Comprehensive Notes on Complex Numbers and Polar Coordinates
- 17a. 8(cos240°+isin240°)
- Convert to rectangular form: 8(−21−i23)=−4−4i3
- 17b. 6(cos711π+isin711π)
- This is already in trigonometric form. To convert, evaluate the cosine and sine and distribute.
- 17c. 10(cos35π+isin35π)
- Convert to rectangular form: 10(21−i23)=5−5i3
- 17d. 6(cos2π+isin2π)
- Convert to rectangular form: 6(1+i(0))=6
- 18a. [2(cos27°+isin27°)][5(cos103°+isin103°)]
- Multiply magnitudes and add angles: 2∗5[cos(27°+103°)+isin(27°+103°)]=10(cos130°+isin130°)
- 18b. [6(cos35π+isin35π)][5(cos34π+isin34π)]
- Multiply magnitudes and add angles: 6∗5[cos(35π+34π)+isin(35π+34π)]=30(cos39π+isin39π)=30(cos3π+isin3π)
- 18c. 2(cos120°+isin120°)22(cos500°+isin500°)
- Divide magnitudes and subtract angles: 222[cos(500°−120°)+isin(500°−120°)]=11(cos380°+isin380°)
- Simplify angle: 11(cos(380°−360°)+isin(380°−360°))=11(cos20°+isin20°)
- 18d. 2(cos330°+isin330°)10(cos70°+isin70°)
- Divide magnitudes and subtract angles: 210[cos(70°−330°)+isin(70°−330°)]=5(cos(−260°)+isin(−260°))
- Simplify angle: 5(cos(−260°+360°)+isin(−260°+360°))=5(cos100°+isin100°)
DeMoivre's Theorem
- 19a. (−2+3i)6
- Convert to polar form: r=(−2)2+32=13, θ=arctan(−23)+π
- Apply DeMoivre's Theorem: (13)6[cos(6θ)+isin(6θ)]
- Convert back to standard form after calculating the values.
- 19b. [3(cos45π+isin45π)]4
- Apply DeMoivre's Theorem: 34[cos(4∗45π)+isin(4∗45π)]=81(cos5π+isin5π)
- Simplify: 81(cosπ+isinπ)=81(−1+0i)=−81
- 19c. [5(cos23π+isin23π)]3
- Apply DeMoivre's Theorem: 53[cos(3∗23π)+isin(3∗23π)]=125(cos29π+isin29π)
- Simplify: 125(cos2π+isin2π)=125(0+i)=125i
- 19d. (4−4i)3
- Convert to polar form: r=42+(−4)2=32=42, θ=arctan(4−4)=−4π
- Apply DeMoivre's Theorem: (42)3[cos(3∗−4π)+isin(3∗−4π)]=(42)3[cos(−43π)+isin(−43π)=1282[cos(−43π)+isin(−43π)]
Polar Coordinate Representations
- 20. A = (5,$\frac{\pi}{3}$)
- Plot the point. Find three additional representations:
- Add 2π to the angle: (5,3π+2π)=(5,37π)
- Add π to the angle and negate r: (−5,3π+π)=(−5,34π)
- Subtract 2π from the original angle: (5,3π−2π)=(5,−35π)
- 21. B = (-2,$\frac{3\pi}{4}$)
- Plot the point. Find three additional representations:
- Add 2π to the angle: (−2,43π+2π)=(−2,411π)
- Add π to the angle and negate r: (2,43π+π)=(2,47π)
- Subtract 2π from the original angle: (−2,43π−2π)=(−2,−45π)
- 22. C = (2,-$\frac{\pi}{4}$)
- Plot the point. Find three additional representations:
- Add 2π to the angle: (2,−4π+2π)=(2,47π)
- Add π to the angle and negate r: (−2,−4π+π)=(−2,43π)
- Subtract 2π from the original angle: (2,−4π−2π)=(2,−49π)
- 23. D = (-4,-$\frac{\pi}{3}$)
- Plot the point. Find three additional representations:
- Add 2π to the angle: (−4,−3π+2π)=(−4,35π)
- Add π to the angle and negate r: (4,−3π+π)=(4,32π)
- Subtract 2π from the original angle: (−4,−3π−2π)=(−4,−37π)
Rectangular to Polar Conversion
- 24. (-3, -3)
- r=(−3)2+(−3)2=18=32
- θ=arctan(−3−3)=arctan(1)
- Since the point is in the third quadrant: θ=45π
- Polar coordinates: (32,45π)
- 25. (-\sqrt{2}, \sqrt{2})
- r=(−2)2+(2)2=2+2=4=2
- θ=arctan(−22)=arctan(−1)
- Since the point is in the second quadrant: θ=43π
- Polar coordinates: (2,43π)
- 26. (1, -\sqrt{3})
- r=12+(−3)2=1+3=4=2
- θ=arctan(1−3)=arctan(−3)
- Since the point is in the fourth quadrant: θ=−3π, equivalent to 35π
- Polar coordinates: (2,35π)
- 27. (5, 0)
- r=52+02=25=5
- θ=arctan(50)=0
- Polar coordinates: (5,0)
Polar to Rectangular Conversion
- 28. (7,$\frac{5\pi}{6}$)
- x=rcosθ=7cos(65π)=7(−23)=−273
- y=rsinθ=7sin(65π)=7(21)=27
- Rectangular coordinates: (−273,27)
- 29. (5,$\frac{11\pi}{6}$)
- x=rcosθ=5cos(611π)=5(23)=253
- y=rsinθ=5sin(611π)=5(−21)=−25
- Rectangular coordinates: (253,−25)
- 30. (-3,$\pi$ )
- x=rcosθ=−3cos(π)=−3(−1)=3
- y=rsinθ=−3sin(π)=−3(0)=0
- Rectangular coordinates: (3,0)
Calculator Conversions
- 31a. (9, 31°)
- x=9cos(31°)≈7.71
- y=9sin(31°)≈4.64
- Rectangular coordinates: (7.71,4.64)
- 31b. (8, 173°)
- x=8cos(173°)≈−7.97
- y=8sin(173°)≈0.96
- Rectangular coordinates: (−7.97,0.96)
Calculator Conversions: Rectangular to Polar
- 32a. (-2, -4)
- r=(−2)2+(−4)2=20≈4.47
- θ=arctan(−2−4)=arctan(2)≈1.11
- Since the point is in the third quadrant, add π: θ≈1.11+π≈4.25
- Polar coordinates: (4.47,4.25)
- 32b. (4, 5)
- r=42+52=41≈6.40
- θ=arctan(45)≈0.896
- Polar coordinates: (6.40,0.90)
Graphing Polar Functions
- 33. r=−4sin(2θ)
- Create a table of values for θ and r to plot the graph. Look for symmetry and critical points.
- Show direction of the graph by indicating how r changes as θ increases.
- Label at least four values of θ on the curve to show orientation.