Comprehensive Study Guide to P-Block Elements (Groups 13 to 18)
General Introduction to P-Block Elements
The -block of the periodic table encompasses elements belonging to Groups through . In these elements, the valence electrons enter the outermost -orbitals. Their general valence shell electronic configuration is (with the exception of Helium, which possesses a configuration).
The maximum oxidation state exhibited by a -block element equals the total number of valence electrons (the sum of the - and -electrons). This is commonly designated as the group oxidation state. Besides the group oxidation state, -block elements also exhibit lower oxidation states that typically differ from the group oxidation state by units of two. The relative stability of these lower oxidation states increases down the group for the heavier members due to the inert pair effect (the reluctance of the valence -electrons to participate in bonding owing to poor shielding by intervening - and -electrons).
Group 15 Elements: The Nitrogen Family
Group elements, historically known as the pnictogens (meaning "suffocation-forming"), include Nitrogen (), Phosphorus (), Arsenic (), Antimony (), Bismuth (), and the synthetic element Moscovium ().
Electronic Configuration and Atomic Numbers
The atomic numbers and electronic configurations follow the standard Aufbau buildup:
Nitrogen (): ; Electronic Configuration:
Phosphorus (): ; Electronic Configuration:
Arsenic (): ; Electronic Configuration:
Antimony (): ; Electronic Configuration:
Bismuth (): ; Electronic Configuration:
Moscovium ():
The general valence shell electronic configuration is . The -orbital is completely filled, and the -orbitals are half-filled, conferring exceptional electronic stability.
Occurrence
Nitrogen: Molecular nitrogen () comprises by volume of the atmosphere. In the earth's crust, it occurs as sodium nitrate (, Chile saltpetre) and potassium nitrate (, Indian saltpetre). It is also found in the form of proteins in plants and animals.
Phosphorus: Occurs primarily in minerals of the apatite family, (where ), such as fluorapatite ( or ). It is an essential constituent of animal and plant matter, bones, living cells, and phosphoproteins present in milk and eggs.
Arsenic, Antimony, and Bismuth: Occur primarily as sulphide minerals in the earth's crust.
Atomic and Physical Properties
Quantitative Data Table (NCERT Table 7.1)
Property | |||||
|---|---|---|---|---|---|
Atomic Number |
| ||||
Atomic Mass () | |||||
Electronic Configuration | |||||
() | |||||
() | |||||
() | |||||
Electronegativity | |||||
Covalent Radius () | |||||
Ionic Radius () | |||||
Melting Point () | |||||
Boiling Point () | |||||
Density ( at ) |
Detailed Periodic Trends
Atomic and Covalent Radii: Covalent radius increases down the group (). A substantial increase is observed from () to (). From () to (), only a small increase is noted due to the poor shielding effect of completely filled - and -orbitals.
Ionisation Enthalpy: Decreases down the group due to the increase in atomic size (). Because of their stable half-filled configurations, Group elements exhibit higher first ionisation enthalpies than the corresponding Group and Group elements. Note an anomaly in higher ionisation steps: and of are slightly higher than those of due to poor shielding by -electrons.
Electronegativity: Decreases down the group with increasing atomic size ().
Boiling and Melting Points:
Boiling Point: Increases from Nitrogen to Antimony and then slightly decreases at Bismuth: (or decreasing: ). The decrease from to is attributed to the inert pair effect reducing bonding tendencies.
Melting Point: Increases up to Arsenic and then decreases down to Bismuth: (decreasing: ). Arsenic possesses a giant layered covalent lattice yielding a peak melting point of .
Density: Increases monotonically down the group ().
Physical Nature: Dinitrogen is a diatomic gas (), whereas all other elements are polyatomic solids (). Nitrogen and phosphorus are non-metals, arsenic and antimony are metalloids, and bismuth is a typical metal. Except for nitrogen, all members exhibit allotropy.
Chemical Properties and Oxidation States
Common Oxidation States: .
Stability of : The tendency to exhibit a oxidation state decreases down the group due to increases in atomic size and metallic character. Bismuth hardly forms any compounds in the state.
Stability of vs : The stability of the oxidation state decreases down the group, while the stability of the oxidation state increases down the group. This is caused by the inert pair effect, where the outermost electrons remain unshared. For bismuth, compounds are powerful oxidising agents; is the only stable pentahalide.
Disproportionation Reactions:
For nitrogen, all oxidation states from to tend to disproportionate in acid solution:
For phosphorus, nearly all intermediate oxidation states ( to ) disproportionate into and in acidic and alkaline media:
For heavier elements (), intermediate oxidation states become increasingly stable toward disproportionation.
Maximum Covalency: Nitrogen is restricted to a maximum covalency of ( + orbitals) because it lacks vacant -orbitals in its valence shell. Heavier elements can expand their covalency to or using vacant -orbitals (e.g., ).
Anomalous Properties of Nitrogen
Nitrogen differs from the rest of the group due to:
Small atomic size.
High electronegativity ().
High ionisation enthalpy ().
Non-availability of -orbitals in its valence shell.
Specific Consequences of Anomalous Nature
Multiple Bonding (): Nitrogen possesses the unique ability to form strong multiple bonds with itself () and with other small, highly electronegative atoms (). Heavier members cannot form bonds because their atomic orbitals are too large and diffuse to undergo effective lateral overlap.
Bond Enthalpy of Dinitrogen: Dinitrogen exists as a diatomic molecule with a triple bond ( and ). Its bond dissociation enthalpy is exceptionally high (), making it chemically inert at room temperature.
