Limiting Reactant Practice Notes

Pre-IB Chemistry Topic 1: Limiting Reactant Practice Notes

1. Phosphorus(V) Oxide and Water Reaction

  • Chemical Reaction:
      - The equation is given as:
        P4O10+6H2O<br>ightarrow4H3PO4P_4O_{10} + 6H_2O <br>ightarrow 4H_3PO_4

  • Problem Statement:
      - A student added 2.20 g of phosphorus(V) oxide (P4O10P_4O_{10}) to 2.00 g of water (H2OH_2O).

  • Goal: To calculate the mass of phosphoric acid (H3PO4H_3PO_4) produced.

2. Ammonia and Oxygen Reaction

  • Chemical Reaction:
      - The reaction is represented by:
        4NH3(g)+5O2(g)<br>ightarrow4NO(g)+6H2O(g)4NH_3(g) + 5O_2(g) <br>ightarrow 4NO(g) + 6H_2O(g)

  • Problem Statement:
      - A 2.00 g sample of ammonia (NH3NH_3) reacts with 4.00 g of oxygen.

  • Goal: To find out how much water (H2OH_2O) is produced, in dm³.

3. Sodium and Oxygen Reaction

  • Chemical Reaction:
      - Sodium reacts with oxygen to produce sodium oxide (Na2ONa_2O).

  • Problem Statement:
      - 5.00 g of sodium (NaNa) reacts with 5.00 g of oxygen (O2O_2).

  • Goal: To determine how many molecules of sodium oxide are produced.

4. Nitrogen and Hydrogen Reaction

  • Chemical Reaction:
      - The production of ammonia from nitrogen gas and hydrogen gas:

  • Problem Statement:
      - 50.0 g of nitrogen reacts with an excess of hydrogen.

  • Goal: To find how many dm³ of ammonia (NH3NH_3) are yielded.

5. Iron and Copper(IV) Sulfate Reaction

  • Chemical Reaction:
      - The reaction is as follows:
        2Fe(s)+Cu(SO4)2(aq)<br>ightarrow2FeSO4(aq)+Cu(s)2Fe (s) + Cu(SO_4)_2 (aq) <br>ightarrow 2FeSO_4 (aq) + Cu (s)

  • Problem Statement:
      - 3.26 g of iron powder (FeFe) are added to 0.016 mol of copper(IV) sulfate solution (Cu(SO4)2Cu(SO_4)_2).

  • Goal: To compute the maximum amount of copper (CuCu) produced, in grams.

6. Aluminium Sulfate and Calcium Hydroxide Reaction

  • Chemical Reaction:
      - The balanced equation is:
        Al2(SO4)3(aq)+3Ca(OH)2(aq)<br>ightarrow2Al(OH)3(g)+3CaSO4(s)Al_2(SO_4)_3(aq) + 3Ca(OH)_2(aq) <br>ightarrow 2Al(OH)_3(g) + 3CaSO_4(s)

  • Problem Statement:
      - 34.2 g of aluminium sulfate (Al2(SO4)3Al_2(SO_4)_3) reacts with 0.400 mol of calcium hydroxide (Ca(OH)2Ca(OH)_2).
      - Subsequently, several calculations need to be done on the reactants and products.

  • Sub-questions:
      - a) Determine how many moles of Al2(SO4)3Al_2(SO_4)_3 are present.
        - Options:
          A. 0.0500 mol
          B. 0.100 mol
          C. 0.150 mol
          D. 0.200 mol
      - b) How many moles of Ca(OH)2Ca(OH)_2 remain unreacted after the reaction goes to completion?
        - Options:
          A. 0.400 mol
          B. 0.300 mol
          C. 0.150 mol
          D. 0.100 mol
      - c) Determine the volume that aluminium hydroxide (Al(OH)3Al(OH)_3) can maximally occupy at standard conditions.
        - Options:
          A. 2.27 dm³
          B. 4.54 dm³
          C. 6.81 dm³
          D. 9.08 dm³

Important Concepts Related to Limiting Reactants

  • Limiting Reactant: The reactant that is completely consumed in a reaction, limiting the amount of product formed.

  • Excess Reactant: The reactant that remains when the reaction is complete.

  • Calculating Moles:
      - The number of moles can be calculated using the formula:
      extMoles=racextMass(g)extMolarMass(g/mol)ext{Moles} = rac{ ext{Mass (g)}}{ ext{Molar Mass (g/mol)}}

  • Determining Mass of Product:
      - To find the mass of the produced substance, use stoichiometry based on the balanced chemical equation.