Gas Laws — Gay-Lussac, Charles & Boyle

Fundamental Gas Variables

  • When studying gases we track four core state variables:

    • Pressure, PP, typically measured in atmospheres (atm) in this course, but other units (kPa, Torr) appear in examples.

    • Volume, VV, expressed in liters (L).

    • Temperature, TT, always converted to Kelvin (K) for calculations.

    • Amount of substance, nn, measured in moles (mol).

  • In every gas-law problem, identify which of these variables change and which stay constant.

  • Converting to Kelvin: T<em>(K)=T</em>(C)+273.15T<em>{(K)} = T</em>{(^\circ C)} + 273.15. This keeps all temperatures on an absolute scale so direct and inverse proportionalities work algebraically.

The Ideal-Gas Constant, RR

  • Introduced only by name in this segment; numerical values (e.g. 0.0821  L⋅atm⋅mol1K10.0821\;\text{L·atm·mol}^{-1}\text{K}^{-1}) come later when the Ideal-Gas Equation PV=nRTPV = nRT is derived.

  • Key point: all four simple gas laws discussed here will later “collapse” into the ideal-gas equation once RR is introduced.

Overview of the Four Simple Gas Laws

  • Each law holds two variables constant and relates the other two:

    1. Gay-Lussac’s Law – PP vs. TT (constant VV, nn).

    2. Charles’s Law – VV vs. TT (constant PP, nn).

    3. Boyle’s Law – PP vs. VV (constant TT, nn).

    4. (Mentioned but not yet covered in the clip) Avogadro’s or a variant relating VV and nn at constant P,TP, T.

Gay-Lussac’s Law (Pressure–Temperature Relationship)

  • Qualitative statement: At constant volume and amount, the pressure of a gas is directly proportional to its absolute temperature.

  • Mathematical form used in lecture:
    P<em>1T</em>1=P<em>2T</em>2=k(with V,n constant)\frac{P<em>1}{T</em>1} = \frac{P<em>2}{T</em>2} = k \qquad(\text{with }V,n\text{ constant})

  • The transcript shows a common typo ("P<em>1V</em>1=P<em>2V</em>2P<em>1V</em>1 = P<em>2V</em>2"). Instructor intent is clearly P<em>1/T</em>1=P<em>2/T</em>2P<em>1/T</em>1 = P<em>2/T</em>2 for Gay-Lussac.

  • Graphical idea: Straight line through origin on a PPTT plot (Kelvin).

Worked Example 1 – Propellant in a Hairspray Can
  • Scenario: Can labelled “Do not incinerate. May burst above 120  F120\;^\circ\text{F}.”

  • Data listed:

    • P1=360  kPaP_1 = 360\;\text{kPa}

    • T1=24  C=297.15  KT_1 = 24\;^\circ\text{C} = 297.15\;\text{K}

    • T2=50  C=323.15  KT_2 = 50\;^\circ\text{C} = 323.15\;\text{K}

    • V,nV,n unchanged (the can is sealed). Solve for P2P_2.

  • Calculation:
    P<em>1T</em>1=P<em>2T</em>2    360297.15=P<em>2323.15\frac{P<em>1}{T</em>1} = \frac{P<em>2}{T</em>2} \;\Rightarrow\; \frac{360}{297.15} = \frac{P<em>2}{323.15} P</em>2=391  kPaP</em>2 = 391\;\text{kPa} (rounded in lecture; keep units!).

  • Conceptual takeaway: Heating a sealed can increases pressure—eventually enough to rupture the container (real-world safety relevance).

Worked Example 2 – Cooling Nitrogen Gas
  • Data:

    • V=45  mLV = 45\;\text{mL} (constant)

    • P1=600  TorrP_1 = 600\;\text{Torr}

    • T1=27  C=300  KT_1 = 27\;^\circ\text{C} = 300\;\text{K}

    • T2=73  C=200  KT_2 = -73\;^\circ\text{C} = 200\;\text{K}

  • Setup:
    600300=P<em>2200    P</em>2=400  Torr\frac{600}{300} = \frac{P<em>2}{200} \;\Rightarrow\; P</em>2 = 400\;\text{Torr}

  • Quick-ratio reasoning offered: T<em>2/T</em>1=23T<em>2/T</em>1 = \tfrac{2}{3} so P<em>2=23P</em>1P<em>2 = \tfrac{2}{3}P</em>1.

