Gases, Solutions, Acids, and Bases Study Guide

Unit B: Forms of Matter: Gases

  • How do observations of gases relate to scientific models?

  • What is the relationship among pressure, temperature, volume, and amount of a gas?

  • How is the behavior of gases used in various technologies?

4.1 Empirical Properties of Gases

  • Importance of gases and technologies relying on their properties.

  • Kinetic Molecular Theory (KMT): Explains gas properties at ordinary temperatures and pressures.

  • Motion of molecules differs in solid, liquid, and gas states.

    • Solid

    • Liquid

    • Gas

  • According to KMT:

    • Gas molecules are in constant motion.

    • The distance between gas molecules is large.

    • The kinetic energy of molecules depends on temperature.

  • Properties distinguishing gases:

    • Gases are compressible.

    • Gases expand as temperature increases.

    • Gases diffuse easily.

    • Gases have lower densities than solids and liquids.

    • Gases mix evenly and completely; considered homogeneous.

Measuring Gases: Volume and Pressure

  • Volume: Amount of space a substance occupies.

    • Measured in mL (convenience) or L (SI units).

    • 1 cm3=1 mL1 \text{ cm}^3 = 1 \text{ mL}

  • Pressure: Force per unit area exerted by moving particles colliding with container walls.

    • SI unit: pascal (Pa).

    • Gases often measured in kilopascals (kPa).

    • Other units: atmospheres (atm), millimeters of mercury (mmHg), Torricelli (torr), bar, pounds per square inch (PSI).

  • Unit Conversions:

    • Pascal (Pa): 1 Pa=1 N/m21 \text{ Pa} = 1 \text{ N/m}^2

    • Atmosphere (atm): 1 atm=101 kPa1 \text{ atm} = 101 \text{ kPa}

    • Millimeters of mercury (mmHg): 760 mmHg=1 atm760 \text{ mmHg} = 1 \text{ atm}

    • Torricelli (torr): 1 torr=1 mmHg1 \text{ torr} = 1 \text{ mmHg}

    • Pounds per square inch (PSI): 1 PSI=6895 Pa1 \text{ PSI} = 6895 \text{ Pa}

    • Bar (bar): 1 bar=100 kPa1 \text{ bar} = 100 \text{ kPa}

  • Conversion examples provided.

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SI Prefixes

  • Prefixes adjust units for convenient measurement.

  • Prefix Table:

    • Tera (T): 101210^{12}

    • Giga (G): 10910^9

    • Mega (M): 10610^6

    • Kilo (k): 10310^3

    • Milli (m): 10310^{-3}

    • Micro ($\mu$): 10610^{-6}

    • Nano (n): 10910^{-9}

    • Pico (p): 101210^{-12}

  • Conversion examples provided.

Standard Conditions for Gases

  • Standard Temperature and Pressure (STP): 0 C0 \text{ }^\circ\text{C} and 101.325 \tet{ kPa}

  • Standard Ambient Temperature and Pressure (SATP): 25 C25 \text{ }^\circ\text{C} and 100 kPa100 \text{ kPa}

The Relationship between Pressure and Volume: Boyle’s Law

  • Boyle's Law: As pressure on a gas increases, volume decreases proportionately if temperature and amount of gas remain constant.

    • Volume of a gas is inversely proportional to its pressure.

    • P<em>1V</em>1=P<em>2V</em>2P<em>1V</em>1 = P<em>2V</em>2

      • 1 = initial conditions

      • 2 = final conditions

  • Examples provided for Boyle's Law calculations.

The Relationship between Temperature and Volume: Charles’ Law

  • Charles' Law: As the temperature of a gas increases, the volume increases proportionately if pressure and amount of gas remain constant.

    • The temperature of a gas is directly proportional to the volume of a gas.

    • V<em>1T</em>1=V<em>2T</em>2\frac{V<em>1}{T</em>1} = \frac{V<em>2}{T</em>2}

  • Temperature is a measure of average kinetic energy.

  • Absolute zero: Point of zero kinetic energy, theoretically -273°C.

  • Kelvin temperature scale: No degree symbol is used for Kelvin.

    • Celsius to Kelvin conversion: K= C+273K = \text{ }^\circ\text{C} + 273

    • Kelvin to Celsius conversion:  C=K273\text{ }^\circ\text{C} = K - 273

  • Examples provided for Charles' Law calculations.

