Thermodynamics Lecture Notes

Thermodynamics

Energy Change with Work and Heat

  • The total change in a system's internal energy is expressed as:
    • ΔE=q+w\Delta E = q + w
    • Where:
    • ΔE\Delta E = total change in internal energy
    • qq = energy transferred as heat
    • ww = energy transferred as work
  • The values of qq and ww can either be positive or negative.
  • Sign Convention:
    • The sign of the energy change is determined from the system's perspective:
    • Energy transferred into the system is positive, indicating an increase in energy.
    • Energy transferred out from the system is negative, indicating a decrease in energy.

Energy Transferred as Heat Only

  • If a system transfers energy only as heat and does not do any work (where w=0w = 0), the equation simplifies to:
    • ΔE=q\Delta E = q
    • This means:
    • If heat flows out of the system, qq is negative, indicating that the system is losing heat.
    • If heat flows into the system, qq is positive, indicating that the system is gaining heat.
  • Analogy: Think of money being transferred in and out of a bank account, reflecting heat flow into and out of a system.

Enthalpy

  • Enthalpy (H) is a thermodynamic variable relevant for reactions at constant pressure. It simplifies certain calculations, eliminating the need to measure PV work.
  • The change in enthalpy (ΔH\Delta H) can be defined as:
    • ΔH=ΔE+PΔV\Delta H = \Delta E + P \Delta V
    • Where:
    • ΔE\Delta E = change in internal energy
    • PP = pressure (assumed constant)
    • ΔV\Delta V = change in volume
  • In cases where only heat is transferred, we find:
    • ΔH=qp\Delta H = q_p
    • Meaning the change in enthalpy is equal to heat added or lost at constant pressure.

Calorimetry

  • Specific Heat Capacity (c):
    • The specific heat capacity of a substance is defined as the amount of heat required to raise the temperature of 1 gram of that substance by 1 Kelvin (or 1 °C). The formula for heat transfer is:
    • q=m×c×ΔTq = m \times c \times \Delta T
      • Where:
      • qq = heat gained or lost (in Joules)
      • mm = mass of the substance (in grams)
      • cc = specific heat capacity (in J/gKJ/g \cdot K)
      • ΔT\Delta T = change in temperature (in K or °C)

Coffee-Cup Calorimeter

  • This instrument is designed to measure heat transfer at constant pressure with the following significant assumptions:
    • No heat escapes from the calorimeter (idealized condition).
    • All heat lost from a hot object is gained by the water in the calorimeter until thermal equilibrium is achieved.
  • The heat exchange is modeled as:
    • q<em>sample=q</em>water-q<em>{sample} = q</em>{water}
  • The expression for heat transfer in terms of mass, specific heat, and temperature change can be further broken down:
    • c<em>s=m</em>w×c<em>w×ΔT</em>wm<em>s×ΔT</em>sc<em>s = - \frac{m</em>w \times c<em>w \times \Delta T</em>w}{m<em>s \times \Delta T</em>s}
      • Where:
      • csc_s = specific heat of the sample
      • mwm_w = mass of water
      • cwc_w = specific heat of water (assumed as constant)
      • ΔTw\Delta T_w = change in water temperature
      • msm_s = mass of sample
      • ΔTs\Delta T_s = change in sample temperature

Reaction in the Calorimeter

  • In a chemical reaction within a calorimeter, the heat released by the reaction (qrxnq_{rxn}) must be absorbed by the calorimeter system:
    • q<em>rxn=+q</em>soln-q<em>{rxn} = +q</em>{soln}
  • After the chemical reaction completes, the resultant solution is the only entity capable of absorbing this energy.
  • Thus:
    • The heat generated from the reaction goes into the solution:
    • q<em>rxn,system=q</em>soln,surroundingsq<em>{rxn, system} = - q</em>{soln, surroundings}
  • To calculate qsolnq_{soln}, we utilize the known values of mass, temperature change, and specific heat capacity regarding the solution.

