biology 2

What is Biology?

  • Biology is the science of how life works.
  • We understand life from multiple levels:
    • Molecular mechanisms within the cell
    • Integrated actions of cells within an organ or individual
    • Interactions among different organisms in nature
  • Reference: Ch. 1.1

The Scientific Approach in Biology

  • There is no single, stepwise pathway to new knowledge about the world.
  • To understand biology, we need to understand what science is (Ch. 1.1).
  • Observations lead to questions, which lead to hypotheses.
  • Hypothesis: a tentative explanation or educated guess that makes testable predictions (Ch. 1.1).
  • Predictions from predictions can be tested through experiments.
  • Design and conduct experiments to test hypotheses.
  • Based on results, we can support or not support a hypothesis; we cannot prove it correct/incorrect.

Hypothesis vs Theory

  • A hypothesis is a testable tentative explanation (correct option: B).
  • In everyday language, "theory" is often used like a guess, but in science:
    • A theory is supported by many hypotheses that have withstood testing and come from a large body of evidence.
    • A theory explains a broad array of natural phenomena and can generate many hypotheses.
    • A good theory also generates predictions that can be tested.
  • Examples of theories (Ch. 1.1):
    • Theory of evolution by natural selection
    • Cell theory
    • Atomic theory
    • Big Bang theory
    • Theory of Quantum Mechanics
    • Theory of Relativity
    • Theory of Plate Tectonics

Evolution: Pattern and Process

  • Biological systems are dynamic and change over time.
    • Changes can occur within individuals over their lifetimes or in populations over generations.
  • Evolution = descent with modification: organisms descend from others, and over generations accumulate unique traits.
  • Understanding evolution requires genetics and phenotype concepts (Ch. 1.4, 20.3).
  • Important distinction:
    • The pattern of evolution is observable (not a theory).
    • The process that explains the pattern is a theory (e.g., natural selection as mechanism).
  • Reference: Evolution by natural selection is a theory for the mechanism driving evolutionary patterns.

Genes, Alleles, Genotypes, and Phenotypes

  • Genes are the units of heredity; they exist as DNA sequences and code for traits (phenotypes).
  • Alleles are genetic variants resulting from differences in DNA sequence.
  • In diploid organisms, we have more than one allele per gene; all alleles for a phenotype constitute an individual’s genotype.
  • Genotype: the specific alleles present in an individual for a given gene.
  • Phenotype: the expressed trait resulting from the genotype and environmental influence.

Key Genetic Concepts (Review Questions)

  • Genes: choose all that apply
    • A) Are only found in gametes — False
    • B) Can be passed down from parents to offspring — True
    • C) Are comprised of DNA sequences — True
    • D) Always produce identical proteins — False
    • E) Always found in a particular location on a chromosome — Generally True (locus is defined)
    • Correct: B, C, E
  • Alleles: choose all that apply
    • A) Are variants of a gene — True
    • B) Can be passed down from parents to offspring — True
    • C) Are comprised of DNA sequences — True
    • D) Always produce identical proteins — False
    • E) Always found in a particular location on a chromosome — True
    • Correct: A, B, C, E
  • A genotype is…
    • A) all the alleles in a population — False (gene pool)
    • B) all the genes of a chromosome — False
    • C) An individual’s set of alleles — True
    • D) An individual’s trait — False
    • E) The entire genome — False
    • Correct: C
  • A phenotype is…
    • A) all the alleles in a population — False
    • B) influenced by the environment and DNA — True
    • C) An individual’s set of alleles — False
    • D) An individual’s trait — True
    • E) The entire genome — False
    • Correct: B, D

DNA, Alleles, and Variation

  • All organisms possess DNA, which stores and transmits information.
  • DNA stores genetic material; some DNA segments code for phenotypes (genes).
  • Alleles are variant forms of a gene.
  • Expression of genes is regulated and influenced by the environment.
  • References: Ch. 1.3; Ch. 13.1; Ch. 1.3 (BIOL1107)

Alleles and Genotypes: Examples

  • Alleles: genetic variants from DNA sequence differences.
  • In diploids, two alleles per gene (for a given phenotype) can be present; all alleles for a phenotype form the genotype.
  • Dominant vs Recessive examples (conceptual):
    • Dominant allele (B) masks recessive (b) in phenotype when present in at least one copy.
    • Genotypes: BB (homozygous dominant), Bb (heterozygous), bb (homozygous recessive).
  • Example: Purple (dominant) vs White (recessive) flower trait.

