Continuity and Differentiability

Introduction to Continuity and Differentiability

  • Philosophical Context: Albert Einstein stated, "The whole of science is nothing more than a refinement of everyday thinking."

  • Historical Figure: Sir Isaac Newton (1642-1727) is a central figure in the development of these mathematical concepts.

  • Chapter Scope: This study guide covers the continuation of polynomial and trigonometric differentiation from Class XI, introducing:   - Continuity and Differentiability and the relations between them.   - Differentiation of inverse trigonometric functions.   - Exponential functions and logarithmic functions.   - Powerful differentiation techniques and fundamental theorems illustrated through differential calculus.

The Concept of Continuity

  • Informal Understanding: Naively, a function is continuous at a fixed point if the graph of the function around that point can be drawn without lifting the pen from the paper.

  • Introductory Instance of Discontinuity (Example 1): Consider f(x)f(x) defined as:   - f(x)=1f(x) = 1 if x0x \leq 0   - f(x)=2f(x) = 2 if x > 0   - Analysis shows that at points to the left of 00 (e.g., 0.1,0.01-0.1, -0.01), the value is 11. At points to the right (e.g., 0.1,0.010.1, 0.01), the value is 22. The left hand limit (11) and right hand limit (22) do not coincide, making the function discontinuous at x=0x = 0.

  • Introductory Instance of Discontinuity (Example 2): Consider f(x)f(x) defined as:   - f(x)=1f(x) = 1 if x0x \neq 0   - f(x)=2f(x) = 2 if x=0x = 0   - Here, the left and right hand limits both equal 11, but the value of the function at x=0x = 0 is 22. Since the limit does not coincide with the function value, it is discontinuous.

  • Mathematical Definition (Definition 1): Suppose ff is a real function on a subset of the real numbers and let cc be a point in the domain of ff. Then ff is continuous at cc if:   - limxcf(x)=f(c)\lim_{x \to c} f(x) = f(c)   - Elaborately: The left hand limit (LHL), right hand limit (RHL), and the function value at x=cx = c must exist and be equal to each other.

  • Discontinuity: If ff is not continuous at cc, it is said to be discontinuous at cc, and cc is called a point of discontinuity of ff.

Analytical Examples of Continuity

  • Example 1: Polynomial at a Point: Check f(x)=2x+3f(x) = 2x + 3 at x=1x = 1.   - Value: f(1)=2(1)+3=5f(1) = 2(1) + 3 = 5.   - Limit: limx1(2x+3)=5\lim_{x \to 1} (2x + 3) = 5.   - Conclusion: Continuous at x=1x = 1.

  • Example 2: Square Function: Examine f(x)=x2f(x) = x^2 at x=0x = 0.   - Value: f(0)=0f(0) = 0.   - Limit: limx0x2=0\lim_{x \to 0} x^2 = 0.   - Conclusion: Continuous at x=0x = 0.

  • Example 3: Modulus Function: Discuss f(x)=xf(x) = |x| at x=0x = 0.   - Defined as: f(x)=xf(x) = -x if x < 0 and f(x)=xf(x) = x if x0x \geq 0.   - LHL: limx0(x)=0\lim_{x \to 0^-} (-x) = 0.   - RHL: limx0+x=0\lim_{x \to 0^+} x = 0.   - Value: f(0)=0f(0) = 0.   - Conclusion: Continuous at x=0x = 0.

  • Example 4: Pointwise Discontinuity: f(x)=x3+3f(x) = x^3 + 3 if x0x \neq 0 and f(x)=1f(x) = 1 if x=0x = 0.   - Limit as x0x \to 0 is 03+3=30^3 + 3 = 3.   - Value is 11.   - Conclusion: Not continuous because 313 \neq 1.

  • Example 5: Constant Function: f(x)=kf(x) = k is continuous at every real number cc because limxck=k=f(c)\lim_{x \to c} k = k = f(c).

