Notes on Simple Stress – Mech 313 (Introduction to Strength of Materials)

Introduction

  • Strength of materials (SOM) definition:

    • When an external force acts on a body, the body tends to deform.

    • Internal resisting forces develop due to cohesion between molecules, opposing deformation. This phenomenon is the essence of strength of materials.

  • Elastic limit concept:

    • Within the elastic limit, resistance offered by the material is proportional to the deformation caused by the external force.

    • Within the elastic limit, the resistance is equal to the external force (i.e., load).

  • Beyond the elastic stage:

    • The resistance offered by the material is less than the applied load.

    • Deformation continues until failure occurs.

  • Stress definition (within elastic stage):

    • The resisting force per unit area is called stress.

    • In symbols: stress is the ratio of the applied force to the resisting area.

Historical Development

  • Strength of materials dates back to ancient times (design of bridges, buildings, tools) but formal science emerged in the 17th century.

    • 1638: Galileo Galilei studied breaking strength of materials.

    • 18th century: Robert Hooke formulated Hooke's Law (linear stress–strain relation within elastic limits).

    • Leonhard Euler contributed to theories on column buckling.

    • 19th century: Augustin-Louis Cauchy advanced the mathematical foundations of stress and strain analysis.

    • Industrial Revolution spurred safer, stronger structures and major field advancements.

  • Modern context: Strength of Materials is essential in the design of buildings, machines, vehicles, and other structures.

Purpose and Key Concepts

  • One of the basic problems in engineering: select proper material and proportion it to enable a structure or machine to function efficiently.

    • This requires determining material properties: strength, stiffness, etc.

  • Stress vs. Strain:

    • Stress is associated with the strength of the material.

    • Strain is a measure of the deformation of the body.

Simple Stresses (Definition and Units)

  • Simple stress is expressed as the ratio of the applied force to the resisting area:

    • S = rac{P}{A}

    • Where:

    • P = external force or load

    • A = cross-sectional area

  • Units: stress has the unit of force per area.

    • ext{Unit of stress} = rac{N}{m^{2}} = ext{Pa}

    • Common engineering units: rac{N}{mm^{2}} = ext{MPa}

Classification of Simple Stress

1) Normal stress: develops when a force is applied perpendicular to the cross-sectional area of the material.

  • a) Tensile stress – force that pulls the material (pulling apart).

  • b) Compressive stress – material is compressed by two opposing forces.
    2) Shear stress – develops when the applied force is parallel to the resisting area.
    3) Bearing stress – contact pressure between two bodies.

Illustrative Example (Visual Reference)

  • Good example often cited: Suspension Bridge (illustrates load transfer and stresses in structural elements).

  • Contextual note: The interaction of forces in real structures demonstrates normal, shear, and bearing stresses in practice.

Normal Stress: Details and Variables

  • Where:

    • P = the applied normal load in Newtons (N)

    • A = the cross-sectional area in square millimeters (mm^2)

  • Relationship basics:

    • S_{normal} = rac{P}{A}

    • Unit considerations: load in N, area in mm^2, yielding stress in MPa when using N/mm^2.

Shear Stress: Details

  • Definition:

    • Shear stress arises when shear force acts parallel to the surface area being sheared.

  • Where:

    • V = the resultant shearing force that passes through the centroid (N)

    • A = area being sheared (mm^2)

  • Relationship: S_{shear} = rac{V}{A} (not explicitly shown in the transcript, but implied by the standard definition of shear stress)

Bearing Stress: Details

  • Definition:

    • Bearing stress is the contact pressure between two bodies in contact.

    • Common example: pressure between a rivet/bolt and the plate surface that it presses against.

  • Relevance: governs design of joints and contact interfaces.

Problem Solving (Normal Stress) – Practice Problems

  • Problem 1:

    • A hollow steel tube with an inside diameter of 100~ ext{mm} must carry a tensile load of 400~ ext{kN}.

    • Determine the outside diameter of the tube if the allowable stress is limited to 120~ ext{MN/m}^{2}.

    • Given data to use:

    • Inner diameter: d_i = 100~ ext{mm}

    • Load: P = 400~ ext{kN} = 4.0 imes 10^{5}~ ext{N}

    • Allowable stress: au_{allow} = 120~ ext{MPa} = 120~ ext{N/mm}^{2} (since 1~ ext{MPa} = 1~ ext{N/mm}^2)

    • Approach (outline): compute required outer cross-sectional area from $$S = rac{P}{A} \