perform a titration and determining the equivalence point pH between
strong and weak acids and bases.
Unit 7
Part 1: Ions in Aqueous Solutions
Dissociation
When an IONIC substance is mixed in water, it
breaks apart into ions. This is called dissociation.
NaCl + H2O 🡪 Na+ + Cl-
BaF2 🡪 Ba2+ + 2F-
Al2(SO4)3 🡪 2Al3+ + 3SO42-
Ionization
When a COVALENT compound (most acids) mixes
with water it reacts with the water to form ions
HCl + H2O 🡪 H3O+ + Cl-
HF + H2O 🡪 H3O+ + F-
H2SO4 + 2H2O 🡪 2H3O+ + SO42-
Hydronium Ion
Complete the following reactions and
label them as dissociation or Ionization.
LiOH + H2O 🡪
HI + H2O 🡪
BaBr2 + H2O 🡪
Li2CO3 + H2O 🡪
Li+ + OH- Dissociation
H3O+ + I- Ionization
Ba2+ + 2Br- Dissociation
2Li+ + CO32- Dissociation
Solubility Rules
Used to determine if an ionic substance will dissolve in water
Determine if the following will be
soluble
NaBrO3
CaSO4
AgBr
FeCO3
V(NO3)2
Soluble: big momma
Insoluble
Soluble: big momma
Insoluble
Insoluble
Determine if the following is soluble or
insoluble:
ZnSO4
AgClO3
LiOH
AgCl
Soluble: big momma
Soluble: big momma
Soluble: SO4
Insoluble
Net Ionic Equations
Equations showing only reacting ions
Steps for writing them
1) Write a balanced equation
2) Break apart anything that is aqueous into
ions
3) Cancel anything that appears on BOTH
sides
4) Write the final product
Write a net ionic equation for the reaction between
aqueous ammonium sulfide and aqueous cadmium
nitrate to yield aqueous ammonium nitrate and solid
cadmium sulfide.
(NH4)2S(aq) + Cd(NO3)2(aq) 🡪 CdS(s) + 2NH4NO3(aq)
2 NH4+ + S2- + Cd2+ + 2 NO3- 🡪 CdS(s) + 2NH4+ + 2NO3-
S2- + Cd2+ 🡪 CdS(s)
Will a precipitate form?
When writing the products of a reaction,
anything that is insoluble will form a
precipitate (solid)
Anything you cross out is called a spectator
ion.
If none of the products are insoluble: you
can’t write a net ionic equation!
Will a reaction occur? If so write a net
ionic equation.
2NaOH(aq) + Li2CO3(aq) 🡪
NaCl(aq) + AgClO4(aq) 🡪
Na2CO3 + 2LiOH
Soluble = (aq)
Soluble = (aq)
NaClO4 + AgCl
Soluble = (aq)
Insoluble = (s)
Na+ + Cl- + Ag+ + ClO4- 🡪 Na+ + ClO4- + AgCl(s)
NO REACTION
Ag+ + Cl- 🡪 AgCl(s)
Write the reaction between aqueous lithium sulfate and
aqueous barium chloride. Determine if a precipitate will
form, if so, write a net ionic equation
Li2SO4(aq) + BaCl2(aq) 🡪 2LiCl + BaSO4
AQ
S
2Li+ + SO42- + Ba2+ + 2Cl- 🡪 2Li+ + 2Cl- + BaSO4(s)
Ba2+ + SO42- 🡪 BaSO4(s)
Part 2: Acids and Bases
Strong vs Weak Electrolytes
Strong electrolyte: a substance that fully ionizes
or dissociates in water.
HCl + H2O 🡪 H3O+ + Cl-
1 mole
1 mole 1 mole
Since HCl is a strong electrolyte every molecule of
HCl breaks apart into hydronium and chloride ions.
Weak electrolyte: Does NOT fully ionize or
dissociate in water
Fe(OH)2 + H2O 🡪 Fe2+ + 2OH-
1 mole
0.000001 mol of each
Since Fe(OH)2 is a weak electrolyte, very few of the
molecules break apart in water.
