Comprehensive Notes on Complex Numbers and Polar Coordinates

Complex Numbers in Standard Form

  • 17a. 8(cos240°+isin240°)8(\cos 240° + i \sin 240°)
    • Convert to rectangular form: 8(12i32)=44i38(-\frac{1}{2} - i\frac{\sqrt{3}}{2}) = -4 - 4i\sqrt{3}
  • 17b. 6(cos11π7+isin11π7)6(\cos \frac{11\pi}{7} + i \sin \frac{11\pi}{7})
    • This is already in trigonometric form. To convert, evaluate the cosine and sine and distribute.
  • 17c. 10(cos5π3+isin5π3)10(\cos \frac{5\pi}{3} + i \sin \frac{5\pi}{3})
    • Convert to rectangular form: 10(12i32)=55i310(\frac{1}{2} - i\frac{\sqrt{3}}{2}) = 5 - 5i\sqrt{3}
  • 17d. 6(cos2π+isin2π)6(\cos 2\pi + i \sin 2\pi)
    • Convert to rectangular form: 6(1+i(0))=66(1 + i(0)) = 6

Operations in Trigonometric Form

  • 18a. [2(cos27°+isin27°)][5(cos103°+isin103°)][2(\cos 27° + i \sin 27°)][5(\cos 103° + i \sin 103°)]
    • Multiply magnitudes and add angles: 25[cos(27°+103°)+isin(27°+103°)]=10(cos130°+isin130°)2 * 5 [\cos(27° + 103°) + i \sin(27° + 103°)] = 10(\cos 130° + i \sin 130°)
  • 18b. [6(cos5π3+isin5π3)][5(cos4π3+isin4π3)][6(\cos \frac{5\pi}{3} + i \sin \frac{5\pi}{3})][5(\cos \frac{4\pi}{3} + i \sin \frac{4\pi}{3})]
    • Multiply magnitudes and add angles: 65[cos(5π3+4π3)+isin(5π3+4π3)]=30(cos9π3+isin9π3)=30(cos3π+isin3π)6 * 5 [\cos(\frac{5\pi}{3} + \frac{4\pi}{3}) + i \sin(\frac{5\pi}{3} + \frac{4\pi}{3})] = 30(\cos \frac{9\pi}{3} + i \sin \frac{9\pi}{3}) = 30(\cos 3\pi + i \sin 3\pi)
  • 18c. 22(cos500°+isin500°)2(cos120°+isin120°)\frac{22(\cos 500° + i \sin 500°)}{2(\cos 120° + i \sin 120°)}
    • Divide magnitudes and subtract angles: 222[cos(500°120°)+isin(500°120°)]=11(cos380°+isin380°)\frac{22}{2} [\cos(500° - 120°) + i \sin(500° - 120°)] = 11(\cos 380° + i \sin 380°)
    • Simplify angle: 11(cos(380°360°)+isin(380°360°))=11(cos20°+isin20°)11(\cos (380° - 360°) + i \sin (380° - 360°)) = 11(\cos 20° + i \sin 20°)
  • 18d. 10(cos70°+isin70°)2(cos330°+isin330°)\frac{10(\cos 70° + i \sin 70°)}{2(\cos 330° + i \sin 330°)}
    • Divide magnitudes and subtract angles: 102[cos(70°330°)+isin(70°330°)]=5(cos(260°)+isin(260°))\frac{10}{2} [\cos(70° - 330°) + i \sin(70° - 330°)] = 5(\cos (-260°) + i \sin (-260°))
    • Simplify angle: 5(cos(260°+360°)+isin(260°+360°))=5(cos100°+isin100°)5(\cos (-260° + 360°) + i \sin (-260° + 360°)) = 5(\cos 100° + i \sin 100°)

