Study Notes on Second Law of Thermodynamics

Kwame Nkrumah University of Science & Technology

Introduction to Engineering Thermodynamics
  • Course: Engineering Thermodynamics (MME 365)

  • Instructor: Kofi Owura Amoabeng, PhD

  • Department of Mechanical Engineering

  • University: Kwame Nkrumah University of Science and Technology, Kumasi, Ghana

Second Law of Thermodynamics
Fundamental Concepts
  • Directional Processes:

    • Processes occur in a specific direction, which cannot be reversed.

    • Example: Water flows down a waterfall (high to low potential energy).

    • Example: Heat naturally flows from a high temperature to a low temperature.

  • Gas Expansion:

    • Gases expand from areas of high pressure to areas of low pressure.

    • Example: Heat generation when electrical current flows.

Thermal Energy Reservoir (Heat Reservoir)
  • Definition:

    • A hypothetical body with a large heat capacity.

    • Can supply or absorb finite amounts of heat without changing temperature.

  • Properties:

    • The temperature of a heat reservoir remains constant, ensuring reversible processes occur within it.

    • A reservoir supplying heat is called a source; one absorbing heat is a sink.

  • Examples of Sinks:

    • Atmosphere, rivers, oceans.

  • Examples of Sources:

    • Boiler, furnace, nuclear reactor, the sun.

Heat Engine
  • Definition:

    • A closed system that operates in a cycle, producing work from heat.

  • Important Notes:

    • It is impossible for a heat engine to convert heat entirely into work (i.e. 100% thermal efficiency is not achievable).

    • Example of Heat Conversion:

    • Types of Heat Flow:

      • High Temperature (hot reservoir) to Low Temperature (cold reservoir).

    • Thermal Efficiency is defined as:
      ηth=WnetQin\eta_{th} = \frac{W_{net}}{Q_{in}} where:

    • WnetW_{net} = Work output,

    • QinQ_{in} = Heat input.

  • Conditions for Heat Engine Operation:

    1. Receives heat from a high-temperature source.

    2. Converts part of this heat to work.

    3. Rejects remaining heat to low-temperature sink.

    4. Completes a thermodynamic cycle.

  • Example:

    • A heat engine with a heat input of 400 MW and a heat output of 160 MW produces 240 MW of work.

  • Operation of Common Heat Engines:

    • Types include steam power plants, gas power plants, and automobile engines.

Thermal Efficiency of a Heat Engine
  • Thermal Efficiency Calculation: For a heat engine: ηth=WnetQin\eta_{th} = \frac{W_{net}}{Q_{in}}

    • Given inputs:

    • Qin=400MWQ_{in} = 400 \, MW

    • Qout=165MWQ_{out} = 165 \, MW

    • Wout=240MWW_{out} = 240 \, MW

    • Thus,
      ηth=160400=0.40=40%\eta_{th} = \frac{160}{400} = 0.40 = 40\%

Kelvin-Planck Statement of the Second Law
  • Statement:

    • It is impossible for any device operating in a cycle to receive heat from a reservoir and do an equivalent amount of work without some waste heat being rejected.

Heat Engine Examples
  1. Example 1:

    • Rate of heat transfer to heat engine = 80 MW

    • Rate of waste heat rejection = 50 MW

    • Wnet=QinQout=30MWW_{net} = Q_{in} - Q_{out} = 30 \, MW

    • ηth=3080=37.5%\eta_{th}= \frac{30}{80} = 37.5\%

  2. Example 2:

    • Steam power plant produces 75 kW, rejects 190 kW.

    • Find: a) Heat supplied = 265 kW; b) Thermal efficiency = 28.3%.

Reversed Heat Engine
  • Definition:

    • A closed system that operates in a cycle, extracting heat from a low-temperature reservoir and rejecting it to a high-temperature reservoir, while doing work on the system.

  • Types:

    • Refrigerators (extract heat) and heat pumps (reject heat).

Performance of Refrigerators and Heat Pumps
  • Coefficient of Performance (COP):

    • For refrigerators:
      COPR=QCWinCOP_{R} = \frac{Q_{C}}{W_{in}}

    • For heat pumps:
      COPHP=QHWinCOP_{HP} = \frac{Q_{H}}{W_{in}}

Clausius Statement of the Second Law
  • Statement:

    • Impossible to operate a system in a cycle, transferring heat from cooler to hotter body without work being done.

Examples of Reversed Heat Engine Performance
  1. Example 1:

    • Refrigerator removing heat = 360 kJ/min, power input = 2 kW.

    • Determine COP and heat rejection rate. Suggested COP = 3, heat rejection = 8 kW.

Entropy
  • Definition:

    • Quantitative measure of a system’s disorder; indicates energy unavailable for work.

  • Mathematical Expressions:

    • For reversible process:
      dS=δQrevTdS = \frac{\delta Q_{rev}}{T}

    • For irreversible process:
      dS > \frac{\delta Q}{T}

Key Theorems and Principles
  • Carnot Principle:

    • A reversible heat engine cycle maximizes net work output between two temperature limits.

  • Carnot Efficiency:

    • Maximum efficiency of a reversible heat engine:
      ηth,rev=1TCTH\eta_{th,rev} = 1 - \frac{T_C}{T_H}

Conclusion
  • Integration of the Laws:

    • Every cyclic process must comply with both the first law (energy conservation) and the second law (entropy considerations).