Systems of Equations Review
Solving Systems of Equations Algebraically
Substitution Method
- Solve one equation for one variable.
- Substitute that expression into the other equation.
- Solve for the remaining variable.
- Substitute the value back to find the other variable.
Elimination Method
- Multiply one or both equations by a constant so that one variable has the same coefficient but opposite signs.
- Add the equations to eliminate that variable.
- Solve for the remaining variable.
- Substitute the value back to find the other variable.
Types of Solutions
- One Solution: The lines intersect at one point.
- No Solution: The lines are parallel and do not intersect.
- Infinitely Many Solutions: The lines are coincident (the same line).
Word Problems
- Define variables.
- Write a system of equations based on the problem.
- Solve the system using substitution or elimination.
- Interpret the solution in the context of the problem.
Examples
- Substitution Example:
- y=5x
- 3x−2y=14
- 3x−2(5x)=14
- 3x−10x=14
- −7x=14
- x=−2
- y=5(−2)=−10
- Solution: (−2,−10)
- Elimination Example:
- x+2y=−7
- x−5y=7
- Subtract the second equation from the first:
- (x+2y)−(x−5y)=−7−7
- 7y=−14
- y=−2
- Substitute back: x+2(−2)=−7
- x−4=−7
- x=−3
- Solution: (−3,−2)
Determining the Number of Solutions Without Solving
- Rewrite equations in slope-intercept form (y=mx+b).
- Compare slopes and y-intercepts:
- Same slope, different y-intercepts: No solution (parallel lines).
- Same slope, same y-intercept: Infinitely many solutions (coincident lines).
- Different slopes: One solution (intersecting lines).
Common Mistakes
- Distributing negatives properly when using elimination.
- Substituting the value back into the correct equation to solve for the other variable.
- Interpreting word problems correctly to set up the system of equations.