Beta Hemoglobin and Sickle Cell Example

  • S allele (sickle cell) and A allele (wild-type) on chromosome 11 (beta hemoglobin gene).
  • Genotypes: AA (wild-type, no sickling), AS (sickle cell trait), SS (sickle cell disease).
  • Phenotypes: AA = normal; AS = trait; SS = disease.
  • Reference: Ch. 13.1; Ch. 20.4

Mutation and Recombination: Sources of Variation

  • Mutation: changes to the DNA sequence; ultimate source of new alleles.
  • Mutations are inherited only if they occur in reproductive cells.
  • Recombinations during meiosis shuffle DNA sequences, creating new allele combinations.
  • Independent assortment of chromosomes leads to genetically unique gametes.
  • Combined, genetic variation arises from mutations and recombination.
  • References: Ch. 13.1; Ch. 14.1; Ch. 20.1; Ch. 14.1; Fig. 14.2; Ch. 20.1
  • The S allele in the beta hemoglobin gene originated via mutation (not present from the start of the population).

Gene Pools and Population Genetics

  • A gene pool is all the alleles present across all individuals in a population.
  • To understand molecular evolution, consider allele frequencies and genotype frequencies within a population, and how these change over generations.
  • Allele frequencies can increase, decrease, or stay the same depending on phenotype effects, environment, and chance.
  • Novel alleles can be harmful, beneficial, or neutral to survival and reproductive success.
  • References: Ch. 20.1

Population-Level Sickle Cell Example: Calculations

  • Population of 1000 people with:
    • AA = 890
    • AS = 100
    • SS = 10
  • Allele frequencies in this population:
    • S allele frequency: f(S)=2N<em>SS+N</em>AS2N=210+10021000=1202000=0.06f(S) = \frac{2\cdot N<em>{SS} + N</em>{AS}}{2N} = \frac{2\cdot 10 + 100}{2\cdot 1000} = \frac{120}{2000} = 0.06
    • A allele frequency: f(A)=1f(S)=0.94f(A) = 1 - f(S) = 0.94
  • Genotype frequencies:
    • f(AA)=8901000=0.890f(AA) = \frac{890}{1000} = 0.890
    • f(AS)=1001000=0.100f(AS) = \frac{100}{1000} = 0.100
    • f(SS)=101000=0.010f(SS) = \frac{10}{1000} = 0.010
  • Alleles in the population:
    • Total alleles = 2N=21000=20002N = 2\cdot 1000 = 2000
  • Practice question: If population becomes 2000 with 1580 AA, 350 AS, 70 SS:
    • S allele count = 2N<em>SS+N</em>AS=270+350=4902\cdot N<em>{SS} + N</em>{AS} = 2\cdot 70 + 350 = 490
    • Total alleles = 22000=40002\cdot 2000 = 4000
    • Allele frequency for S: f(S)=4904000=0.1225f(S) = \frac{490}{4000} = 0.1225
    • Allele frequency for A: f(A)=1f(S)=0.8775f(A) = 1 - f(S) = 0.8775
    • Genotype frequencies: f(AA)=15802000=0.79  ,  f(AS)=3502000=0.175  ,  f(SS)=702000=0.035f(AA) = \frac{1580}{2000} = 0.79\;, \; f(AS) = \frac{350}{2000} = 0.175\;, \; f(SS) = \frac{70}{2000} = 0.035
  • Practice questions also show how to compute genotype frequencies from allele frequencies using Hardy-Weinberg expectations (see below).

