Study Notes on McNemar's Test for Paired Proportions
FMPH 102: Biostatistics in Public Health
Comparing Paired Proportions
Overview of Continuous and Binary Variables
Inference for Means
One Sample
Two Independent Samples
Two Paired Samples
Inference for Proportions
One Sample
Two Independent Samples
Two Paired Samples
Binary Variables and Paired Samples
Focus on Binary Variable: Two Paired Samples
Binary Variables: Conduct exact binomial test using SPSS.
Paired Proportions: Implement the McNemar test.
Paired Samples Designs for Binary Outcomes
Variety of Designs: Paired samples occur in various designs including:
Pre-post Test Study Design: Notable for lacking a control group.
Two Treatments for Same Subject: Examples include:
Skin cancer examined on left vs. right arm of drivers.
Heart disease comparison in smoking vs. non-smoking twins.
Crossover Design: Participants receive both treatments successively.
Paired-Match Case-Control Studies: Each case matches with a similar control individually.
McNemar's Test
Application Context
Applicable to 2x2 contingency tables with matched pairs to analyze marginal frequencies.
McNemar's Test: A statistical method for paired binary data.
Example: Sexual Behaviors in Botswana Military
Study Details
Sample Size: n=161 (Dataset: Botswana.sav).
Reported Behaviors: Comparison of sexual behavior via diary vs. survey recordings.
Outcomes Evaluated:
Sexual relations with spouse: Yes/No
Sexual relations with others: Yes/No
Data Collection:
Participants reported sexual behavior within two weeks through:
Sample 1 (Diary): 13/161 reported having sex.
Sample 2 (Survey): 6/161 reported having sex.
Note: Sample 1 and Sample 2 consist of the same individuals.
Hypotheses:
Null Hypothesis (H0): $p{Diary} = p{Survey}$ (same proportion across instruments).
Alternative Hypothesis (Ha): $p{Diary} \neq p{Survey}$.
Sample Estimates Calculation:
$\hat{p}_1 = \frac{13}{161} \approx 0.081$
$\hat{p}_2 = \frac{6}{161} \approx 0.037$
Constructing the Data Table
Survey (Retrospective) | Total | ||
|---|---|---|---|
No | Yes | ||
Diary (Prospective) | |||
No | 146 | 2 | 148 |
Yes | 9 | 4 | 13 |
Total | 155 | 6 | 161 |
Notes on Table Structure:
Distinct from 2x2 tables for Independent Samples Test.
The counts here represent paired data.
Structure of McNemar’s Test for Paired Proportions
Cross-tabulated Counts:
Variables: a, b, c, d where:
Concordant Pairs (values at a, d):
(No/No) and (Yes/Yes)
Discordant Pairs (values at b, c):
(No/Yes) and (Yes/No)
Table Configuration:
2nd Sample | |||
|---|---|---|---|
No | Yes | ||
1st Sample | |||
No | a | b | |
Yes | c | d |
Statistical Focus of McNemar’s Test:
Focus on Discordant Pairs (Why?)
Formulas for proportions:
$P_1 = \frac{c+d}{a+b+c+d}$
$P_2 = \frac{b+d}{a+b+c+d}$
Hypothesis simplification:
Null Hypothesis (H0): $P1 = P2 \implies \frac{c+d}{a+b+c+d} = \frac{b+d}{a+b+c+d}$. This simplifies to:
Only considering c and b in discordant pairs for statistical significance.
McNemar Test Statistics and Calculations
McNemar Test Statistic (without continuity correction):
$z_M = \frac{b - c}{b + c}$
McNemar Test Statistic (with continuity correction):
Recommended Method:
$z_{M,c} = \frac{b - c - 1}{b + c}$This approach uses continuous distributions to approximate discrete outcomes.
Example: Calculation from Botswana Dataset
Applying Continuity Correction:
For the Botswana dataset:
$z_{M,c} = \frac{|2-9|-1}{\sqrt{9+2}} = \frac{6}{\sqrt{11}} \approx 1.81$
Interpretation:
Results indicate the construction of the null hypothesis and the application of the continuity corrected test.
The Plan for Conducting McNemar’s Test
Calculate McNemar’s test statistic using the continuity correction.
State hypothesis:
$H0: pc = pb, z{M,c} \sim Normal(0,1)$
P-value:
Derived from the standard normal distribution table.
Example Result Analysis
For the Botswana data:
$z_{M,c} = 1.81$
P-value determined through lookup: 0.070.
Conclusion: No significant difference between survey instruments.
Importance of the Continuity Correction
Case Analysis:
Using continuity correction gives $z_{M,c} = 1.81$ with p-value 0.070.
Without correction, $z_M = \frac{7}{\sqrt{11}} = 2.11$, leading to a false significance with p-value = 0.035.
Statistical Analysis Using SPSS for Botswana Dataset
Data Structure: Load Botswana.sav.
Use: Analyze > Descriptive Statistics > Crosstabs.
Set up:
Columns: Survey, Rows: Diary
Count cases by outcome pairs.
Applying McNemar’s Test in SPSS
Execution Steps:
Navigate to Analyze > Descriptive Statistics > Crosstabs.
Under
Statistics, select McNemar for the paired test.Interpret results from the output for p-value (Exact Sig. in SPSS).
Example Output:
P-value = 0.065 leading to the conclusion of no significant difference based on survey instruments.
Cannabis Crossover Study Overview
Study Design:
Investigated the effects of smoked medicinal cannabis on HIV-related neuropathic pain.
Participants: n=28, randomized crossover study design comparing cannabis with placebo.
Key Measures:
Evaluated side effects: used McNemar’s test to analyze occurrences of side effects during cannabis vs. placebo weeks.
Example Comparison: Elevated heart rate observed; test statistics determined as:
$z_{M,c} = \frac{(13-1-1)}{\sqrt{(13+1)}} = \frac{11}{\sqrt{14}} \approx 2.94$, yielding a significant p-value of 0.003.
Statistical Analysis Using SPSS for Cannabis Crossover Study
Create dataset in SPSS:
Input columns for: cannabis, placebo, count on the dataset.
Statistical evaluation followed with weight cases and appropriate statistical tests for McNemar.
Key Ideas on McNemar’s Test
Tests aimed at H0: $pc = pb$ by focusing on discordant cells.
Total number of discordant pairs (b+c) becomes pivotal for analysis.
Designs of McNemar test statistics correlate to one-sample hypothesis tests making it applicable for binary outcome evaluations such as the cannabis study.
Conclusion
Importance of using continuity corrections where inherent bias can cause misinterpretation in results.
Correct statistical approaches such as McNemar’s test remain vital in evaluating health behaviors and treatment outcomes.