AC Circuit Study Notes

Universiti Teknologi MARA (UiTM) - Topic 21: AC Circuit

21.1: Introduction to AC Circuit

  • An AC circuit consists of a combination of circuit elements and an AC generator or source.

  • The output voltage of an AC generator is sinusoidal and varies with time according to the equation: Δv=ΔVmaxsin(2πft)\Delta v = \Delta V_{max} \sin (2\pi f t) where:

    • Δv\Delta v = instantaneous voltage

    • ΔVmax\Delta V_{max} = maximum voltage of the generator

    • ff = frequency at which the voltage changes, measured in Hz

21.2: Resistors in an AC Circuit

21.2.1: Behavior of a Resistor
  • In a simple circuit consisting of an AC source and a resistor:

    • The current (ii) and voltage (ΔV\Delta V) across the resistor reach their maximum values simultaneously.

    • Current and voltage are said to be in phase meaning they oscillate in sync.

21.2.2: Power Dissipation
  • The rate of electrical energy dissipation in the circuit is given by the formula: P=i2RP = i^2 R where:

    • PP = power in watts

    • ii = instantaneous current

    • RR = resistance in ohms

  • The heating effect from an AC current with a maximum value of ImaxI_{max} differs from that of a DC current of the same value.

21.3: rms Current and Voltage

  • The rms (root mean square) current is defined as the direct current that would dissipate the same amount of energy in a resistor as an AC current.

  • Similarly, AC voltages can be expressed in terms of their rms values.

21.3.1: Finding rms Values
  1. The area under the curve of i2i^2 is proportional to the average power dissipation.

  2. The average value of i2i^2 can be expressed as:
    Average value of i2=12Imax2\text{{Average value of }} i^2 = \frac{1}{2}I_{max}^2

21.4: Power in an AC Circuit

  • The average power dissipated across a resistor in an AC circuit carrying a current II is given by:
    P<em>av=I</em>max2RP<em>{av} = I</em>{max}^2 R

21.5: Notation Used in This Chapter

  • Voltage and Current Notations:

    • Instantaneous Voltage: ΔV\Delta V

    • Maximum Voltage: ΔVmax\Delta V_{max}

    • rms Voltage: ΔVrms\Delta V_{rms}

    • Instantaneous Current: ii

    • Maximum Current: ImaxI_{max}

    • rms Current: IrmsI_{rms}

21.6: Ohm’s Law in an AC Circuit

  • Ohm’s Law can be applied in AC circuits using rms values:
    b ΔV<em>R,rms=I</em>rmsR\Delta V<em>{R,rms} = I</em>{rms} R

  • This applies equally to the maximum values of ΔV\Delta V and ii.

Example 21.1: Finding rms Current

  • Problem: An AC voltage source has an output:
    ΔV=(2.00×102V)sin(2πft)\Delta V = (2.00 \times 10^{2} V) \sin(2 \pi f t)
    Connected to a resistor R=1.00×102ΩR = 1.00 \times 10^{2} \Omega. Find the rms voltage and rms current.

  • Solution:

    • Maximum Voltage: ΔVmax=2.00×102V\Delta V_{max} = 2.00 \times 10^{2} V

    • rms Voltage: ΔV<em>rms=ΔV</em>max2\Delta V<em>{rms} = \frac{\Delta V</em>{max}}{\sqrt{2}}

    • rms Current:
      I<em>rms=ΔV</em>rmsRI<em>{rms} = \frac{\Delta V</em>{rms}}{R}

21.7: Power in an RLC Circuit

  • Important Principle:

    • No power loss occurs in pure capacitors and pure inductors.

    • In a pure capacitor, energy is alternately stored and returned to the circuit.

    • In pure inductors, energy is stored when work is done against the back emf, then returned when current decreases.

Example 21.5: Average Power in an RLC Circuit

  • Problem: A series RLC AC circuit has:

    • resistance: R=2.50×102ΩR = 2.50 \times 10^{2} \Omega

    • inductance: L=0.600HL = 0.600 H

    • capacitance: C=3.50μFC = 3.50 \mu F

    • frequency: f=60.0Hzf = 60.0 Hz

    • maximum voltage: ΔVmax=1.50×102V\Delta V_{max} = 1.50 \times 10^2 V

  • Solution:
    To calculate average power:

  • Find the rms current I<em>rmsI<em>{rms} and then use: P</em>av=I<em>rmsΔV</em>rmscosϕP</em>{av} = I<em>{rms} \Delta V</em>{rms} \cos \phi

    • where cosϕ\cos \phi is the power factor.

