Electric Potential, Energy & Capacitors – Comprehensive Exam Notes

Electric Potential (V)

  • Conceptual meaning: Ability of a point in an electric field to possess/transfer electrical potential energy.
  • Operational definition:
    • Work WW done by an external agent in moving a positive unit test charge slowly (no acceleration) from infinity to the point against the electro-static force.
    • Mathematical form V=WqV = \frac{W}{q}.
  • Units & dimensional formula
    • SI unit : 1  Volt=1  JouleCoulomb1\;\text{Volt} = 1\;\dfrac{\text{Joule}}{\text{Coulomb}}.
    • Dimension [ML2T3A1][ML^{2}T^{-3}A^{-1}] (because WW is energy [ML2T2][ML^{2}T^{-2}], charge [AT][AT]).
  • Definition of 1 Volt: Potential at a point where 1  J1\;\text{J} of work is needed to bring 1  C1\;\text{C} from infinity.
  • Direction of charge flow
    • Positive charge: from higher VV to lower VV.
    • Negative charge (electrons): from lower VV to higher VV.

Potential difference (PD)

  • For two points A,BA,B
    V<em>AV</em>B=W<em>BAqV<em>A-V</em>B = \frac{W<em>{BA}}{q}, where W</em>BAW</em>{BA} is work by external agent in moving charge from BAB \to A.
  • If one point is at infinity (V<em>=0V<em>\infty = 0), potential at point PP is V</em>P=W<em>Pq=</em>PEdrV</em>P = \frac{W<em>{\infty P}}{q} = -\int</em>{\infty}^{P} \vec E\cdot d\vec r.
  • Example conversion: 1  eV=1.6×1019  J1\;\text{eV}=1.6\times10^{-19}\;\text{J}.

Electric potential due to discrete charges

  • Single point charge +Q+Q at distance rr:
    V=14πε0QrV=\frac{1}{4\pi\varepsilon_0}\,\frac{Q}{r} (positive if Q>0, negative if Q<0).
  • Group of point charges (scalar superposition):
    V=<em>i14πε</em>0q<em>ir</em>iV = \sum<em>i \frac{1}{4\pi\varepsilon</em>0}\,\frac{q<em>i}{r</em>i}.
  • Continuous charge distributions
    • Line: V=14πε0dqrV=\dfrac{1}{4\pi\varepsilon_0}\int \dfrac{dq}{r}
    • Surface: V=14πε0dqrV=\dfrac{1}{4\pi\varepsilon_0}\iint \dfrac{dq}{r}
    • Volume: V=14πε0dqrV=\dfrac{1}{4\pi\varepsilon_0}\iiint \dfrac{dq}{r}.

Electric dipole potential

  • Dipole moment p=q2ı^\vec p = q\,2\ell\,\hat\imath (assuming two charges ±q\pm q separated by 22\ell).
  • On axial line (θ=0\theta = 0, rr \gg \ell):
    V=14πε02pr2V=\frac{1}{4\pi\varepsilon_0}\,\frac{2p}{r^{2}} (positive on +ve-charge side, negative opposite).
  • On equatorial line (θ=90\theta = 90^\circ): V=0V=0 (no work to move charge along this line).
  • General point (rr\gg\ell):
    V=14πε<em>0pcosθr2=pr^4πε</em>0r2V=\frac{1}{4\pi\varepsilon<em>0}\,\frac{p\cos\theta}{r^{2}} = \frac{\vec p\cdot \hat r}{4\pi\varepsilon</em>0 r^{2}}.

Relation between E\vec E and VV

  • For 1-D along xx: Ex=dVdxE_x = -\frac{dV}{dx}.
  • Vector form E=V\vec E = -\nabla V (gradient points from low to high potential; minus sign gives field direction from high to low VV).

Equipotential surfaces

  • Definition: locus of points with same VV (real or imaginary).
  • Properties:
    1. No work in moving charge on the surface (ΔV=0\Delta V=0).
    2. Surfaces form families parallel to each other.
    3. Electric field everywhere perpendicular (90°) to an equipotential surface.
    4. Two equipotentials never intersect.
    5. Perfect conductors are equipotential volumes; entire surface has single potential.

Electric Potential Energy (EPE)

  • Work–energy theorem: external work in assembling configuration = stored potential energy.