Acids
A substance that when dissolved in water, increases
the concentration of hydrogen ions (H+) or
hydronium ions (H3O+)
Taste sour
Turn blue litmus paper red
Consist of a H bonded with a non-metal or a H bonded
with a polyatomic ion.
HCl, HI, HNO3, H2SO4, HCH3COO
Naming Acids
Binary acids: H and ONE other element
HCl, HF, HI, HBr, H2S
Hydro - (nonmetal)- ic acid
HCl = hydrochloric acid
HBr = Hydrobromic acid
HF = Hydrofouric acid
Acids with polyatomic ions
If the PAI ends in “ate” you name it as (polyatomic ion - ate) + ic
acid
If The PAI ends in “ite” you name it (polyatomic ion -ite) +ous acid
HNO3 = nitric acid
HNO2 = nitrous acid
H2SO4 = sulferic acid
H2SO3 = Sulferous acid
HClO4 = perchloric acid
HClO3 = chloric acid
HClO2 = Chlorous acid
HClO = hypochlorous acid
Strength of Acids
Strong acids are strong electrolytes.
HCl, HBr, HI, HNO3, H2SO4, HClO4, HClO3
These acids fully IONIZE in a solution
Weak acids are weak electrolytes
They do not fully ionize in a solution
Any acid not mentioned before.
Name the following acid and
determine if it is strong or weak
HBr
HCH3COO
H2CO3
H3P
Hydrobromic acid
Strong
Acetic acid
Weak
Carbonic acid
Weak
Hydrophosphoric acid
Weak
Bases
Substances that increase the hydroxide ion concentration in
a solution (OH-) or decease the H+ concentration
Taste bitter
Turn red litmus blue
Typically consist of a metal with a OH or an NH3 or NH2…
NaOH, KOH, Ba(OH)2, NH3, CH2NH2
Strong and Weak bases
Weak bases are weak electrolytes
All organic amino compounds (CH bound with
NH2)
NH3
Most metal hydroxides except…
Strong bases are strong electrolytes
Group I hydroxides
Ba, Sr, Ca Hydroxides
Acid base reactions
Acids react with metals in a single
displacement to make a salt and hydrogen gas
HCl + Na 🡪 NaCl + H2
Acids and bases react to form water and a
salt (double displacement).
HCl + NaOH 🡪 NaCl + H2O
Bronsted Lowry Acids and Bases
Acid: any substance that donates a proton
(H+) in a reaction.
Base: any substance that accepts a proton in a
reaction.
HCl + H2O 🡪 H3O+ + Cl-
Acid
Base
Determine the Bronsted Lowry Acids
and Bases
HF + NH3 🡪 NH4+ + F-
H2O + CH2NH2 🡪 OH- + CH2NH3+
H2O + H2SO4 🡪 H3O+ + HSO4-
Acid
Base
Acid
Acid
Base
Base
Conjugate Acid Base Pairs
With Bronsted Lowry acids and bases, every
acid has a conjugate base pair and each base
has a conjugate acid pair.
HCl + H2O 🡪 H3O+ + Cl-
Acid
Base
Conj. Acid
Conj. Base
Identify the conjugate acid base pairs
HSO4- + OH- 🡪 SO42- + H2O
NH3 + HCH3COO 🡪 NH4+ + CH3COO-
HBr + H2O 🡪 H3O+ + Br-
A
A
A
B
B
B
CB
CB
CB
CA
CA
CA
Strength of CA and CB
The conjugate acid of a strong base is weak
The conjugate acid of a weak base is stronger
that that base
Same for acids
HI 🡪 I-
HI is a strong acid so I- is a weaker conjugate base
NH3 🡪 NH4+
NH3 is a weak base so NH4+ is a stronger acid (not a
strong acid)
HF 🡪 F-
HF is a weak acid so F- is a stronger base (not a
strong base).
