2 - solubility product

Solubility Equilibria

Review of Solubility Concepts

  • Solvent: The substance in which a solute dissolves.

  • Solute: The substance that is dissolved in a solvent.

  • Solution: A homogeneous mixture of solvent and solute.

  • Saturated: A solution that cannot dissolve any more solute at a given temperature.

  • Unsaturated: A solution that can still dissolve more solute.

  • Supersaturated: A solution that holds more dissolved solute than is required to reach equilibrium.

  • Solubility Curve: A graph that shows the relationship between solubility and temperature.

  • Solubility: The ability of a substance to dissolve in a solvent at a given temperature.

  • Dissociation: The separation of ions that occurs when an ionic compound dissolves.

  • Precipitation: The formation of a solid (precipitate) during a chemical reaction in a solution.

  • Ionization: The process of forming ions from neutral atoms or molecules.

  • Net Ionic Equation: A chemical equation that shows only the particles that participate in a reaction.

  • Solubility Chart: A chart that lists the solubility of various substances in specific solvents.

  • Factors Affecting Solubility: Include temperature, pressure, and the nature of solute and solvent.

Solubility Product (Ksp)

  • When a small amount of a salt (solute), AxBy, is placed in water (solvent):

    • It may dissolve completely, liberating ions Ay+ and Bx- into the solution.

  • Saturated Solutions: Once no more solute can dissolve despite being in contact with the solvent, the solution is saturated.

  • Dynamic Equilibrium: At saturation, the system reaches dynamic equilibrium where the rate of dissolving equals the rate of precipitation.

Rate of Dissolving vs. Precipitation

  • Rate of dissolving (Rdiss) and rate of precipitation (Rppt) can be represented as:

    • Rdiss: NaCl(s) ⇌ Na+(aq) + Cl-(aq)

    • The solution is in equilibrium when Rdiss = Rppt.

    • Initially, salt dissolves faster than its ions precipitate, causing a net movement toward dissolution.

Equilibrium Constant Expression

  • General representation:

    • AxBy(s) ⇋ xAy+(aq) + yBx-(aq)

  • Equilibrium Constant:

    [ K_{eq} = \frac{[Ay^+]^x[Bx^-]^y}{[AxBy]} ]

  • Since the concentration of pure solid salt is constant, it leads to modified equilibrium constant:

    • [ K_{eq} \cdot [AxBy] = K_{sp} = [Ay^+]^x[Bx^-]^y ]

  • Ksp is known as the solubility product.

Constants in Saturated Solutions

  • For saturated solutions at equilibrium:

    • The product of the ion concentrations, each raised to their respective coefficients, is constant and termed Ksp.

  • All solubility equilibrium equations represent the dissolution of ionic solids into their ions.

  • Even after reaching equilibrium, dissolving and precipitation processes continue dynamically.

Example: Writing Ksp Expressions

  1. CaCl2(s)Ca2+(aq) + 2Cl-(aq)

    • Ksp = [Ca2+][Cl−]²

  2. Ca3(PO4)2(s)3Ca2+(aq) + 2PO4³-(aq)

    • Ksp = [Ca2+]³[PO4³−]²

Factors Affecting Ksp

  • Ksp is dependent on the solubility of the salt:

    • Higher solubility leads to higher Ksp values.

  • Temperature Impact: As temperature increases, solubility generally increases, thus affecting Ksp.

    • According to Le Chatelier’s Principle, increasing temperature shifts equilibrium in the endothermic direction.

Factors Not Affecting Ksp

  • Adding or removing solid ionic substances does not affect equilibrium or Ksp since solid concentration is constant.

  • Changes in solution volume (addition of water or evaporation) change ion concentration but not Ksp.

Limitations of Ksp

  • Ksp values are reliable only for sparingly soluble salts:

    • Ions should not exceed 0.001 mol/L for valid Ksp values.

  • At higher solubility levels, Ksp may no longer remain constant.

  • Some salts dissolve through multiple steps, each with its own equilibrium constant.

  • If ions react with water post-dissolution (hydrolysis), Ksp calculations may become unreliable.

Calculating Ksp from Solubility Example #2

  • Calculating the concentrations and Ksp for calcium hydroxide with a solubility of 0.012 mol/L:

    • Determine [Ca2+] and [OH-].

Example #3: Calcium Phosphate

  • Solubility given as 2.21 x 10⁻⁴ g/L:

    • Calculate the molar concentrations of calcium ions ([Ca2+]) and phosphate ions ([PO4³-]).

Example #4: Lead(IV) Iodide

  • Given solubility is 0.85 g/100 mL, calculate Ksp = 6.1 x 10⁻⁹.

Calculating Solubility from Ksp

  • Solubility calculated in g/100 mL or g/L, but molar solubility is preferred for Ksp calculations.

    • Let molar solubility of salt = ‘s’ mol/L.

  • Example #5: Calculate molar solubilities for CuCO3 (Ksp = 2.5 x 10⁻¹⁰) and Ag2SO4 (Ksp = 1.7 x 10⁻⁵).

Example #6: Determining Ion Concentration

  • If the equilibrium constant for dissolving lead(II) iodide is 8.5 x 10⁻⁹, calculate the ion concentrations at equilibrium, where s = 1.3 x 10⁻³ mol/L.