Design of Machine Elements – Comprehensive Bullet-Point Notes

Unit 1 – Introduction to Machine Design

• Definition: Use of scientific principles, technical info & imagination to design machines for specific functions with max economy & efficiency.
• Knowledge required: Maths\text{Maths}, physics, statics & dynamics, thermodynamics, heat transfer, vibrations, fluid dynamics, materials & standard components (from PSG, CMTI, Westermann).

Phases of Machine Design

  1. Need recognition ⇢ problem statement.

  2. Data/specification collection (dimensions, capacity, operating parameters, standards).

  3. Feasibility study (technical + economical).

  4. Mechanism selection.

  5. Force analysis.

  6. Material selection (performance, life, reliability, cost).

  7. Component dimensioning (loads, stresses, failure theories, F.S.\text{F.S.}).

  8. Production drawings (views, dimensions, tolerances, finish, HT).

  9. Prototype & testing.

  10. Final product & feedback loop.

Aesthetic Design

• Appearance reflects function, quality, cost & environment.
• Guidelines: aerodynamic usefulness, reflect speed/strength, economical material use, harmony with environment.
• 12 aspects: Form, Symmetry, Colour (Morgan code), Continuity, Variety, Proportion, Contrast, Impression, Style, Material/Finish, Tolerance, Noise.

Ergonomics

• Man–machine–environment study aiming to fit machine to user.
• Areas: Communication (displays & controls), Working env., Anatomy/posture, Energy expenditure.

Displays

• Qualitative vs quantitative; circular, straight, coloured, digital.
• Design tips: clear scale, Heightdistance200\text{Height} \ge \dfrac{\text{distance}}{200}, linear divisions, numbering direction, pointer knife-edge w/mirror, control below/right.

Controls

• Types: handwheels, cranks, knobs, push-buttons, toggles, joysticks, foot pedals.
• Ergo rules: accessible, minimal motion, shape matches anatomy, colour coding (red danger etc.).

Loads & Stresses

• Loads: Static (gradual, constant), Dynamic (magnitude/direction varies).
• Stresses: σ<em>t,σ</em>c,τ\sigma<em>t,\sigma</em>c, \tau plus crushing σ<em>cr\sigma<em>{cr} and bearing σ</em>b\sigma</em>b.
• Eccentric loading introduces bending + direct.

Stress–Strain Diagram (ductile)

• Proportional limit AA, elastic limit BB, upper/lower yield C,DC,D, ultimate EE, breaking FF, proof stress (0.2% offset).

Fatigue & Endurance

• Cyclic/reversed stresses lead to failure below yield.
• Endurance limit σe\sigma_e: max reversed stress for infinite life (S-N curve).

Failure Theories (ductile vs brittle)

• Max principal stress, max shear stress (Tresca), distortion energy (von Mises).
• ASME factors: k<em>m,k</em>tk<em>m,k</em>t for shock & fatigue.

Factor of Safety

F.S.=σ<em>maxσ</em>working\text{F.S.}=\dfrac{\sigma<em>{\text{max}}}{\sigma</em>{\text{working}}}.
Consider reliability of material, loads, consequences of failure etc.

Stress Concentration

• Caused by abrupt section change, holes, keyways, threads.
• Factor K<em>t=σ</em>max/σnomK<em>t=\sigma</em>{max}/\sigma_{nom}.
• Remedies: fillets, relief holes, under-cut threads, notches.


Unit 2 – Design of Joints & Offset Links

Direct Stress Components

• Pure tension/compression σ=P/A\sigma=P/A.
• Combined bending σb=M/Z\sigma_b=M/Z.

C-Clamp Design (combined tension + bending)

σtotal=Pbt+6Peb2t\sigma_{total}=\dfrac{P}{bt}+\dfrac{6Pe}{b^2t}.
Solve for thickness tt (b=2t). Example gives t40mmt\approx40\,\text{mm}.

Offset Link

Similar; eccentricity e=b/2e=b/2, b=3tb=3t.

