Quadratic Equations and Functions - 1st Quarter Review

Quadratic Formula and Roots

  • Quadratic Formula: roots of ax2+bx+c=0ax^2+bx+c=0 are
    x=b±b24ac2a.x=\frac{-b\,\pm\,\sqrt{b^2-4ac}}{2a}.

  • Examples (solve for x):

    • Solve x27x+10=0x^2-7x+10=0.
    • Factorization: x27x+10=(x5)(x2)x^2-7x+10=(x-5)(x-2)
    • Roots: x=5extorx=2.x=5\quad ext{or}\quad x=2.
    • Solve 2x2+3x9=02x^2+3x-9=0.
    • Discriminant: D=b24ac=324(2)(9)=9+72=81.D=b^2-4ac=3^2-4(2)(-9)=9+72=81.
    • Roots: x=3±8122=3±94.x=\frac{-3\pm\sqrt{81}}{2\cdot 2}=\frac{-3\pm9}{4}.
    • So x=64=32orx=124=3.x=\frac{6}{4}=\frac{3}{2}\quad\text{or}\quad x=\frac{-12}{4}=-3.
  • Sum and Product of the Roots

    • For roots r<em>1,r</em>2r<em>1,r</em>2 of ax2+bx+c=0ax^2+bx+c=0,
    • Sum: $r1+r2=-\dfrac{b}{a}$
    • Product: $r1r2=\dfrac{c}{a}$
    • If roots are known, the equation can be written as
      x2(r<em>1+r</em>2)x+(r<em>1r</em>2)=0.x^2-(r<em>1+r</em>2)x+(r<em>1r</em>2)=0.
  • Example: roots 8 and –5

    • Sum: 8+(5)=38+(-5)=3
    • Product: 8(5)=408\cdot(-5)=-40
    • Equation in standard form: x23x40=0.x^2-3x-40=0.
  • Sum and Product without solving (practice)

    • Given equation x212x3=0x^2-12x-3=0 (rewriting x212x=3x^2-12x=3 as x212x3=0x^2-12x-3=0),
    • Sum of roots: 1212
    • Product of roots: 3-3
  • Discriminant and Nature of Roots

    • Discriminant: D=b24ac.D=b^2-4ac.
    • If D=0D=0: roots are real and equal.
    • If D>0 and DD is a perfect square: roots are real, rational, and unequal.
    • If D>0 and DD is not a perfect square: roots are real, irrational, and unequal.
    • If D<0: roots are imaginary (complex).
  • Quick guide for nature of roots

    • D=0D=0\Rightarrow real & equal
    • D>0 and perfect square \Rightarrow real, rational, unequal
    • D>0 and not perfect square \Rightarrow real, irrational, unequal
    • D<0\Rightarrow imaginary
  • Discriminant practice
    1) Find the discriminant of x2+4x+5=0x^2+4x+5=0 and describe the roots.

    • D=4^2-4(1)(5)=16-20=-4<0
    • Roots are imaginary.
      2) Find the discriminant of 3x22x1=03x^2-2x-1=0 and describe the roots.
    • D=(2)24(3)(1)=4+12=16D=(-2)^2-4(3)(-1)=4+12=16
    • D>0 and a perfect square ⇒ real, rational, unequal roots.
  • Rational Algebraic Equations