Two-charge system

  • Charges q<em>1,q</em>2q<em>1,q</em>2 separated by rr: U=14πε<em>0q</em>1q2rU = \frac{1}{4\pi\varepsilon<em>0}\,\frac{q</em>1 q_2}{r}.
    • U>0 (repulsive) for like charges; U<0 (attractive) for unlike.

Three charges / many charges

  • Total energy = sum over all unique pairs:
    U=<em>i<j14πε</em>0q<em>iq</em>jrijU = \sum<em>{i<j} \frac{1}{4\pi\varepsilon</em>0}\,\frac{q<em>i q</em>j}{r_{ij}}.

Dipole in uniform field

  • Torque: τ=pEsinθ\tau = pE\sin\theta.
  • Work done in rotating from θ<em>1\theta<em>1 to θ</em>2\theta</em>2:
    W=pE(cosθ<em>1cosθ</em>2)W = pE(\cos\theta<em>1-\cos\theta</em>2).
  • Potential energy U=pEcosθU = -pE\cos\theta (minimum when aligned with E\vec E).

Capacitors & Dielectrics

Capacitance (C)

  • Charge-voltage relation Q=CVQ = CV.
  • SI unit 1  Farad=1  CV1\;\text{Farad} = 1\;\dfrac{\text{C}}{\text{V}} (very large; practical units: μF,  nF,  pF\mu\text{F},\;\text{nF},\;\text{pF}).
  • Capacitance depends only on geometry & medium, not on charge or voltage.
Isolated spherical conductor
  • Radius RR: C=4πε0RC = 4\pi\varepsilon_0 R (≈ 1  pF1\;\text{pF} for R9  mR≈9\;\text{m}).
  • Earth (R=6400  kmR=6400\;\text{km}): Cearth710  μFC_{\text{earth}} \approx 710\;\mu\text{F}.
Parallel-plate capacitor
  • Plate area AA, separation dd, vacuum between:
    C=ε0AdC = \varepsilon_0\,\frac{A}{d}.
  • Electric field E=σε0=VdE = \dfrac{\sigma}{\varepsilon_0} = \dfrac{V}{d}.
Dielectric insertion
  • Dielectric constant k(ε<em>r)k (\varepsilon<em>r) increases capacitance by factor kk. C=kC=kε</em>0AdC' = k\,C = k\varepsilon</em>0\,\frac{A}{d}.
  • Electric field inside dielectric E=E0kE = \dfrac{E_0}{k} due to induced charges.
  • Electric susceptibility χ<em>e=k1\chi<em>e = k-1; polarization P=ε</em>0χeE\vec P = \varepsilon</em>0 \chi_e \vec E.
  • Dielectric strength: max sustainable field before breakdown (e.g.
    air \approx 3\times10^{6}\;\text{V·m}^{-1}, mica \approx 3{-}6\;\text{kV·mm}^{-1}).
Partially filled capacitor
  • Slab thickness tt (kk) within gap dd: C=ε0Adt+tkC = \frac{\varepsilon_0 A}{d-t+\dfrac{t}{k}}.
    • Limits:
    • t=0t=0 ⇒ vacuum value;
    • t=dt=d ⇒ completely filled C=kε0AdC=k\varepsilon_0 \dfrac{A}{d};
    • Metallic insert (kk\to\infty): C=ε0A/(dt)C=\varepsilon_0 A/(d-t) (plates effectively closer).
  • Multiple layers t<em>1,t</em>2,t<em>1,t</em>2,\dots with k<em>1,k</em>2,k<em>1,k</em>2,\dots (series of dielectrics):
    1C=d<em>1ε</em>0k<em>1A+d</em>2ε<em>0k</em>2A+\dfrac{1}{C}=\dfrac{d<em>1}{\varepsilon</em>0 k<em>1 A}+\dfrac{d</em>2}{\varepsilon<em>0 k</em>2 A}+\dots.
  • Equal-area parallel arrangement (different dielectrics side-by-side) behaves like capacitors in parallel:
    C=ε<em>0A(k</em>1d+k2d+)C = \varepsilon<em>0 A\Bigg(\frac{k</em>1}{d}+\frac{k_2}{d}+\dots\Bigg).
Energy storage
  • Energy U=12CV2=Q22C=12QVU = \dfrac{1}{2}CV^{2} = \dfrac{Q^{2}}{2C} = \dfrac{1}{2}QV.
  • Energy density in field u=12ε<em>0E2u = \dfrac{1}{2}\varepsilon<em>0 E^{2} (vacuum); with dielectric u=12ε</em>0kE2u = \dfrac{1}{2}\varepsilon</em>0 k E^{2}.
  • Force between parallel plates (opposite charges):
    F=12σ2Aε<em>0=12ε</em>0E2AF = \frac{1}{2}\,\frac{\sigma^{2}A}{\varepsilon<em>0}=\frac{1}{2}\varepsilon</em>0 E^{2}A.

