Lewis Theory and Covalent Bonding: Octet Rule, Electron Counting, and Resonance
Octet Rule and Bonding Foundations
- Covalent bonding and the octet rule: most atoms achieve stability by surrounding themselves with eight valence electrons (an octet). Hydrogen is an exception: it follows a duet (2 electrons).
- Incomplete octets and expanded octets: some atoms can have fewer than eight electrons (e.g., the third-row elements like sulfur and phosphorus can exceed eight, while boron and beryllium can have incomplete octets).
- Lewis theory aims to predict molecular structure by counting valence electrons and arranging atoms so that octet/duet rules are satisfied as much as possible.
- The idea of “directionality” in bonding: electrons between two atoms give bonds a direction and help determine a three-dimensional structure.
- Covalent bonds and the ownership concept: in covalent compounds, the atoms involved share electrons and effectively “own” the bonding electrons within the bond; the molecule overall is held together by these covalent bonds.
- Example idea: methane (CH extsubscript{4}) has a carbon atom bonded to four hydrogens; the carbon atom effectively owns the four hydrogens through bonding.
- Contrast with ionic compounds: ionic species involve electrostatic attraction between cations and anions rather than covalent sharing.
Covalent Bonding: Bonding and Lone Pairs
- A bond is a shared pair of electrons; a sigma bond involves end-to-end overlap, while a pi bond involves side-by-side overlap.
- Bond representation: use a straight line to represent a bond; lone pairs are drawn as pairs of dots (but often not drawn when focusing on the bonding framework).
- Two electrons per bond: every covalent bond consists of two electrons, whether sigma or pi.
- Bonding electrons vs nonbonding electrons: bonding electrons are those shared in bonds; nonbonding electrons (lone pairs) sit on atoms and are not part of a bond.
- How electrons contribute to stability: the shared electrons are attracted to both nuclei, stabilizing the molecule.
Simple Bonding Examples: H extsubscript{2} and H–F
- Hydrogen molecule H extsubscript{2}:
- Each hydrogen has one valence electron; to satisfy the duet, two electrons are shared between the two H atoms.
- The H–H bond is represented by a single line; each H ends up with a duet (2 electrons around it).
- Hydrogen does not reach an octet; it reaches a duet of two electrons.
- Hydrogen fluoride HF:
- H has 1 valence electron; F has 7 valence electrons.
- They share one pair of electrons to form one covalent bond (H–F).
- Hydrogen ends with a duet; fluorine ends with an octet (two electrons in bonds plus six nonbonding electrons as lone pairs).
- Pattern: hydrogen contributes one electron to the bond; fluorine contributes one electron to the bond; each atom’s unpaired electrons determine the number of bonds formed.
- Unpaired electrons concept: before bonding, atoms have unpaired electrons that participate in bond formation; after bonding, those unpaired electrons are paired within the bond.
Counting Valence Electrons and Building a Simple Lewis Structure: CH extsubscript{4}
- Start with the simplest atoms; count valence electrons: carbon has 4 valence electrons, hydrogen has 1 each.
- Total valence electrons for CH extsubscript{4}: 4+4imes1=8. In general, total valence electrons for a molecule is the sum of valence electrons of all atoms.
- Carbon’s octet: carbon has no lone pairs and forms four bonds (four C–H bonds). Each bond contributes 2 electrons, so carbon’s bonding electrons total is 4imes2=8, satisfying the octet:
- Carbon: nonbonding electrons = 0; bonding electrons = 8; octet is satisfied with a total of 8 around C.
- Methane structure: a tetrahedral arrangement with four C–H bonds; the carbon “owns” the four hydrogens via covalent bonding.
Bonding Patterns and the Octet Rule in Common Atoms
- General pattern for atoms without charge:
- Hydrogen: 1 bond, 0 lone pairs
- Boron: 3 bonds, 0 lone pairs
- Carbon: 4 bonds, 0 lone pairs
- Oxygen: typically 2 bonds, 2 lone pairs
- Halogens (e.g., F, Cl): 1 bond, 3 lone pairs
- The number of unpaired electrons on an atom often matches the number of bonds it forms in neutral, common cases (e.g., H has 1 unpaired electron and forms 1 bond; C typically forms 4 bonds and has 0 lone pairs).
- Lone pairs are sites of reactivity in many organic molecules; if you see an atom that should have lone pairs but none are drawn, you should add them to reflect likely reactivity.
- Nitrogen example (neutral, no charge): typically has three bonds and one lone pair (e.g., in NH extsubscript{3}). This corresponds to a formal neutral nitrogen in many common neutral compounds.
- Oxygen example (neutral, no charge): typically has two bonds and two lone pairs (e.g., in H extsubscript{2}O design).