Cotter Joint (Socket & Spigot)

• Parameters: d,d<em>1,d</em>2,d<em>3,d</em>4,t,l,c,ad,d<em>1,d</em>2,d<em>3,d</em>4,t,l,c,a.
• Check modes: rod tension Pd/4=σ<em>tPd/4=\sigma<em>t; spigot tearing, cotter shear P=2btτP=2bt\tau, crushing P=bdσ</em>cP=bd\sigma</em>c, socket failure, collars etc.
• Empirical: t0.25d2,  l4dt\approx0.25d_2,\;l\approx4d.

Knuckle Joint

• Parts: eye, fork, pin.
• Proportions: d<em>1=d,  d</em>2=2d,  b=1.25d,  t1=0.75dd<em>1=d,\;d</em>2=2d,\;b=1.25d,\;t_1=0.75d.
• Check rod tension, pin double shear, crushing at eye/fork.

Turn-Buckle

Opposite threads for tensioning rods.
Design for combined shear/tension in rods; nut shear length l=Pπdcτl=\dfrac{P}{\pi d_c \tau}, diameters via bearing & shear.

Lever Design

• Safety-valve lever: forces via moments about fulcrum; size pins (double shear + bearing P=dplpbP=dp\,l\,p_b); lever cross-section rectangular b!3tb!\approx3t; bending σ=M/Z\sigma=M/Z.
• Bell-crank lever ((90^\circ)): resolve loads, reaction at fulcrum, design three pins & arms.


Unit 3 – Shafts & Couplings

Shafts

• Solid vs hollow.
• Torsion T=π16τd3T=\dfrac{\pi}{16}\tau d^3 (solid) ; T=π16τ(d<em>o4d</em>i4)/d<em>oT=\dfrac{\pi}{16}\tau (d<em>o^4-d</em>i^4)/d<em>o (hollow). • Bending M=π32σ</em>bd3M=\dfrac{\pi}{32}\sigma</em>b d^3.
• Combined: τ<em>max=(τ)2+(σ</em>b/2)2\tau<em>{max}=\sqrt{(\tau)^2+(\sigma</em>b/2)^2}; ASME eq. T<em>e=(k</em>tT)2+(kmM)2T<em>e=\sqrt{(k</em>tT)^2+(k_mM)^2}.

Rigidity

θ=TLJGθallow\theta=\dfrac{TL}{JG}\le \theta_{allow}.

Design Examples

Detailed worked problems: power, overhang pulleys, line shafts etc.

Keys

Rectangular: w=0.25d,  t=0.167dw=0.25d,\;t=0.167d.
Shear P=wtlτP=wtl\tau, crushing P=t2wlσ<em>cP=\dfrac{t}{2}wl\sigma<em>c. For equal strength σ</em>c=2τ\sigma</em>c=2\tau.

Couplings

Muff (sleeve): D=2d+15,  L=3.5dD=2d+15,\;L=3.5d.

Check sleeve shear T=τmπ2(D2d2)LT=\tau_m\dfrac{\pi}{2}(D^2-d^2)L.

Flange: hub D=2d,  L=1.5dD=2d,\;L=1.5d; bolts on pitch D13dD_1\approx3d.

Equate T=nP<em>bD</em>1/2T=\sum n P<em>b D</em>1/2 with bolt shear/bearing.

Flexible (bushed-pin): bush bearing W=Pn=p<em>bld</em>2W=\dfrac{P}{n} = p<em>b l d</em>2; pin bending cantilever; combine σ,τ\sigma,\tau.

Unit 4 – Fasteners

Eccentric Bolted Brackets

• Direct shear W<em>s=W/nW<em>s=W/n. • Moment about tilting edge: W</em>iL<em>i=WL\sum W</em>i L<em>i = W L ⇒ load distribution W</em>i=wL<em>iW</em>i=w L<em>i. • Max bolt load W</em>max=W<em>s+wL</em>maxW</em>{max}=W<em>s+w L</em>{max}.
• Check tension σ=W/A<em>c\sigma=W/A<em>c & combined P</em>e=W<em>t2+W</em>s2P</em>e=\sqrt{W<em>t^2+W</em>s^2}.

Welded Joints

• Fillet weld throat t=0.707st=0.707s.
• Strength – single transverse P=0.707slσtP=0.707 s l \sigma_t; double parallel P=1.41slτP=1.41 s l \tau; combined.