Conceptual Shortcuts for Direct Proportions
  • If PTP \propto T or VTV \propto T, any fractional change in one variable produces the same fractional change in the other.

  • Instructor encourages mental checks but still wants full algebra shown in formal work.

Charles’s Law (Volume–Temperature Relationship)

  • Statement: At constant pressure and amount, volume is directly proportional to absolute temperature.

  • Formula:
    V<em>1T</em>1=V<em>2T</em>2\frac{V<em>1}{T</em>1} = \frac{V<em>2}{T</em>2}

  • Example Prompt (CO$_2$):

    • Given: V<em>1=0.300  L,  T</em>1=10  CV<em>1 = 0.300\;\text{L},\;T</em>1 = 10\;^\circ\text{C}, P=750  TorrP = 750\;\text{Torr} (constant).

    • Find V<em>2V<em>2 at T</em>2=30  CT</em>2 = 30\;^\circ\text{C}.

    • Students instructed to convert to Kelvin, plug into the formula, and report the answer in liters (same unit supplied).

  • Additional practice problems follow the same template; rule of thumb reiterated: the unit of your final answer should match the unit initially provided, even if intermediate conversions were needed.

Boyle’s Law (Pressure–Volume Relationship)

  • Statement: At constant temperature and amount, pressure of a gas is inversely proportional to its volume.

  • Algebraic form:
    P<em>1V</em>1=P<em>2V</em>2P<em>1V</em>1 = P<em>2V</em>2

  • Conceptual example provided (no numbers): “If the volume is cut in half, the pressure must double.”

  • Inverse relationship means a hyperbolic curve on a PPVV plot.

General Problem-Solving Strategy Highlighted by Instructor

  • 1 – List given and unknown quantities with units (e.g. P<em>1,T</em>1,P<em>2,T</em>2P<em>1, T</em>1, P<em>2, T</em>2).

  • 2 – Convert temperatures to Kelvin; convert other units only when mixing incompatible units (kPa vs Torr vs atm).

  • 3 – Select the correct law (look at which variables are stated as “the same” or “unchanged”).

  • 4 – Insert data into the proportionality or cross-multiplication form.

  • 5 – Solve algebraically and include units in every step.

  • 6 – Perform a quick reasonableness check (direct vs inverse trends, fraction logic, significant-figure sanity).

Unit Conversions & Notation Tips

  • Pressure:

    • 1  atm=760  Torr=101.325  kPa1\;\text{atm} = 760\;\text{Torr} = 101.325\;\text{kPa} (useful when you must change units to match RR in the ideal-gas equation later).

  • Temperature: add 273.15273.15 to go from C^\circ\text{C} to K; subtract to reverse.

  • Volume: 1000  mL=1  L1000\;\text{mL} = 1\;\text{L}. Keep eye on mL vs L; Charles’s & Boyle’s laws work with any consistent volume unit as long as the ratio is preserved.

Connections to Broader Topics

  • These simple laws stem from the Kinetic Molecular Theory (discussed in earlier lectures): temperature reflects average kinetic energy; pressure arises from molecular collisions; changing volume alters collision frequency.

  • Ethical / safety implication: Warnings on aerosol cans are grounded in Gay-Lussac’s Law—heating a sealed container raises internal pressure and can cause dangerous ruptures.

  • Mathematically, combining the three empirical laws gives the Combined Gas Law P<em>1V</em>1T<em>1=P</em>2V<em>2T</em>2\frac{P<em>1V</em>1}{T<em>1}=\frac{P</em>2V<em>2}{T</em>2}, which leads directly to the Ideal-Gas Equation once nRnR is introduced.


These notes encapsulate every numerical example, formula, shortcut, and conceptual remark provided in the transcript, formatted for quick review before an exam.