DeMoivre's Theorem

  • 19a. (2+3i)6(-2 + 3i)^6
    • Convert to polar form: r=(2)2+32=13r = \sqrt{(-2)^2 + 3^2} = \sqrt{13}, θ=arctan(32)+π\theta = \arctan(\frac{3}{-2}) + \pi
    • Apply DeMoivre's Theorem: (13)6[cos(6θ)+isin(6θ)](\sqrt{13})^6 [\cos(6\theta) + i \sin(6\theta)]
    • Convert back to standard form after calculating the values.
  • 19b. [3(cos5π4+isin5π4)]4[3(\cos \frac{5\pi}{4} + i \sin \frac{5\pi}{4})]^4
    • Apply DeMoivre's Theorem: 34[cos(45π4)+isin(45π4)]=81(cos5π+isin5π)3^4 [\cos(4 * \frac{5\pi}{4}) + i \sin(4 * \frac{5\pi}{4})] = 81(\cos 5\pi + i \sin 5\pi)
    • Simplify: 81(cosπ+isinπ)=81(1+0i)=8181(\cos \pi + i \sin \pi) = 81(-1 + 0i) = -81
  • 19c. [5(cos3π2+isin3π2)]3[5(\cos \frac{3\pi}{2} + i \sin \frac{3\pi}{2})]^3
    • Apply DeMoivre's Theorem: 53[cos(33π2)+isin(33π2)]=125(cos9π2+isin9π2)5^3 [\cos(3 * \frac{3\pi}{2}) + i \sin(3 * \frac{3\pi}{2})] = 125(\cos \frac{9\pi}{2} + i \sin \frac{9\pi}{2})
    • Simplify: 125(cosπ2+isinπ2)=125(0+i)=125i125(\cos \frac{\pi}{2} + i \sin \frac{\pi}{2}) = 125(0 + i) = 125i
  • 19d. (44i)3(4 - 4i)^3
    • Convert to polar form: r=42+(4)2=32=42r = \sqrt{4^2 + (-4)^2} = \sqrt{32} = 4\sqrt{2}, θ=arctan(44)=π4\theta = \arctan(\frac{-4}{4}) = -\frac{\pi}{4}
    • Apply DeMoivre's Theorem: (42)3[cos(3π4)+isin(3π4)]=(42)3[cos(3π4)+isin(3π4)=1282[cos(3π4)+isin(3π4)](4\sqrt{2})^3 [\cos(3 * -\frac{\pi}{4}) + i \sin(3 * -\frac{\pi}{4})] = (4\sqrt{2})^3 [\cos(-\frac{3\pi}{4}) + i \sin(-\frac{3\pi}{4}) = 128 \sqrt{2} [\cos(-\frac{3\pi}{4}) + i \sin(-\frac{3\pi}{4})]

Polar Coordinate Representations

  • 20. A = (5,$\frac{\pi}{3}$)
    • Plot the point. Find three additional representations:
      • Add 2π2\pi to the angle: (5,π3+2π)=(5,7π3)(5, \frac{\pi}{3} + 2\pi) = (5, \frac{7\pi}{3})
      • Add π\pi to the angle and negate r: (5,π3+π)=(5,4π3)(-5, \frac{\pi}{3} + \pi) = (-5, \frac{4\pi}{3})
      • Subtract 2π2\pi from the original angle: (5,π32π)=(5,5π3)(5, \frac{\pi}{3} - 2\pi) = (5, -\frac{5\pi}{3})
  • 21. B = (-2,$\frac{3\pi}{4}$)
    • Plot the point. Find three additional representations:
      • Add 2π2\pi to the angle: (2,3π4+2π)=(2,11π4)(-2, \frac{3\pi}{4} + 2\pi) = (-2, \frac{11\pi}{4})
      • Add π\pi to the angle and negate r: (2,3π4+π)=(2,7π4)(2, \frac{3\pi}{4} + \pi) = (2, \frac{7\pi}{4})
      • Subtract 2π2\pi from the original angle: (2,3π42π)=(2,5π4)(-2, \frac{3\pi}{4} - 2\pi) = (-2, -\frac{5\pi}{4})
  • 22. C = (2,-$\frac{\pi}{4}$)
    • Plot the point. Find three additional representations:
      • Add 2π2\pi to the angle: (2,π4+2π)=(2,7π4)(2, -\frac{\pi}{4} + 2\pi) = (2, \frac{7\pi}{4})
      • Add π\pi to the angle and negate r: (2,π4+π)=(2,3π4)(-2, -\frac{\pi}{4} + \pi) = (-2, \frac{3\pi}{4})
      • Subtract 2π2\pi from the original angle: (2,π42π)=(2,9π4)(2, -\frac{\pi}{4} - 2\pi) = (2, -\frac{9\pi}{4})
  • 23. D = (-4,-$\frac{\pi}{3}$)
    • Plot the point. Find three additional representations:
      • Add 2π2\pi to the angle: (4,π3+2π)=(4,5π3)(-4, -\frac{\pi}{3} + 2\pi) = (-4, \frac{5\pi}{3})
      • Add π\pi to the angle and negate r: (4,π3+π)=(4,2π3)(4, -\frac{\pi}{3} + \pi) = (4, \frac{2\pi}{3})
      • Subtract 2π2\pi from the original angle: (4,π32π)=(4,7π3)(-4, -\frac{\pi}{3} - 2\pi) = (-4, -\frac{7\pi}{3})