  • Example 6: Identity Function: f(x)=xf(x) = x is continuous at every real number cc because limxcx=c=f(c)\lim_{x \to c} x = c = f(c).

Continuity in Domains and Intervals

  • Definition 2: A real function ff is continuous if it is continuous at every point in its domain.

  • Continuity on a Closed Interval [a, b]: For ff to be continuous on [a,b][a, b], it must be continuous at every point in (a,b)(a, b), and:   - limxa+f(x)=f(a)\lim_{x \to a^+} f(x) = f(a)   - limxbf(x)=f(b)\lim_{x \to b^-} f(x) = f(b)

  • Singleton Domain: If the domain of ff is a single point, it is continuous there by definition.

  • Polynomial Continuity (Example 14): Every polynomial function defined by p(x)=a0+a1x++anxnp(x) = a_0 + a_1 x + \dots + a_n x^n is continuous at every real number cc in its domain.

  • Reciprocal Function (Example 9): f(x)=1x,x0f(x) = \frac{1}{x}, x \neq 0 is continuous at every point in its domain. To prove this, for any non-zero constant cc:   - limxc1x=1c=f(c)\lim_{x \to c} \frac{1}{x} = \frac{1}{c} = f(c).

Analysis of Limits and Infinity

  • Concept of Infinity: Analyzed via f(x)=1xf(x) = \frac{1}{x} near x=0x = 0.

  • Right Hand Limit (Table 5.1): As xx approaches 00 from the right:   - Values: 11,0.110,0.01100,10n10n1 \to 1, 0.1 \to 10, 0.01 \to 100, 10^{-n} \to 10^n.   - Notation: limx0+f(x)=+\lim_{x \to 0^+} f(x) = +\infty.

  • Left Hand Limit (Table 5.2): As xx approaches 00 from the left:   - Values: 11,0.110,0.01100,10n10n-1 \to -1, -0.1 \to -10, -0.01 \to -100, -10^{-n} \to -10^n.   - Notation: limx0f(x)=\lim_{x \to 0^-} f(x) = -\infty.

  • Key Distinction: Neither ++\infty nor -\infty are real numbers; therefore, these limits do not exist in the context of real number continuity.

Greatest Integer Function Discontinuity

  • Definition: f(x)=[x]f(x) = [x] denotes the greatest integer less than or equal to xx.

  • Case 1: Non-integral points: For any real number cc that is not an integer, the limit as xcx \to c equals [c][c], matching the function value. It is continuous at these points.

  • Case 2: Integral points: Let cc be an integer and r > 0 be small.   - [cr]=c1[c - r] = c - 1   - [c+r]=c[c + r] = c   - LHL: limxcf(x)=c1\lim_{x \to c^-} f(x) = c - 1.   - RHL: limxc+f(x)=c\lim_{x \to c^+} f(x) = c.   - Conclusion: Since c1cc - 1 \neq c, the function is discontinuous at every integral point.

Algebra of Continuous Functions

  • Theorem 1: Suppose ff and gg are real functions continuous at a real number cc. Then:   1. (f+g)(f + g) is continuous at x=cx = c.   2. (fg)(f - g) is continuous at x=cx = c.   3. (fg)(f \cdot g) is continuous at x=cx = c.   4. (fg)(\frac{f}{g}) is continuous at x=cx = c, provided g(c)0g(c) \neq 0.

  • Rational Functions (Example 16): Since polynomial functions are continuous, rational functions defined by f(x)=p(x)q(x)f(x) = \frac{p(x)}{q(x)} (where q(x)0q(x) \neq 0) are continuous at every point in their domain.

  • Continuity of Sine (Example 17): Uses the fact limx0sin(x)=0\lim_{x \to 0} \sin(x) = 0.   - Proof: Let x=c+hx = c + h. As xc,h0x \to c, h \to 0.   - limh0sin(c+h)=limh0(sin(c)cos(h)+cos(c)sin(h))=sin(c)(1)+cos(c)(0)=sin(c)\lim_{h \to 0} \sin(c + h) = \lim_{h \to 0} (\sin(c)\cos(h) + \cos(c)\sin(h)) = \sin(c)(1) + \cos(c)(0) = \sin(c).