The Relationship between Temperature, Volume, and Pressure: The Combined Gas Law

  • Combined Gas Law: For a fixed amount of gas there is a relationship between volume, temperature, and pressure:

    • P<em>1V</em>1T<em>1=P</em>2V<em>2T</em>2\frac{P<em>1V</em>1}{T<em>1} = \frac{P</em>2V<em>2}{T</em>2}

  • Examples provided for Combined Gas Law calculations.

4.2 Explaining the Properties of Gases

  • Early gas studies were empirical.

  • Kinetic molecular theory explains gas properties.

  • Why are gases compressible?

    • Large spaces between gas molecules allow them to be crowded together.

  • What is gas pressure?

    • The sum of all the forces exerted by the gas molecules when they collide with the walls of the container.

  • Use KMT to explain Boyle’s Law:

    • As volume decreases, molecules collide with walls more frequently, increasing pressure.

  • Use KMT to explain Charles’ Law:

    • As temperature increases, molecules move faster and occupy more space, increasing volume.

  • KMT explains physical but not chemical properties.

  • Avogadro’s Theory: Equal volumes of gases at the same temperature and pressure contain equal numbers of molecules.

4.3 Molar Volume of Gases

  • Mole: measurement of the number of particles in a sample.

    • 1 mole=Avogadro’s number=6.02×1023 atoms or molecules1 \text{ mole} = \text{Avogadro’s number} = 6.02 \times 10^{23} \text{ atoms or molecules}

    • 1 mol of He(g)=6.02×1023 atoms1 \text{ mol of He(g)} = 6.02 \times 10^{23} \text{ atoms}

    • 1 mol of CO2(g)=6.02×1023 molecules1 \text{ mol of CO}_2\text{(g)} = 6.02 \times 10^{23} \text{ molecules}

  • Guy-Lussac’s Law and Avogadro’s Theory can be combined.

  • Molar volume (Vm): the volume that one mole of a gas occupies; is the same for all gases at the same temp and pressure.

    • Vm at STP = 22.4 L/mol

    • Vm at SATP = 24.8 L/mol

  • Molar volume can calculate the chemical amount of a gas.

    • n=VVmn = \frac{V}{V_m}

      • n: chemical amount (moles)

      • V: volume of gas (L)

      • Vm: molar volume (L/mol)

  • Examples provided for molar volume calculations.

Molar Volume and Molar Mass

  • Relate mass to chemical amount using molar mass.

    • n=mMn = \frac{m}{M}

      • n: chemical amount (moles)

      • m: mass (g)

      • M: molar mass (g/mol)

  • Molar Mass (M): mass of one mole of a sample (g/mol).

    • Chemical formula and number of atoms are needed.

    • Multiply the number of each type of atom by the atomic mass, and add together.

  • Examples provided for molar volume and molar mass calculations.

The Law of Combining Volumes

  • Gay-Lussac’s Law (Law of Combining Volumes): Volumes of gases of reactants and products in chemical reactions are always in ratios of whole numbers if measured at the same temperature and pressure.

  • Not all products/reactants need to be gases.

  • Reacting volumes of gases are in whole number ratios, like coefficients in a balanced equation.

  • Correct balanced reaction needed!

  • Examples provided for Law of Combining Volumes.

4.4 The Ideal Gas Law

  • All empirical properties of gases assumed to apply perfectly to all gases: ideal gas.

  • Ideal gas: a hypothetical gas that obeys all gas laws perfectly under all conditions.

    • The size of an ideal gas is negligible.

    • There are no forces of attraction between ideal gas molecules.

    • Ideal gases do not condense when cooled.

    • Ideal gas molecules undergo perfectly elastic collisions in which no energy is lost.

  • Real gas: an actual gas that condenses when cooled and deviates from the gas laws under certain conditions.

    • High pressure (> 1 MPa): Intermolecular attraction leads to condensation.

    • Low temperature: Intermolecular attraction leads to condensation.

  • Real gases behave like ideal gases at relatively low temperatures and pressures (e.g., STP and SATP).

The Ideal Gas Law Equation

  • Ideal-gas equation describes the interrelationship of pressure, temperature, volume, and chemical amount (moles).

