Torque, Angular Momentum, and Moment of Inertia Review
Torque, Angular Momentum, and Moment of Inertia Review
Key Concepts
Torque: The rotational analog of linear force, calculated as au = r imes F where au is the torque, r is the radius vector, and F is the force.
Angular Momentum (L): The product of the moment of inertia (I) and the angular velocity ( heta) of a rotating object, expressed as L = I heta.
Moment of Inertia (I): A measure of an object's resistance to changes in its rotational motion, defined as I = ext{∑} m r^2 where m is the mass and r is the distance from the axis of rotation.
Moment of Inertia Derivations
1. Rod Spinning About Its Midpoint
- Formula: I = rac{1}{12} ml^2
Where:
- m = mass of the rod
- l = length of the rod
Derivation:
- Let linear mass density be rac{m}{L} and the differential mass dm = rac{m}{L} dx.
- Moment of inertia I = ext{∫} r^2 dm:
- I = ext{∫}_{-l/2}^{l/2} x^2 rac{m}{L} dx
- Simplifying leads to I = rac{1}{12} ml^2.
2. Rod Spinning About Its End
- Formula: I = rac{1}{3} ml^2
Derivation:
- Similar to the above: the limits change to [0, l] for the integration:
- I = ext{∫}_0^l x^2 rac{m}{L} dx
- Compute the integral to arrive at I = rac{1}{3} ml^2.
3. Uniform Disk Spinning About Its Center
- Formula: I = rac{1}{2} mr^2
Derivation:
- Use area mass density rac{M}{A} where A = ext{π}r^2:
- dm = ext{σ} dA = ext{σ}(2 ext{π}r dr)
- Resulting in integral I = ext{∫} r^2 dm up to R yields I = rac{1}{2} mr^2.
Examples
Example 1: Ceiling Fan Moment of Inertia
- Angular speed is 2.75 ext{ rad/s}; frictional torque au = 0.120 ext{ N·m}; time t = 22.5 ext{ s}. Compute the moment of inertia using:
- Variables:
- Angular acceleration rac{ ext{d} heta}{ ext{d}t} = rac{2.75}{22.5}
- I = rac{ au}{ ext{acceleration}} gives I.
Example 2: Angular Speed Change on Spinning Stool
- Initially I1 = 5.33 ext{ kg·m}^2, then reducing to I2 = 1.60 ext{ kg·m}^2:
- Angular momentum conservation L1 = L2 results in angular speed heta' calculation:
- I1 heta1 = I2 heta2 implies heta2 = rac{I1 heta1}{I2}.
Example 3: Merry-Go-Round with Person Jumping On
- The initial and the final angular speeds relate through conservation of angular momentum:
- L = I{initial} heta{initial} = I{final} heta{final}
- Calculate combined system moment of inertia as I + m r^2 after the person jumps on.
Additional Calculations and Concepts
- Parallel Axis Theorem: If you know the moment of inertia about an axis through the center of mass, you can find it about any axis parallel to it:
- I' = I_{cm} + md^2
- Calculation for a Rod on a Spinning Framework: Provides practice with inertia calculations on different axes.
Conclusion
- Mastery of the moments of inertia and associated principles is crucial for understanding rotational dynamics. Continuous practice with various problem setups reinforces these concepts.