Linear Equations: Point-Slope Form, Graphing, Parallel & Perpendicular Lines

Introduction to Linear Equation Forms

  • Upcoming lessons include point-slope form, standard form, graphing from all forms, and finding points of intersection.
  • A review of similar triangles will follow before the unit test.
  • The current focus is on mastering graphing skills, with similar triangles to be revisited later.

Derivation of Point-Slope Form

  • Understanding the Slope Formula: The slope (mm) between two points (x<em>1,y</em>1)(x<em>1, y</em>1) and (x<em>2,y</em>2)(x<em>2, y</em>2) is defined as the change in yy divided by the change in xx:
    m=y<em>2y</em>1x<em>2x</em>1m = \frac{y<em>2 - y</em>1}{x<em>2 - x</em>1}
  • Adapting for Point-Slope Form: To derive the point-slope form, one of the two points is kept as a generic variable point (x,y)(x, y), while the other is a known specific point (x<em>1,y</em>1)(x<em>1, y</em>1). Substituting these into the slope formula gives:
    m=yy<em>1xx</em>1m = \frac{y - y<em>1}{x - x</em>1}
  • Rearranging to Point-Slope Form: To eliminate the denominator and isolate the (yy<em>1)(y - y<em>1) term, both sides of the equation are multiplied by (xx</em>1)(x - x</em>1). It's important to remember that the fraction bar implies invisible brackets around the numerator and denominator.
    m(xx<em>1)=yy</em>1xx<em>1(xx</em>1)m(x - x<em>1) = \frac{y - y</em>1}{x - x<em>1} \cdot (x - x</em>1)
    The (xx<em>1)(x - x<em>1) terms on the right side cancel out, resulting in the point-slope form: yy</em>1=m(xx1)y - y</em>1 = m(x - x_1)

Understanding the Components of Point-Slope Form

  • mm: Represents the slope or rate of change of the line. It is a specific numerical value.
  • (x<em>1,y</em>1)(x<em>1, y</em>1): Represents any single known point that lies on the line. x<em>1x<em>1 is its x-coordinate, and y</em>1y</em>1 is its y-coordinate.
  • (x,y)(x, y): These are generic variables and represent all points on the line. They are left as xx and yy in the equation.
  • The Minus Signs: The minus signs in (yy<em>1)(y - y<em>1) and (xx</em>1)(x - x</em>1) are inherent to the formula, originating from the calculation of