L17 - Extensions 3

Section 5.2: Gene Interactions and Epistasis

  • Learning Objectives: At the end of this section, students should be able to:

    • Explain how to determine if two recessive mutants with similar phenotypes have mutations in the same gene or different genes.

    • Explain how gene interactions, including epistatic interactions, affect offspring phenotypic ratios.

    • Identify types of genetic interactions from crosses and use the chi-square test to statistically test if observed phenotypes match expectations for a given type of inheritance.

Gene Interactions

  • The expression of one gene can mask the expression of a second gene, termed Epistasis (derived from the Greek term meaning "stand upon").

  • In double mutants, the phenotype expressed is that of one mutation, while the other mutation remains unnoticed.

  • Epistatic genes: A gene that masks the effect of another gene can be:

    • Dominant: Requires only one allele to mask the other.

    • Recessive: Requires two alleles to mask the effect.

Review from Previous Lecture
  • Two genes influencing a single characteristic can exhibit independent assortment but not act independently in expression, resulting in a phenotypic ratio of 9:3:3:19:3:3:1 for F2 generation for a single trait.

Definitions Related to Epistasis

  • Dominance: Refers to the relationship between alleles of a gene, where one allele masks the expression of another.

    • Complete dominance occurs when one allele completely masks the other at the locus.

  • Epistasis occurs when one gene masks the effect of another gene located at a different locus.

Examples of Epistasis
  • Recessive Epistasis: Illustrated by coat color in Labrador retrievers.

    • B gene: Encodes black pigment (B = dominant; b = recessive for brown color).

    • E gene: Encodes an enzyme essential for pigment deposition.

      • E = enables pigment deposition; e = inhibits pigment deposition.

    • Genotype ee (homozygous recessive) masks the effect of the B gene, resulting in a yellow coat regardless of the B gene alleles.

Crosses and Ratios for Epistasis

  • In a cross between genotypes Bb Ee x Bb Ee, expected phenotypic ratios are derived:

    • The diagnostic ratio for recessive epistasis is 9:3:49:3:4 which indicates the presence of individuals with yellow fur (homozygous recessive 'ee').

Dominant Epistasis Example

  • Illustrated by fruit color in squash.

    • W gene: Dominant W masks the expression of the Y gene.

      • W = dominant (no enzyme I); w = recessive (produces enzyme).

    • Y gene encodes enzyme II involved in further coloration of the fruit.

    • If genotype has W (W_), it will mask any effect from the Y gene, resulting in a specific fruit color.

Dominant Epistasis Cross Example
  • Crossing Ww Yy by Ww Yy, phenotypic ratio expected is 12:3:112:3:1, indicating both dominant and recessive contributions.

  • Characteristics are classifiable to analyze expected phenotypic outcomes relative to interactions.

Statistical Testing with Chi-square

  • A Chi-square test is used to compare observed phenotypic ratios versus expected ratios. If p-value < 0.05 indicates significant deviation, suggesting the effect of non-random factors or epistasis.

  • The null hypothesis states that differences between observed and expected ratios are due to random chance.

Section 5.4: Polygenic Inheritance

  • Many traits are influenced by multiple genes (polygenic characteristics).

  • Traits can present continuous characteristics due to the additive effects of multiple genes during development.

  • Environmental factors can significantly influence phenotype expression, leading to variability.

Effects of Environment on Phenotype

  • External conditions (temperature, nutrition) can alter gene expression and impact observable traits.

    • For example, the Himalayan allele exhibits temperature dependence affecting pigmentation.

  • Continuous (quantitative) traits such as height, weight, and blood pressure often reflect polygenic influences and are subject to environmental modulation.

The Complementation Test

  • Utilized to determine whether two mutations affecting the same phenotype are in the same gene (locus) or different loci.

    • If offspring from a cross of homozygous mutants express a wild-type phenotype, mutations reside on different loci and exhibit complementarity.

    • If mutants expressed the mutant phenotype, they are on the same locus.

Examples and Concepts Discussed

  • 9:7 Phenotypic Ratio: Indicative of complementary gene interactions where any homozygous mutation can block the phenotype produced by the other allele.

  • Connections made to various genetic phenomena such as penetrance and expressivity in pathological cases like cystic fibrosis or phenylketonuria (PKU).

    • Variable expressivity (different manifestations of the same genotype) leads to varied presentations across instances of the same genetic condition.

Practice Problems Suggestions

  • Students are encouraged to practice with textbook examples to enhance proficiency in identifying genotypes and phenotypes resulting from various genetic interactions, particularly before the upcoming midterm assessments.

  • Key practice areas include:

    • Understanding phenotypic ratios (9:3:3:1; 12:3:1) and applying Chi-square tests.

    • Resolving complex interactions with gene queries for continuous traits to assess environmental impact.