Single Bond Enthalpies and Catenation: The single bond is significantly weaker than the single bond ( vs ). This weakness arises from strong interelectronic repulsions among the non-bonding electron pairs situated close together due to the short bond length. Consequently, nitrogen has a much weaker catenation property than phosphorus.
Lack of and Bonding: Nitrogen cannot form bonds, unlike phosphorus and heavier elements (e.g., or ). Furthermore, phosphorus and arsenic form bonds with transition metals when compounds such as and act as ligands.
Group 15 Hydrides ()
All group 15 elements form volatile hydrides of the formula ():
Basic Strength: . Basicity depends on the electron pair availability on the central atom. As size increases, electron density disperses over a larger volume, diminishing basicity.
Thermal Stability and Bond Dissociation Enthalpy: . As the central atom size increases, the bond length increases, bond strength decreases, and thermal stability falls.
Reducing Power: . is the strongest reducing agent among the hydrides because its bond is the weakest and cleaves most readily. is only a mild reducing agent.
Bond Angles: .
Boiling Point Anomaly: . Ammonia () has an abnormally high boiling point compared to and due to extensive intermolecular hydrogen bonding.
Group 15 Oxides and Halides
Oxides: Elements form trioxides () and pentoxides ().
The oxide in the higher oxidation state is more acidic than that in the lower oxidation state: .
Acidic character decreases down the group:
: Purely acidic.
: Amphoteric.
: Predominantly basic.
Halides: Elements form trihalides () and pentahalides ().
According to Fajans' rules, higher oxidation state halides () are more covalent than lower oxidation state halides () because cations with a state have higher polarising power.
Nitrogen cannot form pentahalides due to the absence of vacant -orbitals.
All trihalides of Group elements (except , which is predominantly ionic) are covalent. All trihalides of nitrogen are unstable except .
Group 16 Elements: The Oxygen Family (Chalcogens)
Group comprises Oxygen (), Sulphur (), Selenium (), Tellurium (), Polonium (), and Livermorium (). They are termed chalcogens ("ore-forming") because copper and other metal ores occur predominantly as oxides and sulphides.
Electronic Configuration and Atomic Numbers
Oxygen (): ; Configuration:
Sulphur (): ; Configuration:
Selenium (): ; Configuration:
Tellurium (): ; Configuration:
Polonium (): ; Configuration:
Livermorium ():
The general valence shell electronic configuration is .
Occurrence
Oxygen: Most abundant element on Earth ( by mass of the earth's crust; dry air contains oxygen by volume).
Sulphur: Abundance in the earth's crust is .
Combined as sulphates: Gypsum (), Epsom salt (), Baryte ().
Combined as sulphides: Galena (), Zinc blende (), Copper pyrites ().
Traces of occur in volcanic gases. Organic materials (eggs, proteins, garlic, onion, mustard, hair, wool) contain sulphur.
Selenium & Tellurium: Found as metal selenides and tellurides in sulphide ores.
Polonium: Occurs in nature as a radioactive decay product of thorium and uranium minerals; half-life of is .
Periodic Trends and Atomic Properties
Atomic and Covalent Radii: Increase regularly down the group: .
Ionisation Enthalpy: Decreases down the group: . Group elements have lower first ionisation enthalpies than corresponding Group elements because removing one electron yields a stable half-filled configuration.
Electronegativity: Decreases down the group (). Oxygen is the second most electronegative element after fluorine.
Electron Gain Enthalpy ():
Experimental values: .
Crucial Anomaly: Oxygen has a less negative electron gain enthalpy than sulphur. This is due to the very small size of the oxygen atom, which causes high interelectronic repulsions in the compact -subshell upon electron addition.
Melting and Boiling Points: Increase down the group from to . The large difference between the melting and boiling points of oxygen and sulphur is explained on the basis of their atomicity: oxygen exists as a discrete diatomic molecule (), whereas sulphur exists as an octatomic polyatomic molecule ().
Allotropy: All elements of Group exhibit allotropy.
Sulphur Allotropes: Rhombic (-sulphur) and Monoclinic (-sulphur). The transition temperature is , below which is stable and above which is stable. Both contain puckered crown rings.
At elevated temperatures (), sulphur exists primarily as vapour, which is paramagnetic like because it possesses two unpaired electrons in antibonding orbitals.
Chemical Properties
Oxidation States: Common states are .
Oxygen shows predominantly, but exhibits in , in , in peroxides (), and in superoxides ().
The stability of the oxidation state decreases down the group, while the stability of the oxidation state increases down the group due to the inert pair effect.
Hydrides ():
Acidic Strength: . (Due to a decrease in bond dissociation enthalpy).
Thermal Stability: .
Reducing Power: All hydrides except water are reducing agents. Reducing strength increases down the group: .
Boiling Point: . Water has an abnormally high boiling point due to extensive intermolecular hydrogen bonding.
Drago's Rule: For and , the central atom has an electronegativity and bonded to hydrogen; hybridization does not effectively take place. The bond angles remain close to (), in contrast to (, ).
Oxides ( and ):
is a gas; and are crystalline solids.
Reducing/Oxidising property: is reducing ( to ), whereas is an oxidising agent ( to or ).
Acidic strength: . Acidic nature decreases down the group ().
Halides:
Hexahalides (): Only hexafluorides are stable; all are gaseous with octahedral geometry (). is exceptionally stable due to steric protection around sulphur.
Tetrahalides (): is a gas, is a liquid, is a solid. They have a see-saw shape ( hybridisation with one equatorial lone pair).