Reactions will always go from the
stronger side to the weaker side
HBr + H2O 🡪 H3O+ + Br-
Strong acid
Weaker
Direction of reaction 🡪
HCH3COO + H2O 🡪 H3O+ + CH3COO-
Weak acid
Stronger
Direction of reaction 🡨
Part 3: pH and Titrations
pH
Measure of the Hydronium ion concentration in a
solution
It is a log scale
From 0 = very acidic
To 14 = very basic
pH 7 = neutral
Figure 3.UN05
Acidic
[H+] > [OH−]
Neutral
[H+] = [OH−]
Basic
[H+] < [OH−]
Bases donate OH−
or accept H+ in
aqueous solutions
14
7
Acids donate H+ in
aqueous solutions.
0
Calculating pH
pH + pOH = 14
pH = -log[H3O+]
pOH = -log[OH-]
[H3O+][OH-] = 1*10-14
[H3O+] = 10-pH
[OH-] = 10-pOH
Steps for calculating pH
[] = concentration in molar.
You should always make sure you do an
ionization or dissociation reaction and then
find [] of OH or H3O first.
Use a combination of reactions to solve the
problem.
Find the pH of a 1*10-3 M solution of
HCl?
HCl + H2O 🡪 H3O+ + Cl-
1*10-3 M
: 1*10-3 M
2) pH = -log[H3O] = -log [1*10-3 M]
pH = 3
Find the pH of a 1.0*10-7M solution of
Ba(OH)2
Ba(OH)2 🡪 Ba2+ + 2OH-
1.0*10-7M : 2(1.0*10-7M)
pOH = -log[OH-] = - log[2.0*10-7M]
pOH = 6.7
pH + pOH= 14
pH = 14- 6.7 = 7.3
Find the [H3O+] of a 1.4*10-4M
solution of NaOH.
NaOH 🡪 Na+ + OH-
1.4*10-4 : 1.4*10-4
[H3O+][OH-] = 1*10-14
1*10-14/[OH-] = [H3O+]
1*10-14/ 1.4*10-4 = 7.1 *10-11
Find the [OH-] of a acetic acid solution
with a pH of 4.6
[OH-] = 10-pOH
14- pH = pOH = 14-4.6 = 9.4
[OH-] = 10-9.4
[OH-] = 3.98*10-10
Titrations
A method of
determining the
molarity of a solution.
An acid is added to a
base (or vice versa) until
the endpoint is reached.
An indicator is used to
determine when the
endpoint is reached.
Indicator
A substance that changes colors at certain pH
values.
For example: phenophthalene indicator
Acidic
Basic
End Point
When the acid and base both fully react, the
equivalence point is reached. After this point
1 drop of either the acid or base will make
the indicator change color. This is called the
end-point!
For a strong acid and base, the equivalence
point will be at a pH of 7.
Calculations with Titrations
A 0.500M solution of NaOH is titrated with a solution of
HCl of unknown molarity. If it takes 25mL of NaOH to
fully react with 70 mL of HCl, find the molarity of the
HCl solution.
Write a balanced equation:
NaOH + HCl 🡪 NaCl + H2O
2) Find the moles of the known value:
M = mol/L so for NaOH = moles = M*L = 0.500 * 0.025L = .0125moles NaOH
3) Use ratio to find the moles of the unknown:
Ratio of NaOH : HCl
1 : 1
0.0125 mol : x x = 0.0125 moles of HCl
4) Find molarity
M= moles/L
= 0.0125/ 0.070L = 0.179M of HCl
A 15.5 mL sample of 0.215M LiOH solution is
required to titrate 21.2 mL of acetic acid solution.
Find the molarity of the acetic acid solution.
Write a balanced equation:
LiOH + HCH3COO 🡪 LiCH3COO + H2O
2) Find the moles of the known value:
M = mol/L so for LiOH = moles = M*L = 0.215 * 0.0155 L = 0.0033 moles LiOH
3) Use ratio to find the moles of the unknown:
Ratio of LiOH : HCH3COO
1 : 1
0.0033 mol : x x = 0.0033 moles of HCl
4) Find molarity
M= moles/L
= 0.0033/ 0.0212L = 0.157M