Completing the Square Study Notes
Completing the Square: Detailed Study Notes
Concept Overview
- Completing the square is a method used in algebra to solve quadratic equations.
- A quadratic equation is any equation that can be rearranged in the standard form:
ax^2 + bx + c = 0
where:
- a is the coefficient of x^2
- b is the coefficient of x
- c is the constant term.
Steps to Complete the Square
- Start with the quadratic equation:
- Make sure it is in the standard form.
- Isolate the constant term ($ c $):
- Rearrange the equation to bring the constant term on the right side:
ax^2 + bx = -c
- Rearrange the equation to bring the constant term on the right side:
- Factor out the coefficient of x^2 ($ a $) from the left side:
- If a
eq 1 , factor it out:
a(x^2 + \frac{b}{a}x) = -c
- If a
- Complete the square:
- Take half of the coefficient of x , square it, and add it to both sides:
a \left(x^2 + \frac{b}{a}x + \left(\frac{b}{2a} \right)^2 \right) = -c + a\left(\frac{b}{2a}\right)^2
- Take half of the coefficient of x , square it, and add it to both sides:
- Rewrite the left side as a squared term:
- This can be written as:
a\left(x + \frac{b}{2a}\right)^2 = -c + \frac{b^2}{4a}
- This can be written as:
- Solve for x by taking the square root:
- Isolate the squared term and solve:
x + \frac{b}{2a} = \pm \sqrt{-c + \frac{b^2}{4a}} - Thus,
x = -\frac{b}{2a} \pm \sqrt{-c + \frac{b^2}{4a}}
- Isolate the squared term and solve:
Example Problems
Solve using the completing the square:
- Given Equation:
3x^2 - 2x - 6 = 0 - Step 1: Rearranging yields:
3x^2 - 2x = 6 - Step 2: Factor out the 3:
3(x^2 - \frac{2}{3}x) = 6 - Step 3: Completing the square involves calculating \left(\frac{-2/3}{2}\right)^2 = \left(\frac{-1/3}{2}\right)^2 = \frac{1}{36}
- Step 4: Add and subtract this value inside the brackets:
3\left(x^2 - \frac{2}{3}x + \frac{1}{36} - \frac{1}{36}\right) = 6 - Step 5: Simplifying gives:
3\left((x - \frac{1}{3})^2 - \frac{1}{36}\right) = 6 - Step 6: Introduce the constant correction:
3(x - \frac{1}{3})^2 - \frac{1}{12} = 6 - Step 7: Solving yields:
3(x - \frac{1}{3})^2 = 6 + \frac{1}{12} , followed by
(x - \frac{1}{3})^2 = \frac{73}{36} - Step 8: Combine and solve for x .
- Given Equation:
Second Example:
- Given Equation:
4x^2 + 3x - 7 = 0 - Proceed similarly as above, following outlined steps.
- Given Equation:
Third Example:
- Given Equation:
2x^2 - x - 12 = 0 - Again, follow similar procedures to isolate and complete the square.
- Given Equation:
Additional Notes
- The concept not only aids in solving equations but also helps in understanding the vertex form of a quadratic function:
y = a(x - h)^2 + k
where (h, k) is the vertex. - Applications include physics (projectile motion), economics (profit maximization), and any field dealing with parabolic trajectories.