Notes on Complex Numbers: Addition, Subtraction, Multiplication, Division by Conjugate, and Powers of i

Complex Numbers: Overview, Operations, Division by Conjugate, and Powers of i

  • Definition and notation

    • A complex number is written as z=a+biz = a + bi where:
    • aRa \in \mathbb{R} is the real part
    • bRb \in \mathbb{R} is the imaginary part
    • ii is the imaginary unit with i2=1i^2 = -1
    • Basic idea: separate the real and imaginary components when performing operations
  • Addition and subtraction

    • To add or subtract complex numbers, add/subtract real parts and imaginary parts separately:
    • (a+bi)+(c+di)=(a+c)+(b+d)i(a + bi) + (c + di) = (a + c) + (b + d)i
    • (a+bi)(c+di)=(ac)+(bd)i(a + bi) - (c + di) = (a - c) + (b - d)i
    • Example (conceptual, not from transcript):
    • (3+4i)+(2i)=(3+2)+(41)i=5+3i(3 + 4i) + (2 - i) = (3 + 2) + (4 - 1)i = 5 + 3i
  • Multiplication (FOIL)

    • Multiply as you would polynomials, distributing terms:
    • (a+bi)(c+di)=(acbd)+(ad+bc)i(a + bi)(c + di) = (ac - bd) + (ad + bc)i
    • Intuition: real parts multiply, imaginary parts produce cross terms, and i^2 terms contribute to the real component via i2=1i^2 = -1
    • Example:
    • (3+2i)(1+4i)=(3)(1)+(3)(4i)+(2i)(1)+(2i)(4i)(3 + 2i)(-1 + 4i) = (3)(-1) + (3)(4i) + (2i)(-1) + (2i)(4i)
    • =3+12i2i+8i2=3+10i+8(1)=11+10i= -3 + 12i - 2i + 8i^2 = -3 + 10i + 8(-1) = -11 + 10i
    • Note: in the transcript, there was discussion of using FOIL and recognizing i2=1i^2 = -1, which turns negative terms into real contributions
    • Helpful identity: if you know one factor and its conjugate, you can simplify certain products using the same idea as division (see below)
  • Division by a complex number (conjugate method)

    • To divide by a complex number in the denominator, multiply numerator and denominator by the conjugate of the denominator
    • Conjugate: for a+bia + bi, the conjugate is abia - bi (flip the sign of the imaginary part)
    • Rationale: using (a+bi)(abi)=a2+b2(a + bi)(a - bi) = a^2 + b^2 eliminates the imaginary part in the denominator
    • Procedure:
    • Given ND\dfrac{N}{D} with D=a+biD = a + bi, compute
      • ND=Na+biabiabi=N(abi)(a+bi)(abi)\dfrac{N}{D} = \dfrac{N}{a+bi} \cdot \dfrac{a - bi}{a - bi} = \dfrac{N(a - bi)}{(a+bi)(a-bi)}
      • Denominator becomes real: a2+b2a^2 + b^2
      • Numerator expands to a complex number; you can then separate real and imaginary parts
    • Example from transcript (division):
    • Divide 32i3 - 2i by 7+3i-7 + 3i
    • Multiply numerator and denominator by the conjugate of the denominator 73i-7 - 3i:
      • Denominator: (7+3i)(73i)=(7)2+(3)2=49+9=58(-7 + 3i)(-7 - 3i) = (-7)^2 + (3)^2 = 49 + 9 = 58
      • Numerator:
      • (32i)(73i)=3(7)+3(3i)+(2i)(7)+(2i)(3i)(3 - 2i)(-7 - 3i) = 3(-7) + 3(-3i) + (-2i)(-7) + (-2i)(-3i)
      • =219i+14i+6i2= -21 - 9i + 14i + 6i^2
      • =21+5i+6(1)=27+5i= -21 + 5i + 6(-1) = -27 + 5i
    • Result:
      • 32i7+3i=27+5i58=2758+558i\dfrac{3 - 2i}{-7 + 3i} = \dfrac{-27 + 5i}{58} = -\dfrac{27}{58} + \dfrac{5}{58}i
    • Takeaway: when dividing by a complex number, the conjugate trick eliminates the imaginary part in the denominator and yields a real denominator
  • Powers of i (cyclic behavior)

