Year 8 Unit 13: Sequences Study Guide

Unit Overview: Year 8 Unit 13 - Sequences

  • This unit covers the identification, description, and generation of various numerical and visual sequences.
  • Emphasis is placed on using different rules (term-to-term and position-to-term) and identifying specific types of progressions such as linear, geometric, quadratic, and Fibonacci.

Learning Outcomes

Support Level
  • Describe how a sequence continues: Identify the next numbers in a list based on an observed pattern.
  • Rules in words: Know how to express a rule for a sequence using verbal descriptions.
  • Term-to-term rules: Generate sequences when provided with a specific rule to get from one term to the next.
  • Diagram patterns: Describe patterns shown by diagrams or visual images.
  • Special sequences: Recognize and use sequences of triangular, square, and cube numbers.
Core Level
  • Generating from $n^{th}$ term: Know how to generate a sequence when the nthn^{th} term formula is given.
  • Diagram derivation: Generate simple sequences derived from visual patterns or diagrams.
  • Linear $n^{th}$ term: Find the nthn^{th} term formula for a linear (arithmetic) sequence.
Extension Level
  • Fibonacci-type sequences: Work with sequences where terms are found by adding previous terms.
  • Quadratic sequences: Know how to continue terms of a quadratic sequence.
  • Geometric progressions: Work out the value of a term in a geometrical progression of the form arn1ar^{n-1}, where nn is an integer >0> 0.

Reference Codes and Resources

  • Sparx Codes:   - M381   - U530   - M241   - M981   - M991   - U498   - U680   - M418   - U213
  • Corbett Maths Videos:   - Reference numbers: 286, 287, 287a, 288, 289, 290, 212, 226, 229, 388, 375.

Key Concepts and Definitions

  • Sequence: A list of numbers or items in a specific order.
  • $n^{th}$ term: A formula (position-to-term rule) that allows you to calculate the value of any term in a sequence based on its position nn.
  • Arithmetic or Linear Sequences: Sequences that increase or decrease by a common amount (a common difference) each time.
  • Geometric Series/Sequence: A sequence that has a common multiple (common ratio) between each term.
  • Quadratic Sequences: Sequences that include an n2n^2 term. These sequences have a common second difference.
  • Fibonacci Sequences: Sequences where you add the two previous terms to find the next term.

Arithmetic (Linear) Sequences

General Method for Geometric $n^{th}$ Term
  • Step 1: Find the common difference between terms.
  • Step 2: This difference becomes the coefficient of nn.
  • Step 3: Find the "0th0^{th}" term (the term that would come before the first term) to determine the constant in the formula.
Example 1: 1,8,15,22,1, 8, 15, 22, \dots
  • Common Difference: +7+7
  • $0^{th}$ Term: 17=61 - 7 = -6
  • Formula ($n^{th}$ term): 7n67n - 6
  • Finding the 50th50^{th} term:   - Substitute n=50n = 50   - 7(50)6=3506=3447(50) - 6 = 350 - 6 = 344
  • Verification: Is 120 in the sequence?   - Set up equation: 7n6=1207n - 6 = 120   - 7n=1267n = 126   - n=18n = 18   - Yes, as 1818 is an integer.
Example 2: 4,7,10,13,16,4, 7, 10, 13, 16, \dots
  • Common Difference: +3+3
  • $0^{th}$ Term: 43=+14 - 3 = +1
  • Formula ($n^{th}$ term): 3n+13n + 1
  • Verification: Is 100 in the sequence?   - 3n+1=1003n + 1 = 100   - 3n=993n = 99   - n=33n = 33   - Yes, as 3333 is an integer.
  • Finding the 100th100^{th} term:   - 3(100)+1=3013(100) + 1 = 301

Linear Sequences from Diagrams

Example: Matchstick Patterns
  • Method: Write down the number of matchsticks in each image to create a numeric sequence.
  • Pattern 1: 8 matchsticks
  • Pattern 2: 15 matchsticks
  • Pattern 3: 22 matchsticks
  • Sequence: 8,15,22,8, 15, 22, \dots
  • Difference: +7+7
  • $0^{th}$ term: 87=18 - 7 = 1
  • $n^{th}$ term: 7n+17n + 1

Geometric Sequences

Example sequence: 4,12,36,108,4, 12, 36, 108, \dots
  • Rule: Multiply by 3 each time (×3\times 3).
  • Common multiple: 3.

Quadratic Sequences

Example 1: Use n25n^2 - 5 to find the first 4 terms
  • Term 1 (n=1n=1): 125=41^2 - 5 = -4
  • Term 2 (n=2n=2): 225=12^2 - 5 = -1
  • Term 3 (n=3n=3): 325=43^2 - 5 = 4
  • Term 4 (n=4n=4): 425=114^2 - 5 = 11
  • Resulting Sequence: 4,1,4,11-4, -1, 4, 11
Example 2: Use n2+4n^2 + 4 to find the first 3 terms
  • Term 1 (n=1n=1): 12+4=51^2 + 4 = 5
  • Term 2 (n=2n=2): 22+4=82^2 + 4 = 8
  • Term 3 (n=3n=3): 32+4=133^2 + 4 = 13
  • Resulting Sequence: 5,8,135, 8, 13