    • 1) Solve: x+23=5x.\dfrac{x+2}{3}=5x.
    • Multiply both sides by 3: x+2=15xx+2=15x
    • Bring terms together: 2=14x2=14x
    • x=17.x=\dfrac{1}{7}.
    • 2) Solve: 8x=x18.\dfrac{8}{x}=\dfrac{x}{18}.
    • Cross-multiply: 818=x28\cdot18=x^2
    • x2=144x^2=144
    • x=±12.x=\pm12. (Note: x=0 is not allowed in the original equation.)
    • 3) A rational-application word problem
    • Slower crew takes 8 days; faster crew takes 4 days to complete the same wall.
    • Rates: slower = $1/8$ per day; faster = $1/4$ per day.
    • If slower works alone for 3 days: work done = 318=383\cdot \tfrac{1}{8}=\tfrac{3}{8}; remaining = 138=581-\tfrac{3}{8}=\tfrac{5}{8}
    • Combined rate = 18+14=38\tfrac{1}{8}+\tfrac{1}{4}=\tfrac{3}{8} per day.
    • Time to finish remaining 58\tfrac{5}{8} at 38\tfrac{3}{8} per day:
      t=5838=53 days.t=\dfrac{\tfrac{5}{8}}{\tfrac{3}{8}}=\dfrac{5}{3}\text{ days}.
    • Therefore, time after joining: 53\dfrac{5}{3} days; total time from start: 3+53=1433+\dfrac{5}{3}=\dfrac{14}{3} days (about 4.67 days).
    • 4) Printing presses word problem
    • Slower press: completes order in 10 hours ⇒ rate 1/101/10 per hour; Faster: 6 hours ⇒ 1/61/6 per hour.
    • Slower works alone for 4 hours: amount completed = 4110=254\cdot\tfrac{1}{10}=\tfrac{2}{5}; remaining = 125=35.1-\tfrac{2}{5}=\tfrac{3}{5}.
    • Joined rate = 110+16=830=415\tfrac{1}{10}+\tfrac{1}{6}=\tfrac{8}{30}=\tfrac{4}{15} per hour.
    • Time to finish remaining: t=35415=35154=94=2.25 hours.t=\dfrac{\tfrac{3}{5}}{\tfrac{4}{15}}=\dfrac{3}{5}\cdot\dfrac{15}{4}=\dfrac{9}{4}=2.25\text{ hours}.
    • Total time from start: 4+2.25=6.25 hours4+2.25=6.25\text{ hours}; or remaining work finished in 2.25 hours after joining.
  • Quadratic Inequality

    • 1) Solve x^2+4x-21<0.
    • Factor: (x+7)(x-3)<0.
    • Parabola opens upward; negative between roots: \(-7<x<3).
    • Solution: (7,3).(-7,\,3).
    • 2) Solve x28x+150.x^2-8x+15\ge 0.
    • Factor: (x3)(x5)0.(x-3)(x-5)\ge 0.
    • Since parabola opens upward, inequality holds for x3orx5.x\le 3\quad\text{or}\quad x\ge 5.

Quadratic Functions and Graphs

  • Standard form: f(x)=ax2+bx+c.f(x)=ax^2+bx+c.

  • Vertex form: f(x)=a(xh)2+kf(x)=a(x-h)^2+k where the vertex is (h,k).(h,k).

  • Vertex coordinates from standard form

    • h=b2ah=-\frac{b}{2a}
    • k=4acb24ak=\frac{4ac-b^2}{4a}
  • Vertex form provides direct access to the vertex and allows easy graphing and analysis of shifts, stretches, and vertical translations.

  • Common features

    • Axis of symmetry: x=hx=h
    • If a>0, parabola opens upward; the vertex is a minimum. If a<0, opens downward; the vertex is a maximum.
    • Range: depends on sign of aa and the vertex kk; for example, if a>0, range is [k,)[k,\infty).
  • Example problem 1: Given f(x)=2x28x+11f(x)=2x^2-8x+11

    • Vertex: h=822=84=2h=-\frac{-8}{2\cdot 2}=\frac{8}{4}=2
    • Vertex value: k=f(2)=2(4)16+11=816+11=3k=f(2)=2(4)-16+11=8-16+11=3
    • Vertex form: f(x)=2(x2)2+3f(x)=2(x-2)^2+3
    • Axis of symmetry: x=2x=2
    • Min value: 33; Range: [3,)[3,\infty)
    • Table of values (example):
    • For symmetry around x=2, evaluate at x=0,1,2,3,4:
    • f(0)=11,f(1)=5,f(2)=3,f(3)=5,f(4)=11.f(0)=11,\, f(1)=5,\, f(2)=3,\, f(3)=5,\, f(4)=11.
  • Graph: interpret visually (parabola opens upward, vertex at (2,3))

  • EQUATION 1 (vertex form construction)

    • Task: Determine the equation of the graph in vertex form given a Vertex and a Point on the graph.
    • Method (general): If the vertex is (h,k)(h,k) and a point on the graph is (x<em>1,y</em>1)(x<em>1,y</em>1), then
    • The form is f(x)=a(xh)2+kf(x)=a(x-h)^2+k where
    • a=y<em>1k(x</em>1h)2a=\frac{y<em>1-k}{(x</em>1-h)^2}
    • This yields the explicit vertex-form equation once a, h, k are known.
  • Problem-Solving: Applications involving triangles, area, and projectile paths