    • Powers of the imaginary unit follow a 4-term cycle:
    • i1=ii^1 = i
    • i2=1i^2 = -1
    • i3=ii^3 = -i
    • i4=1i^4 = 1
    • Then it repeats: i5=i,i6=1,<br/>7=i,i8=1,i^5 = i, i^6 = -1, <br />\ni^7 = -i, i^8 = 1, \dots
    • There are only four possible results for powers of ii: i,1,i,1i, -1, -i, 1
    • Quick rule: if the exponent is divisible by 4, the result is 11
    • General shortcut: for any integer n0n \ge 0, write n=4k+rn = 4k + r with r0,1,2,3r \in {0,1,2,3}, then
    • in=ir={1amp;if r=0 iamp;if r=1 1amp;if r=2 iamp;if r=3i^n = i^r = \begin{cases} 1 &amp; \text{if } r=0 \ i &amp; \text{if } r=1 \ -1 &amp; \text{if } r=2 \ -i &amp; \text{if } r=3 \end{cases}
    • Example ideas mentioned: determine quickly whether four divides a given exponent by checking remainder modulo 4
    • Connection to real-world use: powers of i underpin Euler's formula and signal processing, but here we focus on the cyclic pattern relevant to solving equations
  • Key observations and practical implications (from transcript context)

    • Addition/subtraction of complex numbers is straightforward: operate on real parts together and imaginary parts together
    • Multiplication via FOIL is direct; watch out for i^2 terms and simplify using i2=1i^2 = -1
    • Division is the most involved operation among the three basic operations due to the need for the conjugate to rationalize the denominator
    • The conjugate technique is a standard tool from algebra that extends naturally to complex numbers
    • The powers of i exhibit a simple, predictable cycle that can be exploited to simplify expressions like ini^n for large exponents
  • Quick reference table (for memorization)

    • Complex number form: z=a+biz = a + bi where a,bRa,b \in \mathbb{R} and i2=1i^2 = -1
    • Addition: (a+bi)+(c+di)=(a+c)+(b+d)i(a + bi) + (c + di) = (a + c) + (b + d)i
    • Subtraction: (a+bi)(c+di)=(ac)+(bd)i(a + bi) - (c + di) = (a - c) + (b - d)i
    • Multiplication: (a+bi)(c+di)=(acbd)+(ad+bc)i(a + bi)(c + di) = (ac - bd) + (ad + bc)i
    • Conjugate of a+bia + bi: abia - bi
    • Division by conjugate: Na+bi=N(abi)a2+b2\dfrac{N}{a + bi} = \dfrac{N(a - bi)}{a^2 + b^2}
    • Powers of i:
    • i4k=1i^{4k} = 1, i4k+1=ii^{4k+1} = i, i4k+2=1i^{4k+2} = -1, i4k+3=ii^{4k+3} = -i
  • Connections to foundational concepts and examples mentioned in the transcript

    • The concept of Real and Imaginary parts aligns with the idea of decomposing a complex number into two orthogonal components
    • The FOIL approach mirrors polynomial multiplication learned earlier, extended to include imaginary terms
    • The conjugate method for division mirrors the technique of rationalizing denominators from algebra, adapted to complex numbers
    • The cyclic nature of i’s powers reflects the underlying structure of complex arithmetic and connects to broader topics such as roots of unity in higher mathematics
  • Quick practice prompts (to reinforce the notes)

    • Compute the product:
    • (5+2i)(34i)(5 + 2i)(3 - 4i)
    • Divide:
    • 3i2+5i\dfrac{3 - i}{-2 + 5i} using the conjugate of the denominator
    • Determine the value:
    • i17i^{17} and explain using the modulo-4 rule
  • Practical takeaway

    • For quick work with complex numbers, memorize the multiplication formula, the conjugate division method, and the i-cycle. These tools let you handle addition, subtraction, multiplication, and division efficiently, and they provide a foundation for more advanced topics in complex analysis and engineering applications.