Topic 4 – Gases in Solution & Colligative Properties

Significant Figures

  • Definition: digits in a measured number that convey meaningful information about its precision.

  • Rule set (Figure 3.20):

    • All non-zero digits are always significant.

    • Zeros – significance depends on position:

    • Between non-zero digits ⇒ significant

      • Examples: 704 (3 s.f.), 5.02 (3 s.f.), 173.05 (5 s.f.)

    • Trailing zeros in a number containing a decimal point ⇒ significant

      • 0.5000.500 (3 s.f.); 25.16025.160 (5 s.f.); 3.003.00 (3 s.f.)

    • Leading zeros before the first non-zero digit ⇒ NOT significant (placeholders)

      • 0.009210.00921 (3 s.f.); 0.025010.02501 (4 s.f.)

    • Trailing zeros with no decimal point ⇒ ambiguous; use scientific notation to clarify

      • 10001000 could have 1–4 s.f.; write as 1×103,  1.0×103,  1.00×103,  1.000×1031 \times 10^{3},\;1.0 \times 10^{3},\;1.00 \times 10^{3},\;1.000 \times 10^{3}

      • 5905905.9×1025.9 \times 10^{2} (2 s.f.) or 5.90×1025.90 \times 10^{2} (3 s.f.)

  • Exact numbers (counting quantities, unit definitions) have infinite significant figures and zero uncertainty.

Applying Significant Figures in Calculations (Figure 3.21)

  • Multiplying a measurement by a constant ⇒ answer keeps the same number of s.f. as the measurement.

  • Multiplication/Division of two or more measurements ⇒ answer limited by the least precise (fewest s.f.).

  • Addition/Subtraction ⇒ match the smallest number of decimal places among operands.

  • Logarithms/Antilogarithms ⇒ number of digits to the right of the decimal in result equals number of s.f. in original number.

Thermodynamics of Dissolution – Gases in Gases

  • Governing equation: ΔG=ΔHTΔS\Delta G = \Delta H - T\Delta S

  • For mixing ideal gases:

    • ΔH0\Delta H \approx 0 (enthalpy change negligible).

    • Positive entropy change \big(\Delta S > 0\big) drives spontaneity ⇒ \Delta G < 0.

    • Diffusion results because disorder increases.

Thermodynamics of Dissolution – Gases in Liquids

  • ΔG=ΔHTΔS\Delta G = \Delta H - T\Delta S still applies, but enthalpy now matters.

  • ΔsolH\Delta_{sol}H (enthalpy of solution) can be endothermic or exothermic depending on solvent–solute interactions.

  • Entropy term often still favourable (gas spreads through liquid), but may not overcome large positive ΔsolH\Delta_{sol}H.

Energetics & Mechanistic Steps of Dissolution in Organic Solvents

  • Two-step conceptual model (Figures with AH₁ and AH₂):

    1. Expand solvent to create cavities (endothermic, \Delta H_1>0).

    2. Mix gaseous solute with expanded solvent (often exothermic, \Delta H_2<0).

  • Net ΔsolH=ΔH1+ΔH2\Delta{sol}H = \Delta H1 + \Delta H_2 can be positive (overall endothermic) or negative.

  • Dissolution requires more energy when solvent–solvent interactions are strong (harder to separate molecules). Mentimeter poll reinforced this.

“Like Dissolves Like” Principle

  • Polar solvents (e.g., water, ethanol) dissolve polar or ionic solutes; non-polar solvents (e.g., hexane) dissolve non-polar solutes.

  • Ethanol structure: polar OH plus non-polar alkyl → good at dissolving a range of species.

  • Demonstration: Water > Ethanol > Hexane for dissolving table salt.

nhn Product (Ksp)

  • Heterogeneous equilibrium constant for sparingly soluble ionic solids.

  • General form: AmBn(s)mAn+(aq)+nBm(aq)\text{A}m\text{B}n(s) \rightleftharpoons m\,\text{A}^{n+}(aq) + n\,\text{B}^{m-}(aq)
    Ksp=[An+]m[Bm]nK_{sp}= [\text{A}^{n+}]^{m}[\text{B}^{m-}]^{n} (solid excluded from expression).

  • Use symbol ss for molar solubility (instead of xx).

  • Examples:

    • BaSO4(s)Ba2++SO42\text{BaSO}{4}(s) \rightleftharpoons \text{Ba}^{2+}+\text{SO}{4}^{2-}
      Ksp=[Ba2+][SO42]K{sp}= [\text{Ba}^{2+}][\text{SO}{4}^{2-}]

    • PbI2(s)Pb2++2I\text{PbI}{2}(s) \rightleftharpoons \text{Pb}^{2+}+2\text{I}^- Ksp=[Pb2+][I]2K{sp}= [\text{Pb}^{2+}][\text{I}^-]^{2}

  • Worked example (Medical barium meal):

2.45 mg BaSO4\text{BaSO}_4 dissolves in 1 L at 25C25\,^{\circ}\text{C}.

n=0.00245g233.37g⋅mol1=1.05×105moln = \frac{0.00245\,\text{g}}{233.37\,\text{g·mol}^{-1}} = 1.05\times10^{-5}\,\text{mol}
s=1.05×105Ms = 1.05\times10^{-5}\,\text{M}

  • Ksp=s2=1.10×1010K_{sp}=s^{2}=1.10\times10^{-10}

Common Ion Effect

  • Presence of a shared ion suppresses solubility.