Monohalides: Exist as dimers (). Dimeric monohalides undergo disproportionation:
Group 17 Elements: The Halogens
Group contains Fluorine (), Chlorine (), Bromine (), Iodine (), Astatine (, radioactive), and Tennessine (). The name halogens is derived from Greek words meaning "salt producers".
Electronic Configuration and Atomic Numbers
Fluorine (): ; Configuration:
Chlorine (): ; Configuration:
Bromine (): ; Configuration:
Iodine (): ; Configuration:
Astatine (): ; Configuration:
Tennessine ():
General valence shell electronic configuration: .
Occurrence
Fluorine: Occurs mainly as insoluble fluorides: Fluorspar (), Cryolite (), and Fluoroapatite (). Present in small quantities in soil, river plants, bones, and animal teeth.
Chlorine, Bromine, Iodine: Found in seawater as chlorides, bromides, and iodides ( by mass). Dry sea beds contain deposits of carnallite (). Marine life accumulates iodine; seaweeds contain up to iodine, and Chile saltpetre contains up to sodium iodate ().
Atomic and Physical Properties
Atomic and Ionic Radii: Halogens possess the smallest atomic radii in their respective periods. Radii increase down the group: .
Ionisation Enthalpy: Very high, decreasing down the group: .
Electronegativity: Highest in their respective periods: . Fluorine is the most electronegative element in the periodic table.
Electron Gain Enthalpy ():
Order: .
Chlorine has a more negative electron gain enthalpy than fluorine ( vs ) because the small size of the fluorine atom results in strong interelectronic repulsions in the compact -subshell.
Bond Dissociation Enthalpy ():
Order: .
has an anomalously low bond dissociation enthalpy ( compared to and ) due to large lone pair-lone pair repulsions in the compact molecule.
Standard Reduction Potential and Oxidising Power:
Standard electrode potentials: , , , .
Oxidising power decreases down the group: .
is the strongest oxidising agent and displaces all other halide ions from aqueous solution:
Physical State and Colour:
: Yellow gas.
: Greenish-yellow gas.
: Red-brown liquid.
: Violet solid.
Colour arises from the absorption of visible light, causing excitation of outer electrons to higher energy levels.
Chemical Properties
Oxidation States:
Fluorine shows strictly a oxidation state (and lacks variable oxidation states or disproportionation reactions due to the absence of -orbitals and highest electronegativity).
Chlorine, bromine, and iodine show oxidation states. Compounds in intermediate oxidation states undergo disproportionation (e.g., ).
Hydrogen Halides ():
Acidic Strength & Reducing Power: .
Thermal Stability: .
Boiling Point: . has an exceptionally high boiling point due to strong intermolecular hydrogen bonding.
Melting Point: .
Oxides of Halogens:
Fluorine: Forms and . oxidises plutonium to in spent nuclear fuel processing.
Chlorine: Forms . Chlorine oxides tend to explode; is used as a bleaching agent for paper pulp, textiles, and water purification.
Iodine: is a very good oxidising agent and is used in the quantitative estimation of carbon monoxide ().
Stability Order of Oxides: .
Interhalogen Compounds
Interhalogens are formed when two different halogens react. They have the general formula (), where is the larger, less electronegative halogen.

Preparation Conditions
Hydrolysis and Shapes (NCERT Table 7.11)
Hydrolysis Rule: Gives halide of the smaller halogen and an oxoacid of the larger halogen:
Geometries:
(): Linear.
(): Bent T-shaped ( hybridisation with lone pairs).
(): Square pyramidal ( hybridisation with lone pair). Note: is a colourless liquid at room temperature.
(): Pentagonal bipyramidal ( hybridisation with lone pairs).
Group 18 Elements: The Noble Gases
Group comprises Helium (), Neon (), Argon (), Krypton (), Xenon (), Radon (, radioactive), and Oganesson ().
General Characteristics
Electronic Configuration: (Helium is ). Possess completely filled shells and high chemical inertness.
Atomic Radii: Noble gases exhibit the largest atomic radii in their periods because their radii are expressed as van der Waals radii.
Ionisation Enthalpy: Extremely high; decreases down the group from to .
Electron Gain Enthalpy: Have large positive values because added electrons must enter the next higher principal quantum shell.
Melting and Boiling Points: Exceptionally low because monoatomic noble gas atoms are held only by weak dispersion forces. Helium has the lowest boiling point of any known substance ().
Occurrence: All noble gases except radon occur in the atmosphere ( by volume, of which argon is the major constituent). Radon is obtained as a radioactive decay product of Radium:
Bartlett's Discovery of Xenon Compounds
Neil Bartlett observed that platinum hexafluoride () reacts with molecular oxygen () to form an ionic solid, dioxygenyl hexafluoroplatinate(V):
Recognizing that the first ionisation enthalpy of molecular oxygen () is almost identical to that of xenon (), Bartlett reacted xenon with , successfully isolating the first noble gas compound: (a red solid).
Xenon Fluorides and Oxides
Synthesis Conditions
Hydrolysis Reactions
: Undergoes redox reaction with water:
: Disproportionates in water:
Complete Hydrolysis of : Forms xenon trioxide ():
Partial Hydrolysis of :
Fluoride Ion Donor and Acceptor Reactions
Xenon fluorides react with fluoride ion acceptors to form cationic species:
acts as a fluoride acceptor with alkali metal fluorides to form fluoroxenate anions:
Geometry and Structures of Xenon Compounds
Molecule | Hybridisation | Bond Pairs | Lone Pairs | Shape / Geometry |
|---|---|---|---|---|
Linear | ||||
Square planar | ||||
Distorted octahedral | ||||
Square pyramidal | ||||
Pyramidal | ||||
Tetrahedral |
Group 13 Elements: The Boron Family
Group includes Boron (), Aluminium (), Gallium (), Indium (), and Thallium (). General electronic configuration: .