Enthalpy Change of an Aqueous Reaction Example

  1. Example Setup:
    • 50.0 mL of 0.500 M NaOH is mixed with 25.0 mL of 0.500 M HCl in a coffee-cup calorimeter.
    • Both solutions initially at 25.00°C, and final temperature after mixing is 27.21°C.
    • For calculations, assume:
      • Volumes are additive,
      • Density of solution is 1.00 g/mL,
      • Specific heat capacity of solution is 4.184 J/g·K.
  2. Calculation of qsolnq_{soln} (in J):
    • msoln=(50.0extmL+25.0extmL)×1.00 g/mL=75.0extgm_{soln} = (50.0 ext{ mL} + 25.0 ext{ mL}) \times 1.00 \text{ g/mL} = 75.0 ext{ g}
    • Temperature change, ΔTsoln=27.21°C25.00°C=2.21°C=2.21K\Delta T_{soln} = 27.21°C - 25.00°C = 2.21°C = 2.21 K
    • Then:
    • q<em>soln=m</em>soln×c<em>soln×ΔT</em>solnq<em>{soln} = m</em>{soln} \times c<em>{soln} \times \Delta T</em>{soln}
      • So,
      • qsoln=75.0extg×4.184extJ/gK×2.21extK=693extJq_{soln} = 75.0 ext{ g} \times 4.184 ext{ J/g·K} \times 2.21 ext{ K} = 693 ext{ J}
  3. Calculating ΔHrxn\Delta H_{rxn} (in kJ/mol of H2O formed):
    • Given qsoln=693extJq_{soln} = 693 ext{ J},
    • Since this is a coffee-cup calorimeter, by principle, it follows that:
      • q<em>soln=q</em>rxnq<em>{soln} = -q</em>{rxn}
    • Thus, ΔH\Delta H can be computed using moles of water formed.
  4. Balanced Chemical Equation for Reaction:
    • The reaction occurring between NaOH and HCl is:
      • HCl(aq)+NaOH(aq)NaCl(aq)+H2O(l)HCl(aq) + NaOH(aq) → NaCl(aq) + H_2O(l)
    • Molar ratios from the balanced equation become crucial for determining the limiting reagent, which in turn defines how many moles of H2OH_2O are produced.
  5. Calculations of Moles:
    • For 50.0 mL NaOH:
      • 50.0extmL×1extL1000extmL×0.500 mol/L×1extmolH<em>2O1extmolNaOH=0.0250extmolH</em>2O50.0 ext{ mL} \times \frac{1 ext{ L}}{1000 ext{ mL}} \times 0.500 \text{ mol/L} \times \frac{1 ext{ mol } H<em>2O}{1 ext{ mol NaOH}} = 0.0250 ext{ mol } H</em>2O
    • For 25.0 mL HCl:
      • 25.0extmL×1extL1000extmL×0.500 mol/L×1extmolH<em>2O1extmolHCl=0.0125extmolH</em>2O25.0 ext{ mL} \times \frac{1 ext{ L}}{1000 ext{ mL}} \times 0.500 \text{ mol/L} \times \frac{1 ext{ mol } H<em>2O}{1 ext{ mol HCl}} = 0.0125 ext{ mol } H</em>2O
  6. Identifying Limiting Reagent:
    • HCl is the limiting reagent, thus only 0.0125 moles of H2OH_2O can be formed.
  7. Calculating ΔH\Delta H (in kJ/mol):
    • Using the previous findings, we have:
    • If q<em>rxn=693q<em>{rxn} = -693 J (as q</em>solnq</em>{soln} was positive), then:
    • ΔH(kJ/mol)=q<em>rxnmol H</em>2O×1extkJ1000extJ\Delta H \left( kJ/mol \right) = \frac{q<em>{rxn}}{mol \text{ H}</em>2O} \times \frac{1 ext{ kJ}}{1000 ext{ J}}
    • Consequently:
      • ΔH=693extJ0.0125extmolH<em>2O×1extkJ1000extJ=55.4extkJ/molH</em>2O\Delta H = \frac{-693 ext{ J}}{0.0125 ext{ mol H}<em>2O} \times \frac{1 ext{ kJ}}{1000 ext{ J}} = -55.4 ext{ kJ/mol H}</em>2O

Heat Capacity vs Specific Heat Capacity

  • Heat Capacity: Defined as the amount of energy required to increase the temperature of a substance by one degree (K or °C) without regard to mass; thus, it does not depend on mass.
  • Difference from Specific Heat Capacity: Specific heat capacity is defined per unit mass of a substance. Heat capacity may also refer to molar heat capacity, which is the energy required to raise the temperature of one mole of substance by one degree (K or °C).
  • Formula for Heat Capacity:
    • qcal=heat capacity×ΔTq_{cal} = \text{heat capacity} \times \Delta T