    • Boyle’s law: V1PV \propto \frac{1}{P}

    • Charles’ law: VTV \propto T

    • Avogadro’s theory: VnV \propto n

  • VnTPV \propto \frac{nT}{P}

  • PV=nRTPV = nRT

    • P: pressure (kPa)

    • V: volume (L)

    • n: chemical amount (mol)

    • R: ideal gas constant = 8.314LkPamolK8.314 \frac{L \cdot kPa}{mol \cdot K}

    • T: temperature (K)

  • Examples provided for Ideal Gas Law

Unit C: Matter as Solutions, Acids & Bases

  • Covers topics: mixtures, dissolving, concentrations, dilutions, ionization/dissociation, solubility, equilibrium, acid/base nomenclature, pH, Arrhenius definitions, neutralization, strong/weak acids/bases, and titrations.

Chapter 5.1: Solutions and Mixtures

  • Solution: a homogeneous mixture with uniform composition where the components are not visible.

    • Composed of solute and solvent.

      • Solute: substance being dissolved.

      • Solvent: substance doing the dissolving.

  • Solutions are not only aqueous; they can have solutes and solvents that are gases, liquids, or solids.

    • Gasoline: hydrocarbons

    • Air: oxygen in nitrogen

    • Bronze alloy: tin in copper

  • We will focus on aqueous solutions.

Aqueous Solutions

  • Aqueous Solution: Any solution with water as the solvent; denoted with the (aq) symbol after the chemical formula.

  • Most chemical reactions occur in a water environment, therefore we need to understand physical and chemical properties of aqueous solutions

  • Why are chemicals in solution?

    • Easier to handle chemicals

    • Easier to complete reactions

    • Easier to control reactions

Properties of Aqueous Solutions: Solubility

  • Solubility: amount of solute that can be dissolved in a quantity of solvent.

    • Very soluble = HIGH Solubility = (aq)

    • Not very soluble = LOW Solubility = (s)

    • Solubility of a solute is the concentration of solute that dissolves in a given quantity of solvent at a given temperature.

  • Every substance has its own unique solubility data = grams per 100 mL of water

    • Insoluble: less than 0.1 g/100 mL

    • Slightly Soluble: between 0.1 and 1.0 g/100 mL

    • Soluble: greater than 1.0 g/100 mL

  • Example: NaCl is 36 g/100 mL

  • Saturated Solution: contains the maximum amount of dissolved solute at a given temperature; undissolved particles are in the solution.

  • Unsaturated Solution: does not have the maximum amount of solute in it.

  • Range of Solubility: degree of strength based on attraction between solute particles and solvent.

Solubility in Water

  • ELEMENTS generally have low solubility.

  • IONIC COMPOUNDS solubility can be predicted from a solubility chart.

    • Locate anion at the top; decide which row the cation is located in

    • Top row = high solubility (aq); Bottom row = low solubility (s)

  • Trends on the Solubility Chart:

    • All group one ions

    • All compounds containing: NH<em>4+,NO</em>3,ClO<em>3,ClO</em>4NH<em>4^+, NO</em>3^-, ClO<em>3^-, ClO</em>4^-

  • MOLECULAR COMPOUNDS solubility can be predicted based on polarity.

    • “Like dissolves like” so for a substance to dissolve in water, which is polar, the substance must also be polar.

Conductivity

  • Electrolyte: an aqueous solution that conducts electricity:

    • highly soluble ionic compounds

    • soluble ionic hydroxides

    • acids

  • NON-electrolyte: an aqueous solution that does not conduct electricity:

    • molecular compounds and elements

  • Predict the ionic or molecular and electrolyte/non-electrolyte for each substance

  • Diagnostic Test: tested with simple conductivity meter.

Indicators

  • Acids and bases distinguished by their empirical properties in aqueous solutions.

  • Acidic Solutions: blue litmus turns red; pH <7; conductive

    • Hydrogen ion (proton) containing compounds:

  • Basic Solutions: red litmus turns blue; pH >7; conductive

    • Ionic hydroxides:

  • Neutral Solutions: no change in colour of litmus paper, pH =7

    • Ionic; conductive

    • Molecular; not conductive

  • Diagnostic Test: tested using red/blue litmus paper or a pH meter.