Quantitative Data Table (NCERT Table 11.2)
Property | |||||
|---|---|---|---|---|---|
Atomic Number | |||||
Atomic Mass () | |||||
Atomic Radius () | |||||
Ionic Radius () | |||||
() | |||||
() | |||||
() | |||||
Electronegativity | |||||
Density ( at ) | |||||
Melting Point () | |||||
Boiling Point () | |||||
— | |||||
— |
Anomalies and Trends
Atomic Radius Anomaly: . Gallium has a smaller atomic radius than aluminium due to the poor shielding effect of the ten intervening -electrons, leading to a higher effective nuclear charge ().
Ionic Radius (): Follows a normal increasing trend: .
First Ionisation Enthalpy (): Discontinuous trend: .
due to poor shielding of -electrons.
due to the presence of intervening -electrons providing very poor shielding (lanthanoid contraction).
Electronegativity Trend: Decreases from to , then increases marginally down to : .
Melting and Boiling Points:
Boron has an unusually high melting point () because of its extremely strong three-dimensional covalent lattice.
Gallium has an unusually low melting point () and exists as a liquid in summer. Its high boiling point () makes it ideal in high-temperature thermometry.
Melting point order: .
Oxidation States & Inert Pair Effect:
Group oxidation state is ; lower oxidation state is .
Stability of state: .
Stability of state: .
is significantly more stable than ; hence, acts as a powerful oxidising agent ().
Chemical Reactivity:
Oxides: is acidic; and are amphoteric; and are basic.
Reactions with Acid and Alkali: Aluminium dissolves in dilute mineral acids and aqueous bases (amphoteric): Note: Concentrated passivates by forming a thin protective oxide film.
Halides and Dimerisation: Monomeric trihalides are electron-deficient ( valence electrons) and act as strong Lewis acids. Relative Lewis acid strength of boron trihalides: (back-bonding efficiency decreases as ).
dimerises to via chlorine bridge bonds. Boron trihalides cannot dimerise due to the small size of boron and the unavailability of -orbitals.

Group 14 Elements: The Carbon Family
Group contains Carbon (), Silicon (), Germanium (), Tin (), and Lead (). General electronic configuration: .

Quantitative Data Table (NCERT Table 11.3)
Property | |||||
|---|---|---|---|---|---|
Atomic Number | |||||
Atomic Mass () | |||||
Covalent Radius () | |||||
() | |||||
Electronegativity | |||||
Density ( at ) | |||||
Melting Point () | |||||
Boiling Point () |
Key Trends
Atomic Radii: . A marked increase occurs from to , followed by a small increase from to due to inefficient shielding by - and -electrons.
Ionisation Enthalpy: Decreases from to , then increases slightly at : . The inversion at is caused by the poor shielding effect of the -electrons (lanthanoid contraction).
Melting and Boiling Points: Group elements have much higher melting and boiling points than corresponding Group elements due to very strong covalent network structures. Lowest melting point in Group is Tin (, , ).
Electronegativity: Decreases sharply from to , remains identical from to , and increases slightly to .
Oxidation States:
Exhibit and oxidation states.
Stability of decreases down the group: .
Stability of increases down the group: .
acts as a reducing agent (), whereas acts as a strong oxidising agent () due to the inert pair effect.
Oxides:
Monoxides (): (neutral); (acidic); (amphoteric).
Dioxides (): (acidic); (amphoteric).
Acidic character: .
Halides and Complexes:
Tetrahalides () are predominantly covalent (, tetrahedral), except and which are ionic.
does not exist because readily oxidises to .
Species like exist because central atoms have vacant -orbitals. However, does not exist due to the steric crowding of six large chloride ions around and weak interaction between lone pairs of and .
resists hydrolysis due to the absence of vacant -orbitals. Other tetrahalides undergo rapid hydrolysis:
Catenation and Multiple Bonding:
Catenation decreases rapidly down the group: . Lead does not exhibit catenation.
Bond dissociation enthalpies: .
Carbon forms stable multiple bonds (), enabling diverse allotropic forms (diamond, graphite, fullerenes).
Exam Practice Questions and Previous Years' Solved Problems
Group 15 Questions
Question 1 [08 April, 2024 (Shift-II)]
Identify the incorrect statements about group 15 elements: (A) Dinitrogen is a diatomic gas which acts like an inert gas at room temperature. (B) The common oxidation states of these elements are and . (C) Nitrogen has unique ability to form multiple bonds. (D) The stability of oxidation states increases down the group. (E) Nitrogen shows a maximum covalency of .
Choose the correct answer from the options given below: (a) (A), (B), (D) only (b) (A), (C), (E) only (c) (B), (D), (E) only (d) (D) and (E) only
Solution: Statements (A), (B), and (C) are correct. Statement (D) is incorrect because the stability of the oxidation state decreases down the group due to the inert pair effect. Statement (E) is incorrect because nitrogen lacks vacant -orbitals, restricting its maximum covalency to . Therefore, the incorrect statements are (D) and (E). Correct Option: (d)
Question 2 [03 April, 2025 (Shift-I)]
Given below are two statements:
Statement I: The single bond is weaker and longer than that of single bond.
Statement II: Compounds of group 15 elements in oxidation states readily undergo disproportionation reactions.