  • Continuity of Tangent (Example 18): tan(x)=sin(x)cos(x)\tan(x) = \frac{\sin(x)}{\cos(x)}. Being a quotient of two continuous functions, it is continuous wherever cos(x)0\cos(x) \neq 0 (i.e., x(2n+1)π2x \neq (2n + 1)\frac{\pi}{2}).

  • Composite Function Continuity (Theorem 2): If gg is continuous at cc and ff is continuous at g(c)g(c), then the composite function (fg)(f \circ g) is continuous at cc.   - Example: f(x)=sin(x2)f(x) = \sin(x^2) is continuous as a composition of g(x)=sin(x)g(x) = \sin(x) and h(x)=x2h(x) = x^2.   - Example: f(x)=1x+xf(x) = |1 - x + |x|| is continuous as a composition of absolute value and polynomial/modulus sums.

The Basics of Differentiability

  • Definition: The derivative of ff at point cc is defined by:   - f(c)=limh0f(c+h)f(c)hf'(c) = \lim_{h \to 0} \frac{f(c + h) - f(c)}{h}

  • Notation: Denoted as f(x)f'(x), ddx(f(x))\frac{d}{dx}(f(x)), or yy' (if y=f(x)y = f(x)).

  • Algebra of Derivatives Review:   1. (u±v)=u±v(u \pm v)' = u' \pm v'   2. (uv)=uv+uv(uv)' = u'v + uv' (Leibnitz or Product Rule)   3. (uv)=uvuvv2(\frac{u}{v})' = \frac{u'v - uv'}{v^2}, where v0v \neq 0 (Quotient Rule)

  • Standard Derivatives (Table 5.3):   - ddx(xn)=nxn1\frac{d}{dx}(x^n) = nx^{n-1}   - ddx(sin(x))=cos(x)\frac{d}{dx}(\sin(x)) = \cos(x)   - ddx(cos(x))=sin(x)\frac{d}{dx}(\cos(x)) = -\sin(x)   - ddx(tan(x))=sec2(x)\frac{d}{dx}(\tan(x)) = \sec^2(x)

  • Requirement for Existence: A function is differentiable at cc if both the left hand derivative and right hand derivative are finite and equal.

Relation between Continuity and Differentiability

  • Theorem 3: If a function ff is differentiable at a point cc, then it is also continuous at that point.

  • Proof:   - Since ff is differentiable at cc, limxcf(x)f(c)xc=f(c)\lim_{x \to c} \frac{f(x) - f(c)}{x - c} = f'(c).   - For xcx \neq c, f(x)f(c)=(f(x)f(c)xc)(xc)f(x) - f(c) = \left(\frac{f(x) - f(c)}{x - c}\right)(x - c).   - limxc[f(x)f(c)]=limxc[f(x)f(c)xc]limxc[xc]=f(c)0=0\lim_{x \to c} [f(x) - f(c)] = \lim_{x \to c} \left[\frac{f(x) - f(c)}{x - c}\right] \cdot \lim_{x \to c} [x - c] = f'(c) \cdot 0 = 0.   - Hence, limxcf(x)=f(c)\lim_{x \to c} f(x) = f(c).

  • Important Caveat: The converse is not true. Every differentiable function is continuous, but not every continuous function is differentiable.

  • Counter-example: f(x) = |x| at x = 0:   - Left hand limit of derivative: limh00+h0h=limh0hh=1\lim_{h \to 0^-} \frac{|0+h| - 0}{h} = \lim_{h \to 0^-} \frac{-h}{h} = -1.   - Right hand limit of derivative: limh0+h0h=1\lim_{h \to 0^+} \frac{h-0}{h} = 1.   - Since 11-1 \neq 1, x|x| is not differentiable at 00, despite being continuous.