  • Conceptual analogy: harder to dissolve sugar in honey (already concentrated).

  • Example problem (SnF₂ in 0.30 M NaF):

    • SnF2(s)Sn2++2F\text{SnF}_{2}(s) \rightleftharpoons \text{Sn}^{2+} + 2\text{F}^-

    • ICE table with initial [F]=0.30M[\text{F}^-]=0.30\,\text{M}.

    • Ksp=3.6×108=s(0.30)2K_{sp}=3.6\times10^{-8}=s(0.30)^{2}s=4.0×107Ms=4.0\times10^{-7}\,\text{M} (dramatic decrease vs pure water).

Colligative Properties – Overview

  • Depend solely on solute particle concentration, not identity (must be non-volatile solute):

    • Freezing point depression (ΔTₒ lower).

    • Boiling point elevation (ΔTᵦ higher).

    • Vapour pressure lowering.

    • Osmotic pressure.

  • Expressed using molality bb because mass of solvent (kg) is temperature-independent.

Raoult’s Law – Vapour Pressure Lowering

  • Psolution=xsolventPsolventP{solution}=x{solvent}P_{solvent}^{\ast}

    • PsolutionP_{solution} = vapour pressure of solution.

    • xsolventx_{solvent} = mole fraction of solvent.

    • PsolventP_{solvent}^{\ast} = vapour pressure of pure solvent.

  • Vanilla extract example: Water–ethanol mixture at 20C20^{\circ}\text{C} with xwater=0.9x{water}=0.9, Pwater=2.3kPaP^{\ast}{water}=2.3\,\text{kPa}Psolution=2.07kPaP_{solution}=2.07\,\text{kPa}.

  • Dead Sea calculation (32 % w/w NaCl):

    • In 100 g solution: 68 g water (3.78 mol); 32 g NaCl (0.548 mol).

    • xwater=3.783.78+0.548=0.873x_{water}=\frac{3.78}{3.78+0.548}=0.873.

    • Psolution=0.873×2.3kPa=2.01kPaP_{solution}=0.873\times2.3\,\text{kPa}=2.01\,\text{kPa}.

Freezing Point Depression & Boiling Point Elevation

  • Equations:

    • ΔTf=Kfb\Delta Tf = Kf\,b (negative sign indicates lowering).

    • ΔTb=Kbb\Delta Tb = Kb\,b.

  • Road-salt example (MgCl₂ for –10 °C streets):

  • Desired ΔTf=10C\Delta T_f = 10\,^{\circ}\text{C}.

  • Kf(water)=1.86C⋅kg⋅mol1K_f\,(water)=1.86\,^{\circ}\text{C·kg·mol}^{-1}.

b=101.86=5.376mol⋅kg1b=\frac{10}{1.86}=5.376\,\text{mol·kg}^{-1}.
  • Molar mass MMgCl2=95.21g⋅mol1M{\text{MgCl}2}=95.21\,\text{g·mol}^{-1} ⇒ need m=511.9gm=511.9\,\text{g} per kg of water.

Osmotic Pressure

  • Semipermeable membrane allows solvent through, not solute.

  • Osmotic pressure (π) opposes further solvent flow.

  • Conceptual apparatus: solution side B rises until hydrostatic pressure equals π.

  • Formula (ideal dilute): π=iRTc\pi = iRTc where ii is van ’t Hoff factor, RR universal gas constant, TT absolute temperature, cc molarity.

Practice & Conceptual Connections

  • Mentimeter polls used for real-time checks: entropy questions, dissolution energetics, “easiest to dissolve,” definition of solute, saturated solutions.

  • Kitchen-chemistry proposal: Determine maximum sugar mass that still allows an icy-pole to freeze; must consider colligative freezing-point depression.

    • Required data/equipment: accurate mass balance, volumetric flasks, freezer with stable temperature, thermometer.

    • Errors: measurement uncertainty, temperature fluctuations, supercooling.

Study & Exam Tips

  • Work through remaining Topic 4 materials before next class.

  • Complete Topic 3 & 4 quizzes promptly.

  • Keep a separate sheet summarising all K<em>spK<em>{sp} values and K</em>f/KbK</em>f/K_b constants provided.

  • Practise setting up ICE tables quickly; watch significant-figure rules when reporting answers.

  • Connect thermodynamic concepts (ΔG, ΔH, ΔS) to observable solution behaviour.