Combinations of capacitors

Series
  • Same charge QQ on each, voltages add: V=V<em>1+V</em>2+V = V<em>1+V</em>2+\dots.
  • Equivalent capacitance 1C<em>eq=1C</em>i\dfrac{1}{C<em>{eq}}=\sum\dfrac{1}{C</em>i} (less than the smallest).
  • Used when high voltage rating required.
Parallel
  • Same voltage across each, charges add: Q=Q<em>1+Q</em>2+Q = Q<em>1+Q</em>2+\dots.
  • Equivalent capacitance C<em>eq=C</em>iC<em>{eq}=\sum C</em>i (greater than largest).
  • Provides large charge storage at given voltage.
Mixed example (3 capacitors 2 µF each in series across 300 V)
  • C<em>eq=23  μFC<em>{eq}=\dfrac{2}{3}\;\mu\text{F}, charge Q=C</em>eqV=2×1063003=2×104  CQ=C</em>{eq}V=2\times10^{-6}\,\tfrac{300}{3}=2\times10^{-4}\;\text{C}, voltage on each =100  V=100\;\text{V}.
Redistribution / common potential
  • Two charged capacitors C<em>1,C</em>2C<em>1,C</em>2 at V<em>1,V</em>2V<em>1,V</em>2 connected together (same polarities):
    • Charge conserved: Q<em>tot=C</em>1V<em>1+C</em>2V2Q<em>{tot}=C</em>1V<em>1+C</em>2V_2.
    • Common potential V=C<em>1V</em>1+C<em>2V</em>2C<em>1+C</em>2V=\dfrac{C<em>1V</em>1+C<em>2V</em>2}{C<em>1+C</em>2}.
    • New charges Q<em>1=C</em>1V,  Q<em>2=C</em>2VQ<em>1=C</em>1V,\;Q<em>2=C</em>2V.
    • Energy loss (converted to heat/spark)
      ΔU=U<em>iU</em>f=C<em>1C</em>22(C<em>1+C</em>2)(V<em>1V</em>2)2\Delta U = U<em>i-U</em>f = \frac{C<em>1C</em>2}{2(C<em>1+C</em>2)}(V<em>1-V</em>2)^2.

Van-de-Graaff Generator (application)

  • Uses mechanical transport of charge (insulating belt, metal combs) to accumulate large charge on a hollow spherical conductor.
  • Potential V=14πε0QRV=\dfrac{1}{4\pi\varepsilon_0}\,\dfrac{Q}{R}; with radius several metres and continual charging, voltages of 10610^6 V achieved (limited by air breakdown).
  • Employed as high-energy particle accelerator (electrostatic) and for X-ray generation.

Surface electric field & corona

  • Surface charge density on conductor σ=ε<em>0E</em>n\sigma = \varepsilon<em>0 E</em>n (normal component).
  • Sharper curvature (smaller radius RR) ⇒ larger EE and σ\sigma; leads to corona discharge (ionisation of surrounding air) causing leakage and sparks.
  • Lightning rods and spherical terminals minimise sharp points to control discharges.

Quick Reference / Numbers

  • ε0=8.854×1012  C2N1m2\varepsilon_0 = 8.854\times10^{-12}\;\text{C}^2\text{N}^{-1}\text{m}^{-2}.
  • Dielectric constants: air ≈ 1.00061.0006, water 80≈80, mica 36≈3{-}6.
  • Dielectric strengths: air ≈3\times10^{6}\,\text{V·m}^{-1}, mica ≈100\,\text{MV·m}^{-1}.
  • 1 electron-volt (eV) =1.602×1019  J=1.602\times10^{-19}\;\text{J}.

These organised points capture every key definition, formula, example, and practical implication from the transcript, providing a full study replacement for the original notes.