- If an atom has no charge, its typical bonding pattern follows these rules; you can use the pattern to infer the number of lone pairs.
Octet Rule Exceptions: Expanded and Incomplete Octets
- BeH extsubscript{2} (beryllium hydride): Be in the center with two hydrogens; results in an incomplete octet for Be, which is allowed for Be and does not violate the octet rule in this case. This is an example of an incomplete octet.
- BF extsubscript{3} (boron trifluoride): central boron bonded to three fluorines; boron ends up with only six valence electrons around it (incomplete octet), which makes BF extsubscript{3} a Lewis acid because boron can accept electron density from a Lewis base.
- Third-row elements sulfur (S) and phosphorus (P) can have expanded octets: they can accommodate 10, 12, or more valence electrons around them in some compounds (e.g., SF extsubscript{6} with sulfur using more than eight electrons). This does not violate the octet rule for these heavier elements.
- Valence electron counting approaches used in Lewis structures:
- Octet count: ensure each atom (except H) has a total of eight electrons around it (or the appropriate duet for H).
- Charge count: accounts for overall molecular charge and adjusts electron counts to reflect charged species.
- Electron group count: considers regions of electron density (bonds and lone pairs) around a atom.
- Formal charge (FC) is a crucial concept to assess the distribution of electrons in a Lewis structure and to compare resonance forms:
- General formula: FC = V - ig(N + rac{B}{2}ig) where
- V = number of valence electrons for the neutral atom
- N = number of nonbonding electrons on the atom
- B = number of electrons in bonds (bonding electrons around the atom)
- For a neutral carbon with four bonds (e.g., in CH extsubscript{4}): V=4,N=0,B=8⇒FC=4−(0+8/2)=0.
- For ammonia NH extsubscript{3}: V=5,N=2(one lone pair), B=6⇒FC=5−(2+6/2)=5−(2+3)=0.
- Important note from the lecture: if a formal charge is written, you may encounter examples where a lone pair is drawn implicitly and a resonance form may shift the location of the negative charge (e.g., a resonance structure with negative charge on N vs. on O). In many cases, the major resonance contributor places negative charge on the more electronegative atom (e.g., O over N). The resonance forms themselves are not real; the real structure is a resonance hybrid (weighted average of all contributors).
Resonance Structures and the Resonance Hybrid
- Resonance structures illustrate the same connectivity of atoms but differ in the placement of lone pairs and double bonds.
- Key notation:
- Use double-headed arrows (↔) to denote resonance structures and resonance hybridisation rather than a single, static structure.
- The major contributor is the resonance form with the most favorable distribution of formal charges (often minimizing charges) and placing negative charges on the more electronegative atoms.
- Example discussed in the lecture (amide-like scenario):
- Structure A places the negative charge on nitrogen.
- Structure B places the negative charge on oxygen.
- The real structure is the resonance hybrid, in which the negative charge is delocalized between oxygen and nitrogen, weighted toward the more electronegative atom (oxygen).
- Practical takeaway:
- Different resonance forms can imply different local charge distributions and reactive hotspots, but only the resonance hybrid describes the actual electron distribution.
- When solving problems, use resonance to explain bond lengths, bond orders, and reactive sites, and remember that resonance forms are not separate real molecules.
Practical Implications and Problem-Solving Tips
- Lone pairs as reactive sites: identify lone pairs to predict areas of reactivity in organic chemistry.
- Always check for completeness of octets on second-row elements; be aware of exceptions (Be, B) and third-row expansions (S, P).
- Use patterns for quick counting: for neutral atoms, unpaired electrons often indicate the typical bonding pattern (e.g., H:1 bond; C:4 bonds; O:2 bonds; halogens: 1 bond).
- When in doubt about the Lewis structure, go step by step: count valence electrons, determine central atoms (usually the least electronegative unless following typical bonding patterns), place bonds first, then fill lone pairs, and finally assign formal charges to assess stability.
- Octet rule target: 8 valence electrons around most second-row atoms; duet for hydrogen: 2 electrons around H.
- Two electrons per bond: 2 electrons constitute one covalent bond.
- Valence electron total for a molecule: sum of the valence electrons of all atoms.
- Formal charge: FC = V - ig(N + rac{B}{2}ig).
- Bond order intuition: the number of bonds between two atoms corresponds to the bond order (e.g., single bond = 1, double bond = 2, triple bond = 3) with a corresponding count of shared electron pairs.
- Expanded octet exception: third-row elements (e.g., S, P) can have more than eight electrons around them.
- Incomplete octet exception: Be and B can have fewer than eight electrons around them in some stable molecules (e.g., BeH extsubscript{2}, BF extsubscript{3}).
- Resonance: a set of valid Lewis structures for the same molecule; the real structure is the resonance hybrid; use two-headed arrows to denote resonance.