In the light of above statements, choose the correct answer from the options given below: (a) Statement I is true but statement II is false (b) Both statement I and statement II are false (c) Statement I is false but statement II is true (d) Both statement I and statement II are true
Solution:
Statement I is false: The single bond is indeed weaker than the single bond due to strong interelectronic repulsions of non-bonding electrons, but it is shorter (not longer) due to nitrogen's smaller atomic radius ( vs ).
Statement II is false: Compounds of group 15 in intermediate oxidation states of nitrogen ( to ) and phosphorus disproportionate, but states of heavier members () are stable and do not readily disproportionate. Correct Option: (b)
Question 3 [22 Jan, 2025 (Shift-II)]
The maximum covalency of a non-metallic group 15 element 'E' with weakest bond is: (a) (b) (c) (d)
Solution: The non-metallic elements of Group 15 are Nitrogen () and Phosphorus (). Between the two, the single bond is weaker than the single bond. The element with the weakest single bond is Nitrogen (). The maximum covalency of Nitrogen is . Correct Option: (a)
Question 4 [28 Jan, 2025 (Shift-II)]
A group 15 element forms bond with transition metals. It also forms hydride which is a strongest base among the hydrides of other group members that form bond. The atomic number of the element is _____.
Solution: The elements capable of forming bonds with transition metals must possess vacant -orbitals, which includes . Among their hydrides (), basicity decreases down the group: . The strongest base among these is , formed by Phosphorus (). The atomic number of Phosphorus is . Answer: 15
Question 5 [29 Jan, 2025 (Shift-II)]
First ionisation enthalpy values of first four group 15 elements are given below. Choose the correct value for the element that is a main component of apatite family: (a) (b) (c) (d)
Solution: The main component of the apatite family is Phosphorus (). The first ionisation enthalpies of the first four Group 15 elements are: , , , . The value for phosphorus is . Correct Option: (a)
Question 6 [30 Jan, 2024 (Shift-II)]
Choose the correct statements about the hydrides of group 15 elements: A. The stability of the hydrides decreases in the order . B. The reducing ability of the hydrides increases in the order . C. Among the hydrides, is strong reducing agent while is mild reducing agent. D. The basicity of the hydrides increases in the order .
Choose the most appropriate from the option given below: (a) B and C only (b) C and D only (c) A and B only (d) A and D only
Solution: Statements A and B are correct. Statement C is incorrect because is the strongest reducing agent and is mild. Statement D is incorrect because basicity decreases down the group (). Correct Option: (c)
Question 7 [01 Feb, 2024 (Shift-I)]
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): has lower boiling point than .
Reason (R): In liquid state molecules are associated through vander waal's forces, but molecules are associated through hydrogen bonding.
Choose the most appropriate answer: (a) Both (A) and (R) are correct and (R) is not the correct explanation of (A) (b) (A) is not correct but (R) is correct (c) Both (A) and (R) are correct but (R) is the correct explanation of (A) (d) (A) is correct but (R) is not correct
Solution: Assertion (A) is correct ( has a higher boiling point than ). Reason (R) is false because in the liquid state, molecules associate via hydrogen bonding, while molecules associate through weak van der Waals forces. Correct Option: (d)
Question 8 [01 Feb, 2024 (Shift-II)]
The strongest reducing agent among the following is: (a) (b) (c) (d)
Solution: Due to the lowest bond dissociation enthalpy and longest bond length, cleaves most readily to release hydrogen, making it the strongest reducing agent. Correct Option: (c)
Question 9
Given below are two statements:
Statement-I: The pentavalent oxide of group-15 element, , is less acidic than trivalent oxide, , of the same element.
Statement-II: The acidic character of trivalent oxide of group 15 elements, , decreases down the group.
Solution:
Statement-I is false: The oxide in the higher oxidation state () has higher positive oxidation state and polarising power, making it more acidic than .
Statement-II is true: As metallic character increases down the group, the acidic character of decreases ( acidic; amphoteric; basic).
Group 16 Questions
Question 10 [08 April, 2025 (Shift-II)]
Given below are two statements:
Statement I: is more acidic than .
Statement II: has higher bond enthalpy for dissociation than .
Choose the correct answer: (a) Both statement I and Statement II are false. (b) Both statement I and Statement II are true. (c) Statement I is true but Statement II is false. (d) Statement I is false but Statement II is true.
Solution:
Statement I is false: Acidic character increases down the group (); hence, is more acidic than .
Statement II is true: The bond is shorter and stronger than the bond, so has a higher bond dissociation enthalpy than . Correct Option: (d)
Question 11 [02 April, 2025 (Shift-II)]
The nature of oxide () and hydride () formed by , respectively are: (a) Oxidising and acidic (b) Reducing and basic (c) Reducing and acidic (d) Oxidising and basic
Solution: In Group 16 dioxides, is reducing while is an oxidising agent. The hydrides of Group 16 are acidic, with () being acidic. Correct Option: (a)
Question 12 [24 Jan, 2025 (Shift-I)]
The large difference between the melting and boiling points of oxygen and sulphur may be explained on the basis of: (a) Atomic size (b) Atomicity (c) Electron gain enthalpy (d) Electronegativity
Solution: Oxygen exists as discrete diatomic molecules (), whereas sulphur exists as octatomic polyatomic molecules (). This difference in atomicity gives rise to much stronger van der Waals forces in sulphur. Correct Option: (b)
Question 13 [29 Jan, 2024 (Shift-II)]
Anomalous behaviour of oxygen is due to its: (a) large size and high electronegativity (b) small size and low electronegativity (c) small size and high electronegativity (d) large size and low electronegativity
Solution: Anomalous behavior of oxygen arises directly from its small size, high electronegativity, and lack of vacant -orbitals. Correct Option: (c)
Question 14 [27 Jan, 2024 (Shift-I)]
Given below are two statements:
Statement I: Oxygen being the first member of group 16 exhibits only oxidation state.