Unit 5 – Power Screws

Thread Forms

Square, Acme, Buttress (one-way thrust).
Helix angle α=tan1pπdm\alpha = \tan^{-1}\dfrac{p}{\pi d_m}.

Torque to Raise Load

P=W(tanα+μ)1μtanαP=\dfrac{W( \tan\alpha+\mu)}{1-\mu\tan\alpha} ; T=Pd<em>m2+μ</em>1WRT=P\dfrac{d<em>m}{2}+\mu</em>1WR (collar).
Lowering: denominator 1+μtanα1+\mu\tan\alpha.

Efficiency η=tanαtanα+μ\eta=\dfrac{\tan\alpha}{\tan\alpha+\mu}.
Self-locking when \mu>\tan\alpha.
Stresses

Axial σ=W/A<em>c\sigma=W/A<em>c ; torsional τ=16T/πd</em>c3\tau=16T/\pi d</em>c^3 ; max shear τ<em>max=τ2+(σ/2)2\tau<em>{max}=\sqrt{\tau^2+(\sigma/2)^2}; shear of threads W/(πd</em>cnt)W/(\pi d</em>c n t) ; bearing W/(πdmnt)W/(\pi d_m n t).

Screw Jack Design

Steps: core dia from compression; choose standard pp; compute T,  P<em>handle=T/L</em>hT,\;P<em>{handle}=T/L</em>h; check τ,σ\tau,\sigma; nut height nC<em>0Wπd</em>ctpbn\ge \dfrac{C<em>0 W}{\pi d</em>c t p_b}; collar; body dimensions.


Unit 6 – Springs

Helical Compression Spring (circular wire)

• Mean dia DD, wire dd, index C=D/dC=D/d.
• Wahl factor K=4C14C4+0.615CK=\dfrac{4C-1}{4C-4}+\dfrac{0.615}{C}.
• Shear τ=K8WDπd3\tau=K\dfrac{8WD}{\pi d^3}.
• Deflection δ=8WD3nGd4\delta=\dfrac{8WD^3 n}{G d^4}.
• Rate k=W/δ=Gd48D3nk=W/\delta=\dfrac{G d^4}{8 D^3 n}.

Leaf (Semi-elliptic)

• Bending σ=6WLnbt2\sigma=\dfrac{6WL}{n b t^2}; deflection δ=3WL38Enbt3\delta=\dfrac{3WL^3}{8 E n b t^3}.
• Initial nip C=δ<em>Gδ</em>FC=\delta<em>G-\delta</em>F ; leaf lengths progression li=Li1n1(Ll)l_i=L-\tfrac{i-1}{n-1}(L-l).


Unit 7 – Rolling Bearings

Types

• Ball: deep groove, angular contact, double row, self-aligning, thrust.
• Roller: cylindrical, spherical, needle, tapered.

Basic Numbering (ISO)

XYZ..
– Last two digits ×5 → bore dd (00=10 mm, 01=12 mm, 02=15 mm, 03=17 mm).
– Third digit = diameter series; prefix digit/letters = type (6 = deep-groove etc.).
Suffix letters: sealing (ZZ, 2RS), clearance (C3), etc.

Ratings

• Static C<em>0C<em>0: load giving 0.0001d0.0001d permanent deformation. Safety s</em>0=C<em>0/P</em>0s</em>0=C<em>0/P</em>0.
• Dynamic CC: gives life L<em>10=(CP)p!106L<em>{10}=\left(\dfrac{C}{P}\right)^p!10^6 rev (p = 3 balls, 10/3 rollers). Hours L</em>10h=L1060nL</em>{10h}=\dfrac{L_{10}}{60n}.

Equivalent Loads

P=XF<em>r+YF</em>aP=X F<em>r+Y F</em>a (tables for factors).
Select bearing with CPL101/pC\ge P L_{10}^{1/p}.

Mounting

Cold press for d<80 mm; thermal induction heater to 120!C120\,^{\circ}!\text C; never hammer via balls.

Failure Causes

Poor lubrication, mis-alignment, overload, contamination, vibration Brinelling, high temperature, material defects.

Mounting Do’s/Don’ts

Use fitting sleeves, clean, protect from dust, apply uniform force, heat inner ring only, avoid current passage etc.