Rectangular to Polar Conversion

  • 24. (-3, -3)
    • r=(3)2+(3)2=18=32r = \sqrt{(-3)^2 + (-3)^2} = \sqrt{18} = 3\sqrt{2}
    • θ=arctan(33)=arctan(1)\theta = \arctan(\frac{-3}{-3}) = \arctan(1)
    • Since the point is in the third quadrant: θ=5π4\theta = \frac{5\pi}{4}
    • Polar coordinates: (32,5π4)(3\sqrt{2}, \frac{5\pi}{4})
  • 25. (-\sqrt{2}, \sqrt{2})
    • r=(2)2+(2)2=2+2=4=2r = \sqrt{(-\sqrt{2})^2 + (\sqrt{2})^2} = \sqrt{2 + 2} = \sqrt{4} = 2
    • θ=arctan(22)=arctan(1)\theta = \arctan(\frac{\sqrt{2}}{-\sqrt{2}}) = \arctan(-1)
    • Since the point is in the second quadrant: θ=3π4\theta = \frac{3\pi}{4}
    • Polar coordinates: (2,3π4)(2, \frac{3\pi}{4})
  • 26. (1, -\sqrt{3})
    • r=12+(3)2=1+3=4=2r = \sqrt{1^2 + (-\sqrt{3})^2} = \sqrt{1 + 3} = \sqrt{4} = 2
    • θ=arctan(31)=arctan(3)\theta = \arctan(\frac{-\sqrt{3}}{1}) = \arctan(-\sqrt{3})
    • Since the point is in the fourth quadrant: θ=π3\theta = -\frac{\pi}{3}, equivalent to 5π3\frac{5\pi}{3}
    • Polar coordinates: (2,5π3)(2, \frac{5\pi}{3})
  • 27. (5, 0)
    • r=52+02=25=5r = \sqrt{5^2 + 0^2} = \sqrt{25} = 5
    • θ=arctan(05)=0\theta = \arctan(\frac{0}{5}) = 0
    • Polar coordinates: (5,0)(5, 0)

Polar to Rectangular Conversion

  • 28. (7,$\frac{5\pi}{6}$)
    • x=rcosθ=7cos(5π6)=7(32)=732x = r \cos \theta = 7 \cos(\frac{5\pi}{6}) = 7(-\frac{\sqrt{3}}{2}) = -\frac{7\sqrt{3}}{2}
    • y=rsinθ=7sin(5π6)=7(12)=72y = r \sin \theta = 7 \sin(\frac{5\pi}{6}) = 7(\frac{1}{2}) = \frac{7}{2}
    • Rectangular coordinates: (732,72)(- \frac{7\sqrt{3}}{2}, \frac{7}{2})
  • 29. (5,$\frac{11\pi}{6}$)
    • x=rcosθ=5cos(11π6)=5(32)=532x = r \cos \theta = 5 \cos(\frac{11\pi}{6}) = 5(\frac{\sqrt{3}}{2}) = \frac{5\sqrt{3}}{2}
    • y=rsinθ=5sin(11π6)=5(12)=52y = r \sin \theta = 5 \sin(\frac{11\pi}{6}) = 5(-\frac{1}{2}) = -\frac{5}{2}
    • Rectangular coordinates: (532,52)(\frac{5\sqrt{3}}{2}, -\frac{5}{2})
  • 30. (-3,$\pi$ )
    • x=rcosθ=3cos(π)=3(1)=3x = r \cos \theta = -3 \cos(\pi) = -3(-1) = 3
    • y=rsinθ=3sin(π)=3(0)=0y = r \sin \theta = -3 \sin(\pi) = -3(0) = 0
    • Rectangular coordinates: (3,0)(3, 0)

Calculator Conversions

  • 31a. (9, 31°)
    • x=9cos(31°)7.71x = 9 \cos(31°) \approx 7.71
    • y=9sin(31°)4.64y = 9 \sin(31°) \approx 4.64
    • Rectangular coordinates: (7.71,4.64)(7.71, 4.64)
  • 31b. (8, 173°)
    • x=8cos(173°)7.97x = 8 \cos(173°) \approx -7.97
    • y=8sin(173°)0.96y = 8 \sin(173°) \approx 0.96
    • Rectangular coordinates: (7.97,0.96)(-7.97, 0.96)

Calculator Conversions: Rectangular to Polar

  • 32a. (-2, -4)
    • r=(2)2+(4)2=204.47r = \sqrt{(-2)^2 + (-4)^2} = \sqrt{20} \approx 4.47
    • θ=arctan(42)=arctan(2)1.11\theta = \arctan(\frac{-4}{-2}) = \arctan(2) \approx 1.11
    • Since the point is in the third quadrant, add π\pi: θ1.11+π4.25\theta \approx 1.11 + \pi \approx 4.25
    • Polar coordinates: (4.47,4.25)(4.47, 4.25)
  • 32b. (4, 5)
    • r=42+52=416.40r = \sqrt{4^2 + 5^2} = \sqrt{41} \approx 6.40
    • θ=arctan(54)0.896\theta = \arctan(\frac{5}{4}) \approx 0.896
    • Polar coordinates: (6.40,0.90)(6.40, 0.90)

Graphing Polar Functions

  • 33. r=4sin(2θ)r = -4\sin(2\theta)
    • Create a table of values for θ\theta and r to plot the graph. Look for symmetry and critical points.
    • Show direction of the graph by indicating how r changes as θ\theta increases.
    • Label at least four values of θ\theta on the curve to show orientation.