Statement II: Down the group 16 stability of oxidation state decreases and oxidation state increases.
Choose the most appropriate answer: (a) Statement I is correct but Statement II is incorrect. (b) Both Statement I and Statement II are incorrect. (c) Statement I is incorrect but Statement II is correct. (d) Both Statement I and Statement II are correct.
Solution:
Statement I is incorrect because oxygen also exhibits in , in , in , and in .
Statement II is incorrect because down the group, the stability of increases and decreases due to the inert pair effect. Correct Option: (b)
Group 17 Questions
Question 15 [02 April, 2025 (Shift-I)]
The property/properties that show irregularity in first four elements of group-17 is/are: (A) Covalent radius (B) Electron affinity (C) Ionic radius (D) First ionization energy
Choose the correct answer: (a) B and D only (b) A and C only (c) B only (d) A, B, C and D
Solution: Covalent radius, ionic radius, and first ionization energy show regular periodic trends ( for radii; for ionization energy). Only electron affinity (electron gain enthalpy) shows an irregularity, where Chlorine has higher electron affinity than Fluorine (). Correct Option: (c)
Question 16 [08 April, 2024 (Shift-I)]
Among the following halogens and , which can undergo disproportionation reaction? (a) Only (b) and (c) and (d) and
Solution: Fluorine () is the most electronegative element and exhibits only a oxidation state in its compounds; thus, it cannot be oxidised to positive oxidation states and cannot undergo disproportionation. Chlorine, bromine, and iodine display multiple oxidation states and readily disproportionate in alkaline solutions. Correct Option: (b)
Question 17 [09 April, 2024 (Shift-I)]
The ions make the enamel on teeth much harder by converting hydroxyapatite into much harder fluoroapatite having the formula: (a) (b) (c) (d)
Solution: Hydroxyapatite is . Reaction with replaces the hydroxide group to form fluoroapatite, . Correct Option: (a)
Question 18 [27 Jan, 2024 (Shift-I)]
Element not showing variable oxidation state is: (a) Bromine (b) Iodine (c) Chlorine (d) Fluorine
Solution: Fluorine lacks -orbitals and is the most electronegative element, so it exhibits only a oxidation state in its compounds. Correct Option: (d)
Question 19 [29 Jan, 2024 (Shift-I)]
Identify the incorrect pair from the following: (a) Fluorspar — (b) Cryolite — (c) Fluoroapatite — (d) Carnallite —
Solution: Fluorspar is calcium fluoride (), not . Correct Option: (a)
Question 20 [30 Jan, 2024 (Shift-II)]
Reduction potential of ions are given below:
The correct order of their oxidising power is: (a) (b) (c) (d)
Solution: Higher reduction potential corresponds directly to greater oxidising power. Since , the order is . Correct Option: (b)
Question 21 [29 Jan, 2023 (Shift-I)]
The bond dissociation energy is highest for: (a) (b) (c) (d)
Solution: Bond dissociation energies of the halogens follow the order: . Chlorine has the highest value. Correct Option: (a)
Question 22 [01 Feb, 2023 (Shift-I)]
Given below are two statements:
Statement-I: Chlorine can easily combine with oxygen to form oxides, and the product has a tendency to explode.
Statement-II: Chemical reactivity of an element can be determined by its reaction with oxygen and halogens.
Choose the correct answer: (a) Both the statements-I and Statement-II are true (b) Statement-I is true but Statement-II is false (c) Statement-I is false but Statement-II is true (d) Both the Statements-I and II are false
Solution: Both statements are true. Chlorine oxides () are highly reactive and tend to explode violently. Standard chemical reactivity of elements is generally assessed by reaction with electronegative elements like oxygen and halogens. Correct Option: (a)
Question 23 [13 April, 2023 (Shift-I)]
at room temperature is a: (a) Colourless gas with trigonal bipyramidal geometry. (b) Colourless gas with square pyramidal geometry. (c) Colourless liquid with square pyramidal geometry. (d) Colourless liquid with trigonal bipyramidal geometry.
Solution: According to NCERT Table 7.11, is a colourless liquid with a square pyramidal shape ( hybridisation with lone pair). Correct Option: (c)
Question 24 [13 April, 2023 (Shift-II)]
The correct group of halide ions which can be oxidised by oxygen in acidic medium is: (a) only (b) only (c) only (d) only
Solution: In acidic medium, oxygen () can only oxidise iodide ions () spontaneously: Oxygen cannot oxidise bromide ( under standard conditions kinetic barriers prevent it) or chloride (). Correct Option: (d)
Question 25 [27 June, 2022 (Shift-II)]
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.
Assertion A: Fluorine forms one oxoacid.
Reason R: Fluorine has smallest size amongst all halogens and is highly electronegative.
Choose the most appropriate answer: (a) Both A and R are correct and R is the correct explanation of A. (b) Both A and R are correct but R is NOT the correct explanation of A. (c) A is correct but R is not correct. (d) A is not correct but R is correct.
