Stoichiometry and Molar Mass Notes

Stoichiometry Introduction

  • Stoichiometry involves quantitative relationships and ratios.

  • It connects knowledge of formulas, the periodic table, and dimensional analysis.

  • If given 50 grams of a substance, molar mass can be used to find moles.

  • Example: Molar mass of H2H_2 is 2.0162.016 grams per mole.

  • Mole to mole ratio: 2 moles of H<em>2OH<em>2O for every 2 moles of H</em>2H</em>2 burned.

  • Molar mass of H2OH_2O is 18.01618.016 grams per mole.

  • Quantitative relationships allow determining the amount of product formed from a given amount of reactant.

  • Balancing chemical equations correctly is crucial; otherwise, everything gets messed up.

  • Stoichiometry is more complex than simply adding masses; the numbers in the balanced equation matter.

Atomic and Molar Mass

  • Atomic mass is measured in AMUs (atomic mass units), which are too small for practical use.

  • A mole is a unit, similar to a dozen, but represents an astronomically large number.

  • One mole of a substance is equal to 6.022×10236.022 \times 10^{23} particles (Avogadro's number).

  • Analogy: Having 6.022×10236.022 \times 10^{23} dollars and spending a million dollars every second for 100 years, you would still have enough money to give everyone on the planet a million dollars.

  • Moles are more useful than individual atomic masses because atoms are so small.

  • Molar mass is the mass in grams of one mole of a substance.

  • Units of molar mass are grams per mole (g/mol).

  • Molar masses are found on the periodic table as the numbers with decimal places.

  • Molar mass is used to "count" atoms by weighing them, similar to how candy is charged per pound rather than per piece.

Calculating Molar Mass

Example: Calcium Carbonate (CaCO3CaCO_3)

  1. Identify the number of each element in the compound:

    • 1 Calcium (Ca)

    • 1 Carbon (C)

    • 3 Oxygens (O)

  2. Find the molar mass of each element on the periodic table:

    • Ca: ~40.078 g/mol (rounded to 40 for simplicity in the example)

    • C: 12.011 g/mol

    • O: 15.999 g/mol (rounded to 16 for simplicity in the example)

  3. Multiply the molar mass of each element by the number of atoms of that element in the compound:

    • Ca: 1×40=401 \times 40 = 40 g/mol

    • C: 1×12.011=12.0111 \times 12.011 = 12.011 g/mol

    • O: 3×16=483 \times 16 = 48 g/mol

  4. Add the results together to find the molar mass of the compound:

    • 40+12.011+48=100.01140 + 12.011 + 48 = 100.011 g/mol

Comparison of Atomic Mass and Molar Mass

  • Atomic mass (AMU): Mass of a single atom at the atomic level.

  • Molar mass (grams): Mass of one mole of a substance at the macroscopic level.

Example: Sulfuric Acid (H<em>2SO</em>4H<em>2SO</em>4)

  1. Identify the number of each element in the compound:

    • 2 Hydrogen (H)

    • 1 Sulfur (S)

    • 4 Oxygens (O)

  2. Find the molar mass of each element on the periodic table:

    • H: ~1 g/mol

    • S: ~32.06 g/mol

    • O: ~16 g/mol

  3. Multiply the molar mass of each element by the number of atoms of that element in the compound:

    • H: 2×1=22 \times 1 = 2 g/mol

    • S: 1×32.06=32.061 \times 32.06 = 32.06 g/mol

    • O: 4×16=644 \times 16 = 64 g/mol

  4. Add the results together to find the molar mass of the compound:

    • 2+32.06+64=98.062 + 32.06 + 64 = 98.06 g/mol

Example: Water (H2OH_2O)

  • 2 Hydrogens: 2×1=22 \times 1 = 2 g/mol

  • 1 Oxygen: 1×16=161 \times 16 = 16 g/mol

  • Molar mass of H2OH_2O: 2+16=182 + 16 = 18 g/mol

Example: Chloroform (CHCl3CHCl_3)

  • 1 Carbon: 1×12.011=12.0111 \times 12.011 = 12.011 g/mol

  • 1 Hydrogen: 1×1.008=1.0081 \times 1.008 = 1.008 g/mol

  • 3 Chlorines: 3×35.453=106.3593 \times 35.453 = 106.359 g/mol

  • Molar mass of CHCl3CHCl_3: 12.011+1.008+106.359=119.37812.011 + 1.008 + 106.359 = 119.378 g/mol

Example: Ibuprofen (C<em>13H</em>18O2C<em>{13}H</em>{18}O_2)

  • 13 Carbons: 13×12.011=156.14313 \times 12.011 = 156.143 g/mol

  • 18 Hydrogens: 18×1.008=18.14418 \times 1.008 = 18.144 g/mol

  • 2 Oxygens: 2×15.999=31.9982 \times 15.999 = 31.998 g/mol

Molar mass of Ibuprofen: 206.285 g/mol

Example: Aluminum Sulfate (Al<em>2(SO</em>4)3Al<em>2(SO</em>4)_3)

  • 2 Aluminum: 2×26.98=53.962 \times 26.98 = 53.96 g/mol

  • 3 Sulfurs: 3×32.06=96.183 \times 32.06 = 96.18 g/mol

  • 12 Oxygens: 12×15.999=191.98812 \times 15.999 = 191.988 g/mol

  • Molar mass of Al<em>2(SO</em>4)3Al<em>2(SO</em>4)_3: 342.128 g/mol

Examples of Determining Molar Mass
  1. Carbon Monoxide (CO): 1 Carbon + 1 Oxygen = ~ 29 grams/mole . (12 +16 =28)

  2. Sulfur Trioxide (SO3SO_3): ~ 84 grams/mole

  3. Ammonium Sulfate ((NH<em>4)</em>2SO4(NH<em>4)</em>2SO_4): ~ 132 grams/mole

  4. Oxygen Gas (O2O_2): ~ 32 grams/mole .

  5. Silver Nitrate (AgNO3AgNO_3): ~170 grams per mole

It is important to write molar masses with correct units (grams/mole).