21.8: Capacitors in an AC Circuit

21.8.1: Charging and Discharging
  • When connected to an AC source, a capacitor allows current to charge its plates but with a time-dependent behavior.

    • Initially, there’s high current; as charge builds, voltage increases and current decreases.

21.8.2: Voltage and Current Behavior
  • In a capacitor, voltage lags behind current by 90 degrees.

21.8.3: Capacitive Reactance
  • The opposition to current flow by a capacitor in AC is termed capacitive reactance, given by:
    XC=12πfCX_C = \frac{1}{2\pi f C}

  • Ohm’s Law for capacitors states:
    ΔV<em>C,rms=I</em>rmsXC\Delta V<em>{C,rms} = I</em>{rms} X_{C}

Example 21.2: Capacitive Circuit Calculations

  • Problem: A circuit with a capacitor C=8.00μFC = 8.00 \mu F connected to an AC generator outputting rms voltage of 1.50×102V1.50 \times 10^2 V at f=60.0Hzf = 60.0 Hz.

  • Solution:
    Calculate capacitive reactance and rms current:

  1. XC=12π(60.0Hz)(8.00×106F)=332ΩX_C = \frac{1}{2\pi (60.0 Hz)(8.00 \times 10^{-6} F)} = 332 \Omega

  2. Use Ohm’s law to find rms current:
    I<em>rms=V</em>C,rmsXC=0.452AI<em>{rms} = \frac{V</em>{C,rms}}{X_C} = 0.452 A

21.9: Inductors in an AC Circuit

21.9.1: Behavior of Inductors
  • The current is impeded due to the back emf generated by the inductor.

  • Voltage across the inductor leads the current by 90 degrees.

21.9.2: Inductive Reactance
  • Inductive reactance is defined as:
    XL=2πfLX_L = 2\pi f L

  • Ohm’s law for inductors indicates that:
    ΔV<em>L,rms=I</em>rmsXL\Delta V<em>{L,rms} = I</em>{rms} X_{L}

Example 21.3: Inductive Circuit Calculations

  • Problem: Consider a purely inductive AC circuit with L=25.0mHL = 25.0 mH and rms voltage of 1.50×102V1.50 \times 10^2 V.

  • Solution:

  1. Find inductive reactance:
    XL=2π(60.0s1)(25.0×103H)=9.42ΩX_L = 2\pi (60.0 s^{-1})(25.0 \times 10^{-3} H) = 9.42 \Omega

  2. Find rms current:
    I<em>rms=1.50×102VX</em>L=15.9AI<em>{rms} = \frac{1.50 \times 10^2 V}{X</em>L} = 15.9 A

21.10: The RLC Series Circuit

21.10.1: RLC Series Configuration
  • The circuit combines resistance, inductance, and capacitance.

  • The current varies sinusoidally over time.

21.10.2: Voltage-Current Relationships
  • Instantaneous voltage across the resistor is in phase with current (90 degrees lead from inductor, 90 degrees lag from capacitor).

Phasor Diagrams

21.11: Diagrams of Voltage Relationships
  • To manage the different voltage phases, phasor diagrams can be used to visually represent voltage in the circuit.

21.12: Calculating Impedance
  • Total impedance (ZZ) represented as:
    Z=R2+(X<em>LX</em>C)2Z = \sqrt{R^2 + (X<em>L - X</em>C)^2}

  • Applied to AC circuits through parts of the Ohm's Law, ΔV<em>max=I</em>maxZ\Delta V<em>{max} = I</em>{max} Z.

21.13: Example for RLC Circuits
  • An example illustrates solving for RLC circuits, considering resistance RR, inductance LL, and capacitance CC in relation to frequency ff and voltage. Materials such as reactance and phase calculation principles apply.

21.14: Resonance in AC Circuits

  • Resonance occurs at a frequency where current achieves its maximum when inductive reactance equals capacitive reactance (X<em>L=X</em>CX<em>L = X</em>C).

  • Phases influence resonance conditions in AC circuits.

  • Examples include radio tuning and metal detectors, demonstrating practical applications of resonance and changes in current due to alterations in circuit characteristics.

Example 21.6: Circuit Resonance Calculation

  • Consider a series RLC circuit, finding capacitance for maximum rms current based on the circuit resistance and inductance parameters.

  • Approach includes applying the resonance frequency calculation, demonstrating effective application of theoretical principles to real-world circuit behavior.