Solution: Assertion A is correct (, hypofluorous acid, is the only oxoacid of fluorine). Reason R is also correct: because of its small size, high electronegativity, and lack of -orbitals, fluorine cannot act as a central atom surrounded by oxygen or form higher oxoacids. Correct Option: (a)
Question 26 [25 July, 2022 (Shift-I)]
The interhalogen compound formed from the reaction of bromine with excess of fluorine is: (a) Hypohalite (b) Halate (c) Perhalate (d) Halite
Solution: Reaction of bromine with excess fluorine produces bromine pentafluoride (): Hydrolysis of produces bromic acid (), whose salts are halates (bromates): Correct Option: (b)
Group 13 Questions
Question 27 [07 April, 2025 (Shift-II)]
The correct statements from the following are: (A) is a powerful oxidising agent (B) does not get reduced easily (C) Both and are very stable in solution (D) is more stable than (E) and are highly stable
Choose the correct answer: (a) (A), (B), (C), (D) and (E) (b) (A), (B), (D) and (E) only (c) (B), (D) and (E) only (d) (A), (C) and (D) only
Solution: Due to the inert pair effect, is much more stable than , making an unstable ion that acts as a powerful oxidising agent (). Therefore, statement (C) is false because is not stable in solution. Statements (A), (B), (D), and (E) are all correct. Correct Option: (b)
Question 28 [04 April, 2025 (Shift-II)]
The elements of Group 13 with highest and lowest first ionisation enthalpies are respectively: (a) (b) (c) (d)
Solution: The first ionisation enthalpies are: , , , , . The highest is Boron () and the lowest is Indium (). Correct Option: (d)
Question 29 [04 April, 2025 (Shift-I)]
Given below are the pairs of group 13 elements showing their relation in terms of atomic radius: Identify the elements present in the incorrect pair and in that pair find out the element (X) that has higher ionic radius () than the other one. The atomic number of the element (X) is: (a) (b) (c) (d)
Solution: The incorrect pair is because the atomic radius of () is greater than that of (). Comparing their ionic radii (): and . The element with higher ionic radius is Gallium (), which has an atomic number of . Correct Option: (a)
Question 30 [03 April, 2025 (Shift-II)]
The correct orders among the following are:
Atomic radius:
Electronegativity:
Density:
1st Ionisation Energy:
Choose the correct answer: (a) B and D Only (b) A and C Only (c) C and D Only (d) A and B Only
Solution:
Atomic radius is incorrect ().
Electronegativity order is correct ().
Density is incorrect (density increases down the group: ).
1st Ionisation Energy is correct (). Therefore, statements B and D are correct. Correct Option: (a)
Question 31 [02 April, 2025 (Shift-I)]
Given below are two statements:
Statement (I): The metallic radius of is less than that of .
Statement (II): The ionic radius of is less than that of .
Choose the most appropriate answer: (a) Both Statement I and Statement II are incorrect (b) Statement I is incorrect but Statement II is correct (c) Statement I is correct but Statement II is incorrect (d) Both Statement I and Statement II are correct
Solution:
Statement (I) is incorrect because the metallic radius of () is greater than that of ().
Statement (II) is correct because the ionic radius of () is less than that of (). Correct Option: (b)
Question 32 [27 Jan, 2024 (Shift-I)]
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): Melting point of Boron () is unusually high in group 13 elements.
Reason (R): Solid Boron has very strong crystalline lattice.
Choose the most appropriate answer: (a) Both (A) and (R) are correct but (R) is not the correct explanation of (A) (b) Both (A) and (R) are correct and (R) is the correct explanation of (A) (c) (A) is true but (R) is false (d) (A) is false but (R) is true
Solution: Boron forms an extremely hard non-metallic solid composed of icosahedral units in a three-dimensional covalent lattice, resulting in an unusually high melting point (). Correct Option: (b)
Question 33 [04 April, 2024 (Shift-II)]
The correct order of the first ionisation enthalpy is: (a) (b) (c) (d)
Solution: The values are: , , and . Thus, the order is . Correct Option: (d)
Question 34 [08 April, 2024 (Shift-I)]
Given below are two statements: One is labelled as Assertion (A) and other is labelled as Reason (R).
Assertion (A): The stability order of oxidation state of and is .
Reason (R): The inert pair effect stabilises the lower oxidation state down the group.
Choose the correct answer: (a) A is false, but R is true. (b) Both A and R are true but R is not the correct explanation of A. (c) Both A and R are true and R is the correct explanation of A. (d) A is true, but R is false.
Solution: The inert pair effect increases down the group, which increasingly stabilises the oxidation state for the heavier elements (). Correct Option: (c)
Question 35 [06 April, 2024 (Shift-I)]
Given below are two statements:
Statement I: Gallium is used in the manufacturing of thermometers.
Statement II: A thermometer containing gallium is useful for measuring the freezing point () of brine solution.
Choose the correct answer: (a) Statement I is true but Statement II is false (b) Statement I is false but Statement II is true (c) Both Statement I and Statement II are true (d) Both Statement I and Statement II are false
Solution: Gallium has a melting point of (); below this temperature, gallium freezes solid. Therefore, it cannot be used to measure low temperatures like the freezing point of brine solution (). It is used for measuring high temperatures up to its boiling point (). Correct Option: (a)
Question 36 [05 April, 2024 (Shift-I)]
Given below are two statements:
Statement I: In group 13, the stability of oxidation state increases down the group.
Statement II: The atomic size of gallium is greater than that of aluminium.
Choose the most appropriate answer: (a) Both Statement I and Statement II are correct. (b) Statement I is incorrect but Statement II is correct. (c) Statement I is correct but Statement II is incorrect. (d) Both Statement I and Statement II are incorrect.
