MA129: Week 6 Study Notes
- Course: MA129
- Week: 6
- Instructor: Dr. L. Howe
- Department: Mathematics, Wilfrid Laurier University
Differentiation as a Process
Notation for Derivatives
- Let ( y = f(x) )
- The derivative is represented as:
- ( f'(x) ) or ( y' ) (Easiest notation)
- ( \frac{dy}{dx} ) or ( \frac{df}{dx} ) (Leibniz notation: useful for later applications)
- For a small change in ( x ) denoted by ( h ):
- ( f'(x) = \lim_{h \to 0} \frac{f(x + h) - f(x)}{h} )
- More explicitly, ( f'(x) = \lim_{\Delta x \to 0} \frac{f(x + \Delta x) - f(x)}{\Delta x} )
- The derivative can also be denoted as ( \frac{d}{dx}[f(x)] ) (useful for formulas)
Example of Notation
- Example: Let ( y = f(x) = x^2 ). Its derivative is ( 2x ). This is correct in any of the following forms:
- ( f'(x) = 2x )
- ( y' = 2x )
- ( \frac{dy}{dx} = 2x )
- ( \frac{df}{dx} = 2x )
- ( \frac{d}{dx}[x^2] = 2x )
Constant Rule
- If ( f(x) = k ) where ( k ) is a constant, then:
- ( f'(x) = 0 )
- Or, in Leibniz notation: ( \frac{d}{dx}[k] = 0 )
Power Rule
- If ( f(x) = x^n ), where ( n ) is any real number, then:
- ( f'(x) = nx^{n-1} )
- In Leibniz notation: ( \frac{d}{dx}[x^n] = nx^{n-1} )
- Mental Instructions: Bring the exponent down in front as a multiplier and decrease the exponent by 1.
Examples
- If ( f(x) = e ): \
- ( f'(x) = 0 ) since ( f(x) ) is constant.
- If ( f(x) = x^2 ): \
- Using the Power Rule, ( f'(x) = 2x^{1} = 2x ).
- ( \frac{d}{dx}[x] = \frac{d}{dx}[x^{1}] = 1 \cdot x^{0} = 1 ).
- If ( f(x) = \frac{1}{x^2} = x^{-2} ): \
- For ( g(t) = \sqrt[3]{t} ): find ( g'(8) ):
- ( g(t) = t^{1/3} )
- ( g'(t) = \frac{1}{3}t^{-2/3} )
- ( g'(8) = \frac{1}{3} 8^{-2/3} = \frac{1}{12} )
Constant Multiple Rule
- Let ( k ) be a real number. If ( f(x) ) is differentiable, then so is ( kf(x) ), and:
- ( \frac{d}{dx}[kf(x)] = k \frac{d}{dx}[f(x)] )
- Example: If ( f(x) = 5x^2 ): \
- ( \frac{d}{dx}[5x^2] = 5 \frac{d}{dx}[x^2] = 5 \cdot 2x = 10x ) \
- Therefore, ( f'(x) = 10x )
Sum & Difference Rules
- If both functions ( f(x) ) and ( g(x) ) are differentiable, then:
- ( \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)] )
- ( \frac{d}{dx}[f(x) - g(x)] = \frac{d}{dx}[f(x)] - \frac{d}{dx}[g(x)] )
Product and Quotient Rules
Product Rule
- If both functions ( f(x) ) and ( g(x) ) are differentiable, then:
- ( \frac{d}{dx}[f(x)g(x)] = f'(x)g(x) + f(x)g'(x) )
- Mental Instructions: The derivative of the first function, times the second function, plus the derivative of the second function, times the first.
Quotient Rule
- If both functions ( f(x) ) and ( g(x) ) are differentiable, then:
- ( \frac{d}{dx}[\frac{f(x)}{g(x)}] = \frac{f'(x)g(x) - g'(x)f(x)}{[g(x)]^{2}} )
- Mental Instructions: The derivative of the top function times the bottom function minus the derivative of the bottom function times the top function, all over the bottom function squared.
Chain Rule
- If two functions ( f(x) ) and ( g(x) ) are differentiable, then:
- ( \frac{d}{dx}[f(g(x))] = f'(g(x))g'(x) )
- Mental Instructions: The derivative of the outer function evaluated at the inner function times the derivative of the inner function.
Derivative of the Exponential Function
- The base ( e ) is commonly used because:
- ( \frac{d}{dx}[e^x] = e^x )
- Using this and the Chain Rule to compute ( \frac{d}{dx}[a^x] ) for any ( a > 0 ):
- ( a^x = e^{x ext{ln} a} )
- Therefore, ( \frac{d}{dx}[a^x] = a^x ext{ln} a )
Derivatives of Logarithmic Functions
- The derivative of the natural logarithm is given by:
- ( \frac{d}{dx}[ ext{ln} x] = \frac{1}{x} ) (for ( x > 0 ))
- Using the Change of Base Formula:
- ( ext{log}_a x = \frac{ ext{ln} x}{ ext{ln} a} ) gives:
- ( \frac{d}{dx}[ ext{log}_a x] = \frac{1}{x ext{ln} a} )
End of Notes
- This document contains a comprehensive overview of differentiation rules, procedures, and examples essential for understanding calculus principles related to derivatives.