Limitations of Coffee-Cup Calorimeter

  • Despite its usefulness for rapid estimates, the coffee-cup calorimeter is not perfect.
    • It does not account for all potential heat losses, as it is based on the assumption that it completely insulates the contents.
  • Correcting factor for heat transfer associated with the calorimeter is given by:
    • q<em>rxn=q</em>soln+qcal-q<em>{rxn} = q</em>{soln} + q_{cal}

Standard Enthalpies of Formation at 25°C

  • For an element in its standard state:
    • ΔHf=0\Delta H_f^\circ = 0
  • Standard states to note:
    • Metals are in solid state (e.g., CaCa)
    • Molecular elements are in their molecular form (e.g., Cl2Cl_2)
    • For elements existing as allotropes, only one form is designated as the standard state (e.g., C(graphite)C(graphite)).

Hess's Law

  • Principle: The total enthalpy change for a reaction is equal to the sum of the enthalpy changes for the individual steps.
    • ΔH<em>overall=ΔH</em>1+ΔH<em>2++ΔH</em>n\Delta H<em>{overall} = \Delta H</em>1 + \Delta H<em>2 + \ldots + \Delta H</em>n
  • Hess's law can be applied to calculate ΔHrxn\Delta H_{rxn} using standard enthalpy of formation values:
    • ΔH<em>rxn=ΣmΔH</em>f(products)ΣnΔHf(reactants)\Delta H<em>{rxn}^\circ = \Sigma m \Delta H</em>f^\circ(products) - \Sigma n \Delta H_f^\circ(reactants)

Experimental Procedures for Coffee-Cup Calorimeter

General Setup
  1. Constraining Structure: Stack two coffee cups and secure a lid on the top. Poke a small hole for a thermometer and avoid contact with the cup.
  2. Stirring Method: Use a glass stirring rod through the lid; remove the rod after stirring. After filling, ensure to keep the lid secured.
Procedure 1: Preparation for Heating Metal
  1. Hot-Water Bath Preparation:
    • Fill a 400-mL beaker with ~300 mL of water and use a magnetic stir bar.
    • Heat to a gentle boil while observing to prevent excessive boiling.
  2. Metal Sample: Weigh the metal sample before submerging in the water bath.
  3. Suspension with Stir Rod: Loop a string around the metal and hang it in the water bath.
Procedure 2: Heat of Solution
  1. Initial Set-Up: Measure 50.0 mL of DI water in a graduated cylinder. Add to the calorimeter.
  2. Temperature Stabilization: Secure the lid and wait for the temperature to stabilize.
  3. Adding Substance: Weigh ~3.2 g of ammonium nitrate (NH₄NO₃) and introduce it quickly to the calorimeter, immediately sealing it.
  4. Final Temperature Recording: Stir gently and record the equilibrated final temperature.
  5. Rinsing: Rinse the calorimeter and dry it after draining.
Procedure 3: Heat of Neutralization for Strong Acid & Strong Base
  1. HCl Preparation: Measure 50.0 mL of 3.0 M hydrochloric acid (HCl) and allow temperature to equilibrate; record Ti,HClT_{i,HCl}.
  2. NaOH Preparation: Measure 50.0 mL of 3.0 M sodium hydroxide (NaOH) and equilibrate; record Ti,NaOHT_{i,NaOH}.
  3. Mixing: Quickly add HCl to the NaOH in the calorimeter, seal immediately, and stir.
  4. Final Temperature Measurement: After equilibrium, record final temperature and drain.
Procedure 4: Heat of Neutralization for Weak Acid & Strong Base
  1. Acetic Acid Preparation: Measure 50.0 mL of 3.0 M acetic acid (HC₂H₃O₂) and equilibrate.
  2. Repeat NaOH Measurement: Do the same with the NaOH and then mix them rapidly.
  3. Final Temperatures: Record final temperature post-reaction and drain solution appropriately.
Procedure 5: Specific Heat of a Metal
  1. Initial Water Setup: Measure 100.0 mL of DI water in the calorimeter, equilibrate, and measure its initial temperature (T<em>i,H</em>2O)(T<em>i, H</em>2O).
  2. Metal Preparation: Right before retrieval, record the boiling water temperature as Ti,metalT_i, metal.
  3. Metal Introduction: Insert the hot metal into the calorimeter, ensure no contact with the thermometer, seal it immediately.
  4. Final Temperature Measurement: Allow to equilibrate, and record final temperature. Upon completion, drain and return all materials to their proper locations.