Solution: Statement I is correct (inert pair effect). Statement II is incorrect because the atomic radius of () is smaller than that of (). Correct Option: (c)
Question 37 [31 Jan, 2024 (Shift-II)]
Given below are two statements:
Statement I: Group 13 trivalent halides get easily hydrolysed by water due to their covalent nature.
Statement II: upon hydrolysis in acidified aqueous solution forms octahedral ion.
Choose the correct answer: (a) Both statement I and statement II are false. (b) Both statement I and statement II are true. (c) Statement I is false but statement II is true. (d) Statement I is true but statement II is false.
Solution: Both statements are true. Group 13 halides hydrolyse in water; in acidified aqueous solution, forms the octahedral complex ion because aluminium expands its coordination number using vacant -orbitals. Correct Option: (b)
Group 14 Questions
Question 38 [28 Jan, 2025 (Shift-I)]
Consider the following elements: . The most stable oxidation states of elements with highest and lowest first ionisation enthalpies, respectively, are: (a) (b) (c) (d)
Solution: Comparing first ionisation enthalpies among the given elements:
The element with the highest first ionisation enthalpy is Germanium (, ), whose most stable oxidation state is . The element with the lowest first ionisation enthalpy is Indium (, ), whose most stable oxidation state is . Correct Option: (d)
Question 39 [23 Jan, 2025 (Shift-II)]
Given below are the atomic numbers of some group 14 elements. The atomic number of the element with lowest melting point is: (a) (b) (c) (d)
Solution: Melting points of Group 14 elements: . The lowest melting point belongs to Tin (), which has an atomic number of . Correct Option: (a)
Question 40 [04 April, 2025 (Shift-II)]
Given below are two statements:
Statement (I): The first ionisation enthalpy of group 14 elements is higher than the corresponding elements of group 13.
Statement (II): Melting points and boiling points of group 13 elements are in general much higher than those the corresponding elements of group 14.
Choose the most appropriate answer: (a) Statement I is correct but Statement II is incorrect (b) Statement I is incorrect but Statement II is correct (c) Both Statement I and Statement II are incorrect (d) Both Statement I and Statement II are correct
Solution:
Statement (I) is correct because Group 14 elements have a higher effective nuclear charge () and smaller atomic radii than Group 13 elements.
Statement (II) is incorrect because Group 14 elements have much higher melting and boiling points than the corresponding elements of Group 13 due to strong four-coordinate network covalent bonding. Correct Option: (a)
Question 41 [07 April, 2025 (Shift-I)]
The group 14 elements and have the first ionisation enthalpy values of and respectively. The above values are lowest among their group members. The nature of their ions and respectively is: (a) both reducing (b) both oxidising (c) reducing and oxidising (d) oxidising and reducing
Solution: From the NCERT data table for Group 14, element () is Tin (), and element () is Lead (). For tin, the state is more stable than , so () acts as a reducing agent (). For lead, due to the inert pair effect, the state is more stable than , so () acts as an oxidising agent (). Correct Option: (c)
Question 42 [06 April, 2024 (Shift-I)]
Which of the following material is not a semiconductor? (a) Silicon (b) Graphite (c) Germanium (d) Copper oxide
Solution: Silicon, germanium, and copper oxide are well-known semiconductors. Graphite has delocalised -electrons free to move across hexagonal layers, making it a good metallic conductor of electricity. Correct Option: (b)
Question 43 [06 April, 2024 (Shift-II)]
The number of ions from the following that are expected to behave as oxidising agent is: (a) (b) (c) (d)
Solution: An ion behaves as an oxidising agent if it easily gains electrons to attain a more stable lower oxidation state. Down Groups 13 and 14, lower oxidation states are stabilized by the inert pair effect:
is readily reduced to (), behaving as a strong oxidising agent.
is readily reduced to , behaving as a strong oxidising agent.
and are stable in their states and do not act as oxidising agents under normal conditions ( is reducing). Thus, exactly ions ( and ) behave as oxidising agents. Correct Option: (d)
Question 44 [01 Feb, 2024 (Shift-II)]
Given below are two statements:
Statement I: and are acidic while and are amphoteric in nature.
Statement II: Allotropic forms of carbon are due to property of catenation and bond formation.
Choose the most appropriate answer: (a) Both Statement I and Statement II are false (b) Statement I is true but Statement II is false (c) Statement I is false but Statement II is true (d) Both Statement I and Statement II are true
Solution:
Statement I is true: and are acidic dioxides, whereas and are amphoteric monoxides.
Statement II is false: Carbon forms allotropes through catenation and multiple bond formation. Carbon lacks -orbitals entirely and cannot form bonds. Correct Option: (b)
Question 45 [31 Jan, 2024 (Shift-I)]
Consider the oxides of group 14 elements: . The amphoteric oxides are: (a) (b) (c) (d)
Solution: is neutral; and are acidic. Both and are amphoteric. Correct Option: (b)
Question 46 [29 Jan, 2024 (Shift-I)]
Given below are two statements:
Statement I: The electronegativity of group 14 elements from to , gradually decreases.
Statement II: Group 14 contains non-metallic, metallic, as well as metalloid elements.
Choose the most appropriate answer: (a) Statement I is false but Statement II is true. (b) Both Statement I and Statement II are false. (c) Statement I is true but Statement II is false. (d) Both Statement I and Statement II are true.
Solution:
Statement I is false: The electronegativity values are: , , , , and . It remains essentially constant from to and slightly increases at , rather than gradually decreasing.
Statement II is true: Carbon and silicon are non-metals, germanium is a metalloid, and tin and lead are metals. Correct Option: (a)