Qualitative Chemical Analysis

  • Use known diagnostic tests to determine the identity of four unknown solutions

  • Problem: Which of the solutions (labeled A, B, C, and D) is calcium chloride, citric acid, glucose, and calcium hydroxide?

Qualitative Analysis by Colour

  • Qualitative Analysis by Colour: Color of a solution or a flame produced identifies ions present.

  • NOTE: ion/flame color for various substances can be found on the back of your Periodic Table.

  • Examples of using color to identify substances

Chapter 5.2: Explaining Solutions

  • Arrhenius’ Theory: when a substance dissolves, particles separate and disperse.

    • Determines the type of dissolving particles (electrolyte, nonelectrolyte)

    • Electrolyte: releases charged particles; ionic compounds, acids, and bases

    • Non-electrolyte: disperses w/o neutral particles; molecular compounds

  • Aqueous reactions require knowing major entities present when any substance is in water; use dissociation.

  • Dissociation: separation of ions when an ionic compound dissolves in water.

Arrhenius’s Theory

  • Arrhenius’s theory and how it applies to acids and bases: Acids are substances that ionize in aqueous solution to form hydrogen ions, and bases are substances that dissociate to form hydroxide ions in aqueous solution.

  • Acids ionize in water to produce hydrogen ions ○ Acid → H+(aq)+anionH^+ (aq) + anion

  • Bases dissociate in water to produce hydroxide ions ○ Base → Cation+OH(aq)Cation + OH^- (aq)

  • Acid properties related to H+H^+ and basic properties related to OHOH^-

  • Tiny proton exist on its own forming a hydronium ion, H3O+(aq)H_3O^+ (aq)

  • Limitations of the Arrhenius Theory of Acids and Bases: does not explain certain substances failing to produce neutral solutions!

Modified Arrhenius Theory

  • Modified Arrhenius Theory: involves the collision of dissolved substances with water molecules.

  • Remember that all acidic and basic substances are aqueous solutions, so the particles will constantly be colliding with, and may also react with, water molecules.

  • An acid reacts with water to produce H<em>3O+(aq)H<em>3O^+ (aq) in aqueous solution Acid+H</em>2OH3O+(aq)Acid + H</em>2O → H_3O^+ (aq)

  • A base dissociates and reacts with water to produce OH(aq)OH^- (aq) in aqueous solution Base+H2OOH(aq)Base + H_2O → OH^-(aq)

Acid Nomenclature

  • Two systems for naming acids:

    • IUPAC Nomenclature: names the acid as though it were an ionic compound and adds aqueous in front of it.

    • Classical System:

      • Hydrogen ide = hydroic acid

      • Hydrogen ate = ___ic acid

      • Hydrogen ite = ___ous acid

  • Practice using the modified Arrhenius theory

Strength of Acids and Bases

  • Acids with the same initial concentration can have different degrees of acidic properties!

  • Strong and Weak Acids:

    • Strong Acid Reacts completely with water; ex: HCl+H<em>2OCl+H</em>3O+</p></li><li><p>WeakAcidReactsincompletelywithwaterH3COOH+H2OH3O++CH3COOH</p><p>Many[H3O+(aq)]ionsinsolution/Few[H3O+(aq)]ionsinsolution;Highconductivity/Lowconductivity;RelativelylowpH/RelativelyhighpH(closerto7)<br>Highrateofreactionwithactivemetals/carbonates/Lowerrateofreactionwithactivemetals/carbonatesFewstrongacids/Manyweakacidsalltheonesthatarentstrong!</p></li></ul></li><li><p>StrongandWeakBases:</p><ul><li><p>StrongBaseDissociatescompletelytoreleaseOH(aq)ions/WeakBaseReactsincompletelywithwatertoproducefewOHions</p><p>MOH(aq)M+(aq)+OH(aq)WhereM=metalion/B(aq)+H2O(l)OH(aq)+BalancingEntityWhereB=base(molecule/ion)</p></li></ul></li><li><p>PolyproticSubstances:</p><ul><li><p>MonoproticAcids:1acidichydrogenEx:HCl</p></li><li><p>PolyproticAcids:acidswmorethanoneacidichydrogenEx:H3PO4</p></li></ul></li><li><p>MonoproticBasesvsPolyproticBases</p><ul><li><p>Bariumexamples</p></li></ul></li></ul><h3id="5b733d4b808a4ae49dc0a0a852cf020a"datatocid="5b733d4b808a4ae49dc0a0a852cf020a"collapsed="false"seolevelmigrated="true">DissociationEquations</h3><ul><li><p>DissociationEquationsforsolubleioniccompounds:cation(aq),anion(aq),H2O(l)</p><ul><li><p>Sodiumfluorideisplacedinwater<br>DissociationEquationsNaF(s)Na+(aq)+F(aq);MajorEntitiesNa+(aq),F(aq),H2O(l)</p></li><li><p>Insolubleioniccompounds:MajorEntities:compound(s),H2O(l)<br>DissociationEquationsMgCO3(s)MgCO3(s);MajorEntities:MgCO3(s),H2O(l)</p></li><li><p>MolecularCompounds:doNOTdissociateinwater;MajorEntities:H2O(l)andmoleculestatewilldependonpolarity</p></li><li><p>AcidicCompounds:ArrheniustheorystatesthatacidsionizeinwatertoproduceH+(aq)ionsandnegativeions;ModifiedArrheniustheorystatesthatacidsreactwithwatertoproduceH3O+(aq);Bothareacceptablewhenwritingthedissociationequationforacids,howeverwetypicallywritedissociationequationsbasedonArrheniusoriginaltheory</p></li></ul><p>StrongAcids:HIGHionization,MajorEntities:H+(aq),anion,H2O(l)</p><p>HCl(aq)H+(aq)+Cl(aq);MajorEntitiesH+(aq),Cl(aq),H2O(l)</p><p>WeakAcids:lowdegreeofionizationandareweakconductors;MajorEntities:acid(aq),H2O(l)</p><p>CH3COOH(aq)H+(aq)+CH3COO(aq);MajorEntities:CH3COOH(aq),H+(aq),CH3COO(aq),H2O(l)</p></li></ul><p>NOTE:SummaryofDissociationEquationsandMajorEntities</p><h3id="e9ac51e74eb3406da601a9a31fb50c0d"datatocid="e9ac51e74eb3406da601a9a31fb50c0d"collapsed="false"seolevelmigrated="true">EnergyChangesinDissolving</h3><ul><li><p>Difficultypredictingwhetherthedissolvingofasolutewillbeendothermicorexothermic;Weonlyobservethenetenergychange.<br>:endothermic/exothermic</p></li><li><p>Breakingbondsrequiresenergyendothermic;<br>:Formingnewbondsreleasesenergyexothermic;</p></li><li><p>Theoverallenergyinthedissolvingprocessrequiresconsideringbothenergyabsorbedandreleased.</p></li><li><p>GeneralizationsforSolubilityinWater:</p></li></ul><h3id="4aaead120d7b46dfa77effc55ab0fc1b"datatocid="4aaead120d7b46dfa77effc55ab0fc1b"collapsed="false"seolevelmigrated="true">Generalization</h3><ul><li><p>Solids:energyisneededtobreakbondsholdingthesolutetogetherthereforeastemperatureincreases;thesolubilityofasolidalsoincreases.<br>:Gases:athightemperaturesadissolvedgasgainsenergyandescapesfromtheliquid(solvent);thereforethesolubilityofagasdecreasesathighertemperatures;Gaseshavedecreasessolubilityatincreasestemperaturesandincreasespressures<br>:Liquids:Difficulttogeneralizeeffectoftemp:1)polarliquidshaveincreasesolubilityatincreasetemperatureandaresaidtobemiscible.2)nonpolarliquidsdonotdissolveandformaseparatelayerandaresaidtobeimmiscibleinwater.<br>:Elements:generallyhavelowsolubilityinwater</p></li></ul><h3id="7619c166f15847a694bd44e84cb637cb"datatocid="7619c166f15847a694bd44e84cb637cb"collapsed="false"seolevelmigrated="true">Equilibrium</h3><ul><li><p>DynamicEquilibrium:Amountofundissolvedsoluteatthebottomremainsunchanged;undissolveddissolvesanddissolvedprecipitatesoutofsolutionandcrystallizeandissaidtobeininastateofdynamicequilibrium.