CFR 14
Chemical Equilibrium
- Definition: Chemical equilibrium exists when the rates of the forward and reverse reactions are equal, and the concentrations of reactants and products remain constant.
- Concepts:
- Reactants convert to Products and vice versa.
- Dynamic process where both reactions occur simultaneously.
Equilibrium Constant (K)
- General Form:
- For a reaction: "aA + bB ⇌ cC + dD"
- K = [C]^c [D]^d / [A]^a [B]^b (where concentrations are raised to the power of their respective coefficients)
- Characteristics:
- K is unit-less and dependent on temperature.
Equilibrium Constant Expressions
Solids in Reactions:
The concentration of solids does not change and is therefore not included in the equilibrium expression.
Example: For the reaction: Fe(s) + 5CO(g) ⇌ Fe(CO)5(g), K = [Fe(CO)5]/[CO]^5
Liquids in Reactions:
Similar to solids, pure liquids are also excluded from equilibrium expressions due to constant density.
Example: CH3CO2H + H2O ⇌ CH3COO- + H3O+, therefore K = [CH3COO-][H3O+]
Forward and Reverse Reactions Relationship
- Equation: Kfor = 1/Krev
- Example: For the reaction SO2 + O2 ⇌ SO3, Kfor = [SO3]^2 / ([SO2]^2[O2]) and Krev = 1 / K_for.
Interpreting Equilibrium Constants
- K >> 1: Indicates a reaction that favors products.
- K << 1: Indicates a reaction that favors reactants.
- Example at 25°C: CH3CO2H + H2O (K = 1.8 x 10^-5) vs. 2H2 + O2 ⇌ 2H2O (K = 3.5 x 10^81).
Le Chatelier’s Principle
- Concept: If a system at equilibrium experiences a change (stress), the system will adjust to counteract the change and restore equilibrium.
- Types of Stress:
- Change in concentration of reactants/products.
- Change in pressure/volume for gaseous reactions.
- Change in temperature.
Solubility Product (Ksp)
- Definition: Ksp is the equilibrium constant for the dissolution of a solid substance.
- General Form: e.g., for CaF2 ⇌ Ca^2+ + 2F^-, Ksp = [Ca^2+][F^-]^2.
- Greater surface area of the solid can lead to greater solubility, hence influencing Ksp.
Factors Influencing Solubility
Common Ion Effect
- Adding a common ion decreases solubility.
- Example: Adding AgNO3 reduces the solubility of Ag2CrO4 in a solution with Ag+ ions already present.
pH Influence
- Changes in pH influence solubility for certain compounds:
- Increasing [OH-] can shift equilibrium leftward, reducing solubility (e.g., Mg(OH)2).
- Decreasing [OH-] increases solubility by shifting equilibrium rightward.
Applications in Biological and Pharmaceutical Systems
- Understanding Ksp is crucial for drug solubility in biological systems versus formulations requiring specific solubility characteristics (e.g., suspensions with barium sulfate).
- Fluoridation prevents tooth decay by forming a more soluble fluorapatite compared to hydroxyapatite under acidic conditions.
Calculating Molar Solubility
- Example with PbI2:
- Ksp: 7.1 x 10^-9, derived from dissolution: PbI2 ⇌ Pb^2+ + 2I^-
- Let "s" be molar solubility: Ksp = (s)(2s)^2 = 7.1 x 10^-9 generates results leading to s = 1.2 x 10^-3.
Summary of Learning Outcomes
- Understand and define the solubility product, calculate it from molar solubility, and recognize the common ion effect and pH influence on solubility.