    • 1) Rectangular garden
    • Length is 5 meters longer than width; area is 84 m^2.
    • Let width = w; length = w+5.
    • Equation: w(w+5)=84w2+5w84=0.w(w+5)=84\Rightarrow w^2+5w-84=0.
    • Discriminant: D=524(1)(84)=25+336=361=192.D=5^2-4(1)(-84)=25+336=361=19^2.
    • Solutions: w=5±192w=\frac{-5\pm19}{2}w=7 or w=12.w=7\text{ or }w=-12.
    • Physical width: w0w\ge 0, so w=7w=7, and length = 1212.
    • 2) Soccer ball trajectory
    • Model: y=2x2+8x+6y=-2x^2+8x+6 with xx in seconds, yy in feet.
    • Vertex: x=b2a=82(2)=2x=-\dfrac{b}{2a}=-\dfrac{8}{2(-2)}=2
    • Vertex value: y=f(2)=2(4)+16+6=14y=f(2)=-2(4)+16+6=14
    • Axis of symmetry: x=2x=2
    • Max value: 1414 (since a<0)
    • Range: (,14](-\infty, 14]
    • Table of Values: compute around the vertex, e.g., at x = 0,1,2,3,4 to illustrate the shape.
  • Connections and relevance

    • The discriminant connects to the nature of the roots and helps decide whether solving numerically is needed.
    • Sum/product relationships connect the roots to the coefficients, enabling construction of quadratic equations from given roots.
    • Vertex form provides a direct link to the graph: vertex location, symmetry, and extremum values, facilitating graphing and optimization tasks.
    • Real-world problems (area, motion) are naturally modeled by quadratic relationships; solving these translates algebra into practical answers.
  • Practical and ethical considerations

    • When applying algebra to real-world problems, respect constraints (e.g., width must be positive in geometry problems).
    • Interpret the domain and physical feasibility of solutions; some mathematical results may be extraneous in real contexts (like negative dimensions).
  • Summary of key formulas to memorize

    • Quadratic Formula: x=b±b24ac2ax=\frac{-b\pm\sqrt{b^2-4ac}}{2a}
    • Discriminant: D=b24acD=b^2-4ac
    • Sum of roots: r<em>1+r</em>2=bar<em>1+r</em>2=-\frac{b}{a}
    • Product of roots: r<em>1r</em>2=car<em>1r</em>2=\frac{c}{a}
    • Vertex: h=b2a,k=4acb24ah=-\frac{b}{2a},\quad k=\frac{4ac-b^2}{4a}
    • Vertex form: f(x)=a(xh)2+kf(x)=a(x-h)^2+k
    • Range indications from vertex and a: if a>0, range begins at kk; if a<0, range ends at kk.
  • Quick reference table (selected results)

    • For f(x)=2x28x+11f(x)=2x^2-8x+11:
    • Vertex: (2,3)(2,3); Vertex form: f(x)=2(x2)2+3f(x)=2(x-2)^2+3
    • Axis: x=2x=2; Min value: 33; Range: [3,)[3,\infty)
    • For the discriminant problems:
    • x^2+4x+5=0\Rightarrow D=-4<0 (imaginary roots)
    • 3x^2-2x-1=0\Rightarrow D=16>0 (real, rational, unequal roots)
  • Note on units and dimensions in word problems

    • Keep track of units (meters, seconds, inches, etc.) and ensure consistency when forming equations.
  • Quick study tips

    • Practice deriving the sum/product relations from the quadratic coefficient structure.
    • Check cases for D to quickly classify roots without solving fully.
    • Use vertex form to quickly identify extremum and axis of symmetry when graphing.
  • References to the material in this review

    • Quadratic Formula and roots; Sum and Product of Roots; Discriminant and Nature of Roots.
    • Rational Algebraic Equations; Quadratic Inequalities.
    • Quadratic Functions: standard form, vertex form, vertex calculations, and graph features.
    • Problem-solving applications and real-world modeling with quadratics.
  • Final notes

    • Practice solving both algebraic and application problems to strengthen connections between formulas and real-world interpretations.