<br>:Equilibriumoccurswhenaprocess(dissolving)andthereverseprocess(crystallization)takeplaceatthesamerateinaclosedsystem;RepresentingDissolving,Crystallization,andEquilibriumforaSaturatedSolution:<br>:Dissolving:X(s)X(aq)<br>:Crystallization:X(aq)X(s)<br>:Equilibrium:X(s)X(aq)</p></li></ul><h3id="a9931ba2aa3a4973be05d874db719db5"datatocid="a9931ba2aa3a4973be05d874db719db5"collapsed="false"seolevelmigrated="true">Chapter5.3:SolutionConcentration/awaytocompareamt</h3><ul><li><p>Solutioncontainssolute+solvent1)solute:substanceparticle.2)Solventdissolvessolute<br>:Concentration(quantity;Typically,concentration=quantityofsolutequantityofsolution)1)Diluteiflessparticlesperunitvolume.2)Concentratedifmoreparticlesperunitvolume.</p></li></ul><h3id="bf96949f05f24d72a182c676438c75b5"datatocid="bf96949f05f24d72a182c676438c75b5"collapsed="false"seolevelmigrated="true">ThreeMainMethodsofConcentration</h3><ul><li><p>1.AmountConcentration/Molarity/MolarConcentration:thechemicalamount(moles)ofsolutedissolvedinonelitreofsolution.HCl + H<em>2O → Cl^- + H</em>3O^+</p></li><li><p>Weak Acid Reacts incompletely with water H3COOH+ H2O ↔ H3O+ + CH3COOH-</p><p>Many [H3O+ (aq)] ions in solution / Few [H3O+ (aq)] ions in solution; High conductivity / Low conductivity; Relatively low pH / Relatively high pH (closer to 7)<br>High rate of reaction with active metals/carbonates / Lower rate of reaction with active metals/carbonates Few strong acids / Many weak acids - all the ones that aren’t strong!</p></li></ul></li><li><p>Strong and Weak Bases:</p><ul><li><p>Strong Base Dissociates completely to release OH- (aq) ions / Weak Base Reacts incompletely with water to produce few OH- ions</p><p>MOH(aq)→ M+ (aq) + OH- (aq) Where M = metal ion / B(aq) + H2O(l) ↔ OH- (aq) + Balancing Entity Where B = base (molecule/ ion)</p></li></ul></li><li><p>Polyprotic Substances:</p><ul><li><p>Monoprotic Acids: 1 acidic hydrogen Ex: HCl</p></li><li><p>Polyprotic Acids: acids w more than one acidic hydrogen Ex: H3PO4</p></li></ul></li><li><p>Monoprotic Bases vs Polyprotic Bases</p><ul><li><p>Barium examples</p></li></ul></li></ul><h3 id="5b733d4b-808a-4ae4-9dc0-a0a852cf020a" data-toc-id="5b733d4b-808a-4ae4-9dc0-a0a852cf020a" collapsed="false" seolevelmigrated="true">Dissociation Equations</h3><ul><li><p>Dissociation Equations for soluble ionic compounds: cation(aq), anion(aq), H2O(l)</p><ul><li><p>Sodium fluoride is placed in water<br>Dissociation Equations NaF (s) → Na+ (aq) + F- (aq) ; Major Entities Na+(aq), F-(aq), H2O(l)</p></li><li><p>Insoluble ionic compounds: Major Entities: compound(s), H2O(l)<br>Dissociation Equations MgCO3 (s) → MgCO3 (s); Major Entities: MgCO3 (s), H2O (l)</p></li><li><p>Molecular Compounds: *do NOT dissociate in water; Major Entities: H2O(l) and molecule state will depend on polarity</p></li><li><p>Acidic Compounds: Arrhenius’ theory states that acids ionize in water to produce H+ (aq) ions and negative ions; Modified Arrhenius’ theory states that acids react with water to produce H3O+ (aq); Both are acceptable when writing the dissociation equation for acids, however we typically write dissociation equations based on Arrhenius’ original theory</p></li></ul><p>Strong Acids: HIGH ionization, Major Entities: H+ (aq), anion, H2O(l)</p><p>HCl (aq) → H+ (aq) + Cl- (aq) ; Major Entities H+ (aq), Cl- (aq), H2O(l)</p><p>Weak Acids: low degree of ionization and are weak conductors; Major Entities: acid(aq), H2O(l)</p><p>CH3COOH (aq) ↔ H+ (aq) + CH3COO- (aq); Major Entities: CH3COOH (aq), H+ (aq), CH3COO- (aq),H2O(l)</p></li></ul><p>NOTE: Summary of Dissociation Equations and Major Entities</p><h3 id="e9ac51e7-4eb3-406d-a601-a9a31fb50c0d" data-toc-id="e9ac51e7-4eb3-406d-a601-a9a31fb50c0d" collapsed="false" seolevelmigrated="true">Energy Changes in Dissolving</h3><ul><li><p>Difficulty predicting whether the dissolving of a solute will be endothermic or exothermic; We only observe the net energy change.