The Chain Rule

  • Definition (Theorem 4): If f=vuf = v \circ u, and t=u(x)t = u(x), then:   - dfdx=dvdtdtdx\frac{df}{dx} = \frac{dv}{dt} \cdot \frac{dt}{dx}

  • Extended Chain Rule: For f=(wu)vf = (w \circ u) \circ v, where t=v(x)t = v(x) and s=u(t)s = u(t), then:   - dfdx=dwdsdsdtdtdx\frac{df}{dx} = \frac{dw}{ds} \cdot \frac{ds}{dt} \cdot \frac{dt}{dx}

  • Implicit Functions Differentiation: When xyπ=0x - y - \pi = 0, we can re-evaluate as y=xπy = x - \pi. However, in forms like y+sin(y)=cos(x)y + \sin(y) = \cos(x), we differentiate directly with respect to xx using the chain rule on the variable yy.   - Example: For y+sin(y)=cos(x)y + \sin(y) = \cos(x), differentiation yields:     - dydx+cos(y)dydx=sin(x)\frac{dy}{dx} + \cos(y)\frac{dy}{dx} = -\sin(x)     - dydx=sin(x)1+cos(y)\frac{dy}{dx} = \frac{-\sin(x)}{1 + \cos(y)} where y(2n+1)πy \neq (2n+1)\pi.

Derivatives of Inverse Trigonometric Functions

  • General Identity: Derivatives are found assuming they exist and applying the chain rule.

  • Derivation for sin⁻¹ x:   - Let y=sin1(x)y = \sin^{-1}(x), so x=sin(y)x = \sin(y).   - Differentiating w.r.t. xx: 1=cos(y)dydx1 = \cos(y)\frac{dy}{dx}.   - dydx=1cos(y)=11sin2(y)=11x2\frac{dy}{dx} = \frac{1}{\cos(y)} = \frac{1}{\sqrt{1-\sin^2(y)}} = \frac{1}{\sqrt{1-x^2}}.   - Defined for x(1,1)x \in (-1, 1).

  • Derivative Table:   - ddx(sin1(x))=11x2\frac{d}{dx}(\sin^{-1}(x)) = \frac{1}{\sqrt{1-x^2}} for domain (1,1)(-1, 1).   - ddx(cos1(x))=11x2\frac{d}{dx}(\cos^{-1}(x)) = -\frac{1}{\sqrt{1-x^2}} for domain (1,1)(-1, 1).   - ddx(tan1(x))=11+x2\frac{d}{dx}(\tan^{-1}(x)) = \frac{1}{1+x^2} for domain R\mathbb{R}.

Exponential and Logarithmic Functions

  • Growth Rate Discussion: Polynomial functions grow based on their degree (x15x^{15} grows faster than x10x^{10}). However, exponential functions like 10x10^x grow faster than any polynomial function xnx^n.   - Evidence: If x=103x = 10^3, x100=10300x^{100} = 10^{300}, while 10x=10100010^x = 10^{1000}.

  • Definition 3 (Exponential): The exponential function with base b > 1 is y=bxy = b^x.   - Features: Domain is R\mathbb{R}, range is R+\mathbb{R}^+, passes through (0,1)(0, 1), ever increasing.   - Natural Exponential: Using the series sum 1+11!+12!+=e1 + \frac{1}{1!} + \frac{1}{2!} + \dots = e (approx 2.7182.718). The function is y=exy = e^x.

  • Definition 4 (Logarithm): logb(a)=x\log_b(a) = x if bx=ab^x = a.   - Common Logarithm: Base 1010.   - Natural Logarithm: Base ee, denoted as ln\ln or log\log.   - Features: Domain is R+\mathbb{R}^+, range is R\mathbb{R}, passes through (1,0)(1, 0), ever increasing.