Hardy–Weinberg Equilibrium (HWE)

  • HWE describes a non-evolving population for a single gene with two alleles, with random mating in a diploid species.
  • Null hypothesis for evolutionary change: a population is not evolving with respect to the studied gene.
  • Conditions for HWE (Ch. 20.3):
    • 1) No selection: no differences in survival and reproduction among genotypes.
    • 2) No mutations: the gene is not mutating.
    • 3) No migration: population size is unaffected by movement of individuals.
    • 4) Large population: no genetic drift (sampling errors are negligible).
    • 5) Random mating: individuals pair by chance.
  • If these conditions hold, genotype frequencies follow: p2,2pq,q2p^2, 2pq, q^2 where p=f(A)p = f(A) and q=f(a)q = f(a), with p+q=1p + q = 1.
  • The beta hemoglobin example (S vs A) does not meet HWE, so the population evolves with respect to this trait.
  • Practical use: Deviations from HWE serve as a baseline to explore evolutionary mechanisms.

Evolutionary Implications: Selection and Maintenance of Alleles

  • If a harmful allele reduces survival to adulthood, its frequency is expected to decline over generations (Ch. 13.1, Ch. 20.3-20.4).
  • Why is a harmful allele like S still present in some populations?
    • Possible explanations include heterozygote advantage (sickle cell trait provides malaria resistance in some environments; AS individuals have a survival advantage in malaria-endemic regions).
    • Other forces include mutation, migration, genetic drift, and balancing selection.

Calculating Allele Frequencies: Classic Examples

  • Example 1: Mendel’s pea colors (AA yellow, Aa yellow, aa green). If every plant is green (phenotype aa), what are allele frequencies?

    • If all are aa, then f(a) = 1, f(A) = 0.
    • General approach: use counts to compute allele totals and divide by twice the number of individuals.
  • Example 2: Population with genotype frequencies: 50% aa, 25% Aa, 25% AA in a population of 100 individuals.

    • Allele frequency for a:f(a)=2f(aa)+f(Aa)2=20.50+0.252=1.252=0.625f(a) = \frac{2\cdot f(aa) + f(Aa)}{2} = \frac{2\cdot 0.50 + 0.25}{2} = \frac{1.25}{2} = 0.625
    • Allele frequency for A: f(A)=1f(a)=0.375f(A) = 1 - f(a) = 0.375

Measuring Genotype/Allele Frequencies: DNA Sequencing Example

  • DNA sequencing can detect all genetic variation in a gene.
  • Example: For a gene position in 50 diploid individuals, if 70 alleles are A and 30 alleles are G at a position:
    • Allele frequency for A: f(A)=70100=0.70f(A) = \frac{70}{100} = 0.70
    • Allele frequency for G: f(G)=30100=0.30f(G) = \frac{30}{100} = 0.30
  • Note: Protein-level analyses may miss silent mutations; sequencing reveals DNA-level variation.

Practical Takeaways for Exam Preparation

  • Distinguish between pattern (observable) versus process (theory-driven mechanism) in evolution.
  • Be able to define and apply the following terms: gene, allele, genotype, phenotype, mutation, recombination, gene pool, allele frequency, genotype frequency.
  • Be able to compute allele frequencies from genotype counts using the formula: f(A)=2N<em>AA+N</em>Aa2Nf(A) = \frac{2N<em>{AA} + N</em>{Aa}}{2N} and to compute genotype frequencies from counts: f(AA)=N<em>AAN,  f(Aa)=N</em>AaN,  f(aa)=NaaNf(AA) = \frac{N<em>{AA}}{N}, \; f(Aa) = \frac{N</em>{Aa}}{N}, \; f(aa) = \frac{N_{aa}}{N}.
  • Understand Hardy–Weinberg principles, including the conditions and the expected genotype frequencies p2,2pq,q2p^2, 2pq, q^2 with p+q=1p+q=1.
  • Practice with real numbers from the transcript (beta hemoglobin example, pea example, and the sequencing example) to solidify intuition.

Homework and Assessments (Overview)

  • Due: 29th Aug at 12 pm
  • Tasks:
    • Who are you? (Discussion)
    • Syllabus quiz
    • Time management activity
    • Intro survey (check Assessment document for point breakdown and policies)
  • Grade distribution (illustrative):
    • Introductory activities: 5–10 points
    • Intro post, Surveys, Time management: variable points totaling 30
    • Individual activities and quizzes: ~130–400 points
    • In-class U1–U4 activities: 20 points each
    • Graded writing (GR writing 1 & 2): 25 points each
    • Unit exams and Final: ~100 + 200 points
    • Total possible points: 1000