<br>: endothermic / exothermic</p></li><li><p>Breaking bonds requires energy endothermic;<br>: Forming new bonds releases energy exothermic;</p></li><li><p>The overall energy in the dissolving process requires considering both energy absorbed and released.</p></li><li><p>Generalizations for Solubility in Water:</p></li></ul><h3 id="4aaead12-0d7b-46df-a77e-ffc55ab0fc1b" data-toc-id="4aaead12-0d7b-46df-a77e-ffc55ab0fc1b" collapsed="false" seolevelmigrated="true">Generalization</h3><ul><li><p>Solids: energy is needed to break bonds holding the solute together therefore as temperature increases; the solubility of a solid also increases.<br>: Gases: at high temperatures a dissolved gas gains energy and escapes from the liquid (solvent); therefore the solubility of a gas decreases at higher temperatures; Gases have decreases solubility at increases temperatures and increases pressures<br>: Liquids: Difficult to generalize effect of temp: 1) polar liquids have increase solubility at increase temperature and are said to be miscible. 2) nonpolar liquids do not dissolve and form a separate layer and are said to be immiscible in water.<br>: Elements: generally have low solubility in water</p></li></ul><h3 id="7619c166-f158-47a6-94bd-44e84cb637cb" data-toc-id="7619c166-f158-47a6-94bd-44e84cb637cb" collapsed="false" seolevelmigrated="true">Equilibrium</h3><ul><li><p>DynamicEquilibrium: Amount of undissolved solute at the bottom remains unchanged; undissolved dissolves and dissolved precipitates out of solution and crystallize and is said to be in in a state of dynamic equilibrium.<br>: Equilibrium occurs when a process (dissolving) and the reverse process (crystallization) take place at the same rate in a closed system; Representing Dissolving, Crystallization, and Equilibrium for a Saturated Solution:<br>: Dissolving: X(s) → X(aq)<br>: Crystallization: X(aq) → X(s)<br>: Equilibrium: X(s) ↔ X(aq)</p></li></ul><h3 id="a9931ba2-aa3a-4973-be05-d874db719db5" data-toc-id="a9931ba2-aa3a-4973-be05-d874db719db5" collapsed="false" seolevelmigrated="true">Chapter 5.3: Solution Concentration/ a way to compare amt</h3><ul><li><p>Solution contains solute+ solvent 1) solute: substance particle. 2) Solvent dissolves solute<br>: Concentration (quantity;Typically, concentration = quantity of solute_ quantity of solution) 1)Dilute if less particles per unit volume. 2)Concentrated if more particles per unit volume.</p></li></ul><h3 id="bf96949f-05f2-4d72-a182-c676438c75b5" data-toc-id="bf96949f-05f2-4d72-a182-c676438c75b5" collapsed="false" seolevelmigrated="true">Three Main Methods of Concentration</h3><ul><li><p>1.AmountConcentration/Molarity/MolarConcentration: the chemical amount (moles) of solute dissolved in one litre of solution.FORMULA: 𝑐 = 𝑛/𝑣Units:mol/LWhere:c=concentration(mol/L);n=numberofmoles(mol);V=volume(L)</p></li><li><p>2.Partspermillion(ppm):usedfordilutesolutions;alteredppmunitsbyalteringppmtoincorporateafactorof<em>FORMULA:Units: mol/L Where: c = concentration (mol/L); n = number of moles (mol); V = volume (L)</p></li><li><p>2. Parts per million (ppm):used for dilute solutions; altered ppm units by altering ppm to incorporate a factor of <em>FORMULA:𝑐=\frac{𝑚𝑠𝑜𝑙𝑢𝑡𝑒(𝑚𝑔)}{𝑚𝑠𝑜𝑙𝑢𝑡𝑖𝑜𝑛(𝑘𝑔)}Units:mg/L,mg/kg,ppm,(1ppm=1mg/L=1mg/kg)Becauseverydiluteaqueoussolutionsaresimilartopurewater,theirdensitiesareconsideredtobethesame(1g/mL),therefore:Units: mg/L, mg/kg, ppm, (1 ppm = 1 mg/L = 1 mg/kg) Because very dilute aqueous solutions are similar to pure water, their densities are considered to be the same (1 g/mL), therefore:1 \text{ ppm} = 1 \frac{g}{10^6 mL} = 1 \frac{mg}{L} = 1 \frac{mg}{kg}$$\n 3. percent concentration= solute / solution X 100%: 1) percent volume by volume concentration (% v/v):volume in mL that dissolves in every 100 mL of solution. 2) percent by mass/ volume(% w/v= mass solute=grams that dissolves in every 100 mL of solution.3) percent by mass/mass (% w/w) mass solute=grams dissolved in every 100 grams of solution.