  • Logarithmic Properties:   1. Change of Base: loga(p)=logb(p)logb(a)\log_a(p) = \frac{\log_b(p)}{\log_b(a)}.   2. Product Rule: logb(pq)=logb(p)+logb(q)\log_b(pq) = \log_b(p) + \log_b(q).   3. Power Rule: logb(pn)=nlogb(p)\log_b(p^n) = n\log_b(p).   4. Quotient Rule: logb(xy)=logb(x)logb(y)\log_b(\frac{x}{y}) = \log_b(x) - \log_b(y).   5. Inversion: x=elog(x)x = e^{\log(x)} for x > 0.

  • Theorems of Differentiation (Theorem 5):   - ddx(ex)=ex\frac{d}{dx}(e^x) = e^x   - ddx(log(x))=1x\frac{d}{dx}(\log(x)) = \frac{1}{x}

Logarithmic Differentiation

  • Purpose: Used for functions of the form y=[u(x)]v(x)y = [u(x)]^{v(x)}. Both functions must be positive.

  • Process:   1. Take log on both sides: log(y)=v(x)log(u(x))\log(y) = v(x)\log(u(x)).   2. Differentiate implicitly using chain and product rules: 1ydydx=v(x)u(x)u(x)+v(x)log(u(x))\frac{1}{y}\frac{dy}{dx} = v(x)\frac{u'(x)}{u(x)} + v'(x)\log(u(x)).   3. Multiply by yy to get the final derivative.

  • Example (Example 28): Differentiate axa^x.   - log(y)=xlog(a)\log(y) = x\log(a).   - 1ydydx=log(a)\frac{1}{y}\frac{dy}{dx} = \log(a).   - dydx=axlog(a)\frac{dy}{dx} = a^x\log(a).

Parametric Forms and Second Order Derivatives

  • Parametric Form: When x=f(t)x = f(t) and y=g(t)y = g(t), where tt is the parameter.   - dydx=dydtdxdt\frac{dy}{dx} = \frac{\frac{dy}{dt}}{\frac{dx}{dt}}, provided dxdt0\frac{dx}{dt} \neq 0.

  • Example (Example 32): Find dydx\frac{dy}{dx} if x=at2,y=2atx = at^2, y = 2at.   - dxdt=2at\frac{dx}{dt} = 2at, dydt=2a\frac{dy}{dt} = 2a.   - dydx=2a2at=1t\frac{dy}{dx} = \frac{2a}{2at} = \frac{1}{t}.

  • Second Order Derivative: Denoted by d2ydx2\frac{d^2y}{dx^2} or f(x)f''(x) or y2y_2.   - Defined as ddx(dydx)\frac{d}{dx}(\frac{dy}{dx}).

  • Higher Order Derivatives: Defined by repeating the differentiation process sequentially.

  • Example (Example 35): Find d2ydx2\frac{d^2y}{dx^2} if y=x3+tan(x)y = x^3 + \tan(x).   - dydx=3x2+sec2(x)\frac{dy}{dx} = 3x^2 + \sec^2(x).   - d2ydx2=6x+2sec(x)sec(x)tan(x)=6x+2sec2(x)tan(x)\frac{d^2y}{dx^2} = 6x + 2\sec(x) \cdot \sec(x)\tan(x) = 6x + 2\sec^2(x)\tan(x).

Summary of Principles

  • Continuity: A function is continuous if the limit equals the function value at a point. Sums, differences, products, and quotients of continuous functions remain continuous.

  • Differentiability: Implies continuity, but not vice versa. Standard differentiation rules (Product, Quotient, Chain) apply.

  • Inverse Trig: Derivatives involve algebraic expressions (e.g., 11+x2\frac{1}{1+x^2} for tan1(x)\tan^{-1}(x)).

  • Exponentials/Logs: exe^x is invariant under differentiation; log(x)\log(x) differentiates to its reciprocal 1/x1/x.

  • Parametrics: Differentiation involves ratios of derivatives of the parameter.