calc u2


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1. Tangent Line & Normal Line Formulas



Tangent line equation:

y - y_1 = f’(x_1)(x - x_1)


Normal line equation:


  • Normal line ⟶ perpendicular to tangent line
    \text{slope of normal} = -\frac{1}{f’(x_1)}
    y - y_1 = -\frac{1}{f’(x_1)}(x - x_1)



🧠 Remember:


  • Tangent = same slope as the curve

  • Normal = opposite reciprocal slope






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2. Derivative Notation (dy/dx)



If y = f(x):

\frac{dy}{dx} = f’(x)


When using implicit differentiation, treat y as a function of x — so when you differentiate anything with y, multiply by dy/dx.


Example:

x^2 + y^2 = 25

Differentiate both sides:

2x + 2y\frac{dy}{dx} = 0

Solve for \frac{dy}{dx}:

\frac{dy}{dx} = -\frac{x}{y}





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3. Logarithm Rules (for log differentiation or simplifying before deriv)



Key properties you need:


  1. \ln(ab) = \ln a + \ln b

  2. \ln\left(\frac{a}{b}\right) = \ln a - \ln b

  3. \ln(a^r) = r \ln a

  4. e^{\ln a} = a

  5. \frac{d}{dx}[\ln x] = \frac{1}{x}






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4. Logarithmic Differentiation (used when powers or products are messy)



If y = x^x, take \ln of both sides:

\ln y = \ln(x^x) = x\ln x

Differentiate both sides:

\frac{1}{y}\frac{dy}{dx} = \ln x + 1

Then multiply by y:

\frac{dy}{dx} = x^x(\ln x + 1)


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5. Derivative Rules (what you’ll actually need on tests)



Power Rule:

\frac{d}{dx}[x^n] = n x^{n-1}


Constant Rule:

\frac{d}{dx}[c] = 0


Sum/Difference Rule:

\frac{d}{dx}[f(x) \pm g(x)] = f’(x) \pm g’(x)


Product Rule:

(fg)’ = f’g + fg’


Quotient Rule:

\left(\frac{f}{g}\right)’ = \frac{f’g - fg’}{g^2}


Chain Rule:

If y = f(g(x)), then

\frac{dy}{dx} = f’(g(x)) \cdot g’(x)





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6. Trig Derivatives (must memorize)


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7. How to Remember dy/dx Steps (Implicit/Chain)



Steps:


  1. Differentiate both sides term by term

  2. When you hit y, multiply by \frac{dy}{dx}

  3. Collect all \frac{dy}{dx} terms on one side

  4. Factor it out

  5. Solve for \frac{dy}{dx}



Example:

x^2 + xy + y^2 = 7

Differentiate:

2x + (x\frac{dy}{dx} + y) + 2y\frac{dy}{dx} = 0

Combine:

(x + 2y)\frac{dy}{dx} = - (2x + y)

So,

\frac{dy}{dx} = \frac{-(2x + y)}{x + 2y}