    Concentration of Ions

    • Solutions of ionic compounds and strong acids are able to conduct electricity therefore there must be ions present in solution * Molar concentration of ions in solution depends on the number of ions making up the compound. Examples: Na3PO4 (aq) / CaCl2 (aq)
      Follow steps for calculating Ion Concentration: 1) Write a balanced dissociation/ionization equation. 2) The ion concentration is always a whole number multiple of the compound concentration. NOTE: Square brackets around an [ion] or formula indicate the concentration of the substance within the brackets.

    Ions in Solution

    • Problems to practice

    Chapter 5.4: Preparation of Solutions

    • When a solid, you must calculate the amount of mass required to form the desired concentration and then mix that amount carefully with water following the steps outlined:
      : Standard Solution: solution w known concentration. Mass solid reqd / Mass solute is in a clean/dry beaker/Dissolved solid in distilled water/Transfer solution to a clean flask/ Add distilled to bottom of meniscus/ Invert and mix

    Calculating the mass needed can be done using the following equations that we know: 1)C = n/V 2) m = Mn / Example: What mass of lead (II) nitrate must be used to produce 350 mL of solution with concentration 0.125 mol/L?

    Methods of Concentration:

    • Dilution = (decreasing solution concentration by adding solution) / During the process of dilution, the volume increases while the concentration decreases.
      1) Calculating mass needed: mass solution reqd 2) Add distilled water that is half way reqd. 3) Reqd volume of solution using a pipette . 4) Add stock solution to the clean volumetric flask. 5)Solution of meniscus must be on line on a flask 6) Invert and mix / C1V1 = C2V2 / This works because the quantity of solute is not changing ni = nf *On tests, you must not only calculate the solution needed, but needed procedures/ when diluting all concentrated reagents, especially acids, ALWAYS add the stock solution TO the quantity of water… not the other way around!

    PH

    • calculating power of hydrogen w 2 methods! 1 trace amt of hydronium hydrozide ion from is water that does ionize to small degree/ hydrate protin/1) H20= hydronium+ hyroxide = acid + base) 2 water molecules + hydronium= concentration 1 ^-7 power
      acid increase-concentration ; increase hydronium/ increase acid // hydrozide in base solution ;/ increase conc base PH increase/ decrease concentration power hydrogen is shortmethod communication hydrogen concentration powerhydrogen = hyrdounium . in power hydrogen is 0 -14scale / hydronium concentration is neutral-concentration .

    PH Calculations

    • PH is defined as power to hydronium and the hydronium concentration / Example: GIVEN concentration CALCULATE PH = POWER HYDROGEN CONCENTRATION!/ PH has not unit the PH is negative on log scale of hdyronium = power + /significant fig rules are normal and concentration sig figs sig figs / the number sig fig that comes after decimal PH and ph needs to follow sig fig /sample; questions and chart!
      : Calculating pH and pOH. Using the formulas, pH(H3O+ (hydronium ion))=-log (H30). pOH ( hydroxide)=- log.1)pOH +PH =14!!!!/2) 14+log (H3O)=POH!!!/3) OH 14+ log ( OH ) =PH!!!

    • Calculating phOH/ acid base indicator: is substance changer color is related ph change. Indicator exists in 2 colors 1 of color and another / Indicators PH range inside cover