Key Exam Notes: Algebra, Equations, Indices, Measurement, and Quadratics

Algebra Review

  • Like Terms: Add/subtract like terms only (e.g., 2x+4x+y=6x+y2x + 4x + y = 6x + y).

  • Multiplication: 3x×2y=6xy3x \times 2y = 6xy

  • Division: 4ab÷(2b)=2a4ab \div (2b) = 2a

  • Expansion: a(b+c)=ab+aca(b + c) = ab + ac, a(bc)=abaca(b - c) = ab - ac

  • Solving Linear Equations: Use inverse operations and collect like terms.

Algebraic Fractions

  • Addition/Subtraction: Find a common denominator.

    • E.g., 2x+3+13=3(x+3)+2(x+1)6=5x+116\frac{2}{x + 3} + \frac{1}{3} = \frac{3(x + 3) + 2(x + 1)}{6} = \frac{5x + 11}{6}

  • Solving Equations: Combine fractions, then multiply both sides by the denominator.

Linear Inequalities

  • Solving: Solve as linear equations, but reverse the inequality symbol when multiplying or dividing by a negative number.

  • Graphing: Represent solutions on a number line.

Graphs of Linear Relations

  • Form: y=mx+cy = mx + c, where mm is the gradient and cc is the y-intercept.

  • Graphing: Use the gradient and y-intercept, or locate x-intercept (y=0)(y = 0) and y-intercept (x=0)(x = 0).

Regions on the Cartesian Plane

  • Inequalities represent regions above or below a line.

  • Shade above the line for \geqslant, use a dashed line for > .

  • Test (0,0)(0, 0) to decide which region to shade for inequalities like 2x + 3y < 6.

Midpoint and Length

  • Midpoint: M=(x<em>1+x</em>22,y<em>1+y</em>22)M = (\frac{x<em>1 + x</em>2}{2}, \frac{y<em>1 + y</em>2}{2})

  • Length/Distance: d=(x<em>2x</em>1)2+(y<em>2y</em>1)2d = \sqrt{(x<em>2 - x</em>1)^2 + (y<em>2 - y</em>1)^2}

Parallel and Perpendicular Lines

  • Parallel: Same gradient (e.g., y=2x+7y = 2x + 7 and y=2x4y = 2x - 4).

  • Perpendicular: Gradients m<em>1m<em>1 and m</em>2m</em>2 satisfy m<em>1×m</em>2=1m<em>1 \times m</em>2 = -1

Finding a Line Equation

  • Use y=mx+cy = mx + c or yy<em>1=m(xx</em>1)y - y<em>1 = m(x - x</em>1).

  • Find the gradient and y-intercept, or substitute a point if cc is unknown.

Simultaneous Equations

  • Solve using substitution (when one pronumeral is the subject) or elimination (adding/subtracting multiples to eliminate a variable).

Exponential Equations

  • If ax=aya^x = a^y, then x=yx = y.

Scientific Notation

  • Numbers in the form * a x 10^m*, where 1 \leqslant a < 10 or -10 < a \leqslant -1, and mm is an integer.

Index Laws

  • Multiply: am×an=am+na^m \times a^n = a^{m+n}

  • Divide: am÷an=amna^m \div a^n = a^{m-n}

  • Power of a Power: (am)n=amn(a^m)^n = a^{mn}

  • Product to a Power: (ab)m=ambm(ab)^m = a^m b^m

  • Quotient to a Power: (a/b)m=am/bm(a/b)^m = a^m / b^m

Zero and Negative Indices

  • Zero index: a0=1,a0a^0 = 1, a \ne 0

  • Negative index: am=1ama^{-m} = \frac{1}{a^m}

Fractional Indices

  • a1n=ana^{\frac{1}{n}} = \sqrt[n]{a}

Logarithms

  • Definition: logay=xlog_a y = x is equivalent to ax=ya^x = y, where a > 0

  • Log law for addition: log<em>ax+log</em>ay=loga(xy)log<em>a x + log</em>a y = log_a (xy)

  • Log law for subtraction: log<em>axlog</em>ay=loga(xy)log<em>a x - log</em>a y = log_a (\frac{x}{y})

  • Log law involving powers: log<em>axn=nlog</em>axlog<em>a x^n = n log</em>a x

Compound Interest

  • Formula: A=P(1+r100)nA = P(1 + \frac{r}{100})^n

    • where:

    • A (amount): total value

    • P (principal): initial amount

    • r (interest rate): per period

    • n (period): number of periods

Chapter 4: Measurement and Surds

Simplifying Surds (10A)

  • Use the highest square factor to simplify surds (e.g., 12=23\sqrt{12} = 2\sqrt{3}).

  • Rationalise the denominator to express with a whole number in the denominator (e.g., 25=255\frac{2}{\sqrt{5}} = \frac{2\sqrt{5}}{5}).

  • Add/Subtract like surds only.

  • Multiply/Divide surds using the rule x×=xy\sqrt{x} \times=\sqrt{xy}

Pythagoras theorem

c2=a2+b2c^2= a^2 + b^2

Circle

Circumference =2πr=πd2\pi r = \pi d
Area= πr2\pi r^2

Chapter 5: Quadratic expressions and equations

Quadratic formula

If ax2+bx+c=0ax^2 + bx + c = 0 , then
x=b±b24ac2ax=\frac{-b \pm \sqrt{b^2 -4ac}}{2a}

The discriminant

Δ=b24ac\Delta = b^2 - 4ac

  • If \Delta>0 Two solutions
    -If Δ=0\Delta=0 One solutions
    -If \Delta<0 Zero solutions
    ## Factorising
    Factorising and Difference of two squares
    a2b2=(ab)(a+b)a^2 - b^2 = (a-b)(a+b)

Applications

1 Define the variable

  1. Set up the equation

  2. Solve by factorising and using the Null Factor Law or quadratic formula

  3. Determine the suitable answer(s)